cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A308129 Number of (undirected) Hamiltonian paths on the n X n king graph.

Original entry on oeis.org

1, 12, 392, 171592, 364618672, 6544911081900, 829555065360355292, 817534730458899350635436, 6154392250018061759082363305112, 360916610325065945171647827293872547848, 165298493343313203241690299664254975948394404072
Offset: 1

Views

Author

Eric W. Weisstein, May 14 2019

Keywords

Crossrefs

Main diagonal of A350729.

Formula

a(n) = A158651(n)/2 for n > 1.

Extensions

a(1) corrected by Andrew Howroyd, Jan 16 2022

A339760 Number of (undirected) Hamiltonian paths in the 2 X n king graph.

Original entry on oeis.org

1, 12, 48, 208, 768, 2752, 9472, 32000, 106496, 351232, 1150976, 3756032, 12222464, 39698432, 128778240, 417398784, 1352138752, 4378591232, 14175698944, 45886734336, 148520304640, 480679821312, 1555633799168, 5034389536768, 16292153131008, 52723609239552, 170619454881792, 552140862914560
Offset: 1

Views

Author

Seiichi Manyama, Dec 16 2020

Keywords

Crossrefs

Programs

  • PARI
    Vec((1 + 6*x - 16*x^2 + 24*x^3 - 16*x^4) / ((1 - 2*x)^2 * (1 - 2*x - 4*x^2)) + O(x^20)) \\ Andrew Howroyd, Jan 17 2022
  • Python
    # Using graphillion
    from graphillion import GraphSet
    def make_nXk_king_graph(n, k):
        grids = []
        for i in range(1, k + 1):
            for j in range(1, n):
                grids.append((i + (j - 1) * k, i + j * k))
                if i < k:
                    grids.append((i + (j - 1) * k, i + j * k + 1))
                if i > 1:
                    grids.append((i + (j - 1) * k, i + j * k - 1))
        for i in range(1, k * n, k):
            for j in range(1, k):
                grids.append((i + j - 1, i + j))
        return grids
    def A(start, goal, n, k):
        universe = make_nXk_king_graph(n, k)
        GraphSet.set_universe(universe)
        paths = GraphSet.paths(start, goal, is_hamilton=True)
        return paths.len()
    def B(n, k):
        m = k * n
        s = 0
        for i in range(1, m):
            for j in range(i + 1, m + 1):
                s += A(i, j, n, k)
        return s
    def A339760(n):
        return B(n, 2)
    print([A339760(n) for n in range(1, 21)])
    

Formula

Empirical g.f.: x*(1 + 6*x - 16*x^2 + 24*x^3 - 16*x^4) / ((1 - 2*x)^2 * (1 - 2*x - 4*x^2)). - Vaclav Kotesovec, Dec 16 2020
The above formula is correct. - Andrew Howroyd, Jan 17 2022

A339761 Number of (undirected) Hamiltonian paths in the 3 X n king graph.

Original entry on oeis.org

1, 48, 392, 4678, 43676, 406396, 3568906, 30554390, 254834078, 2085479610, 16791859330, 133416458104, 1048095087616, 8154539310958, 62918331433308, 481954854686434, 3668399080453520, 27766093432542984, 209120844634276158, 1568050593805721822
Offset: 1

Views

Author

Seiichi Manyama, Dec 16 2020

Keywords

Crossrefs

Programs

  • Python
    # Using graphillion
    from graphillion import GraphSet
    def make_nXk_king_graph(n, k):
        grids = []
        for i in range(1, k + 1):
            for j in range(1, n):
                grids.append((i + (j - 1) * k, i + j * k))
                if i < k:
                    grids.append((i + (j - 1) * k, i + j * k + 1))
                if i > 1:
                    grids.append((i + (j - 1) * k, i + j * k - 1))
        for i in range(1, k * n, k):
            for j in range(1, k):
                grids.append((i + j - 1, i + j))
        return grids
    def A(start, goal, n, k):
        universe = make_nXk_king_graph(n, k)
        GraphSet.set_universe(universe)
        paths = GraphSet.paths(start, goal, is_hamilton=True)
        return paths.len()
    def B(n, k):
        m = k * n
        s = 0
        for i in range(1, m):
            for j in range(i + 1, m + 1):
                s += A(i, j, n, k)
        return s
    def A339761(n):
        return B(n, 3)
    print([A339761(n) for n in range(1, 11)])

Formula

G.f.: x*(1 + 33*x - 292*x^2 + 815*x^3 + 782*x^4 - 3649*x^5 - 4630*x^6 + 1517*x^7 + 3835*x^8 - 3822*x^9 - 5722*x^10 - 5418*x^11 - 7562*x^12 - 4808*x^13 - 240*x^14 + 720*x^15 + 216*x^16)/((1 - x)*(1 - 4*x - 15*x^2 - 8*x^3 - 6*x^4)^2*(1 - 6*x - 12*x^2 + 27*x^3 - 2*x^4 - 30*x^5 - 4*x^6 + 6*x^7)). - Andrew Howroyd, Jan 17 2022

A339762 Number of (undirected) Hamiltonian paths in the 4 X n king graph.

Original entry on oeis.org

1, 208, 4678, 171592, 4743130, 132202038, 3461461060, 88405359072, 2197293738684, 53565801482634, 1284136961473864, 30365618160010650, 709700882866473654, 16422374051280905778, 376744989106882359402, 8578133199326578887346, 194030408441913214687458
Offset: 1

Views

Author

Seiichi Manyama, Dec 16 2020

Keywords

Crossrefs

Programs

  • Python
    # Using graphillion
    from graphillion import GraphSet
    def make_nXk_king_graph(n, k):
        grids = []
        for i in range(1, k + 1):
            for j in range(1, n):
                grids.append((i + (j - 1) * k, i + j * k))
                if i < k:
                    grids.append((i + (j - 1) * k, i + j * k + 1))
                if i > 1:
                    grids.append((i + (j - 1) * k, i + j * k - 1))
        for i in range(1, k * n, k):
            for j in range(1, k):
                grids.append((i + j - 1, i + j))
        return grids
    def A(start, goal, n, k):
        universe = make_nXk_king_graph(n, k)
        GraphSet.set_universe(universe)
        paths = GraphSet.paths(start, goal, is_hamilton=True)
        return paths.len()
    def B(n, k):
        m = k * n
        s = 0
        for i in range(1, m):
            for j in range(i + 1, m + 1):
                s += A(i, j, n, k)
        return s
    def A339762(n):
        return B(n, 4)
    print([A339762(n) for n in range(1, 11)])

A339763 Number of (undirected) Hamiltonian paths in the 5 X n king graph.

Original entry on oeis.org

1, 768, 43676, 4743130, 364618672, 28808442502, 2125185542510, 153198148096800, 10739936528121270, 738599412949227054, 49945111084852186032, 3331294312194018084810, 219599512046978073473186, 14331641424452867055092544, 927231520831830806024847178
Offset: 1

Views

Author

Seiichi Manyama, Dec 16 2020

Keywords

Crossrefs

Programs

  • Python
    # Using graphillion
    from graphillion import GraphSet
    def make_nXk_king_graph(n, k):
        grids = []
        for i in range(1, k + 1):
            for j in range(1, n):
                grids.append((i + (j - 1) * k, i + j * k))
                if i < k:
                    grids.append((i + (j - 1) * k, i + j * k + 1))
                if i > 1:
                    grids.append((i + (j - 1) * k, i + j * k - 1))
        for i in range(1, k * n, k):
            for j in range(1, k):
                grids.append((i + j - 1, i + j))
        return grids
    def A(start, goal, n, k):
        universe = make_nXk_king_graph(n, k)
        GraphSet.set_universe(universe)
        paths = GraphSet.paths(start, goal, is_hamilton=True)
        return paths.len()
    def B(n, k):
        m = k * n
        s = 0
        for i in range(1, m):
            for j in range(i + 1, m + 1):
                s += A(i, j, n, k)
        return s
    def A339763(n):
        return B(n, 5)
    print([A339763(n) for n in range(1, 11)])
Showing 1-5 of 5 results.