A379007 a(n) = (n^2) XOR ((n^2)-1).
1, 7, 1, 31, 1, 7, 1, 127, 1, 7, 1, 31, 1, 7, 1, 511, 1, 7, 1, 31, 1, 7, 1, 127, 1, 7, 1, 31, 1, 7, 1, 2047, 1, 7, 1, 31, 1, 7, 1, 127, 1, 7, 1, 31, 1, 7, 1, 511, 1, 7, 1, 31, 1, 7, 1, 127, 1, 7, 1, 31, 1, 7, 1, 8191, 1, 7, 1, 31, 1, 7, 1, 127, 1, 7, 1, 31, 1, 7, 1, 511, 1, 7, 1, 31, 1, 7, 1, 127, 1, 7, 1, 31, 1, 7, 1, 2047
Offset: 1
Links
Programs
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Mathematica
Map[BitXor[#, # - 1] &, Range[100]^2] (* Paolo Xausa, Dec 18 2024 *)
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PARI
A379007(n) = bitxor(n^2, ((n^2)-1));
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Python
def A379007(n): return (m:=n**2)^m-1 # Chai Wah Wu, Dec 17 2024
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