cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-10 of 11 results. Next

A167170 a(6) = 14, for n >= 7, a(n) = a(n-1) + gcd(n, a(n-1)).

Original entry on oeis.org

14, 21, 22, 23, 24, 25, 26, 39, 40, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 87, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 177, 180, 181, 182, 189, 190, 195
Offset: 6

Views

Author

Vladimir Shevelev, Oct 29 2009, Nov 06 2009

Keywords

Comments

For every n >= 7, a(n) - a(n-1) is 1 or prime. This Rowland-like "generator of primes" is different from A106108 (see comment to A167168).

Crossrefs

Programs

  • Maple
    A167170 := proc(n) option remember; if n = 6 then 14; else procname(n-1)+igcd(n,procname(n-1)) ; end if; end proc: seq(A167170(i),i=6..80) ; # R. J. Mathar, Oct 30 2010
  • Mathematica
    RecurrenceTable[{a[n] == a[n - 1] + GCD[n, a[n - 1]], a[6] == 14}, a, {n, 6, 100}] (* G. C. Greubel, Jun 04 2016 *)
    nxt[{n_,a_}]:={n+1,a+GCD[a,n+1]}; NestList[nxt,{6,14},60][[All,2]] (* Harvey P. Dale, Nov 03 2019 *)
  • PARI
    first(n)=my(v=vector(n-5)); v[1]=14; for(k=7,n, v[k-5]=v[k-6]+gcd(k,v[k-6])); v \\ Charles R Greathouse IV, Aug 22 2017

Extensions

Terms > 91 from R. J. Mathar, Oct 30 2010

A167195 a(2)=3, for n>=3, a(n)=a(n-1)+gcd(n, a(n-1)).

Original entry on oeis.org

3, 6, 8, 9, 12, 13, 14, 15, 20, 21, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 44, 45, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 92, 93, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116
Offset: 2

Views

Author

Vladimir Shevelev, Oct 30 2009, Nov 06 2009

Keywords

Comments

For every n>=3, a(n)-a(n-1) is 1 or prime. This Rowland-like "generator of primes" is different from A106108 and from generators A167168. Generalization: Let p be a prime. Let N(p-1)=p and for n>=p, N(n)=N(n-1)+gcd(n, N(n-1)). Then, for every n>=p, N(n)-N(n-1) is 1 or prime.

Crossrefs

Programs

  • Mathematica
    RecurrenceTable[{a[n] == a[n - 1] + GCD[n, a[n - 1]], a[2] == 3}, a, {n, 2, 100}] (* G. C. Greubel, Jun 05 2016 *)

Formula

a(n) = a(n-1) + 1 if gcd(a(n-1), n) = 1, or a(n) = 2*n otherwise. - Yifan Xie, Aug 20 2025

Extensions

Edited by Charles R Greathouse IV, Nov 02 2009

A167495 Records in A167494.

Original entry on oeis.org

2, 3, 5, 13, 31, 61, 139, 283, 571, 1153, 2311, 4651, 9343, 19141, 38569, 77419, 154873, 310231, 621631, 1243483, 2486971, 4974721
Offset: 1

Views

Author

Vladimir Shevelev, Nov 05 2009

Keywords

Comments

Conjecture: each term > 3 of the sequence is the greater member of a twin prime pair (A006512).
Indices of the records are 1, 2, 4, 6, 9, 10, 15, 18, 21, 25, 28, 30, 38, 72, 90, ... [R. J. Mathar, Nov 05 2009]
One can formulate a similar conjecture without verification of the primality of the terms (see Conjecture 4 in my paper). [Vladimir Shevelev, Nov 13 2009]

Crossrefs

Programs

  • Mathematica
    nxt[{n_, a_}] := {n + 1, If[EvenQ[n], a + GCD[n+1, a], a + GCD[n-1, a]]};
    A167494 = DeleteCases[Differences[Transpose[NestList[nxt, {1, 2}, 10^7]][[2]]], 1];
    Tally[A167494][[All, 1]] //. {a1___, a2_, a3___, a4_, a5___} /; a4 <= a2 :> {a1, a2, a3, a5} (* Jean-François Alcover, Oct 29 2018, using Harvey P. Dale's code for A167494 *)

Extensions

Simplified the definition to include all records; one term added by R. J. Mathar, Nov 05 2009
a(16) to a(21) from R. J. Mathar, Nov 19 2009
a(22) from Jean-François Alcover, Oct 29 2018

A167197 a(6) = 7, for n >= 7, a(n) = a(n - 1) + gcd(n, a(n - 1)).

Original entry on oeis.org

7, 14, 16, 17, 18, 19, 20, 21, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 52, 53, 54, 55, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 116, 117, 120, 121, 122, 123, 124, 125, 126, 127, 128
Offset: 6

Views

Author

Vladimir Shevelev, Oct 30 2009, Nov 06 2009

Keywords

Comments

For every n >= 7, a(n) - a(n - 1) is 1 or prime. This Rowland-like "generator of primes" is different from A106108 (see comment to A167168) and from A167170. Note that, lim sup a(n) / n = 2, while lim sup A106108(n) / n = lim sup A167170(n) / n = 3.
Going up to a million, differences of two consecutive terms of this sequence gives primes about 0.009% of the time. The rest are 1's. [Alonso del Arte, Nov 30 2009]

Crossrefs

Programs

  • Maple
    A[6]:= 7:
    for n from 7 to 100 do A[n]:= A[n-1] + igcd(n,A[n-1]) od:
    seq(A[i],i=6..100); # Robert Israel, Jun 05 2016
  • Mathematica
    a[6] = 7; a[n_ /; n > 6] := a[n] = a[n - 1] + GCD[n, a[n - 1]]; Table[a[n], {n, 6, 58}]
  • Python
    from math import gcd
    def aupton(nn):
        alst = [7]
        for n in range(7, nn+1): alst.append(alst[-1] + gcd(n, alst[-1]))
        return alst
    print(aupton(68)) # Michael S. Branicky, Jul 14 2021

Extensions

Verified and edited by Alonso del Arte, Nov 30 2009

A167493 a(1) = 2; thereafter a(n) = a(n-1) + gcd(n, a(n-1)) if n is odd, and a(n) = a(n-1) + gcd(n-2, a(n-1)) if n is even.

Original entry on oeis.org

2, 4, 5, 6, 7, 8, 9, 12, 15, 16, 17, 18, 19, 20, 25, 26, 27, 28, 29, 30, 33, 34, 35, 36, 37, 38, 39, 52, 53, 54, 55, 60, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 124, 125, 126
Offset: 1

Views

Author

Vladimir Shevelev, Nov 05 2009

Keywords

Comments

Conjectures. 1) For n >= 2, every difference a(n) - a(n-1) is 1 or prime; 2) Every record of differences a(n) - a(n-1) greater than 3 belongs to the sequence of the greater of twin primes (A006512).
Conjecture #1 above fails at n = 620757, with a(n) = 1241487 and a(n-1) = 1241460, difference = 27. Additionally, the terms of related A167495(m) quickly tend to index n/2. So for example, A167495(14) = 19141 is seen at n = 38284. - Bill McEachen, Jan 20 2023
It seems that, for n > 4, (3*n-3)/2 <= a(n) <= 2n - 3. Can anyone find a proof or disproof? - Charles R Greathouse IV, Jan 22 2023

Crossrefs

Programs

  • Mathematica
    nxt[{n_,a_}]:={n+1,If[EvenQ[n],a+GCD[n+1,a],a+GCD[n-1,a]]}; Transpose[ NestList[nxt,{1,2},70]][[2]] (* Harvey P. Dale, Dec 05 2015 *)
  • PARI
    lista(nn)=my(va = vector(nn)); va[1] = 2; for (n=2, nn, va[n] = if (n%2, va[n-1] + gcd(n, va[n-1]), va[n-1] + gcd(n-2, va[n-1]));); va; \\ Michel Marcus, Dec 13 2018
    
  • Python
    from math import gcd
    from itertools import count, islice
    def agen(): # generator of terms
        an = 2
        for n in count(2):
            yield an
            an = an + gcd(n, an) if n&1 else an + gcd(n-2, an)
    print(list(islice(agen(), 66))) # Michael S. Branicky, Jan 22 2023

Formula

For n > 3, n < a(n) < n*(n-1)/2. - Charles R Greathouse IV, Jan 22 2023

Extensions

More terms from Harvey P. Dale, Dec 05 2015

A167494 List of first differences of A167493 that are different from 1.

Original entry on oeis.org

2, 3, 3, 5, 3, 13, 5, 3, 31, 61, 7, 5, 3, 7, 139, 5, 3, 283, 5, 3, 571, 7, 5, 3, 1153, 5, 3, 2311, 31, 4651, 17, 5, 13, 3, 3, 5, 3, 9343, 5, 3, 11, 3, 59, 3, 29, 3, 19, 7, 5, 3, 7, 19, 5, 3, 17, 3, 113
Offset: 1

Views

Author

Vladimir Shevelev, Nov 05 2009

Keywords

Comments

Conjecture. All terms of the sequence are primes.
The conjecture is false: a(144)=27, a(146)=25, a(158)=45, etc., which are composite numbers. - Harvey P. Dale, Dec 05 2015

Crossrefs

Programs

  • Mathematica
    nxt[{n_,a_}]:={n+1,If[EvenQ[n],a+GCD[n+1,a],a+GCD[n-1,a]]}; DeleteCases[ Differences[ Transpose[NestList[nxt,{1,2},20000]][[2]]],1] (* Harvey P. Dale, Dec 05 2015 *)
  • PARI
    lista(nn) = {my(va = vector(nn)); va[1] = 2; for (n=2, nn, va[n] = if (n%2, va[n-1] + gcd(n, va[n-1]), va[n-1] + gcd(n-2, va[n-1]));); select(x->(x!=1), vector(nn-1, n, va[n+1] - va[n]));} \\ Michel Marcus, Dec 13 2018

A168143 a(17)=37; for n>=17, a(n)=3n-14 if gcd(n,a(n-1))>1 and all prime divisors of n more than 17; a(n)=a(n-1)+1, otherwise.

Original entry on oeis.org

37, 38, 43, 44, 45, 46, 55, 56, 57, 58, 59, 60, 61, 62, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 127, 128, 129, 130, 131, 132, 133, 134, 135, 136, 137, 138, 139, 140, 141, 142, 143, 144, 145, 146, 147, 148, 149, 150, 151, 152, 153, 154, 155, 156, 157
Offset: 17

Views

Author

Vladimir Shevelev, Nov 19 2009

Keywords

Comments

a(n+1)-a(n)+14 is either 15 or a prime > 17. For a generalization, see the second Shevelev link. - Edited by Robert Israel, Aug 21 2017

Crossrefs

Programs

  • Maple
    A[17]:= 37:
    q:= convert(select(isprime,[$2..17]),`*`);
    for n from 18 to 100 do
      if igcd(n,A[n-1]) > 1 and igcd(n,q) = 1 then A[n]:= 3*n-14
        else A[n]:= A[n-1]+1 fi
    od:
    seq(A[i],i=17..100); # Robert Israel, Aug 21 2017
  • Mathematica
    nxt[{n_,a_}]:={n+1,If[GCD[n+1,a]>1&&FactorInteger[n+1][[1,1]]>17,3(n+1)-14,a+1]}; NestList[nxt,{17,37},60][[All,2]] (* Harvey P. Dale, Aug 15 2017 *)

Extensions

Corrected by Harvey P. Dale, Aug 15 2017

A291528 First term s_n(1) of equivalence classes of prime sequences {s_n(k)} for k > 0 derived by records of first differences of Rowland-like recurrences with increasing even starting values e(n) >= 4.

Original entry on oeis.org

2, 7, 17, 19, 31, 43, 53, 71, 67, 79, 97, 103, 109, 113, 127, 137, 151, 163, 181, 173, 191, 197, 199, 211, 229, 239, 241, 251, 269, 257, 271, 283, 293, 317, 331, 337, 349, 367, 373, 419, 409, 431, 433, 439, 443, 463, 491, 487, 499, 523, 557, 547, 577, 593, 607, 599, 601
Offset: 1

Views

Author

Ralf Steiner, Aug 25 2017

Keywords

Comments

These kinds of equivalence classes {s_n(k)} were defined by Shevelev, see Crossrefs.
Some equivalence classes of prime sequences {s_n(k)} have the same tail for a constant C_n < k, such as {s_2(k)} = {a(2),...} = {7,13,29,59,131,...} and {s_5(k)} = {a(5),...} = {31,61,131,...} with common tail {131,...}. Thus it seems that all terms are leaves of a kind of an inverse prime-tree with branches in A291620 and the root at infinity.
In each equivalence class {s_n(k)} the terms hold: s_n(k+1)-2*s_n(k) >= -1;
(s_n(k+1)+1)/s_n(k) >= 2; lim_{k -> inf} (s_n(k+1)+1)/s_n(k) = 2.

Examples

			For n=1 the Rowland recurrence with e(1)=4 is A084662 with first differences A134734 and records {2,3,5,11,...} gives the least new prime a(1)=2 as the first term of a first equivalence class {2,3,5,11,...} of prime sequences.
For n=2 with e(2)=8 and records {2,7,13,29,59,...} gives the least new prime a(2)=7 as the first term of a second equivalence class {7,13,29,59,...} of prime sequences.
For n=3 with e(3)=16, a(3)=17 the third equivalence class is {17,41,83,167,...}.
		

Crossrefs

Cf. A291620 (branches), A167168 (equivalence classes), A134734 (first differences of A084662), A134162.

Programs

  • Mathematica
    For[i = 2; pl = {}; fp = {}, i < 350, i++,
    ps = Union@FoldList[Max, 1, Rest@# - Most@#] &@
       FoldList[#1 + GCD[#2, #1] &, 2 i, Range[2, 10^5]];
    p = Select[ps, (i <= #) && ! MemberQ[pl, #] &, 1];
    If[p != {}, fp = Join[fp, {p}];
      pl = Union[pl,
        Drop[ps, -1 + Position[ps, p[[1]]][[1]][[1]]]]]]; Flatten@fp

Formula

a(n) >= 2*n; a(n) > 10*n - 50; a(n) < 12*n.
a(n) >= e(n) - 1, for n > 1; a(n) < e(n) + n.

A291620 Branch term s_n(b), b > 1 of equivalence classes of prime sequences {s_n(k)} for k > 0 derived by records of first differences of Rowland-like recurrences with increasing even start values >= 4.

Original entry on oeis.org

0, 0, 0, 0, 131, 0, 233, 167, 2381, 647, 0, 233, 0, 941, 263, 0, 0, 353, 0, 0, 797, 0, 0, 0, 941, 0, 0, 8273, 569, 0, 0, 569, 1181, 0, 0, 22133, 761, 0, 761, 1721, 839, 1811, 881, 0, 1811, 929, 1973, 0, 0, 1049, 1181, 9323, 2309, 1187, 0, 2441, 2441
Offset: 1

Views

Author

Ralf Steiner, Aug 28 2017

Keywords

Comments

See A291528 (leaves) for equivalence classes.
If the conjecture of an inverse tree of primes with the leaves in A291528 using the same index n holds, except a(1)=0 all terms a(n) == 0 indicates that the branch point is not yet found.
This is a k-ary tree, k > 2, such as a(7) == a(12) == 233.
Maybe these simple Rowland-like recurrences giving all primes are related to a simple bounded physical quantum system with a "Hamiltonian for the zeros of the Riemann zeta function" (cf. Bender et al.) having degenerated energy eigenvalues a(n).
[Note: the editors feel that any such connection is extremely unlikely. - N. J. A. Sloane, Oct 30 2017]

Examples

			n=5: Some equivalence classes of prime sequences {s_n(k)} have the same tail for a constant C_n < k, such as {s_2(k)} = {7,13,29,59,131,...} and {s_5(k)} = {31,61,131,...} with common tail {a(5),...} = {131,...} and the branch 131 = a(5). Thus it seems that all terms != 0 are branches of a kind of an inverse prime-tree with the root at infinity.
		

Crossrefs

Cf. A134162, A134734, A167168 (equivalence classes), A291528 (leaves)

Programs

  • Mathematica
    For[i = 2; pl = {}; fp = {}; bp = {}, i < 350, i++,
    ps = Union@FoldList[Max, 1, Rest@# - Most@#] &@
       FoldList[#1 + GCD[#2, #1] &, 2 i, Range[2, 10^5]];
    p = Select[ps, (i <= #) && ! MemberQ[pl, #] &, 1];
    If[p != {},
      fp = Join[fp, {p}];
      b = Select[Drop[ps, po = Position[ps, p[[1]]][[1]][[1]]],
        MemberQ[pl, #] &, 1];
      If[b != {}, bp = Join[bp, {b}], bp = Join[bp, {{0}}]];
      pl = Union[pl, Drop[ps, po - 1]]]]; Flatten@bp

Formula

a(n) > A291528(n) || a(n) == 0.

A168144 First differences of A168143 which are different from 1, incremented by 14.

Original entry on oeis.org

19, 23, 31, 47, 79
Offset: 1

Views

Author

Vladimir Shevelev, Nov 19 2009

Keywords

Comments

All terms of the sequence are primes greater than 17.
Are there more than 5 terms?

Crossrefs

Programs

Extensions

Corrected and edited by Eric Rowland, Jan 27 2019
Showing 1-10 of 11 results. Next