A329335 Continued fraction of A328905 = 0.5638955242599..., solution to 1 + 2^x = 5^x.
0, 1, 1, 3, 2, 2, 2, 1, 3, 3, 1, 5, 3, 1, 1, 3, 1, 1, 6, 1, 36, 20, 18, 3, 1, 3, 2, 1, 2, 9, 3, 2, 1, 1, 1, 2, 7, 1, 1, 5, 1, 112, 2, 1, 6, 2, 1, 1, 1, 1, 2, 44, 1, 2, 3, 70, 1, 1, 1, 12, 3, 1, 5, 6, 1, 1, 10, 4, 4, 2, 3, 1, 7, 1, 4, 1, 1, 1, 5, 2, 1, 5, 1, 4, 3, 1, 1, 1, 1, 2, 1, 1, 4, 6, 7, 2
Offset: 0
Examples
0.5638955242599... = 0 + 1/(1 + 1/(1 + 1/(3 + 1/(2 + 1/(2 + 1/(2 + 1/...))))))
Crossrefs
Programs
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PARI
contfrac(c=solve(x=0,1, 1+2^x-5^x))[^-1] \\ discarding possibly incorrect last term. Use e.g. \p999 to get more terms. - M. F. Hasler, Oct 31 2019
Comments