cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Previous Showing 21-27 of 27 results.

A080677 a(n) = n + 1 - A004001(n).

Original entry on oeis.org

1, 2, 2, 3, 3, 3, 4, 5, 5, 5, 5, 6, 6, 7, 8, 9, 9, 9, 9, 9, 10, 10, 10, 11, 11, 12, 13, 13, 14, 15, 16, 17, 17, 17, 17, 17, 17, 18, 18, 18, 18, 19, 19, 19, 20, 20, 21, 22, 22, 22, 23, 23, 24, 25, 25, 26, 27, 28, 28, 29, 30, 31, 32, 33, 33, 33, 33, 33, 33, 33, 34, 34, 34, 34, 34, 35, 35, 35
Offset: 1

Views

Author

N. J. A. Sloane, Mar 03 2003

Keywords

Comments

From Antti Karttunen, Jan 10 2016: (Start)
This is the sequence b(n) mentioned on page 229 (page 5 of PDF) in Kubo & Vakil paper, but using starting offset 1 instead of 2.
The recursive sum formula for A004001, a(n) = a(a(n-1)) + a(n-a(n-1)) can be written also as a(n) = a(a(n-1)) + a(A080677(n-1)).
This is the least monotonic left inverse for sequence A087686. Proof: Taking the first differences of this sequence yields the characteristic function for the complement of A188163, because A188163 gives the positions where A004001 increases, and this sequence increases by one whenever A004001 does not increase (and vice versa). Sequence A188163 is also 1 followed by A088359 (see comment in former), whose complement A087686 is, thus A087686 is also the complement of A188163, apart from the initial one. Note also how A087686 is closed with respect to A004001 (see A266188).
(End)

References

  • J. Arkin, D. C. Arney, L. S. Dewald and W. E. Ebel, Jr., Families of recursive sequences, J. Rec. Math., 22 (No. 22, 1990), 85-94.

Crossrefs

Programs

Formula

a(n) = n + 1 - A004001(n).
Other identities. For all n >= 1:
a(A087686(n)) = n. [See comments.] - Antti Karttunen, Jan 10 2016

A093879 First differences of A004001.

Original entry on oeis.org

0, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1, 1, 1, 1, 0, 1, 1, 0, 1, 0, 0, 1, 0, 0, 0, 0, 1, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 1, 0, 0, 1, 1, 0, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 1, 0, 0, 1, 1, 1, 0, 1, 1, 0, 1, 0, 0, 1, 1, 0, 1, 0, 0, 1, 0, 0, 0
Offset: 1

Views

Author

N. J. A. Sloane, May 27 2004

Keywords

Comments

All the terms are 0 or 1: it is easy to show that if {b(n)} = A004001, b(n)>=b(n-1) and b(n)Benoit Cloitre, Jun 05 2004

Crossrefs

Programs

  • Magma
    h:=[n le 2 select 1 else Self(Self(n-1)) + Self(n-Self(n-1)): n in [1..160]];
    A093879:= func< n | h[n+1] - h[n] >;
    [A093879(n): n in [1..120]]; // G. C. Greubel, May 19 2024
    
  • Mathematica
    a[1] = a[2] = 1; a[n_] := a[n] = a[a[n - 1]] + a[n - a[n - 1]]; t = Table[a[n], {n, 110}]; Drop[t, 1] - Drop[t, -1] (* Robert G. Wilson v, May 28 2004 *)
  • PARI
    {m=106;v=vector(m,j,1);for(n=3,m,a=v[v[n-1]]+v[n-v[n-1]];v[n]=a);for(n=2,m,print1(v[n]-v[n-1],","))}
    
  • SageMath
    @CachedFunction
    def h(n): return 1 if (n<3) else h(h(n-1)) + h(n - h(n-1))
    def A093879(n): return h(n+1) - h(n)
    [A093879(n) for n in range(1,101)] # G. C. Greubel, May 19 2024
  • Scheme
    (define (A093879 n) (- (A004001 (+ 1 n)) (A004001 n))) ;; Code for A004001 given in that entry. - Antti Karttunen, Jan 18 2016
    

Formula

From Antti Karttunen, Jan 18 2016: (Start)
a(n) = A004001(n+1) - A004001(n).
Other identities. For all n >= 1:
a(A087686(n+1)-1) = 0.
a(A088359(n)-1) = 1.
a(n) = 1 if and only if A051135(n+1) = 1.
(End)

Extensions

More terms and PARI code from Klaus Brockhaus and Robert G. Wilson v, May 27 2004

A051135 a(n) = number of times n appears in the Hofstadter-Conway $10000 sequence A004001.

Original entry on oeis.org

2, 2, 1, 3, 1, 1, 2, 4, 1, 1, 1, 2, 1, 2, 3, 5, 1, 1, 1, 1, 2, 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 6, 1, 1, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 2, 1, 2, 3, 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 1, 2, 3, 4, 5, 7, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 2, 1, 2, 3, 1, 1, 1, 2, 1, 1, 2, 1, 2, 3, 1, 1, 2, 1, 2, 3, 1, 2, 3
Offset: 1

Views

Author

Robert Lozyniak (11(AT)onna.com)

Keywords

Comments

If the initial 2 is changed to a 1, the resulting sequence (A265332) has the property that if all 1's are deleted, the remaining terms are the sequence incremented. - Franklin T. Adams-Watters, Oct 05 2006
a(A088359(n)) = 1 and a(A087686(n)) > 1; first differences of A188163. - Reinhard Zumkeller, Jun 03 2011
From Robert G. Wilson v, Jun 07 2011: (Start)
a(k)=1 for k = 3, 5, 6, 9, 10, 11, 13, 17, 18, 19, 20, 22, 23, 25, 28, ..., ; (A088359)
a(k)=2 for k = 1, 2, 7, 12, 14, 21, 24, 26, 29, 38, 42, 45, 47, 51, 53, ..., ; (1 followed by A266109)
a(k)=3 for k = 4, 15, 27, 30, 48, 54, 57, 61, 86, 96, 102, 105, 112, ..., ; (A267103)
a(k)=4 for k = 8, 31, 58, 62, 106, 116, 120, 125, 192, 212, 222, 226, ..., ;
a(k)=5 for k = 16, 63, 121, 126, 227, 242, 247, 253, 419, 454, 469, ..., ;
a(k)=6 for k = 32, 127, 248, 254, 475, 496, 502, 509, 894, 950, 971, ..., ;
a(k)=7 for k = 64, 255, 503, 510, 978, 1006, 1013, 1021, 1872, 1956, ..., ;
a(k)=8 for k = 128, 511, 1014, 1022, 1992, 2028, 2036, 2045, 3864, ..., ;
a(k)=9 for k = 256, 1023, 2037, 2046, 4029, 4074, 4083, 4093, 7893, ..., ;
a(k)=10 for k = 512, 2047, 4084, 4094, 8113, 8168, 8178, 8189, ..., . (End)
Compare above to array A265903. - Antti Karttunen, Jan 18 2016

Crossrefs

Cf. A088359 (positions of ones).
Cf. A265332 (essentially the same sequence, but with a(1) = 1 instead of 2).

Programs

  • Haskell
    import Data.List (group)
    a051135 n = a051135_list !! (n-1)
    a051135_list = map length $ group a004001_list
    -- Reinhard Zumkeller, Jun 03 2011
    
  • Magma
    nmax:=200;
    h:=[n le 2 select 1 else Self(Self(n-1)) + Self(n - Self(n-1)): n in [1..5*nmax]]; // h = A004001
    A188163:= function(n)
       for j in [1..3*nmax+1] do
           if h[j] eq n then return j; end if;
       end for;
    end function;
    A051135:= func< n | A188163(n+1) - A188163(n) >;
    [A051135(n): n in [1..nmax]]; // G. C. Greubel, May 20 2024
    
  • Maple
    a[1]:=1: a[2]:=1: for n from 3 to 300 do a[n]:=a[a[n-1]]+a[n-a[n-1]] od: A:=[seq(a[n],n=1..300)]:for j from 1 to A[nops(A)-1] do c[j]:=0: for n from 1 to 300 do if A[n]=j then c[j]:=c[j]+1 else fi od: od: seq(c[j],j=1..A[nops(A)-1]); # Emeric Deutsch, Jun 06 2006
  • Mathematica
    a[1] = 1; a[2] = 1; a[n_] := a[n] = a[a[n - 1]] + a[n - a[n - 1]]; t = Array[a, 250]; Take[ Transpose[ Tally[t]][[2]], 105] (* Robert G. Wilson v, Jun 07 2011 *)
  • SageMath
    @CachedFunction
    def h(n): return 1 if (n<3) else h(h(n-1)) + h(n - h(n-1)) # h=A004001
    def A188163(n):
        for j in range(1,2*n+1):
            if h(j)==n: return j
    def A051135(n): return A188163(n+1) - A188163(n)
    [A051135(n) for n in range(1,201)] # G. C. Greubel, May 20 2024
  • Scheme
    (define (A051135 n) (- (A188163 (+ 1 n)) (A188163 n))) ;; Antti Karttunen, Jan 18 2016
    

Formula

From Antti Karttunen, Jan 18 2016: (Start)
a(n) = A188163(n+1) - A188163(n). [after Reinhard Zumkeller's Jun 03 2011 comment above]
Other identities:
a(n) = 1 if and only if A093879(n-1) = 1. [See A188163 for a reason.]
(End)

Extensions

More terms from Jud McCranie
Added links (in parentheses) to recently submitted related sequences - Antti Karttunen, Jan 18 2016

A188163 Smallest m such that A004001(m) = n.

Original entry on oeis.org

1, 3, 5, 6, 9, 10, 11, 13, 17, 18, 19, 20, 22, 23, 25, 28, 33, 34, 35, 36, 37, 39, 40, 41, 43, 44, 46, 49, 50, 52, 55, 59, 65, 66, 67, 68, 69, 70, 72, 73, 74, 75, 77, 78, 79, 81, 82, 84, 87, 88, 89, 91, 92, 94, 97, 98, 100, 103, 107, 108, 110, 113, 117, 122
Offset: 1

Views

Author

Reinhard Zumkeller, Jun 03 2011

Keywords

Comments

How is this related to A088359? - R. J. Mathar, Jan 09 2013
It is not hard to show that a(n) exists for all n, and in particular a(n) < 2^n. - Charles R Greathouse IV, Jan 13 2013
From Antti Karttunen, Jan 10 & 18 2016: (Start)
Positions of records in A004001. After 1 the positions where A004001 increases (by necessity by one).
An answer to the question of R. J. Mathar above: This sequence is equal to A088359 with prepended 1. This follows because at each of its unique values (terms of A088359), A004001 must grow, but it can grow nowhere else. See Kubo and Vakil paper and especially the illustrations of Q and R-trees on pages 229-230 (pages 5 & 6 in PDF) and also in sequence A265332.
Obviously A004001 can obtain unique values only at points which form a subset (A266399) of this sequence.
(End)

Crossrefs

Equal to A088359 with prepended 1.
Column 1 of A265901, Row 1 of A265903.
Cf. A051135 (first differences).
Cf. A087686 (complement, apart from the initial 1).
Cf. A004001 (also the least monotonic left inverse of this sequence).
Cf. A266399 (a subsequence).

Programs

  • Haskell
    import Data.List (elemIndex)
    import Data.Maybe (fromJust)
    a188163 n = succ $ fromJust $ elemIndex n a004001_list
    
  • Magma
    h:=[n le 2 select 1 else Self(Self(n-1)) + Self(n - Self(n-1)): n in [1..500]]; // h=A004001
    A188163:= function(n)
       for j in [1..2*n+1] do
           if h[j] eq n then return j; end if;
       end for;
    end function;
    [A188163(n): n in [1..100]]; // G. C. Greubel, May 20 2024
    
  • Maple
    A188163 := proc(n)
        for a from 1 do
            if A004001(a) = n then
                return a;
            end if;
        end do:
    end proc: # R. J. Mathar, May 15 2013
  • Mathematica
    h[1] = 1; h[2] = 1; h[n_] := h[n] = h[h[n-1]] + h[n - h[n-1]];
    a[n_] := For[m = 1, True, m++, If[h[m] == n, Return[m]]];
    Array[a, 64] (* Jean-François Alcover, Jan 27 2018 *)
  • SageMath
    @CachedFunction
    def h(n): return 1 if (n<3) else h(h(n-1)) + h(n - h(n-1)) # h=A004001
    def A188163(n):
        for j in range(1,2*n+2):
            if h(j)==n: return j
    [A188163(n) for n in range(1,101)] # G. C. Greubel, May 20 2024
  • Scheme
    (define A188163 (RECORD-POS 1 1 A004001))
    ;; Code for A004001 given in that entry. Uses also my IntSeq-library. - Antti Karttunen, Jan 18 2016
    

Formula

Other identities. For all n >= 1:
A004001(a(n)) = n and A004001(m) < n for m < a(n).
A051135(n) = a(n+1) - a(n).

A267110 If A051135(n) = 1, then a(n) = A004001(n) - 1, otherwise a(n) = n - A004001(n).

Original entry on oeis.org

0, 1, 1, 2, 2, 3, 3, 4, 4, 5, 6, 5, 7, 6, 7, 8, 8, 9, 10, 11, 9, 12, 13, 10, 14, 11, 12, 15, 13, 14, 15, 16, 16, 17, 18, 19, 20, 17, 21, 22, 23, 18, 24, 25, 19, 26, 20, 21, 27, 28, 22, 29, 23, 24, 30, 25, 26, 27, 31, 28, 29, 30, 31, 32, 32, 33, 34, 35, 36, 37, 33, 38, 39, 40, 41, 34, 42, 43, 44, 35, 45, 46, 36, 47
Offset: 1

Views

Author

Antti Karttunen, Jan 16 2016

Keywords

Comments

For n > 1, a(n) gives the contents of the parent of the node which contains n in A267112-tree.
Each n > 0 occurs exactly twice, in positions A088359(n) and A087686(n+1).
The sequence maps each n > 1 to a number which is one digit shorter in binary system (cf. "Other identities"). This follows because A004001 is monotonic and A004001(2^n) = 2^(n-1) (see properties (2) and (3) given on page 227 of Kubo & Vakil paper, or page 3 in PDF), and also how the frequency counts Q_n for A004001 are recursively constructed (see Kubo & Vakil paper, p. 229 or A265332 for the illustration).

Crossrefs

Programs

Formula

If A051135(n) = 1 [Equally: if A265332(n) = 1], then a(n) = A004001(n) - 1, otherwise a(n) = n - A004001(n).
Other identities. For all n >= 2:
A070939(a(n)) = A070939(n) - 1. [See Comments section.]

A162598 Ordinal transform of A265332.

Original entry on oeis.org

1, 1, 2, 1, 3, 4, 2, 1, 5, 6, 7, 3, 8, 4, 2, 1, 9, 10, 11, 12, 5, 13, 14, 6, 15, 7, 3, 16, 8, 4, 2, 1, 17, 18, 19, 20, 21, 9, 22, 23, 24, 10, 25, 26, 11, 27, 12, 5, 28, 29, 13, 30, 14, 6, 31, 15, 7, 3, 32, 16, 8, 4, 2, 1, 33, 34, 35, 36, 37, 38, 17, 39, 40, 41, 42, 18, 43, 44, 45, 19, 46, 47
Offset: 1

Views

Author

Keywords

Comments

This is a fractal sequence.
It appears that each group of 2^k terms starts with 1 and ends with the remaining powers of two from 2^k down to 2^1.
From Antti Karttunen, Jan 09-12 2016: (Start)
This is ordinal transform of A265332, which is modified A051135 (with a(1) = 1, instead of 2). - after Franklin T. Adams-Watters' original definition for this sequence.
A000079 (powers of 2) indeed gives the positions of ones in this sequence. This follows from the properties (3) and (4) of A004001 given on page 227 of Kubo & Vakil paper (page 3 of PDF), which together also imply the pattern observed above, more clearly represented as:
a(2) = 1.
a(3..4) = 2, 1.
a(6..8) = 4, 2, 1.
a(13..16) = 8, 4, 2, 1.
a(28..31) = 16, 8, 4, 2, 1.
etc.
(End)

Crossrefs

Row index of A265901, column index of A265903.
Cf. A265332 (corresponding other index).
Cf. A000079 (positions of ones).
Cf. A000225 (from the term 3 onward the positions of 2's).
Cf. A000325 (from its third term 5 onward the positions of 3's, which occur always as the last term before the next descending subsequence of powers of two).

Programs

  • Mathematica
    terms = 100;
    h[1] = 1; h[2] = 1;
    h[n_] := h[n] = h[h[n - 1]] + h[n - h[n - 1]];
    t = Array[h, 2*terms];
    A051135 = Take[Transpose[Tally[t]][[2]], terms];
    b[_] = 1;
    a[n_] := a[n] = With[{t = If[n == 1, 1, A051135[[n]]]}, b[t]++];
    Array[a, terms] (* Jean-François Alcover, Dec 19 2021, after Robert G. Wilson v in A051135 *)

Formula

Let b(1) = 1, b(n) = A051135(n) for n > 1. Then a(n) is the number of b(k) that equal b(n) for 1 <= k <= n: sum( 1, 1<=k<=n and a(k)=a(n) ).
If A265332(n) = 1, then a(n) = A004001(n), otherwise a(n) = a(A080677(n)-1) = a(n - A004001(n)). - Antti Karttunen, Jan 09 2016

Extensions

Name amended by Antti Karttunen, Jan 09 2016

A267103 Row 3 of A265903; numbers that occur exactly three times in A004001.

Original entry on oeis.org

4, 15, 27, 30, 48, 54, 57, 61, 86, 96, 102, 105, 112, 115, 119, 124, 157, 172, 182, 188, 191, 202, 208, 211, 218, 221, 225, 233, 236, 240, 245, 251, 293, 314, 329, 339, 345, 348, 364, 374, 380, 383, 394, 400, 403, 410, 413, 417, 429, 435, 438, 445, 448, 452, 460, 463, 467, 472, 481, 484, 488, 493, 499, 506, 558
Offset: 1

Views

Author

Antti Karttunen, Jan 18 2016

Keywords

Comments

Numbers n for which A051135(n) = 3.

Crossrefs

Column 3 of A265901, row 3 of A265903.

Formula

a(n) = A087686(1+A266109(n)) = A087686(1+A087686(1+A188163(n))).
Previous Showing 21-27 of 27 results.