A322919 Numbers k such that k and k-1 both first appear in the same power of 2 (in base 10).
59, 74, 111, 785, 793, 914, 957, 985, 1070, 1467, 2019, 2099, 2332, 2610, 2934, 3028, 3083, 3311, 3334, 3973, 4198, 4208, 4334, 4590, 4689, 4785, 5247, 5350, 5535, 6166, 6335, 6669, 6761, 7167, 7340, 7707, 7980, 8668, 8990, 9180, 9840, 11110, 13096, 16285, 17418, 18091, 18361, 19219, 20522, 21494, 21827
Offset: 1
Examples
For instance 2019 is in the sequence since 2018 and 2019 both appear in 2^212 and neither appear in any smaller power of two.
Links
- David A. Corneth, Table of n, a(n) for n = 1..3106
Crossrefs
Indices of consecutive repeats in A030000.
Programs
-
C
#include
int main() { int n = 1000001; /* Highest term */ int p = 2; /* Powers of two. Test throughly if you change it. */ int r = 10; /* Base ten. Test throughly if you change it. */ char a[n]; int b,c,i,j,k,k2,l,lk,m,ok,ok2,u,d[7],f[n],g[n],v[n]; u = n; for (j=0;j M. F. Hasler, Jul 05 2021*/ f[j] = g[j] = -1; } a[0] = 1; for (m=0;(m -1;l--) { ok = 1; for (j=lk-1;j>-1;j--) if (a[l+j] != d[j]) ok = 0; if (ok) ok2 = 1; } if (ok2) { f[k] = m; u--; } } if ((g[k]==-1) && (lk<=b+1)) { ok = 1; for (j=lk-1;j>-1;j--) if (a[b-lk+j+1] != d[j]) ok = 0; if (ok) g[k] = m; } } c = 0; for (j=0;j r-1) { c = a[j] / r; a[j] %= r; } } } for (i=1;i -
PARI
uptoQdigits(n) = {v = vector(10^n); p = 1/2; todo = 10^n; my(res = List()); for(i = 1, oo, p<<=1; process(p, n); if(todo <= 0, break)); for(i = 1, #v - 1, if(v[i] == v[i+1], listput(res, i))); res} process(p, n) = {my(dp = digits(p), vd, lp = logint(p, 2)); qdp = #dp; my(t = min(n, qdp)); for(qd = 1, t, for(j = 1, qdp - qd + 1, vd = fromdigits(vector(qd, i, dp[j+i-1])); if(v[vd + 1] == 0, v[vd + 1] = lp; todo--)))} \\ David A. Corneth, Dec 31 2018
Comments