A353848 Numbers k such that the k-th composition in standard order (row k of A066099) has all equal run-sums.
0, 1, 2, 3, 4, 7, 8, 10, 11, 14, 15, 16, 31, 32, 36, 39, 42, 46, 59, 60, 63, 64, 127, 128, 136, 138, 143, 168, 170, 175, 187, 238, 248, 250, 255, 256, 292, 316, 487, 511, 512, 528, 543, 682, 750, 955, 1008, 1023, 1024, 2047, 2048, 2080, 2084, 2090, 2111, 2184
Offset: 0
Keywords
Examples
The terms together with their binary expansions and corresponding compositions begin: 0: 0 () 1: 1 (1) 2: 10 (2) 3: 11 (1,1) 4: 100 (3) 7: 111 (1,1,1) 8: 1000 (4) 10: 1010 (2,2) 11: 1011 (2,1,1) 14: 1110 (1,1,2) 15: 1111 (1,1,1,1) 16: 10000 (5) 31: 11111 (1,1,1,1,1) 32: 100000 (6) 36: 100100 (3,3) 39: 100111 (3,1,1,1) 42: 101010 (2,2,2) 46: 101110 (2,1,1,2) 59: 111011 (1,1,2,1,1) 60: 111100 (1,1,1,3) For example: - The 59th composition in standard order is (1,1,2,1,1), with run-sums (2,2,2), so 59 is in the sequence. - The 2298th composition in standard order is (4,1,1,1,1,2,2), with run-sums (4,4,4), so 2298 is in the sequence. - The 2346th composition in standard order is (3,3,2,2,2), with run-sums (6,6), so 2346 is in the sequence.
Links
- Mathematics Stack Exchange, What is a sequence run? (answered 2011-12-01)
Crossrefs
Programs
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Mathematica
stc[n_]:=Differences[Prepend[Join@@ Position[Reverse[IntegerDigits[n,2]],1],0]]//Reverse; Select[Range[0,100],SameQ@@Total/@Split[stc[#]]&]
Formula
A353849(a(n)) = 1.
Comments