cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A122902 First occurrence of exponent n in A080121 corresponding to the minimum prime of the form (k^(2^n) + (k+1)^(2^n)) = A122900(k).

Original entry on oeis.org

1, 3, 23, 21, 10, 95, 255, 86, 59
Offset: 1

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Author

Alexander Adamchuk, Sep 18 2006, Oct 01 2006

Keywords

Comments

Minimum primes of the form n^(2^m) + (n+1)^(2^m) are listed in A122900. The exponents m are listed in A080121.
a(10)-a(13)>1000, a(14)-a(16)>100.

Examples

			A080121 begins with 1,1,2,1,1,2,1,2,1,5,?,1,2,1,?,2,1,?,1,?,4,1,3,1,..., where the unknown terms (denoted with ?) are at least 10. So a(1) = 1, a(2) = 3, a(3) = 23, a(4) = 21, a(5) = 10.
		

Crossrefs

Extensions

Edited by Max Alekseyev, Sep 09 2020

A122901 Erroneous duplicate of A080121.

Original entry on oeis.org

1, 1, 2, 1, 1, 2, 1, 2, 1, 5, 0, 1, 2, 1, 0, 2, 1, 0, 1, 0, 4, 1, 3, 1, 1, 2, 2, 0, 1, 1, 2, 1, 2, 1, 1, 2, 2, 2, 1, 2, 4, 1, 2, 0, 4, 0, 1, 2, 0, 1, 0, 0, 0, 2, 0, 4, 0, 0, 9, 1, 0, 0, 2, 0, 1, 3, 2, 2, 1, 1, 0, 1, 0, 2, 4, 3, 0, 2, 1, 4, 0, 1, 0, 1, 1, 8, 1, 2, 2, 1, 0, 0, 4, 0, 6, 4, 1, 2, 1, 1
Offset: 1

Views

Author

Alexander Adamchuk, Sep 18 2006

Keywords

A077659 a(n) = smallest k>1 such that the sum n^k + (n+1)^k is prime, or -1 if no such k exists.

Original entry on oeis.org

2, 2, 4, 2, 2, 4, 2, 4, 2, 32
Offset: 1

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Author

T. D. Noe, Nov 14 2002

Keywords

Comments

Checking k up through 1024 suggests that the sequence may continue -1, 2, 4, 2, -1, 4, 2, -1, 2, -1, 16, 2, 8, 2, 2, 4, 4, -1, 2, 2, 4, 2, 4, 2, 2, 4, 4, 4, 2, ...
For any a>1 and b>1, a^k + b^k is composite for all odd k>1. Hence if n^k + (n+1)^k is prime then k must be a power of 2.
It is known that a(11) > 2^22. Is it possible that 11^2^m + 12^2^m is composite for all m > 0?

Examples

			a(3)=4 because 3^2 + 4^2 = 25 is not prime, but 3^4 + 4^4 = 337 is prime.
		

Crossrefs

Cf. A078902.
Cf. A080121.

Programs

  • Mathematica
    lst={}; For[n=1, n<=100, n++, k=2; While[k<=2^10 && !PrimeQ[n^k+(n+1)^k], k=2*k]; If[k<=2^10, AppendTo[lst, k], AppendTo[lst, -1]]]; lst

A122900 Minimum prime of the form n^k + (n+1)^k for k>1, or 0 if no such prime exists.

Original entry on oeis.org

5, 13, 337, 41, 61, 3697, 113, 10657, 181, 2211377674535255285545615254209921
Offset: 1

Views

Author

Alexander Adamchuk, Sep 18 2006

Keywords

Comments

Currently a(n) is unknown for n = {11, 15, 18, 20, 28, 44, 46, 49, 51, 52, 53, 55, 57, 58, 61, 62, 64, 71, 73, 77, 81, 83, 91, 92, 94, ...}. All n < 100 and 1 < k < 2^10 have been checked.
All nonzero a(n) have a form n^(2^m) + (n+1)^(2^m).
The exponents m are listed in A080121. The first occurrence of each exponent m in A080121 is listed in A122902.

Examples

			a(1) = 5 because 1^2 + 2^2 = 5 is prime.
a(2) = 13 because 2^2 + 3^2 = 13 is prime.
a(3) = 337 because 3^4 + 4^4 = 337 is prime but 3^3 + 4^3 = 91 and 3^2 + 4^2 = 25 are composite.
		

Crossrefs

Extensions

Edited by Max Alekseyev, Sep 09 2020

A253242 Least k>=0 such that n^(2^k)+1 is prime (for even n), or (n^(2^k)+1)/2 is prime (for odd n); -1 if no such k exists.

Original entry on oeis.org

0, 0, 0, 0, 0, 2, -1, 0, 0, 1, 0, 0, 1, 1, 0, 2, 0, 1, 1, 0, 0, 2, 1, 0, 1, -1, 0, 1, 0
Offset: 2

Views

Author

Eric Chen, Apr 19 2015

Keywords

Comments

Least k such that the generalized Fermat number in base n (GFN(k,n)) is prime.
a(n) = -1 if n is in A070265 (perfect powers with an odd exponent).
a(n) is currently unknown for n = {31, 38, 50, 55, 62, 63, 67, 68, 77, 83, 86, 89, 91, 92, 97, 98, 99, 104, 107, 109, 122, 123, 127, 135, 137, ...}
Corresponding primes are {3, 2, 5, 3, 7, 1201, 0, 5, 11, 61, 13, 7, 197, 113, 17, 41761, 19, 181, 401, 11, 23, 139921, 577, 13, 677, 0, 29, 421, 31, ...}. (use 0 if a(n) = -1)
All 2 <= n <= 1500 and 0 <= k <= 14 are checked, the first occurrence of k (start with k = 0) in a(n) are {2, 11, 7, 43, 41, 75, 274, 234, 331, 1342, 824, ...}.

Examples

			a(7) = 2 since (7^(2^0)+1)/2 and (7^(2^1)+1)/2 are not primes, but (7^(2^2)+1)/2 = 1201 is prime.
a(14) = 1 since 14^(2^0)+1 is not prime, but 14^(2^1)+1 = 197 is prime.
		

Crossrefs

Programs

  • Mathematica
    Table[k=0; While[p=If[EvenQ[n], (2n)^(2^k)+1, ((2n)^(2^k)+1)/2]; k<12 && !PrimeQ[p], k=k+1]; If[k==12, -1, k], {n, 2, 1500}]
  • PARI
    f(n) = for(k=0, 11, if(ispseudoprime(n^(2^k)+1), return(k))); -1
    g(n) = for(k=0, 11, if(ispseudoprime((n^(2^k)+1)/2), return(k))); -1
    a(n) = if(n%2==0, f(n), g(n))
    
  • PARI
    f(n,k)=if(n%2, (n^(2^k)+1)/2, n^(2^k)+1)
    a(n)=if(ispower(-n), -1, my(k); while(!ispseudoprime(f(n,k)), k++); k) \\ Charles R Greathouse IV, Apr 20 2015

Formula

a(2n) = A228101(n) = log_2(A079706(n)).
a(A006093(n)) = 0, a(A076274(n)) = 0, a(A070265(n)) = -1.
Showing 1-5 of 5 results.