cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A048194 Total number of split graphs (chordal + chordal complement) on n vertices.

Original entry on oeis.org

1, 2, 4, 9, 21, 56, 164, 557, 2223, 10766, 64956, 501696, 5067146, 67997750, 1224275498, 29733449510, 976520265678, 43425320764422, 2616632636247976, 213796933371366930, 23704270652844196754, 3569464106212250952762, 730647291666881838671052
Offset: 1

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Keywords

Comments

Also number of bipartite graphs with n vertices and no isolated vertices in distinguished bipartite block, up to isomorphism; so a(n) equals first differences of A049312. - Vladeta Jovovic, Jun 17 2000
All split graphs are perfect. - Falk Hüffner, Nov 29 2015
Inverse Euler transform gives A007776 with initial 1. - Andrew Howroyd, Oct 03 2018

Crossrefs

Detlef Pauly remarks that this is the unlabeled analog of A001831.

Programs

  • Mathematica
    b[n_, i_] := b[n, i] = If[n == 0, {0}, If[i < 1, {}, Flatten @ Table[ Map[ Function[{p}, p + j*x^i], b[n - i*j, i - 1]], {j, 0, n/i}]]];
    g[n_, k_] := g[n, k] = Sum[Sum[2^Sum[Sum[GCD[i, j]*Coefficient[s, x, i]* Coefficient[t, x, j], {j, 1, Exponent[t, x]}], {i, 1, Exponent[s, x]}]/ Product[i^Coefficient[s, x, i]*Coefficient[s, x, i]!, {i, 1, Exponent[s, x]}]/Product[i^Coefficient[t, x, i]*Coefficient[t, x, i]!, {i, 1, Exponent[t, x]}], {t, b[n + k, n + k]}], {s, b[n, n]}];
    A[n_, k_] := g[Min[n, k], Abs[n - k]];
    a[d_] := Sum[A[n, d - n], {n, 0, d}] - Sum[A[n, d - n - 1], {n, 0, d - 1}];
    Table[a[n], {n, 1, 25}] (* Jean-François Alcover, May 26 2019, after Alois P. Heinz in A049312 *)

Formula

a(n) = A049312(n) - A049312(n-1) (see the Collins and Trenk link, Thms. 5 and 15). - Justin M. Troyka, Oct 29 2018
a(n) ~ A049312(n) ~ (1/n!) * Sum_{k=0..n} binomial(n,k) * 2^(k(n-k)) (see the Troyka link, Thms. 3.7 and 3.10). - Justin M. Troyka, Oct 29 2018
a(n) = A263859(n,1) + 1. - Geoffrey Critzer, Feb 05 2024