cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A350152 Abelian orders m for which there exist at least 2 groups with order m.

Original entry on oeis.org

4, 9, 25, 45, 49, 99, 121, 153, 169, 175, 207, 245, 261, 289, 325, 361, 369, 423, 425, 475, 477, 529, 531, 539, 575, 637, 639, 725, 747, 765, 801, 833, 841, 845, 847, 909, 925, 931, 961, 963, 1017, 1035, 1075, 1127, 1175, 1179, 1225, 1233, 1305, 1325, 1341, 1369, 1445, 1475
Offset: 1

Views

Author

Bernard Schott, Dec 18 2021

Keywords

Comments

This sequence lists the abelian orders when there is an abelian group that is distinct from cyclic group. When there is only one group of order k, then k is in A003277 and this group is the cyclic group C_k.
Except for a(1) = 4, all the terms are odd, because of the existence of a non-abelian dihedral group D_{2*n} of order 2*n for each n > 2.
Every p^2, p prime, is a term and the 2 corresponding abelian groups are C_{p^2} and C_p X C_p.

Examples

			4 is a term because the 2 groups of order 4 that are C_4 and C_2 X C_2, the Klein four-group, are both abelian and a(1) = 4 because there is no smallest order with 2 abelian groups.
45 is a term because the 2 groups of order 45 that are C_45 and C_5  X C_3 X C_3 are both abelian.
99 is another term because the 2 groups of order 99 that are C_99 and C_11 X C_3 X C_3 are both abelian.
		

Crossrefs

Equals A051532 \ A003277.
A001248 is a subsequence.

Programs

  • Mathematica
    f[p_, e_] := Product[1 - p^i, {i, 1, e}]; q[n_] := !CoprimeQ[EulerPhi[n], n] && Module[{fct = FactorInteger[n], e}, e = fct[[;; , 2]]; Max[e] < 3 && CoprimeQ[Abs[Times @@ f @@@ fct], n]]; Select[Range[1500], q] (* Amiram Eldar, Dec 18 2021 *)

Formula

m such that A000001(m) = A000688(m) > 1.

Extensions

More terms from Michel Marcus, Dec 18 2021

A350342 Numbers k such that k^2 is an abelian order.

Original entry on oeis.org

1, 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 35, 37, 41, 43, 47, 53, 59, 61, 65, 67, 71, 73, 77, 79, 83, 85, 89, 97, 101, 103, 107, 109, 113, 115, 119, 127, 131, 133, 137, 139, 143, 149, 151, 157, 161, 163, 167, 173, 179, 181, 185, 187, 191, 193, 197, 199, 209
Offset: 1

Views

Author

Jianing Song, Dec 25 2021

Keywords

Comments

Such k must be squarefree. Actually, such k must be a cyclic number (A003277).
Number of the form p_1*p_2*...*p_r where the p_i are distinct primes and no (p_j)^2-1 is divisible by any p_i.
The smallest term with exactly n distinct prime factors is given by A350340.
From the term 5 on, no term can be divisible by 2 or 3.

Examples

			For primes p, p is a term since every group of order p^2 is abelian. Such group is isomorphic to either C_{p^2} or C_p X C_p.
For primes p, q, if p^2 !== 1 (mod q), q^2 !== 1 (mod p), then p*q is a term since every group of that order is abelian. Such group is isomorphic to C_{p^2*q^2}, C_p X C_{p*q^2}, C_q X C_{p^2*q} or C_{p*q} X C_{p*q}.
		

Crossrefs

Cf. A051532 (abelian orders), A003277 (cyclic numbers), A350343, A350340.
A350344 is the subsequence of composite numbers.

Programs

  • PARI
    isA051532(n) = my(f=factor(n), v=vector(#f[, 1])); for(i=1, #v, if(f[i, 2]>2, return(0), v[i]=f[i, 1]^f[i, 2])); for(i=1, #v, for(j=i+1, #v, if(v[i]%f[j, 1]==1 || v[j]%f[i, 1]==1, return(0)))); 1 \\ Charles R Greathouse IV's program for A051532
    isA350342(n) = isA051532(n^2)

Formula

A350343(n) = a(n)^2.

A350344 Composite k such that k^2 is an abelian order.

Original entry on oeis.org

35, 65, 77, 85, 115, 119, 133, 143, 161, 185, 187, 209, 215, 217, 221, 235, 247, 259, 265, 299, 319, 323, 329, 335, 341, 365, 371, 377, 391, 403, 407, 413, 415, 427, 437, 451, 469, 481, 485, 493, 511, 515, 517, 527, 533, 535, 551, 553, 559, 565, 583, 589, 595
Offset: 1

Views

Author

Jianing Song, Dec 25 2021

Keywords

Comments

Numbers k such that k^2 is an abelian order with at least 4 groups.
Number of the form p_1*p_2*...*p_r where r > 1, the p_i are distinct primes and no (p_j)^2-1 is divisible by any p_i.
The smallest number k such that k^2 is an abelian order with at least 8 groups is A350340(3) = 595.
No term can be divisible by 2 or 3.

Examples

			For primes p, q, if p^2 !== 1 (mod q), q^2 !== 1 (mod p), then p*q is a term since every group of that order is abelian. Such group is isomorphic to C_{p^2*q^2}, C_p X C_{p*q^2}, C_q X C_{p^2*q} or C_{p*q} X C_{p*q}.
95 is not a term since 95^2 = 5^2 * 19^2 is not an abelian order. Note that 95 itself is a cyclic number.
		

Crossrefs

Cf. A051532 (abelian orders), A050384, A350340.
Equals A350342 \ ({1} U A000040).

Programs

  • PARI
    isA051532(n) = my(f=factor(n), v=vector(#f[, 1])); for(i=1, #v, if(f[i, 2]>2, return(0), v[i]=f[i, 1]^f[i, 2])); for(i=1, #v, for(j=i+1, #v, if(v[i]%f[j, 1]==1 || v[j]%f[i, 1]==1, return(0)))); 1 \\ Charles R Greathouse IV's program for A051532
    isA350344(n) = (n>1) && !isprime(n) && isA051532(n^2)

Formula

A350345(n) = a(n)^2.

A350345 Squares of composite numbers k that are abelian orders.

Original entry on oeis.org

1225, 4225, 5929, 7225, 13225, 14161, 17689, 20449, 25921, 34225, 34969, 43681, 46225, 47089, 48841, 55225, 61009, 67081, 70225, 89401, 101761, 104329, 108241, 112225, 116281, 133225, 137641, 142129, 152881, 162409, 165649, 170569, 172225, 182329, 190969
Offset: 1

Views

Author

Jianing Song, Dec 25 2021

Keywords

Comments

Square numbers k that are abelian orders with at least 4 groups.
Number of the form (p_1*p_2*...*p_r)^2 where r > 1, the p_i are distinct primes and no (p_j)^2-1 is divisible by any p_i.
The smallest square number k that is an abelian order with at least 8 groups is A350341(3) = 354025.
No term can be divisible by 2 or 3.

Examples

			For primes p, q, if p^2 !== 1 (mod q), q^2 !== 1 (mod p), then p^2*q^2 is a term since every group of that order is abelian. Such group is isomorphic to C_{p^2*q^2}, C_p X C_{p*q^2}, C_q X C_{p^2*q} or C_{p*q} X C_{p*q}.
		

Crossrefs

Cf. A051532 (abelian orders), A050384, A350341.
Equals A350343 \ ({1} U A001248).
A350323 is a subsequence.

Programs

  • PARI
    isA051532(n) = my(f=factor(n), v=vector(#f[, 1])); for(i=1, #v, if(f[i, 2]>2, return(0), v[i]=f[i, 1]^f[i, 2])); for(i=1, #v, for(j=i+1, #v, if(v[i]%f[j, 1]==1 || v[j]%f[i, 1]==1, return(0)))); 1 \\ Charles R Greathouse IV's program for A051532
    isA350345(n) = issquare(n) && (n>1) && !isprime(sqrtint(n)) && isA051532(n^2)

Formula

a(n) = A350344(n)^2.

A350421 Numbers p^2*q, p > q odd primes such that q does not divide p-1, and q does not divide p+1.

Original entry on oeis.org

245, 845, 847, 1445, 1859, 2023, 2527, 2645, 3179, 3703, 3757, 3971, 4693, 6137, 6727, 6845, 6877, 8993, 9245, 9251, 9583, 10051, 10571, 10933, 11045, 12493, 14045, 14297, 15059, 15463, 15979, 16337, 17797, 18259, 18491, 19343, 19663, 21853, 22103, 22445, 23273
Offset: 1

Views

Author

Bernard Schott, Dec 30 2021

Keywords

Comments

As odd prime q does not divide p-1 and does not divide also p+1, then q >= 5, so p >= 7.
For these terms m, there are precisely 2 groups of order m, so this is a subsequence of A054395.
The 2 groups are abelian; they are C_{p^2*q} and (C_p X C_p) X C_q, where C means cyclic groups of the stated order and the symbol X means direct product.

Examples

			245 = 7^2 * 5, 5 and 7 are odd primes, 5 does not divide 7-1 = 10 and does not divide 7+1 = 8, hence 245 is a term.
		

References

  • Pascal Ortiz, Exercices d'Algèbre, Collection CAPES / Agrégation, Ellipses, problème 1.35, pp. 70-74, 2004.

Crossrefs

Equals A350422 \ A350332.
Subsequence of A051532, A054395, A054753, A060687 and A350322.
Other subsequences of A054753 linked with order of groups: A079704, A143928, A349495, A350115, A350245.

Programs

  • Magma
    f:=Factorisation; [n:n in [3..24000 ]|#PrimeDivisors(n) eq 2 and  f(n)[1][1] lt f(n)[2][1] and f(n)[1][2] eq 1 and f(n)[2][2] eq 2  and (f(n)[2][1]-1) mod f(n)[1][1] ne 0 and (f(n)[2][1]+1) mod f(n)[1][1] ne 0]; // Marius A. Burtea, Dec 30 2021
    
  • Mathematica
    q[n_] := Module[{f = FactorInteger[n], p, e}, p = f[[;; , 1]]; e = f[[;; , 2]]; e == {1, 2} && ! Or @@ Divisible[p[[2]] + {-1, 1}, p[[1]]]]; Select[Range[1, 24000, 2], q] (* Amiram Eldar, Dec 30 2021 *)
  • PARI
    isok(m) = my(f=factor(m)); if (f[, 2] == [1, 2]~, my(p=f[2, 1], q=f[1, 1]); ((p-1) % q) && ((p+1) % q)); \\ Michel Marcus, Dec 30 2021
  • Python
    from sympy import integer_nthroot, primerange
    def aupto(limit):
        aset, maxp = set(), integer_nthroot(limit**2, 3)[0]
        for p in primerange(3, maxp+1):
            pp = p*p
            for q in primerange(1, min(p, limit//pp+1)):
                if (p-1)%q != 0 and (p+1)%q != 0:
                    aset.add(pp*q)
        return sorted(aset)
    print(aupto(24000)) # Michael S. Branicky, Dec 30 2021
    

Extensions

More terms from Marius A. Burtea and Hugo Pfoertner, Dec 30 2021

A060653 Minimal number of conjugacy classes (which is also the number of irreducible representations) in G where G is a finite group of order n.

Original entry on oeis.org

1, 2, 3, 4, 5, 3, 7, 5, 9, 4, 11, 4, 13, 5, 15, 7, 17, 6, 19, 5, 5, 7, 23, 5, 25, 8, 11, 10, 29, 9, 31, 11, 33, 10, 35, 6, 37, 11, 7, 10, 41, 7, 43, 14, 45, 13, 47, 8, 49, 14, 51, 7, 53, 10, 7, 8, 9, 16, 59, 5, 61, 17, 15, 13, 65, 18, 67, 8, 69, 19, 71, 6, 73
Offset: 1

Views

Author

Noam Katz (noamkj(AT)hotmail.com), Apr 17 2001

Keywords

Comments

a(n) <= n with equality iff n belongs to sequence A051532.

Examples

			a(6) = 3 because there are two groups of order 6, the cyclic group with 6 classes and S_3 with 3 classes.
		

Crossrefs

Programs

  • GAP
    A060653 := function(n) local min, i; min := n; for i in [1..NumberSmallGroups(n)] do min := Minimum(min, NrConjugacyClasses(SmallGroup(n,i))); od; return min; end; # Eric M. Schmidt, Aug 30 2012

Extensions

More terms from Eric M. Schmidt, Aug 30 2012

A061064 Maximal number of zeros in the character table of a group with n elements.

Original entry on oeis.org

0, 0, 0, 0, 0, 1, 0, 3, 0, 2, 0, 4, 0, 3, 0, 12, 0, 9, 0, 8, 4, 5, 0, 27, 0, 6, 16, 12, 0, 25, 0, 48, 0, 8, 0, 36, 0, 9, 8, 75, 0, 49, 0, 20, 0, 11, 0, 108, 0, 50, 0, 24, 0, 81, 8, 147, 12, 14, 0, 100, 0, 15, 36, 192, 0, 121, 0, 32, 0, 98, 0, 243, 0, 18, 16
Offset: 1

Views

Author

Ahmed Fares (ahmedfares(AT)my-deja.com), Jun 05 2001

Keywords

Comments

A finite non-Abelian group G has an irreducible representation of degree >= 2 and the character of such representation always has a zero; so a(n) = 0 iff every group of order n is Abelian, i.e. n belongs to A051532.

Examples

			a(6) = 1 because the character table of the symmetric group S_3 is / 1, 1, 1 / 1, 1, -1 / 2, -1, 0 /.
		

Crossrefs

Cf. A051532.

Programs

  • GAP
    A061064 := function(n) local max, i; max := 0; for i in [1..NumberSmallGroups(n)] do max := Maximum(max, Sum(Irr(SmallGroup(n,i)), chi->Number(chi, x->x=0))); od; return max; end; # Eric M. Schmidt, Aug 24 2012

Extensions

Added terms a(n) for n>=24, Eric M. Schmidt, Aug 24 2012.

A241276 Number of partitions of n that come from sizes of conjugacy classes of groups of order n.

Original entry on oeis.org

1, 1, 1, 1, 1, 2, 1, 2, 1, 2, 1, 3, 1, 2, 1, 3, 1, 3, 1, 3, 2, 2, 1, 7, 1, 2, 2, 2, 1, 4, 1, 6, 1, 2, 1, 6, 1, 2, 2, 5, 1, 6, 1, 2, 1, 2, 1, 13, 1, 3, 1, 3, 1, 7, 2, 5, 2, 2, 1, 9, 1, 2, 2, 16, 1, 4, 1, 3, 1, 4, 1, 17, 1, 2, 2, 2, 1, 6, 1, 11, 3, 2, 1, 9, 1, 2, 1, 4, 1, 6, 1, 2, 2, 2, 1, 30, 1, 3, 1, 7
Offset: 1

Views

Author

W. Edwin Clark, Apr 18 2014

Keywords

Comments

a(n) = 1 if every group of order n is abelian, that is, if n is in A051532.
Upper bounds are given by A000001 (number of groups of order n) and A018818 (number of partitions of n into divisors of n).
A077191 is an upper bound. - Eric M. Schmidt, Oct 16 2014

Examples

			If n = 6 there are two groups of order 6: Z_6, all of whose conjugacy classes are of order 1 giving the partition [1,1,1,1,1,1] and S_6, which has three conjugacy classes whose sizes are 1, 2 and 3, giving the partition [1,2,3]. Hence a(6) = 2.
		

Programs

  • GAP
    a:=[];;
    for n in [1..100] do
      P:=[];
      for i in [1..NumberSmallGroups(n)] do
       g:=SmallGroup(n,i);
       cc:=ConjugacyClasses(g);
       L:=List(cc,Size);
       Sort(L);
       Add(P,L);
       P:=Set(P);
      od;
      Add(a,Length(P));
    od;
    a;
    
  • GAP
    a := function(n) local i, p, P; P := []; for i in [1..NrSmallGroups(n)] do p := List(ConjugacyClasses(SmallGroup(n,i)), Size); Sort(p); MakeImmutable(p); AddSet(P, p); od; return Length(P); end; # Eric M. Schmidt, Oct 16 2014

A060938 Maximal degree of an irreducible representation of a group with n elements.

Original entry on oeis.org

1, 1, 1, 1, 1, 2, 1, 2, 1, 2, 1, 3, 1, 2, 1, 2, 1, 2, 1, 4, 3, 2, 1, 3, 1, 2, 3, 2, 1, 2, 1, 4, 1, 2, 1, 4, 1, 2, 3, 4, 1, 6, 1, 2, 1, 2, 1, 4, 1, 2, 1, 4, 1, 6, 5, 7, 3, 2, 1, 5, 1, 2, 3, 4, 1, 2, 1, 4, 1, 2, 1, 8, 1, 2, 3, 2, 1, 6, 1, 5, 3, 2, 1, 6, 1, 2, 1
Offset: 1

Views

Author

Ahmed Fares (ahmedfares(AT)my-deja.com), May 07 2001

Keywords

Comments

a(n) = 1 iff every group of order n is Abelian i.e. n belongs to sequence A051532.
a(m)a(n) <= a(mn). - Eric M. Schmidt, Oct 17 2012

Examples

			a(6) = 2 because for the Abelian group with 6 elements the degrees are all 1 and for the symmetric group S_3 the degrees are 1,1,2.
		

Crossrefs

Cf. A051532.

Programs

  • GAP
    A060938 := function(n) local max, divs, maxpos, degs, i; if (n=1) then return 1; fi; divs := DivisorsInt(n); maxpos := divs[Int(Length(divs)/2)]; max := 1; for i in [1..NumberSmallGroups(n)] do degs := CharacterDegrees(SmallGroup(n, i)); max := Maximum(max, degs[Length(degs)][1]); if (max = maxpos) then return max; fi; od; return max; end;

Extensions

More terms from Eric M. Schmidt, Oct 17 2012

A243592 Numbers n such that there is no indecomposable group of order n.

Original entry on oeis.org

1, 15, 33, 35, 45, 51, 65, 69, 77, 85, 87, 91, 95, 99, 105, 115, 119, 123, 133, 135, 141, 143, 145, 153, 159, 161, 165, 175, 177, 185, 187, 195, 207, 209, 213, 215, 217, 221, 231, 235, 245, 247, 249, 255, 259, 261, 265, 267, 285, 287, 295, 297, 299, 303, 315, 319, 321, 323, 325, 329, 335, 339, 341, 345, 357, 365, 369, 371
Offset: 1

Views

Author

Joerg Arndt, Jun 07 2014

Keywords

Comments

Numbers n such that A090751(n) = 0.
Includes all non-prime-power members of A051532. - Eric M. Schmidt, Jun 07 2014
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