A263861 Triangle read by rows: T(n,k) (n>=0, k>=n+1) is the number of posets with n elements and whose order polytope has k facets.
1, 1, 1, 1, 1, 3, 1, 1, 7, 6, 2, 1, 13, 26, 17, 4, 2, 1, 22, 85, 112, 60, 27, 7, 3, 1
Offset: 0
A263862 Triangle read by rows: T(n,k) (n>=0, k>=n+1) is the number of posets with n elements and whose chain polytope has k facets.
1, 1, 1, 1, 1, 3, 1, 1, 7, 6, 2, 1, 13, 25, 18, 4, 2, 1, 22, 80, 111, 60, 32, 7, 4, 1
Offset: 0
Comments
Row sums give A000112.
Is this the same as A263858? - R. J. Mathar, Nov 03 2015
Examples
Triangle begins: 1, 1, 1,1, 1,3,1, 1,7,6,2, 1,13,25,18,4,2, 1,22,80,111,60,32,7,4,1, ...
Links
- FindStat - Combinatorial Statistic Finder, The number of facets in the chain polytope of the poset.
Crossrefs
Cf. A000112.
A263863 Triangle read by rows: T(n,k) (n>=0, k>=n+1) is the number of posets with n elements and k chains.
1, 1, 1, 1, 1, 1, 2, 0, 1, 1, 1, 3, 3, 2, 2, 0, 3, 0, 0, 0, 1, 1, 1, 3, 5, 8, 5, 7, 4, 8, 2, 5, 1, 5, 0, 3, 0, 0, 0, 4, 0, 0, 0, 0, 0, 0, 0, 1
Offset: 0
Comments
Row sums give A000112.
Examples
Triangle begins: 1, 1, 1,1, 1,1,2,0,1, 1,1,3,3,2,2,0,3,0,0,0,1, 1,1,3,5,8,5,7,4,8,2,5,1,5,0,3,0,0,0,4,0,0,0,0,0,0,0,1, ...
Links
- FindStat - Combinatorial Statistic Finder, The number of chains of a poset.
Crossrefs
Cf. A000112.
A340318 Minimum size of a partial order that contains all partial orders of size n.
0, 1, 3, 5, 8, 11, 16
Offset: 0
Comments
a(n) is the minimum number of elements in a poset P such that every poset of size n is isomorphic to a subset of P, where the subset inherits the order from P.
Elementary bounds are a(n) >= 2n-1 because it must contain a chain and an antichain, and a(n) <= 2^n-1 because every partial order embeds into the powerset partial order on n elements. It is shown in the MathOverflow link that a(n) has no polynomial upper bound. This is in particular derived from binomial(a(n),n) >= A000112(n).
a(4) = 8 verified using a computer-assisted proof with a SAT solver.
a(5) = 11 proven on MathOverflow.
a(6) = 16 and 16 <= a(7) <= 25 proven on MathOverflow. - Jukka Kohonen, Jan 15 2021
Examples
a(2) = 3 because there are 2 nonisomorphic posets on two elements, and both embed into the poset of three elements {a, b, c} with ordering a < b (and other pairs are incomparable). a(3) = 5 because all posets on three elements can be embedded into {a, b, c, d, e} with ordering a < d, b < c < d, and b < e.
Links
- Joel David Hamkins and Fedor Petrov, What is the minimal size of a partial order that is universal for all partial orders of size n?, MathOverflow.
- Jukka Kohonen, What is the minimum size of a partial order containing all partial orders of size 5? (proofs of a(5)=11, a(6)=16 and 16 <= a(7) <= 25), MathOverflow.
- Caleb Stanford, Alloy program to verify a(n) for small n, GitHub.
Programs
-
Sage
# Find an u-poset that contains all n-posets as induced posets. def find_universal_poset(n,u): PP = list(Posets(n)) for U in Posets(u): ok = True for P in PP: if not U.has_isomorphic_subposet(P): ok = False break if ok: return U return None
Extensions
a(6) from Jukka Kohonen, Jan 15 2021
A354693 Number of unlabeled prime posets with n elements.
1, 0, 0, 1, 4, 28, 234, 2585, 36326, 646405, 14528011, 412212506
Offset: 1
Comments
A poset P is called prime if it is not decomposable. A poset Q is called decomposable if Q can be obtained as the composition (lexicographic product) of the outer poset Q' and the inner posets Qi, 1 <= i <= r, where |Q'| = r > 1 and at least one of the posets Qi is nonsingleton.
Links
- S. M. Khamis, On numerical counting of prime, UPO, and the general type of posets according to heights, Congressus Numerantium, 146 (2000), 157-171.
- S. M. Khamis, Recognition of prime posets and one of its applications, J. Egypt. Math. Soc., 14 (1) (2006), 5-13.
A363911 n! times the number of posets with n unlabeled elements.
1, 1, 4, 30, 384, 7560, 228960, 10306800, 685399680, 66490865280, 9316160179200, 1866087527673600, 529244914160793600, 210621677079215001600, 116661392964364363315200, 89281569344544938769408000, 93799600948326479830880256000
Offset: 0
Keywords
Comments
Let H be Green's H relation on the semigroup of binary relations on [n]. Then a(n) is the number of elements that are H-related to a poset.
Links
- Wikipedia, Green's relations
Programs
A376894 Stationary differences in A342447: a(n) = A342447(2k-n+1,k)-A342447(2k-n,k) which does not depend on k if k>= 2n-2 (for n>0).
1, 3, 14, 61, 273, 1228, 5631, 26141, 123261, 589251, 2855815, 14021038, 69707192
Offset: 1
Comments
Number of unlabeled posets A342447(j,k) with j points, without isolated points, with k arcs in the Hasse diagramm missing n points to achieve saturation of the poset i.e. j=2k-n+1.
A342447 is the number of unlabeled posets of j points with k arcs in the Hasse diagram.
Proof will soon be submitted to JOIS.
Examples
See the table of A342447 1 ; 1 ; 1 1 ; 1 1 3 ; 1 1 4 8 2 ; 1 1 4 11 29 12 5 ; 1 1 4 12 43 105 92 45 12 3 ; 1 1 4 12 46 156 460 582 487 204 71 14 7 ; 1 1 4 12 47 170 670 2097 3822 4514 3271 1579 561 186 44 16 4 ; ... The differences between row j and j-1 of column k (convergence indicated by | |): 0 ; 0 ; 0 |1| ; 0 0 |3| ; 0 0 |1| 8 2 ; 0 0 0 |3| 27 12 5 ; 0 0 0 |1| |14| 93 87 45 12 ... ; 0 0 0 0 |3| 51 368 537 475 ... ; 0 0 0 0 |1| |14| 210 1515 3335 ... ; 0 0 0 0 0 |3| |61| 857 6691 ... ; 0 0 0 0 0 |1| |14| 258 3683 ... ; 0 0 0 0 0 0 |3| |61| 1127 ... ; 0 0 0 0 0 0 |1| |14| |273| ... ; a(n) = A342447(2k-n+1,k)-A342447(2k-n,k) for n>=1 e.g. for n = 2 -> k = 2n-2 = 2 a(2) = A342447(3,2) - A342447(2,2) = 3 - 0 = 3 for n = 3 -> k >= 2n-2 = 6 a(3) = A342447(10,6) - A342447(9,6) = 745 - 731 = 14
References
- R. P. Stanley, Enumerative Combinatorics I, 2nd. ed.
Extensions
a(8)-a(13) from Konrad Handrich, Jan 07 2025
A379608 Number of unlabeled Riordan posets with n elements.
1, 2, 5, 11, 33, 74, 144, 232, 639
Offset: 1
Comments
Posets associated to binary Riordan matrices are called Riordan posets.
Examples
For example, all the posets up to 3 elements are Riordan posets.
Links
- G. S. Cheon et al., Riordan posets and associated incidence matrices, Linear Algebra and its Applications, 632 (2022), 308-331.
Extensions
a(9) from Salah Uddin Mohammad, Jun 28 2025
A381121 Number of partially ordered sets ("posets") covering n unlabeled elements.
1, 0, 1, 3, 11, 47, 255, 1727, 14954, 166232, 2384053, 44182143, 1058142319, 32718935706, 1304369332319, 66936884741385, 4414855587293931
Offset: 0
Examples
For n = 3 there are 5 posets, but 2 of them have at least 1 unrelated element, so there are 5 - 2 = 3 = a(3) posets without an unrelated element.
Crossrefs
Partial differences of A000112.
A382829 Number of distinct rank vectors of distributive lattices of height n.
1, 1, 2, 5, 15, 51, 197, 864, 4325, 24922
Offset: 0
Comments
Distributive lattices are ranked posets, and we define the rank vector of a ranked poset P as the vector whose k-th coordinate (starting at k = 0) is the number of elements of rank k in P.
By Birkhoff's representation theorem, elements of a finite distributive lattice L are in bijection with lower sets of the poset of join-irreducible elements of L, an element of rank k corresponding to a lower of set size k.
Examples
The rank vectors corresponding to a(4) = 15 are: (1, 1, 1, 1, 1), (1, 1, 1, 2, 1), (1, 1, 2, 1, 1), (1, 1, 2, 2, 1), (1, 1, 3, 3, 1), (1, 2, 1, 1, 1), (1, 2, 1, 2, 1), (1, 2, 2, 1, 1), (1, 2, 2, 2, 1), (1, 2, 3, 2, 1), (1, 2, 3, 3, 1), (1, 3, 3, 1, 1), (1, 3, 3, 2, 1), (1, 3, 4, 3, 1), (1, 4, 6, 4, 1). Two non-isomorphic distributive lattices have for rank vector (1, 2, 2, 2, 1).
Comments
Examples
Links
Crossrefs