A042984 Number of n-dimensional partitions of 6.
1, 11, 48, 140, 326, 657, 1197, 2024, 3231, 4927, 7238, 10308, 14300, 19397, 25803, 33744, 43469, 55251, 69388, 86204, 106050, 129305, 156377, 187704, 223755, 265031, 312066, 365428, 425720, 493581, 569687, 654752, 749529, 854811, 971432
Offset: 0
References
- G. E. Andrews, The Theory of Partitions, Addison-Wesley, 1976, p. 190.
Links
- Vincenzo Librandi, Table of n, a(n) for n = 0..1000
- Index entries for linear recurrences with constant coefficients, signature (6,-15,20,-15,6,-1).
Programs
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GAP
List([0..40],n->(n+1)*(n+4)*(n^3+40*n^2+61*n+30)/120); # Muniru A Asiru, Feb 17 2019
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Magma
[1 + 10*n + 27*Binomial(n,2) + 28*Binomial(n,3) + 11*Binomial(n,4) + Binomial(n,5): n in [0..40]]; // Vincenzo Librandi, Oct 27 2013
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Maple
a:= n-> 1+10*n+27*binomial(n, 2)+28*binomial(n, 3) +11*binomial(n, 4)+binomial(n, 5): seq(a(n), n=0..34);
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Mathematica
LinearRecurrence[{6,-15,20,-15,6,-1},{1,11,48,140,326,657},40] (* Harvey P. Dale, Jan 27 2013 *) CoefficientList[Series[(x^4 -3x^3 -3x^2 +5x +1)/(x-1)^6, {x, 0, 40}], x] (* Vincenzo Librandi, Oct 27 2013 *)
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PARI
my(x='x+O('x^40)); Vec((x^4-3*x^3-3*x^2+5*x+1)/(x-1)^6) \\ G. C. Greubel, Feb 17 2019
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Sage
((x^4-3*x^3-3*x^2+5*x+1)/(x-1)^6).series(x, 40).coefficients(x, sparse=False) # G. C. Greubel, Feb 17 2019
Formula
a(n) = A008780(n) - binomial(n, 4) - binomial(n, 3).
G.f.: (x^4 - 3*x^3 - 3*x^2 + 5*x + 1)/(x-1)^6. - Colin Barker, Jul 22 2012
a(n) = (n+1)*(n+4)*(n^3 + 40*n^2 + 61*n + 30)/120. - Robert Israel, Jul 06 2016
Extensions
More terms from Erich Friedman