cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A338711 Erroneous version of A130132.

Original entry on oeis.org

0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 4, 19, 47, 287, 1002, 3365, 10853, 34088, 104574, 315116, 935321, 2743364, 7966723, 22951010, 65681536
Offset: 1

Views

Author

R. J. Mathar, Aug 05 2024

Keywords

Comments

Included in accordance with OEIS policy of including published but erroneous sequences to serve as pointers to the correct values.

A130131 Number of n-lobsters.

Original entry on oeis.org

1, 1, 1, 2, 3, 6, 11, 23, 47, 105, 231, 532, 1224, 2872, 6739, 15955, 37776, 89779, 213381, 507949, 1209184, 2880382, 6861351, 16348887, 38955354, 92831577, 221219963, 527197861, 1256385522, 2994200524, 7135736613, 17005929485, 40528629737, 96588403995, 230190847410
Offset: 1

Views

Author

Eric W. Weisstein, May 11 2007

Keywords

Comments

A lobster graph is a tree having the property that the removal of all leaf nodes leaves a caterpillar graph (see A005418). - N. J. A. Sloane, Nov 05 2020

Examples

			a(10) = 105 = A000055(10) - 1 because all trees with 10 vertices are lobsters except this one:
    o-o-o
   /
  o-o-o-o
   \
    o-o-o
Also, all trees with 10 vertices are linear (all vertices of degree >2 belong to a single path) except this one:
     o   o
      \ /
       o
       |
       o
     /   \
    o     o
   / \   / \
  o   o o   o
		

Crossrefs

Row sums of A380363.
Cf. k-linear trees for k = 1..4: A004250, A338706, A338707, A338708.

Programs

  • Mathematica
    eta = QPochhammer;
    s[n_] := With[{ox = O[x]^n}, x^2 ((1/eta[x + ox] - 1/(1 - x))^2/(1 - x/eta[x + ox]) + (1/eta[x^2 + ox] - 1/(1 - x^2))(1 + x/eta[x + ox])/(1 - x^2/eta[x^2 + ox]))/2 + x/eta[x + ox] - x^3/((1 - x)^2*(1 + x))];
    CoefficientList[s[32], x] // Rest (* Jean-François Alcover, Nov 17 2020, after Andrew Howroyd *)
  • PARI
    s(n)={my(ox=O(x^n)); x^2*((1/eta(x+ox)-1/(1-x))^2/(1-x/eta(x+ox)) + (1/eta(x^2+ox)-1/(1-x^2))*(1+x/eta(x+ox))/(1-x^2/eta(x^2+ox)))/2 + x/eta(x+ox) - x^3/((1-x)^2*(1+x))}
    Vec(s(30)) \\ Andrew Howroyd, Nov 02 2017

Extensions

a(15)-a(32) from Washington Bomfim, Feb 23 2011

A300576 Number of nights required in the worst case to find the princess in a castle with n rooms arranged in a line (Castle and princess puzzle).

Original entry on oeis.org

1, 2, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, 100, 102, 104, 106, 108, 110, 112, 114, 116, 118, 120, 122
Offset: 1

Views

Author

Dmitry Kamenetsky, Mar 09 2018

Keywords

Comments

This is a logic puzzle. There is a castle with n rooms arranged in a line. The princess living in the castle sleeps in a different room each night, but always one adjacent to the one in which she slept on the previous night. She is free to choose any room in which to sleep on the first night. A prince would like to find the princess, but she will not tell him where she is going to sleep each night. Each night the prince can look in a single room. What strategy should he follow in order to guarantee that he finds the princess in a minimum number of nights?
The strategy to find the princess guaranteed within a(n) nights takes on average k(n) nights until the princess is found with lim_{n->oo} k(n) = n-1.5. For n>4, strategies with lower average numbers of trials exist; A386462 provides this strategy for n=8. See there for more information. - Ruediger Jehn, Aug 05 2025
Christian Perfect (see link) considered the case when the rooms are arranged as a general graph. He showed that the set of solvable graphs is exactly the set of trees not containing the "threesy" subgraph, which is A130131. He also showed that for d-level binary trees with 1 <= d <= 4 the number of required nights is 1, 2, 6, 18. Binary trees with d >= 5 are unsolvable as they contain "threesy".

Examples

			For n = 1, there is only one room to search, so a(1) = 1.
For n = 2, the prince searches room 1 on the first night. If the princess is not there that means she was in room 2. If the prince searches room 1 again then he is guaranteed to see the princess as she has to move from room 2 to room 1 (she cannot stay in the same room). So a(2) = 2.
For n = 3, the prince searches room 2 on the first night. If the princess is not there that means she was either in room 1 or 3. On the second night she must go to room 2 and this is where the prince will find her. So a(3) = 2.
For n = 4, a solution that guarantees to find the princess in a(4)=4 nights is to search rooms (2,3,3,2).
For n = 5, a solution that guarantees to find the princess in a(5)=6 nights is to search rooms (2,3,4,4,3,2).
In the general case for n >= 3, a solution guaranteeing success in the minimum number of nights is to search rooms (2,3,...,n-1,n-1,...,3,2), so a(n) = 2*n - 4.
		

Crossrefs

Essentially the same as A005843, A004277 and A004275.

Programs

  • Mathematica
    CoefficientList[ Series[(2x^3 - x^2 + 1)/(x - 1)^2, {x, 0, 62}], x] (* Robert G. Wilson v, Mar 12 2018 *)
    Join[{1,2},Range[2,200,2]] (* Harvey P. Dale, Jan 25 2019 *)

Formula

For n >= 3, a(n) = 2*n - 4.
From Chai Wah Wu, Apr 14 2024: (Start)
a(n) = 2*a(n-1) - a(n-2) for n > 4.
G.f.: x*(2*x^3 - x^2 + 1)/(x - 1)^2. (End)
E.g.f.: 4 + 2*exp(x)*(x - 2) + 3*x + x^2. - Stefano Spezia, Aug 15 2025

A331693 Number of Tom graphs with n vertices.

Original entry on oeis.org

1, 1, 2, 3, 6, 10, 20, 37, 76, 153, 328, 705, 1576, 3551, 8179, 18980, 44559, 105111, 249426, 593484, 1416269, 3384581, 8099819, 19398194, 46487665, 111447044, 267260387, 641022947, 1537706522, 3688974818, 8850411933, 21234093757, 50946316856, 122234742311
Offset: 0

Views

Author

Bobby Jacobs, Jan 24 2020

Keywords

Comments

This sequence is from a Project Euler problem called "Tom and Jerry". A cat named Tom and a mouse named Jerry play a game on a graph G. Each vertex of G is a mousehole. Jerry starts in one of the vertices. Every day, Tom tries to catch Jerry in one of the holes. If there is a vertex adjacent to Jerry's hole, then Jerry moves to one of the adjacent holes. A Tom graph is a graph on which Tom can always catch Jerry by following a sequence of holes.
All Tom graphs are loop-free graphs, but not all loop-free graphs are Tom graphs. The smallest loop-free graph that is not a Tom graph has 10 vertices:
1
|
2
|
3
|
4
/ \
5 8
/ \
6 9
/ \
7 10
From Hugo Pfoertner, Feb 20 2020 (Start):
The sequence is an equivalent of A005195 (number of forests with n unlabeled nodes), but made from trees that don't have the unlabeled 10-node graph shown above as a subgraph. This is described in the comment of A300576 and there is also a link to Christian Perfect's website.
In order to find a term of the current sequence, the number of trees containing the shown subgraph must be subtracted from the total number A000055. For n = 10 this is exactly one, for n = 11 it is trivially 4 and for n = 12 it is 19 (A130132).
The marked illustrations from the Steinbach graph catalog show these manually counted tree graphs.
The formulas of A005195 (Euler transform) can then be used to calculate the number of forests if the reduced number of trees A130131 is used instead of A000055. (End)
a(0) = 1: the empty graph is a Tom graph, since Jerry cannot hide from Tom. - Rainer Rosenthal, Mar 01 2020

Examples

			The graph
  1---2---3
is a Tom graph: Tom can follow the sequence 2, 2 to guarantee that he catches Jerry.
The graph
    1
   / \
  2---3
is not a Tom graph: Jerry always has 2 vertices to go to, and whatever vertex Tom picks, Jerry can choose another to evade Tom.
		

Crossrefs

Formula

a(n) <= A005195(n) with equality only for n in {1, ..., 9}.

Extensions

a(11)-a(12) from Hugo Pfoertner, Feb 20 2020
a(0), a(13)-a(33) from Rainer Rosenthal, Feb 29 2020
Showing 1-4 of 4 results.