0, 0, 1, 0, 1, 2, 0, 2, 3, 4, 0, 2, 3, 4, 5, 0, 3, 5, 6, 7, 8, 0, 3, 5, 6, 7, 8, 9, 0, 4, 6, 8, 9, 10, 11, 12, 0, 5, 8, 10, 11, 13, 14, 15, 16, 0, 5, 8, 10, 12, 13, 14, 15, 16, 17, 0, 5, 8, 10, 12, 13, 14, 15, 16, 17, 18, 0, 7, 11, 14, 16, 18, 19, 21, 22, 23, 24, 25
Offset: 1
(For row 4.) A completely additive sequence requires T(4,1) = 0. Strict monotonicity requires T(4,4) > T(4,3) > T(4,2). So T(4,4) >= T(4,2) + 2. Using the additivity this becomes T(4,2) + T(4,2) >= T(4,2) + T(4,1) + 2. Subtracting T(4,2) and substituting 0 for T(4,1) we get T(4,2) >= 2. So from T(4,4) > T(4,3) > T(4,2), we see T(4,3) >= 3, T(4,4) >= 4. So row 4 = (0, 2, 3, 4) as it is strictly monotonic and completely additive and from the preceding arguments is seen to be the lexicographically earliest such.
Triangle starts:
0;
0, 1;
0, 1, 2;
0, 2, 3, 4;
0, 2, 3, 4, 5;
0, 3, 5, 6, 7, 8;
0, 3, 5, 6, 7, 8, 9;
0, 4, 6, 8, 9, 10, 11, 12;
0, 5, 8, 10, 11, 13, 14, 15, 16;
0, 5, 8, 10, 12, 13, 14, 15, 16, 17;
0, 5, 8, 10, 12, 13, 14, 15, 16, 17, 18;
0, 7, 11, 14, 16, 18, 19, 21, 22, 23, 24, 25;
0, 7, 11, 14, 16, 18, 19, 21, 22, 23, 24, 25, 26;
0, 7, 11, 14, 16, 18, 20, 21, 22, 23, 24, 25, 26, 27;
0, 8, 13, 16, 19, 21, 23, 24, 26, 27, 28, 29, 30, 31, 32;
0, 9, 14, 18, 21, 23, 25, 27, 28, 30, 31, 32, 33, 34, 35, 36;
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