cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A277911 Self-inverse permutation of natural numbers induced when A118306 is restricted to A007310.

Original entry on oeis.org

1, 3, 2, 5, 4, 7, 6, 10, 17, 8, 13, 26, 11, 15, 14, 18, 9, 16, 31, 21, 20, 40, 24, 23, 27, 12, 25, 30, 45, 28, 19, 54, 34, 33, 36, 35, 38, 37, 68, 22, 57, 115, 44, 43, 29, 47, 46, 74, 73, 51, 50, 87, 55, 32, 53, 58, 41, 56, 180, 61, 60, 96, 83, 65, 64, 67, 66, 39, 101, 100, 75, 110, 49, 48, 71, 77, 76, 80, 124, 78, 84, 283, 63, 81, 126, 88, 52
Offset: 1

Views

Author

Antti Karttunen, Nov 05 2016

Keywords

Crossrefs

Cf. A277908, A277909, A277910 (for "almost fixed points"), also A277907.

Programs

Formula

a(n) = A126760(A118306(A007310(n))).

A064989 Multiplicative with a(2^e) = 1 and a(p^e) = prevprime(p)^e for odd primes p.

Original entry on oeis.org

1, 1, 2, 1, 3, 2, 5, 1, 4, 3, 7, 2, 11, 5, 6, 1, 13, 4, 17, 3, 10, 7, 19, 2, 9, 11, 8, 5, 23, 6, 29, 1, 14, 13, 15, 4, 31, 17, 22, 3, 37, 10, 41, 7, 12, 19, 43, 2, 25, 9, 26, 11, 47, 8, 21, 5, 34, 23, 53, 6, 59, 29, 20, 1, 33, 14, 61, 13, 38, 15, 67, 4, 71, 31, 18, 17, 35, 22, 73, 3, 16
Offset: 1

Views

Author

Vladeta Jovovic, Oct 30 2001

Keywords

Comments

From Antti Karttunen, May 12 2014: (Start)
a(A003961(n)) = n for all n. [This is a left inverse function for the injection A003961.]
Bisections are A064216 (the terms at odd indices) and A064989 itself (the terms at even indices), i.e., a(2n) = a(n) for all n.
(End)
From Antti Karttunen, Dec 18-21 2014: (Start)
When n represents an unordered integer partition via the indices of primes present in its prime factorization (for n >= 2, n corresponds to the partition given as the n-th row of A112798) this operation subtracts one from each part. If n is of the form 2^k (a partition having just k 1's as its parts) the result is an empty partition (which is encoded by 1, having an "empty" factorization).
For all odd numbers n >= 3, a(n) tells which number is located immediately above n in square array A246278. Cf. also A246277.
(End)
Alternatively, if numbers are represented as the multiset of indices of prime factors with multiplicity, this operation subtracts 1 from each element and discards the 0's. - M. F. Hasler, Dec 29 2014

Examples

			a(20) = a(2^2*5) = a(2^2)*a(5) = prevprime(5) = 3.
		

Crossrefs

Cf. A064216 (odd bisection), A003961 (inverse), A151799.
Other sequences whose definition involve or are some other way related with this sequence: A105560, A108951, A118306, A122111, A156552, A163511, A200746, A241909, A243070, A243071, A243072, A243073, A244319, A245605, A245607, A246165, A246266, A246268, A246277, A246278, A246361, A246362, A246371, A246372, A246373, A246374, A246376, A246380, A246675, A246682, A249745, A250470.
Similar prime-shifts towards smaller numbers: A252461, A252462, A252463.

Programs

  • Haskell
    a064989 1 = 1
    a064989 n = product $ map (a008578 . a049084) $ a027746_row n
    -- Reinhard Zumkeller, Apr 09 2012
    (MIT/GNU Scheme, with Aubrey Jaffer's SLIB Scheme library)
    (require 'factor)
    (define (A064989 n) (if (= 1 n) n (apply * (map (lambda (k) (if (zero? k) 1 (A000040 k))) (map -1+ (map A049084 (factor n)))))))
    ;; Antti Karttunen, May 12 2014
    (definec (A064989 n) (if (= 1 n) n (* (A008578 (A055396 n)) (A064989 (A032742 n))))) ;; One based on given recurrence and utilizing memoizing definec-macro.
    (definec (A064989 n) (cond ((= 1 n) n) ((even? n) (A064989 (/ n 2))) (else (A163511 (/ (- (A243071 n) 1) 2))))) ;; Corresponds to one of the alternative formulas, but is very unpractical way to compute this sequence. - Antti Karttunen, Dec 18 2014
    
  • Maple
    q:= proc(p) prevprime(p) end proc: q(2):= 1:
    [seq(mul(q(f[1])^f[2], f = ifactors(n)[2]), n = 1 .. 1000)]; # Robert Israel, Dec 21 2014
  • Mathematica
    Table[Times @@ Power[Which[# == 1, 1, # == 2, 1, True, NextPrime[#, -1]] & /@ First@ #, Last@ #] &@ Transpose@ FactorInteger@ n, {n, 81}] (* Michael De Vlieger, Jan 04 2016 *)
  • PARI
    { for (n=1, 1000, f=factor(n)~; a=1; j=1; if (n>1 && f[1, 1]==2, j=2); for (i=j, length(f), a*=precprime(f[1, i] - 1)^f[2, i]); write("b064989.txt", n, " ", a) ) } \\ Harry J. Smith, Oct 02 2009
    
  • PARI
    a(n) = {my(f = factor(n)); for (i=1, #f~, if ((p=f[i,1]) % 2, f[i,1] = precprime(p-1), f[i,1] = 1);); factorback(f);} \\ Michel Marcus, Dec 18 2014
    
  • PARI
    A064989(n)=factorback(Mat(apply(t->[max(precprime(t[1]-1),1),t[2]],Vec(factor(n)~))~)) \\ M. F. Hasler, Dec 29 2014
    
  • Python
    from sympy import factorint, prevprime
    from operator import mul
    from functools import reduce
    def a(n):
        f=factorint(n)
        return 1 if n==1 else reduce(mul, [1 if i==2 else prevprime(i)**f[i] for i in f])
    print([a(n) for n in range(1, 101)]) # Indranil Ghosh, Jun 15 2017
    
  • Python
    from math import prod
    from sympy import prevprime, factorint
    def A064989(n): return prod(prevprime(p)**e for p, e in  factorint(n>>(~n&n-1).bit_length()).items()) # Chai Wah Wu, Jan 05 2023

Formula

From Antti Karttunen, Dec 18 2014: (Start)
If n = product A000040(k)^e(k) then a(n) = product A008578(k)^e(k) [where A000040(n) gives the n-th prime, and A008578(n) gives 1 for 1 and otherwise the (n-1)-th prime].
a(1) = 1; for n > 1, a(n) = A008578(A055396(n)) * a(A032742(n)). [Above formula represented as a recurrence. Cf. A252461.]
a(1) = 1; for n > 1, a(n) = A008578(A061395(n)) * a(A052126(n)). [Compare to the formula of A252462.]
This prime-shift operation is used in the definitions of many other sequences, thus it can be expressed in many alternative ways:
a(n) = A200746(n) / n.
a(n) = A242424(n) / A105560(n).
a(n) = A122111(A122111(n)/A105560(n)) = A122111(A052126(A122111(n))). [In A112798-partition context: conjugate, remove the largest part (the largest prime factor), and conjugate again.]
a(1) = 1; for n > 1, a(2n) = a(n), a(2n+1) = A163511((A243071(2n+1)-1) / 2).
a(n) = A249818(A250470(A249817(n))). [A250470 is an analogous operation for "going one step up" in the square array A083221 (A083140).]
(End)
Product_{k=1..n} a(k) = n! / A307035(n). - Vaclav Kotesovec, Mar 21 2019
Sum_{k=1..n} a(k) ~ c * n^2, where c = (1/2) * Product_{p prime} ((p^2-p)/(p^2-q(p))) = 0.220703928... , where q(p) = prevprime(p) (A151799) if p > 2 and q(2) = 1. - Amiram Eldar, Nov 18 2022

A277907 a(n) = A007310(A277908(n)).

Original entry on oeis.org

5, 7, 11, 13, 17, 19, 41, 43, 59, 61, 67, 71, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 179, 181, 191, 193, 197, 199, 227, 229, 269, 271, 277, 281, 307, 311, 313, 317, 347, 349, 379, 383, 419, 421, 431, 433, 439, 443, 461, 463, 487, 491, 499, 503, 599, 601, 617, 619, 643, 647, 739, 743, 823, 827, 853, 857, 859, 863, 877, 881
Offset: 1

Views

Author

Antti Karttunen, Nov 05 2016

Keywords

Comments

It seems that all terms are primes, and moreover, that all those primes occur in pairs with distance of 2 or 4. However, not all terms of A001359 are present.

Crossrefs

Programs

Formula

a(n) = A007310(A277908(n)).

A118305 Numbers k such that 3*k^k-1 is prime.

Original entry on oeis.org

1, 2, 6, 16, 5436, 6238
Offset: 1

Views

Author

Rick L. Shepherd, Apr 22 2006

Keywords

Comments

Six terms found and primes proved by PrimeForm ([N+1, Brillhart-Lehmer-Selfridge]). 3*6238^6238-1 has 23674 digits. No more terms <= 8800.
No more terms <= 25000. - Michael S. Branicky, Oct 13 2024

Crossrefs

Programs

Showing 1-4 of 4 results.