cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A276738 Irregular triangle read by rows: T(n,m) = coefficients in a power/Fourier series expansion of an arbitrary anharmonic oscillator's exact phase space trajectory.

Original entry on oeis.org

-1, -1, 5, -1, 12, -32, -1, 14, 7, -126, 231, -1, 16, 16, -160, -160, 1280, -1792, -1, 18, 18, -198, 9, -396, 1716, -66, 2574, -12870, 14586, -1, 20, 20, -240, 20, -480, 2240, -240, -240, 6720, -17920, 2240, -35840, 129024, -122880, -1, 22, 22, -286, 22, -572, 2860, 11, -572, -286, 8580, -24310, -286, 4290, 8580, -97240, 184756, 715
Offset: 1

Views

Author

Bradley Klee, Sep 16 2016

Keywords

Comments

Irregular triangle read by rows (see examples). Consider an arbitrary anharmonic oscillator with Hamiltonian energy: H=(1/2)*b^2=(1/2)*(p^2+q^2) + Sum_{i=3} 2*v_i*q^i, and a stable minimum at (p,q)=(0,0). The phase space trajectory can be written in polar phase space coordinates as (q,p) = (R(x)cos(x),R(x)sin(x))=(R(Q)Q,R(Q)P). The present triangle determines a power / Fourier series of R(Q): R(Q) = b * (1 + sum b^n*T(n,m)*f(n,m) ); where the sum runs over n = 1,2,3 ... and m = 1,2,3...A000041(n). The basis functions f(n,m) are constructed from partitions of "n" listed in reverse lexicographic order. Partition n=(z_1+z_2+...z_j) becomes 2*Q^((z_1+2)+(z_2+2)+...(z_j+2))*v_{z_1+2}*v_{z_2+2}*...*v_{z_j+2} (see examples). This sequence transforms into A273506/A273507 by setting v_i=0 for odd i, v_i:=(-1)^(i/2-1)/2/(i!) otherwise, and (1/2)*b^2 = 2*k. For more details read "Plane Pendulum and Beyond by Phase Space Geometry" (Klee, 2016).

Examples

			n/m  1    2     3     4     5     6      7
--------------------------------------------
1  | -1
2  | -1   5
3  | -1   12   -32
4  | -1   14    7   -126   231
5  | -1   16    16  -160  -160   1280  -1792
--------------------------------------------
R[1,Q] = -2*v_3*Q^3
R[2,Q] = -2*v_4*Q^4 + 10*v_3^2*Q^6
R[Q]   = b*(1+b*(-2*v_3*Q^3)+b^2*(-2*v_4*Q^4 + 10*v_3^2*Q^6 ))+O(b^4)
Construct basis for R[4,Q]; List partitions: {{4}, {3, 1}, {2, 2}, {2, 1, 1}, {1, 1, 1, 1}}; Transform Plus 2: {{v_6}, {v_5, v_3}, {v_4, v_4}, {v_4, v_3, v_3}, {v_3, v_3, v_3, v_3}}; Multiply: {v_6, v_5*v_3, v_4^2, v_4*v_3^2, v_3^4}; don't forget power of Q and factor of 2: {2*v_6*Q^6, 2*v_5*v_3*Q^8, 2*v_4^2*Q^8, 2*v_4*v_3^2*Q^10, 2*v_3^4*Q^12}.
		

Crossrefs

Programs

  • Mathematica
    R[n_] := b Plus[1, Total[b^# R[#, q] & /@ Range[n]]]
    Vp[n_] := Total[2 v[# + 2] q^(# + 2) & /@ Range[n]]
    H[n_] := Expand[1/2*r^2 + Vp[n]]
    RRules[n_] :=  With[{H = Series[ReplaceAll[H[n], {q -> R[n] Q, r -> R[n]}], {b, 0, n + 2}]},  Function[{rules},
        Nest[Rule[#[[1]], ReplaceAll[#[[2]], rules]] & /@ # &, rules, n]][
       Flatten[R[#, q] -> Expand[-ReplaceAll[ Coefficient[H, b^(# + 2)], {R[#, q] -> 0}]] & /@ Range[n]]]]
    basis[n_] :=  Times[Times @@ (v /@ #), Q^Total[#],2] & /@ (IntegerPartitions[n] /. x_Integer :> x + 2)
    TriangleRow[n_, rules_] := With[{term = Expand[rules[[n, 2]]]},
      Coefficient[term, #] & /@ basis[n]]
    With[{rules = RRules[10]}, TriangleRow[#, rules] & /@ Range[10]]

A276816 Irregular triangle read by rows: T(n,m) = coefficients in power/Fourier series expansion of an arbitrary anharmonic oscillator's exact period.

Original entry on oeis.org

-24, 480, -120, 6720, 3360, -241920, 1774080, -560, 40320, 40320, -1774080, 20160, -3548160, 61501440, -591360, 92252160, -1845043200, 8364195840, -2520, 221760, 221760, -11531520, 221760, -23063040, 461260800, 110880, -23063040, -11531520, 1383782400, -15682867200, -11531520, 691891200, 1383782400, -62731468800, 476759162880
Offset: 1

Views

Author

Bradley Klee, Sep 18 2016

Keywords

Comments

The phase space trajectory A276738 has phase space angular velocity A276814 and differential time dependence A276815. We calculate the period K = Int dt over the range [2*Pi, 0], trivial to compute from A276815 using A273496. Then K/(2*Pi) = 1 + sum b^(2n)*T(n,m)*f'(n,m); where the sum runs over n = 1, 2, 3 ... and m = 1, 2, 3, ... A000041(2n), and f'(n,m) = f(2n,m) of A276738 with Q=1/2. Choosing one point from the infinite dimensional coefficient space--v_i=0 for odd i, v_i=(-1)^(i/2-1)/2/(i!) otherwise--setting b^2 = 4*k, and summing over the entire table obtains the EllipticK expansion 2*A038534/A038533. For more details read "Plane Pendulum and Beyond by Phase Space Geometry" (Klee, 2016).

Examples

			n/m   1     2     3         4         5
------------------------------------------
1  | -24   480
2  | -120  6720  3360   -241920   1774080
------------------------------------------
For pendulum values, f'(1,*)={(-1/384), 0}, f'(2,*) = {1/46080, 0, 1/294912, 0, 0}. Then K/(2Pi) = 1+(-1/384)*(-24)*4*k+((1/46080)*(-120)+(1/294912)*3360)*16*k^2=1+(1/4)*k + (9/64)*k^2, the first few terms of EllipticK.
		

Crossrefs

Programs

  • Mathematica
    RExp[n_]:=Expand[b Plus[R[0], Total[b^# R[#] & /@ Range[n]]]]
    RCalc[n_]:=With[{basis =Subtract[Tally[Join[Range[n + 2], #]][[All, 2]],Table[1, {n + 2}]] & /@ IntegerPartitions[n + 2][[3 ;; -1]]},
    Total@ReplaceAll[Times[-2, Multinomial @@ #, v[Total[#]],Times @@ Power[RSet[# - 1] & /@ Range[n + 2], #]] & /@ basis, {Q^2 -> 1, v[2] -> 1/4}]]
    dt[n_] := With[{exp = Normal[Series[-1/(1 + x)/.x -> Total[(2 # v[#] RExp[n - 1]^(# - 2) &/@Range[3, n + 2])], {b, 0, n}]]},
    Expand@ReplaceAll[Coefficient[exp, b, #] & /@ Range[n], R -> RSet]]
    RingGens[n_] :=Times @@ (v /@ #) & /@ (IntegerPartitions[n]/. x_Integer :> x + 2)
    tri[m_] := MapThread[Function[{a, b},Times[-# /. v[n_] :> Q^n /. Q^n_ :>  Binomial[n, n/2],(1/2) Coefficient[a, #]] & /@ b], {dt[2 m][[2 #]] & /@ Range[m], RingGens[2 #] & /@ Range[m]}]
    RSet[0] = 1; Set[RSet[#], Expand@RCalc[#]] & /@ Range[2*7];
    tri7 = tri[7]; tri7 // TableForm
    PeriodExpansion[tri_, n_] := ReplaceAll[ 1 + Dot[MapThread[ Dot, {tri,
      2 RingGens[2 #] & /@ Range[n]}], (2 h)^(Range[n])], {v[m_] :> (v[m]*(1/2)^m)}]
    {#,SameQ[Normal@Series[(2/Pi)*EllipticK[k],{k,0,7}],#]}&@ReplaceAll[
    PeriodExpansion[tri7,7],{v[n_/;OddQ[n]]:>0,v[n_]:> (-1)^(n/2-1)/2/(n!),h->2 k}]

A276817 Irregular triangle read by rows: T(n,m) = coefficients in power/Fourier series expansion of an arbitrary anharmonic oscillator's exact differential precession.

Original entry on oeis.org

-1, 2, 6, -3, -16, 8, -48, 4, 30, -20, 140, 10, -140, 420, -5, -48, 36, -288, -24, 384, -1280, 12, -192, -96, 1920, -3840, 6, 70, -56, 504, 42, -756, 2772, -28, 504, 252, -5544, 12012, 14, -252, -252, 2772, 2772, -24024, 36036, -7, -96, 80, -800, -64, 1280, -5120, 48, -960, -480, 11520, -26880, -32, 640, 640, -7680
Offset: 0

Views

Author

Bradley Klee, Sep 18 2016

Keywords

Comments

Irregular triangle read by rows (see examples).
Consider an axially symmetric oscillator in two dimensions with polar coordinates ( r, y ). By conservation of angular momentum, replace the cyclic angle coordinate y with dy/dt = 1/r^2. The system becomes one-dimensional in r, with an effective potential including the 1/r^2 term. Assume that the effective potential has a minimum around r0 and apply a linear transform r --> q = r-r0. Radial oscillations around the effective potential minimum follow the exact solution of A276738, A276814, A276815, A276816. Now dy = dx (dy/dt) / (dx/dt) = dx * Sum b^n*T(n,m)*F(n,m), with n=1,2,3.... and m=1,2,3...A000070(n). Basis functions F(n,m) are an ordered union over A276738's f(n,m): F(n,m')={ (1/r0^2)*(Q/r0)^n } & Append_{i=1..n}_{m=1..A000041(n)} (1/2/r0^2)*(Q/r0)^(n - i)*f(i,m), where each successive term f(i,m) is appended such that index m' inherets the ordering of each m index (see examples). Integrating dx over a range of 2 Pi loses all odd rows, as in A276815 / A276816. This sequence is a useful tool in classical and relativistic astronomy (follow links to Wolfram demonstrations).

Examples

			n/m   1   2    3    4      5     6    7
------------------------------------------
0  | -1
1  |  2   6
2  | -3  -16   8   -48
3  |  4   30  -20   140   10   -140   420
------------------------------------------
Construction of F(2,_). List f(i,_) basis sets: {f(1,_)={2*Q^3*v_3},f(2,_)= {2*Q^4*v_4, 2*Q^6*v_3^2}}; Integrate and join: F(2,_)={(1/r0^2)*(Q/r0)^2,2*Q^3*v_3*(1/2/r0^2)*(Q/r0),2*Q^4*v_4*(1/2/r0^2), 2*Q^6*v_3^2*(1/2/r0^2)}={Q^2/r0^4,Q^4*v_3/r0^3,Q^4*v_4/r0^2,Q^6*v_3^2/r0^2}.
dy Expansion to second order: dy=dx(-(1/r0^2)+b^2*(2*Q/r0^3 + 6*Q^3*v_3/r0^2)+b^3*(-3*Q^2/r0^4 - 16*Q^4*v_3/r0^3 - 48*Q^6*v_3^2/r0^2 + 8*Q^4*v_4/r0^2)+O(b^3).
Cancellation of higher orders 1 to infinity and closed orbits. Kepler values {r0 = 1, v_n := ((n - 1)/4)*(-1)^n} yield dy = -dx. Harmonic oscillator values {r0 = Sqrt[2], v_n := ((-1)^n*(n + 1)/4/2)/sqrt[2]^n} yield dy = -(1/2)*dx. Parity symmetric conjectured values {r0=Sqrt[1/R],v_n odd n := 0,v_n even n := R^(n/2 - 1)*(n/8)} yield dy = -R*dx (see attached image "Pentagonal Orbits")?
		

References

  • R. M. Wald, General Relativity, University of Chicago press, 2010, pages 139-143.
  • J.A. Wheeler, A Journey into Gravity and Spacetime, Scientific American Library, 1990, pages 168-183.

Crossrefs

Programs

  • Mathematica
    R[n_] := b Plus[1, Total[b^# R[#, q] & /@ Range[n]]]
    Vp[n_] := Total[2 v[# + 2] q^(# + 2) & /@ Range[n]]
    H[n_] := Expand[1/2*r^2 + Vp[n]]
    RRules[n_] :=  With[{H = Series[ReplaceAll[H[n], {q -> R[n] Q, r -> R[n]}], {b, 0, n + 2}]},  Function[{rules},
        Nest[Rule[#[[1]], ReplaceAll[#[[2]], rules]] & /@ # &, rules, n]][
       Flatten[R[#, q] -> Expand[-ReplaceAll[ Coefficient[H, b^(# + 2)], {R[#, q] -> 0}]] & /@ Range[n]]]]
    xDot[n_] := Expand[Normal@Series[ReplaceAll[ Q^2 D[D[q[t], t]/q[t], t], {D[q[t], t] -> R[n] P, q[t] -> R[n] Q, r -> R[n], D[q[t], {t, 2}]
    ->  ReplaceAll[D[-(q^2/2 + Vp[n]), q], q -> R[n] Q]} ], {b, 0, n}] /. RRules[n] /. {P^2 -> 1 - Q^2}]
    ydot[n__] := Expand[Normal@Series[1/(r0 + q)^2 /. {q -> R[n] Q} /. RRules[n], {b, 0, n}]]
    dy[n_] := Expand@Normal@Series[ydot[n]/xDot[n], {b, 0, n}]
    basis[n_] :=  Times[Times @@ (v /@ #), Q^Total[#],2] & /@ (IntegerPartitions[n] /. x_Integer :> x + 2)
    extendedBasis[n_] :=Flatten[(1/2/r0^2) (Q/r0)^(n - #) basis[#] & /@ Range[0, n]]
    TriangleRow[n_, func_] := Coefficient[func, b^n #] & /@ extendedBasis[n]
    With[{dy5 = dy[5]}, TriangleRow[#, dy5] /. v[_] -> 0 & /@ Range[0, 5]]
    (*Kepler Test*)TrigReduce[dy[5] /. {Q -> Cos[x]}] /. {r0 -> 1, Cos[] -> 0, v[n] :> ((n - 1)/4)*(-1)^n}
    (*Harmonic Test*)TrigReduce[dy[5] /. {Q -> Cos[x]}] /. {Cos[] -> 0, v[n] :> ((-1)^n*(n + 1)/4/2)/Sqrt[2]^n, r0 -> Sqrt[2]}
    (*Conjecture*)TrigReduce[dy[5] /. {Q -> Cos[x]}] /. {Cos[] -> 0, v[n /; OddQ[n]] :> 0, v[n_] :> RR^(n/2 - 1)*n/8, r0 -> Sqrt[1/RR]}

A038535 Numerators of coefficients of EllipticE/Pi.

Original entry on oeis.org

1, -1, -3, -5, -175, -441, -4851, -14157, -2760615, -8690825, -112285459, -370263621, -19870814327, -67607800225, -931331941875, -3241035157725, -2913690606794775, -10313859829588425, -147068001273760875, -527570807893408125, -30451387031607516975
Offset: 0

Views

Author

Wouter Meeussen, revised Jan 03 2001

Keywords

Comments

Contribution from Wolfdieter Lang, Nov 08 2010: (Start)
a(n)/A056982(n) = -(binomial(2*n,n)^2)/((2*n-1)*2^(4*n)), n>=0, are the coefficients of x^n of hypergeometric([1/2,-1/2],[1],x).
The series hypergeometric([1/2,-1/2],[1],e^2)=L/(2*Pi*a) with L the perimeter of an ellipse with major axis a and numerical eccentricity e. (End)

Crossrefs

a(n) divides A000891(n+1).

Programs

  • Mathematica
    Numerator[CoefficientList[Series[EllipticE[m]/Pi,{m,0,25}],m]] (* Harvey P. Dale, Dec 16 2011 *)

Formula

a(n) = 2^(-2 w[n])binomial[2n, n]^2 (-1)^(2n)/(1-2n) with w[n]=A000120 = number of 1's in binary expansion of n

A069955 Let W(n) = Product_{k=1..n} (1 - 1/4k^2), the partial Wallis product (lim_{n->oo} W(n) = 2/Pi); then a(n) = numerator(W(n)).

Original entry on oeis.org

1, 3, 45, 175, 11025, 43659, 693693, 2760615, 703956825, 2807136475, 44801898141, 178837328943, 11425718238025, 45635265151875, 729232910488125, 2913690606794775, 2980705490751054825, 11912508103174630875, 190453061649520333125, 761284675790187924375
Offset: 0

Views

Author

Benoit Cloitre, Apr 27 2002

Keywords

Comments

Equivalently, denominators in partial products of the following approximation to Pi: Pi = Product_{n>=1} 4*n^2/(4*n^2-1). Numerators are in A056982.

References

  • Orin J. Farrell and Bertram Ross, Solved Problems in Analysis, Dover, NY, 1971; p. 77.

Crossrefs

Not the same as A001902(n).
Cf. A056982 (denominators), A001790, A046161.
W(n)=(3/4)*(A120995(n)/A120994(n)), n>=1.

Programs

  • Mathematica
    a[n_] := Numerator[Product[1 - 1/(4*k^2), {k, 1, n}]]; Array[a, 20, 0] (* Amiram Eldar, May 07 2025 *)
  • PARI
    a(n) = numerator(prod(k=1, n, 1-1/(4*k^2))); \\ Michel Marcus, Oct 22 2016

Formula

a(n) = numerator(W(n)), where W(n) = (2*n)!*(2*n+1)!/((2^n)*n!)^4.
W(n) = (2*n+1)*(binomial(2*n,n)/2^(2*n))^2 = (2*n+1)*(A001790(n)/A046161(n))^2 in lowest terms.
a(n) = (-1)^n*A056982(n)*C(-1/2,n)*C(n+1/2,n). - Peter Luschny, Apr 08 2016

A274659 Triangle entry T(n, m) gives the m-th contribution T(n, m)*sin((2*m+1)*v) to the coefficient of q^n in the Fourier expansion of Jacobi's elliptic sn(u|k) function when expressed in the variables v = u/(2*K(k)/Pi) and q, the Jacobi nome, written as series in (k/4)^2. K is the real quarter period of elliptic functions.

Original entry on oeis.org

1, 1, 1, -1, 0, 1, -1, -2, 0, 1, 2, 1, -2, 0, 1, 2, 3, 0, -2, 0, 1, -4, -2, 3, 0, -2, 0, 1, -4, -5, 1, 3, 0, -2, 0, 1, 7, 3, -6, 0, 3, 0, -2, 0, 1, 7, 9, -2, -6, 0, 3, 0, -2, 0, 1, -11, -5, 11, 1, -6, 0, 3, 0, -2, 0, 1, -11, -15, 3, 11, 0, -6, 0, 3, 0, -2, 0, 1, 17, 9, -17, -2, 11, 0, -6, 0, 3, 0, -2, 0, 1
Offset: 0

Views

Author

Wolfdieter Lang, Jul 18 2016

Keywords

Comments

If one takes the row polynomials as R(n, x) = Sum_{m=0..n} T(n, m)*x^(2*m+1), n >= 0, Jacobi's elliptic sn(u|k) function in terms of the new variables v and q becomes sn(u|k) = Sum_{n>=0} R(n, x)*q^n, if one replaces in R(n, x) x^j by sin(j*v).
v=v(u,k^2) and q=q(k^2) are computed with the help of A038534/A056982 for (2/Pi)*K and A002103 for q expanded in powers of (k/4)^2.
A test for sn(u|k) with u = 1, k = sqrt(1/2), that is v approximately 0.8472130848 and q approximately 0.04321389673, with rows n=0..10 (q powers not exceeding 10) gives 0.8030018002 to be compared with sn(1|sqrt(1/2)) approximately 0.8030018249.
For the derivation of the Fourier series formula of sn given in Abramowitz-Stegun (but there the notation sn(u|m=k^2) is used for sn(u|k)) see, e.g., Whittaker and Watson, p. 511 or Armitage and Eberlein, Exercises on p. 55.
For the cn expansion see A274661.
See also the W. Lang link, equations (34) and (35).

Examples

			The triangle T(n, m) begins:
      m  0   1  2  3  4  5  6  7  8  9 10 11
n\ 2m+1  1   3  5  7  9 11 13 15 17 19 21 23
0:       1
1:       1   1
2:      -1   0  1
3:      -1  -2  0  1
4:       2   1 -2  0  1
5:       2   3  0 -2  0  1
6:      -4  -2  3  0 -2  0  1
7:      -4  -5  1  3  0 -2  0  1
8:       7   3 -6  0  3  0 -2  0  1
9:       7   9 -2 -6  0  3  0 -2  0  1
10:    -11  -5 11  1 -6  0  3  0 -2  0  1
11:    -11 -15  3 11  0 -6  0  3  0 -2  0  1
...
T(4, 0) = 2 from the x^1 term in b(0, x)*a(4) + b(2, x)*a(2) + b(4, x)*a(0), that is x^1*3 + x^1*(-2) + x^1*1 = +2*x^1.
n=4: R(4, x) = 2*x^1 + 1*x^3 - 2*x^5 + 0*x^7 + 1*x^9, that is the sn(u|k) contribution of order q^4 in the new variables v and q is (2*sin(1*v) + 1*sin(3*v) - 2*sin(5*v) + 1*sin(9*v))*q^4.
		

References

  • J. V. Armitage and W. F. Eberlein, Elliptic Functions, London Mathematical Society, Student Texts 67, Cambridge University Press, 2006.
  • E. T. Whittaker and G. N. Watson, A Course of Modern Analysis, fourth edition, reprinted, 1958, Cambridge at the University Press.

Crossrefs

Formula

T(n, m) = [x^(2*m+1)]Sum_{j=0..n} b(j, x)*a(n-j), with a(k) = A274621(k/2) if k is even and a(k) = 0 if k is odd, and b(j, x) = Sum_{r | 2*j+1} x^r = Sum_{k=1..A099774(j+1)} x^(A274658(j, k)), for j >= 0.

A276814 Irregular triangle read by rows T(n,m), coefficients in power/Fourier series expansion of an arbitrary anharmonic oscillator's exact phase space angular velocity.

Original entry on oeis.org

-3, -4, 6, -5, 22, -30, -6, 36, 16, -168, 192, -7, 54, 46, -294, -266, 1428, -1386, -8, 76, 64, -480, 30, -832, 2560, -128, 3520, -12800, 10752, -9, 102, 86, -738, 78, -1260, 4356, -594, -558, 11484, -23166, 3564, -42900, 118404, -87516, -10, 132, 112, -1080, 100, -1840, 7040, 48, -1680, -800, 18240, -40320, -760, 8640
Offset: 1

Views

Author

Bradley Klee, Sep 18 2016

Keywords

Comments

Irregular triangle read by rows ( see examples ). The phase space trajectory of A276738 has one time dependent variable, the phase space angle "x" defined as Tan[x]=p/q. Then dx/dt = cos[x]^2* d/dt(p/q), which can be written as a function of Q=cos[x] by application of the classical equations of motion d/dt(p,q) = ( -d/dq H, d/dp H ), with H the anharmonic oscillator Hamiltonian. Substituting the result of A276738 and expanding in powers of b, we obtain dx/dt = -1 + sum b^n*T(n,m)*f(n,m); where the sum runs over n=1,2,3... and m = 1,2,3, ... A000041(n). The basis functions f(n,m) are the same as in A276738. Observe the limit where Q --> 0, dx/dt --> -1, the harmonic oscillator value. Similarly if v_i --> 0 then dx/dt --> -1.

Examples

			n/m  1    2     3     4     5     6      7
---------------------------------------------
1  | -3
2  | -4,  6
3  | -5,  22,  -30
4  | -6,  36,   16,  -168   192
5  | -7,  54,   46,  -294  -266   1428  -1386
---------------------------------------------
		

Crossrefs

Programs

  • Mathematica
    R[n_] := b Plus[1, Total[b^# R[#, q] & /@ Range[n]]]
    Vp[n_] := Total[2 v[# + 2] q^(# + 2) & /@ Range[n]]
    H[n_] := Expand[1/2*r^2 + Vp[n]]
    RRules[n_] :=  With[{H = Series[ReplaceAll[H[n], {q -> R[n] Q, r -> R[n]}], {b, 0, n + 2}]},  Function[{rules},
        Nest[Rule[#[[1]], ReplaceAll[#[[2]], rules]] & /@ # &, rules, n]][
       Flatten[R[#, q] -> Expand[-ReplaceAll[ Coefficient[H, b^(# + 2)], {R[#, q] -> 0}]] & /@ Range[n]]]]
    xDot[n_] := Expand[Normal@Series[ReplaceAll[ Q^2 D[D[q[t], t]/q[t], t], {D[q[t], t] -> R[n] P, q[t] -> R[n] Q, r -> R[n], D[q[t], {t, 2}]
    ->  ReplaceAll[D[-(q^2/2 + Vp[n]), q], q -> R[n] Q]} ], {b, 0, n}] /. RRules[n] /. {P^2 -> 1 - Q^2}]
    basis[n_] :=  Times[Times @@ (v /@ #), Q^Total[#],2] & /@ (IntegerPartitions[n] /. x_Integer :> x + 2)
    TriangleRow[n_, fun_] := Coefficient[fun, b^n #] & /@ basis[n]
    With[{xd = xDot[10]},TriangleRow[#, xd] /. v[_] -> 0 & /@ Range[10]]

A276815 Irregular triangle read by rows T(n,m), coefficients in power/Fourier series expansion of an arbitrary anharmonic oscillator's exact differential time dependence.

Original entry on oeis.org

3, 4, -24, 5, -70, 210, 6, -96, -48, 960, -1920, 7, -126, -126, 1386, 1386, -12012, 18018, 8, -160, -160, 1920, -80, 3840, -17920, 640, -26880, 143360, -172032, 9, -198, -198, 2574, -198, 5148, -25740, 2574, 2574, -77220, 218790, -25740, 437580, -1662804, 1662804, 10, -240, -240, 3360, -240, 6720, -35840, -120, 6720, 3360
Offset: 1

Views

Author

Bradley Klee, Sep 18 2016

Keywords

Comments

The phase space trajectory A276738 has phase space angular velocity A276814, which allows expansion of dt = dx /(dx/dt) = dx(-1 + sum b^n*T(n,m)*f(n,m)); where the sum runs over n = 1, 2, 3 ... and m = 1, 2, 3, ... A000041(n). The basis functions f(n,m) are the same as in A276738. To obtain period K, we integrate the function of Q=cos[x] over a range of [2*pi,0]. All odd powers of Q integrate to zero, so the period is an expansion in E=(1/2)*b^2 (Cf. A276816). This sequence transforms into A274076/A274078 by setting v_i=0 for odd i, v_i=(-1)^(i/2-1)/2/(i!) otherwise, and (1/2)*b^2 = 2*k. For more details read "Plane Pendulum and Beyond by Phase Space Geometry" (Klee, 2016).

Examples

			n/m  1    2     3     4      5      6      7
------------------------------------------------
1  | 3
2  | 4   -24
3  | 5   -70    210
4  | 6   -96   -48   960   -1920
5  | 7   -126  -126  1386   1386  -12012  18018
------------------------------------------------
		

Crossrefs

Programs

  • Mathematica
    R[n_] := b Plus[1, Total[b^# R[#, q] & /@ Range[n]]]
    Vp[n_] := Total[2 v[# + 2] q^(# + 2) & /@ Range[n]]
    H[n_] := Expand[1/2*r^2 + Vp[n]]
    RRules[n_] :=  With[{H = Series[ReplaceAll[H[n], {q -> R[n] Q, r -> R[n]}], {b, 0, n + 2}]},  Function[{rules},
        Nest[Rule[#[[1]], ReplaceAll[#[[2]], rules]] & /@ # &, rules, n]][
       Flatten[R[#, q] -> Expand[-ReplaceAll[ Coefficient[H, b^(# + 2)], {R[#, q] -> 0}]] & /@ Range[n]]]]
    xDot[n_] := Expand[Normal@Series[ReplaceAll[ Q^2 D[D[q[t], t]/q[t], t], {D[q[t], t] -> R[n] P, q[t] -> R[n] Q, r -> R[n], D[q[t], {t, 2}]
    ->  ReplaceAll[D[-(q^2/2 + Vp[n]), q], q -> R[n] Q]} ], {b, 0, n}] /. RRules[n] /. {P^2 -> 1 - Q^2}]
    dt[n_] := Expand[Normal@Series[1/xDot[n], {b, 0, n}]]
    basis[n_] :=  Times[Times @@ (v /@ #), Q^Total[#],2] & /@ (IntegerPartitions[n] /. x_Integer :> x + 2)
    TriangleRow[n_, fun_] := Coefficient[fun, b^n #] & /@ basis[n]
    With[{dt10 = dt[10]}, TriangleRow[#, dt10] /. v[_] -> 0 & /@ Range[10]]

A277233 Numerators of the partial sums of the squares of the expansion coefficients of 1/sqrt(1-x). Also the numerators of the Landau constants.

Original entry on oeis.org

1, 5, 89, 381, 25609, 106405, 1755841, 7207405, 1886504905, 7693763645, 125233642041, 508710104205, 33014475398641, 133748096600189, 2165115508033649, 8754452051708621, 9054883309760265929, 36559890613417481741, 590105629859261338481, 2379942639329101454549
Offset: 0

Views

Author

Wolfdieter Lang, Nov 12 2016

Keywords

Comments

This is the instance m=1/2 of the partial sums r(m,n) = Sum_{k=0..n} (risefac(m,k)/ k!)^2, where risefac(x,k) = Product_{j=0..k-1} (x+j), and risefac(x,0) = 1.
The limit n -> oo does not exist. It would be hypergeometric([1/2,1/2],[1],z -> 1), which diverges.
The partial sums of the cubes converge for |m| < 2/3. See Morley's series under A277232 (for m=1/2).
a(n)/A056982(n) are the Landau constants. These constants are defined as G(n) = Sum_{j=0..n} g(j)^2, where g(n) = (2*n)!/(2^n*n!)^2 = A001790(n)/A046161(n). - Peter Luschny, Sep 27 2019

Examples

			The rationals r(n) begin: 1, 5/4, 89/64, 381/256, 25609/16384, 106405/65536, 1755841/1048576, 7207405/4194304, 1886504905/1073741824, 7693763645/4294967296, ...
		

Crossrefs

Programs

  • Maple
    a := n -> numer(add(binomial(-1/2, j)^2, j=0..n));
    seq(a(n), n=0..19); # Peter Luschny, Sep 26 2019
    # Alternatively:
    G := proc(x) hypergeom([1/2,1/2], [1], x)/(1-x) end: ser := series(G(x), x, 20):
    [seq(coeff(ser,x,n), n=0..19)]: numer(%); # Peter Luschny, Sep 28 2019
  • Mathematica
    Accumulate[CoefficientList[Series[1/Sqrt[1-x],{x,0,20}],x]^2]//Numerator (* Harvey P. Dale, Feb 10 2019 *)
    G[x_] := (2 EllipticK[x])/(Pi (1 - x));
    CoefficientList[Series[G[x], {x, 0, 19}], x] // Numerator (* Peter Luschny, Sep 28 2019 *)
  • SageMath
    def A277233(n):
        return sum((A001790(k)*(2^(A005187(n) - A005187(k))))^2 for k in (0..n))
    print([A277233(n) for n in (0..19)]) # Peter Luschny, Sep 30 2019

Formula

a(n) = numerator(r(n)), with the fractional
r(n) = Sum_{k=0..n} (risefac(1/2,k)/k!)^2;
r(n) = Sum_{k=0..n} (binomial(-1/2,k))^2;
r(n) = Sum_{k=0..n} ((2*k-1)!!/(2*k)!!)^2.
The rising factorial has been defined in a comment above. The double factorials are given in A001147 and A000165 with (-1)!! := 1.
r(n) ~ (log(n+3/4) + EulerGamma + 4*log(2))/Pi. - Peter Luschny, Sep 27 2019
Rational generating function: (2*K(x))/(Pi*(1-x)) where K is the complete elliptic integral of the first kind. - Peter Luschny, Sep 28 2019
a(n) = Sum_{k=0..n}(A001790(k)*(2^(A005187(n) - A005187(k))))^2. - Peter Luschny, Sep 30 2019

A274653 Numerators of coefficients of z^n/n! for the expansion of Fricke's hypergeometric function F_1(1/2,1/2;z).

Original entry on oeis.org

0, 1, 21, 185, 18655, 307503, 12548151, 305496477, 138343008375, 4464248592375, 323592065474535, 13015087974100485, 2301190559547593805, 110887163426713235625, 11570760017278599886875, 649837647729572203369125, 1250848387902442801195686375, 80233244659365977333374518375
Offset: 0

Views

Author

Wolfdieter Lang, Jul 07 2016

Keywords

Comments

For the denominators see A274654.
The coefficients of z^n for the expansion of F_1(1/2,1/2;z) are A274655(n)/A274656(n).
Fricke's hypergeometric function F_1(a,b;z) = Sum_{n > = 0} f(a,b;n)*z^n/n!, satisfies the recurrence
f(a,b,n) = ((a+n-1)*(b+n-1)/n)*f(a,b;n-1) + c(a,b;n)*(1/(a+n-1) + 1/ (b+n-1) - 2/n), with c(a,b;n) = [z^n/n!]hypergeometric([a,b],[1],z) = risefac(a,n) * risefac(b,n)/n!, where risefac is the rising factorial (Pochhammer's symbol) and the input is f(a,b;0)= 0. See the Fricke I reference, p. 114.
The hypergeometric function F_1(1/2,1/2;z) appears in the formula for (2/Pi) K'(k) + (1/Pi)*log(k^2/16)*(2/Pi)*K(k) = F_1(1/2,1/2;k^2), where K and sqrt(-1)*K' are the real and imaginary quarter periods, and k is the modulus (k^2 is the parameter) of elliptic functions. See the Fricke I reference p. 465, eq. (11), and also Fricke III, p. 2, eq. (3).
(2/Pi)*K(k) = hypergeometric([1/2,1/2],[1],k^2). For the expansion coefficients see A038534/A056982 and also A274657/A123854.

Examples

			The sequence of rationals {r(n)} begins:
0, 1/2, 21/32, 185/128, 18655/4096, 307503/16384, 12548151/131072, 305496477/524288, 138343008375/33554432, 4464248592375/134217728, 323592065474535/1073741824, ....
The expansion of F_1(1/2,1/2;z) begins:
(1/2)*z + (21/32)*z^2/2! + (185/128)*z^3/3! + (18655/4096)*z^4/4! + (307503/16384)*z^5/5! + ..., or
(1/2)*z + (21/64)*z^2 + (185/768)*z^3 + (18655/98304)*z^4 + (102501/655360)*z^5 + ...
		

Crossrefs

Formula

a(n) = numerator(r(n)), with the rationals (in lowest terms) r(n) = [z^n/n!]F_1(1/2,1/2;z), with the hypergeometric function F_1 given by Fricke. The recurrence of the coefficients r(n) = f(1/2,1/2;n) is obtained from the general one given above.
r(n) = ((2*n-1)^2/(4*n))*r(n-1) + 2*c(n)/(n*(2*n-1)), n >= 1, r(0) = 0, with c(n) = c(1/2,1/2;n) = ((2*n)!)^2 / (n!^3*2^(4*n)) (see A274657/A123854).
E.g.f. for r(n) is Fricke's F_1(1/2,1/2;z).
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