A328913 Continued fraction expansion of A328900 = 1.50712659... solution to 2^x + 3^x = 4^x.
1, 1, 1, 34, 1, 1, 2, 1, 1, 1, 2, 3, 28, 2, 1, 1, 2, 4, 3, 2, 7, 2, 35, 3, 1, 1, 2, 1, 2, 53, 1, 33, 1, 1, 1, 2, 2, 2, 35, 10, 52, 1, 1, 1, 2, 3, 1, 1, 2, 2, 1, 2, 1, 1, 3, 1, 1, 1, 18, 1, 1, 7, 2, 14, 2, 84, 1, 4, 5, 3, 2, 3, 1, 2, 2, 1, 2, 40, 1, 3, 5
Offset: 0
Examples
A328900 = 1.50712659... = 1 + 1/(1 + 1/(1 + 1/(34 + 1/(1 + 1/(1 + 1/(2 + ...))))))
Programs
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Mathematica
ContinuedFraction[ x /. FindRoot[2^x + 3^x == 4^x, {x, 1.5}, WorkingPrecision -> 100]] (* Robert G. Wilson v, Nov 12 2019 *)
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PARI
contfrac(solve(s=1,2,1+1.5^s-2^s)) \\ Use e.g. \p999 to get more terms.
Comments