A106618 a(n) = numerator of n/(n+17).
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 1, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 2, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 3, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 4, 69, 70, 71, 72, 73, 74
Offset: 0
Links
- G. C. Greubel, Table of n, a(n) for n = 0..10000
- Index entries for linear recurrences with constant coefficients, signature (0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,-1).
Crossrefs
Programs
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GAP
List([0..80],n->NumeratorRat(n/(n+17))); # Muniru A Asiru, Feb 19 2019
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Magma
[Numerator(n/(n+17)): n in [0..100]]; // Vincenzo Librandi, Apr 18 2011
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Maple
seq(numer(n/(n+17)),n=0..80); # Muniru A Asiru, Feb 19 2019
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Mathematica
f[n_]:=Numerator[n/(n+17)];Array[f,100,0] (* Vladimir Joseph Stephan Orlovsky, Feb 17 2011 *)
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PARI
vector(100, n, n--; numerator(n/(n+17))) \\ G. C. Greubel, Feb 19 2019
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Sage
[lcm(n,17)/17 for n in range(0, 100)] # Zerinvary Lajos, Jun 12 2009
Formula
Dirichlet g.f.: zeta(s-1)*(1 - 16/17^s). - R. J. Mathar, Apr 18 2011
a(n) = 2*a(n-17) - a(n-34). - G. C. Greubel, Feb 19 2019
From Amiram Eldar, Nov 25 2022: (Start)
Multiplicative with a(17^e) = 17^(e-1), and a(p^e) = p^e if p != 17.
Sum_{k=1..n} a(k) ~ (273/578) * n^2. (End)
Sum_{n>=1} (-1)^(n+1)/a(n) = 33*log(2)/17. - Amiram Eldar, Sep 08 2023
Comments