cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A278241 Least number with the same prime signature as the n-th partition number: a(n) = A046523(A000041(n)).

Original entry on oeis.org

1, 1, 2, 2, 2, 2, 2, 6, 6, 30, 30, 24, 6, 2, 24, 48, 30, 24, 30, 60, 30, 360, 30, 6, 180, 30, 420, 210, 60, 30, 60, 30, 60, 180, 30, 60, 2, 30, 60, 1680, 420, 210, 30, 240, 60, 30, 210, 420, 30, 60, 30, 60, 2310, 60, 2310, 420, 30, 30, 420, 4620, 30, 2310, 420, 30, 2310, 6, 6720, 6, 420, 30, 3360, 30, 30, 30, 2520, 120120, 6, 2, 420, 420, 1260, 6, 840, 30, 4620, 12
Offset: 0

Views

Author

Antti Karttunen, Nov 16 2016

Keywords

Comments

This sequence works as a "sentinel" for partition numbers by matching to any sequence that is obtained as f(A000041(n)), where f(n) is any function that depends only on the prime signature of n (see the index entry for "sequences computed from exponents in ..."). The last line in Crossrefs section lists such sequences that were present in the database as of Nov 11 2016.

Crossrefs

Sequences that partition N into same or coarser equivalence classes: A085543, A085561, A087175.

Programs

Formula

a(n) = A046523(A000041(n)).

A194259 Number of distinct prime factors of p(1)*p(2)*...*p(n), where p(n) is the n-th partition number.

Original entry on oeis.org

0, 1, 2, 3, 4, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 7, 7, 8, 9, 9, 10, 11, 12, 13, 14, 15, 16, 17, 17, 18, 19, 20, 21, 21, 21, 22, 23, 24, 25, 27, 28, 30, 31, 32, 33, 34, 35, 36, 37, 39, 40, 42, 43, 44, 45, 47, 48, 49, 51, 52, 53, 54, 56, 57, 59, 60, 61
Offset: 1

Views

Author

Jonathan Sondow, Aug 20 2011

Keywords

Comments

Schinzel and Wirsing proved that a(n) > C*log n, for any positive constant C < 1/log 2 and all large n. In fact, it appears that a(n) > n for all n > 115 (see A194260).
It also appears that a(n) > a(n-1), for all n > 97, so that some prime factor of p(n) does not divide p(1)*p(2)*...*p(n-1). See A194261, A194262.

Examples

			p(1)*p(2)*...*p(8) = 1*2*3*5*7*11*15*22 = 2^2 * 3^2 * 5^2 * 7 * 11^2, so a(8) = 5.
		

Crossrefs

Programs

  • Maple
    with(combinat): with(numtheory):
    b:= proc(n) option remember;
          `if`(n=1, {}, b(n-1) union factorset(numbpart(n)))
        end:
    a:= n-> nops(b(n)):
    seq(a(n), n=1..100); # Alois P. Heinz, Aug 20 2011
  • Mathematica
    a[n_] := Product[PartitionsP[k], {k, 1, n}] // PrimeNu; Table[a[n], {n, 1, 100}] (* Jean-François Alcover, Jan 28 2014 *)
    PrimeNu[FoldList[Times,PartitionsP[Range[80]]]] (* Harvey P. Dale, May 29 2025 *)
  • PARI
    a(n)=my(v=[]);for(k=2,n,v=concat(v,factor(numbpart(k))[,1])); #vecsort(v,,8) \\ Charles R Greathouse IV, Feb 01 2013

Formula

a(n) = A001221(product(k=1..n, A000041(k))).

A194260 A194259(n) - n, where A194259(n) is the number of distinct prime factors of p(1)*p(2)*...*p(n) and p(n) is the n-th partition number.

Original entry on oeis.org

-1, -1, -1, -1, -1, -1, -2, -3, -4, -5, -6, -7, -7, -8, -9, -10, -11, -12, -13, -13, -14, -14, -14, -15, -15, -15, -15, -15, -15, -15, -15, -15, -16, -16, -16, -16, -16, -17, -18, -18, -18, -18, -18, -17, -17, -16, -16, -16, -16, -16, -16, -16, -16, -15, -15, -14, -14, -14, -14, -13, -13, -13, -12, -12, -12, -12, -11, -11, -10, -10, -10, -10, -9, -9, -9, -9, -9, -8, -7, -7, -7, -8, -8, -8, -8, -7, -7, -7, -7, -6, -5, -4, -4, -4, -3, -3, -4, -4, -4, -4, -4, -3, -3, -3, -3, -3, -3, -3, -3, -2, -2, -2, -2, -2, 0, 1
Offset: 1

Views

Author

Jonathan Sondow, Aug 20 2011

Keywords

Comments

Schinzel and Wirsing proved that a(n) > C*log n - n, for any positive constant C < 1/log 2 and all large n. In fact, it appears that a(n) > 0 for all n > 115.
It also appears that a(n) >= a(n-1), for all n > 97, so that some prime factor of p(n) does not divide p(1)*p(2)*...*p(n-1).

Examples

			p(1)*p(2)*...*p(8) = 1*2*3*5*7*11*15*22 = 2^2 * 3^2 * 5^2 * 7 * 11^2, so a(8) = 5 - 8 = -3.
		

Crossrefs

Programs

  • Maple
    with(combinat): with(numtheory):
    b:= proc(n) option remember;
          `if`(n=1, {}, b(n-1) union factorset(numbpart(n)))
        end:
    a:= n-> nops(b(n)) -n:
    seq(a(n), n=1..116); # Alois P. Heinz, Aug 20 2011
  • Mathematica
    a[n_] := PrimeNu[Product[PartitionsP[k], {k, 1, n}]] - n; Table[a[n], {n, 1, 116}] (* Jean-François Alcover, Jan 28 2014 *)

Formula

a(n) = A001221(product(k=1..n, A000041(k))) - n.

A111353 Number of distinct prime factors of P(6*n+1) where P(m) is the partition number.

Original entry on oeis.org

2, 1, 3, 3, 3, 3, 3, 3, 4, 5, 2, 3, 4, 2, 3, 7, 4, 5, 5, 2, 4, 4, 3, 5, 3, 1, 4, 3, 3, 2, 4, 5, 3, 3, 5, 3, 6, 4, 2, 2, 3, 4, 5, 4, 4, 3, 4, 4, 4, 3, 5, 3, 5, 5, 6, 3, 4, 4, 3, 3, 3, 5, 6, 3, 4, 6, 4, 4, 4, 4, 4, 3, 6, 7, 3, 4, 4, 7, 2, 8
Offset: 1

Views

Author

Parthasarathy Nambi, Nov 05 2005

Keywords

Examples

			If n=1 then the number of distinct prime factors of P(6*n+1) = P(7) is 2, which is the first term in the sequence.
		

Programs

  • Mathematica
    Table[Length[FactorInteger[PartitionsP[6n + 1]]], {n, 1, 80}] (* Stefan Steinerberger, Feb 17 2006 *)
    PrimeNu[PartitionsP[6*Range[80]+1]] (* Harvey P. Dale, Mar 31 2019 *)

Formula

a(n) = A087175(6n+1). - R. J. Mathar, Aug 25 2011

Extensions

More terms from Stefan Steinerberger, Feb 17 2006

A366581 a(n) = phi(p(n)), where phi is Euler's totient function (A000010) and p(n) is the number of partitions of n (A000041).

Original entry on oeis.org

1, 1, 1, 2, 4, 6, 10, 8, 10, 8, 12, 24, 60, 100, 72, 80, 120, 180, 240, 168, 360, 240, 332, 1000, 720, 880, 672, 1008, 1560, 3280, 1864, 3100, 4840, 5544, 4920, 8800, 17976, 16800, 18480, 12960, 10584, 23040, 24160, 37800, 57600, 43440, 34560, 49896, 84144
Offset: 0

Views

Author

Sean A. Irvine, Oct 13 2023

Keywords

Crossrefs

Programs

Formula

a(n) = A000010(A000041(n)).
Showing 1-5 of 5 results.