cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A151800 Least prime > n (version 2 of the "next prime" function).

Original entry on oeis.org

2, 2, 3, 5, 5, 7, 7, 11, 11, 11, 11, 13, 13, 17, 17, 17, 17, 19, 19, 23, 23, 23, 23, 29, 29, 29, 29, 29, 29, 31, 31, 37, 37, 37, 37, 37, 37, 41, 41, 41, 41, 43, 43, 47, 47, 47, 47, 53, 53, 53, 53, 53, 53, 59, 59, 59, 59, 59, 59, 61, 61, 67, 67, 67, 67, 67, 67, 71, 71, 71, 71, 73, 73, 79
Offset: 0

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Author

N. J. A. Sloane, Jun 29 2009

Keywords

Comments

Version 1 of the "next prime" function is A007918: smallest prime >= n.
Maple's nextprime() is this version 2; PARI/GP's nextprime() is version 1.
See A007918 for references and further information.
a(n) is the smallest number greater than one that is not divisible by any 1 < k <= n. Consider a multi-round election in which, in each round, voters each cast one vote for one of the remaining candidates. Then, any candidates which receive the fewest votes in that round are eliminated. This repeats until either one candidate remains, who wins the election, or no candidates remain. a(n) is the smallest nontrivial number of voters that can guarantee a winner if the election initially has n > 0 candidates. This is a consequence of the first fact. - Thomas Anton, Mar 30 2020
Conjecture: if n > 3, then a(n) < n^(n^(1/n)). - Thomas Ordowski, Feb 23 2023

Crossrefs

Programs

Formula

a(n) = A007918(n+1).
a(n) = 1 + Sum_{k=1..2n} (floor((n!^k)/k!) - floor(((n!^k)-1)/k!)). - Anthony Browne, May 11 2016
a(n) = A000040(A036234(n)). - Ridouane Oudra, Sep 30 2024

A317058 a(n) is the smallest composite k such that 1^(k-1) + 2^(k-1) + ... + n^(k-1) == n (mod k).

Original entry on oeis.org

4, 341, 473, 4, 4, 133, 497, 4, 4, 15, 9, 4, 4, 143, 35, 4, 4, 51, 57, 4, 4, 77, 253, 4, 4, 65, 9, 4, 4, 115, 155, 4, 4, 187, 35, 4, 4, 9, 247, 4, 4, 287, 2051, 4, 4, 15, 33, 4, 4, 35, 85, 4, 4, 9, 9, 4, 4, 551, 1711, 4, 4, 713, 21, 4, 4, 55, 77, 4, 4, 35, 35, 4
Offset: 1

Views

Author

Thomas Ordowski, Jul 26 2018

Keywords

Comments

According to the Agoh-Giuga conjecture, a(n) <> n+1.
a(n) = 4 if and only if n == {0, 1} (mod 4).

Crossrefs

Programs

  • Mathematica
    a[n_] := Block[{k = 4}, While[PrimeQ[k] || Mod[Sum[PowerMod[j, k-1, k], {j, n}], k] != Mod[n, k], k++]; k]; Array[a, 72] (* Giovanni Resta, Jul 26 2018 *)
  • PARI
    a(n) = forcomposite(k=1,, if (sum(j=1,n, Mod(j,k)^(k-1)) == n, return (k));); \\ Michel Marcus, Jul 26 2018
    
  • Python
    from sympy import isprime
    def g(n,p,q): # compute (-n + sum_{k=1,n} k^p)  mod q
        c = (-n) % q
        for k in range(1,n+1):
            c = (c+pow(k,p,q)) % q
        return c
    def A317058(n):
        k = 2
        while isprime(k) or g(n,k-1,k):
            k += 1
        return k # Chai Wah Wu, Jul 30 2018

Extensions

More terms from Giovanni Resta, Jul 26 2018

A317358 a(n) is the smallest number k > 1 such that 1^(k-1) + 2^(k-1) + ... + n^(k-1) == n (mod k).

Original entry on oeis.org

2, 3, 5, 2, 2, 7, 11, 2, 2, 3, 3, 2, 2, 17, 17, 2, 2, 3, 3, 2, 2, 23, 29, 2, 2, 5, 3, 2, 2, 31, 37, 2, 2, 37, 35, 2, 2, 3, 41, 2, 2, 43, 47, 2, 2, 3, 3, 2, 2, 5, 5, 2, 2, 3, 3, 2, 2, 59, 61, 2, 2, 67, 3, 2, 2, 55, 71, 2, 2, 35, 35, 2, 2, 3, 5, 2, 2, 5, 5, 2, 2
Offset: 1

Views

Author

Thomas Ordowski, Jul 26 2018

Keywords

Comments

a(n) = 2 if and only if n == {0, 1} (mod 4).
a(n) <= A151800(n).
A133906(n) <= a(n) <= A133907(n).
The sequence is unbounded.
Numbers n such that a(n-1) = n are 2, 3, 7, 23, 31, 43, 59, 139, 283, ...
By the Agoh-Giuga conjecture, if a(n-1) = n, then n is a prime.
It seems that if a(n) > n, then a(n) is a prime (the next prime after n).
If a(n) = n, then n is in A121707. These numbers are 35, 143, 187, 215, ...
Conjecture: all composite terms of the sequence are A121707.

Crossrefs

Programs

  • Mathematica
    a[n_] := Block[{k=2}, While[Mod[Sum[PowerMod[j, k-1, k], {j, n}], k] != Mod[n, k], k++]; k]; Array[a, 81] (* Giovanni Resta, Jul 29 2018 *)
  • PARI
    a(n) = for(k=2,oo, if (sum(j=1,n, Mod(j,k)^(k-1)) == n, return (k));); \\ Michel Marcus, Jul 26 2018
    
  • Python
    def g(n,p,q): # compute (-n + sum_{k=1,n} k^p)  mod q
        c = (-n) % q
        for k in range(1,n+1):
            c = (c+pow(k,p,q)) % q
        return c
    def A317358(n):
        k = 2
        while g(n,k-1,k):
            k += 1
        return k # Chai Wah Wu, Jul 30 2018

Extensions

More terms from Michel Marcus, Jul 26 2018

A317587 a(n) is the smallest number m > n such that Sum_{k=1..n-1} k^(m-1) == n-1 (mod m).

Original entry on oeis.org

3, 5, 5, 6, 7, 11, 11, 11, 11, 13, 13, 16, 17, 17, 17, 19, 19, 23, 23, 23, 23, 29, 29, 29, 29, 29, 29, 31, 31, 37, 37, 37, 36, 37, 37, 40, 41, 41, 41, 43, 43, 47, 47, 47, 47, 53, 53, 53, 53, 53, 53, 59, 59, 59, 59, 59, 59, 61, 61, 67, 67, 67, 67, 67, 67, 71, 71, 71, 71
Offset: 2

Views

Author

Thomas Ordowski, Aug 01 2018

Keywords

Comments

a(n) <= A317357(n-1).
a(n) <= A151800(n), where a(n) < A151800(n) for n = 5, 13, 34, 37, ... with composite terms a(n) = 6, 16, 36, 40, ...
The smallest odd composite term is a(201) = 207. Are there any more? - Michel Marcus, Jul 02 2018
Conjecture: If p is a prime, then odd a(p) is the next prime after p. - Thomas Ordowski, Aug 06 2018

Crossrefs

Programs

  • Mathematica
    Array[Block[{m = # + 1}, While[Mod[Sum[k^(m - 1), {k, # - 1}], m] != # - 1, m++]; m] &, 69, 2] (* Michael De Vlieger, Aug 02 2018 *)
  • PARI
    a(n) = for(m=n+1, oo, if (sum(k=1, n-1, Mod(k, m)^(m-1)) == Mod(n-1, m), return (m)); ); \\ Michel Marcus, Aug 01 2018

Extensions

More terms from Michel Marcus, Aug 01 2018
Showing 1-4 of 4 results.