1, 2, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, 100, 102, 104, 106, 108, 110, 112, 114, 116, 118, 120, 122
Offset: 1
For n = 1, there is only one room to search, so a(1) = 1.
For n = 2, the prince searches room 1 on the first night. If the princess is not there that means she was in room 2. If the prince searches room 1 again then he is guaranteed to see the princess as she has to move from room 2 to room 1 (she cannot stay in the same room). So a(2) = 2.
For n = 3, the prince searches room 2 on the first night. If the princess is not there that means she was either in room 1 or 3. On the second night she must go to room 2 and this is where the prince will find her. So a(3) = 2.
For n = 4, a solution that guarantees to find the princess in a(4)=4 nights is to search rooms (2,3,3,2).
For n = 5, a solution that guarantees to find the princess in a(5)=6 nights is to search rooms (2,3,4,4,3,2).
In the general case for n >= 3, a solution guaranteeing success in the minimum number of nights is to search rooms (2,3,...,n-1,n-1,...,3,2), so a(n) = 2*n - 4.
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