cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-10 of 11 results. Next

A002966 Egyptian fractions: number of solutions of 1 = 1/x_1 + ... + 1/x_n where 0 < x_1 <= ... <= x_n.

Original entry on oeis.org

1, 1, 3, 14, 147, 3462, 294314, 159330691
Offset: 1

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Author

Keywords

Comments

All denominators in the expansion 1 = 1/x_1 + ... + 1/x_n are bounded by A000058(n-1), i.e., 0 < x_1 <= ... <= x_n < A000058(n-1). Furthermore, for a fixed n, x_i <= (n+1-i)*(A000058(i-1)-1). - Max Alekseyev, Oct 11 2012
From R. J. Mathar, May 06 2010: (Start)
This is the leading edge of the triangle A156869. This is also the row n=1 of an array T(n,m) which gives the number of ways to write 1/n as a sum over m (not necessarily distinct) unit fractions:
1, 1, 3, 14, 147, 3462, 294314, ...
1, 2, 10, 108, 2892, 270332, ...
1, 2, 21, 339, 17253, ...
1, 3, 28, 694, 51323, ...
...
T(.,2) = A018892. T(.,3) = A004194. T(.,4) = A020327, T(.,5) = A020328. T(2,6) is computed by D. S. McNeil, who conjectures that the 2nd row is A003167. (End)
If on the other hand, all x_k must be unique, see A006585. - Robert G. Wilson v, Jul 17 2013

Examples

			For n=3 the 3 solutions are {2,3,6}, {2,4,4}, {3,3,3}.
For n=4 the solutions are: {2,3,7,42}, {2,3,8,24}, {2,3,9,18}, {2,3,10,15}, {2,3,12,12}, {2,4,5,20}, {2,4,6,12}, {2,4,8,8}, {2,5,5,10}, {2,6,6,6}, {3,3,4,12}, {3,3,6,6}, {3,4,4,6}, {4,4,4,4}. [Neven Juric, May 14 2008]
		

References

  • R. K. Guy, Unsolved Problems in Number Theory, D11.
  • D. Singmaster, The number of representations of one as a sum of unit fractions, unpublished manuscript, 1972.
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Crossrefs

Programs

  • PARI
    a(n,rem=1,mn=1)=if(n==1,return(numerator(rem)==1)); sum(k=max(1\rem+1,mn), n\rem, a(n-1,rem-1/k,k)) \\ Charles R Greathouse IV, Jan 04 2015

Formula

a(n) <= binomial(A007018(n), n-1). - Charles R Greathouse IV, Jul 29 2024

Extensions

a(7) from Jud McCranie, Nov 15 1999. Confirmed by Marc Paulhus.
a(8) from John Dethridge (jcd(AT)ms.unimelb.edu.au) and Jacques Le Normand (jacqueslen(AT)sympatico.ca), Jan 06 2004

A006585 Egyptian fractions: number of solutions to 1 = 1/x_1 + ... + 1/x_n in positive integers x_1 < ... < x_n.

Original entry on oeis.org

1, 0, 1, 6, 72, 2320, 245765, 151182379
Offset: 1

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Author

Keywords

Comments

All denominators in the expansion 1 = 1/x_1 + ... + 1/x_n are bounded by A000058(n-1), i.e., 0 < x_1 < ... < x_n < A000058(n-1). Furthermore, for a fixed n, x_i <= (n+1-i)*(A000058(i-1)-1). - Max Alekseyev, Oct 11 2012
If on the other hand, x_k need not be unique, see A002966. - Robert G. Wilson v, Jul 17 2013

Examples

			The 6 solutions for n=4 are 2,3,7,42; 2,3,8,24; 2,3,9,18; 2,3,10,15; 2,4,5,20; 2,4,6,12.
		

References

  • Marc LeBrun, personal communication.
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Crossrefs

Formula

a(n) = A280520(n,1).

Extensions

a(1)-a(7) are confirmed by Jud McCranie, Dec 11 1999
a(8) from John Dethridge (jcd(AT)ms.unimelb.edu.au), Jan 08 2004

A038034 Number of compositions (ordered partitions) of 1 into {1/1, 1/2, 1/3, ..., 1/n}.

Original entry on oeis.org

1, 2, 3, 7, 8, 52, 53, 288, 1209, 5247, 5248, 71395, 71396, 375779, 6957533, 52310862, 52310863, 1152622553, 1152622554, 45575902465, 1296407854551, 1580527987951, 1580527987952, 73245316681199, 584407520822198, 639887219617512, 11355804443049274, 516959218512416104, 516959218512416105, 29213061562205847736, 29213061562205847737, 886912328033731357358, 31286298736622399674197, 31349361777225437765677
Offset: 1

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Author

Christian G. Bower, Jun 15 1998

Keywords

Comments

a(n) = number of Egyptian fractions 1 = 1/x_1 + ... + 1/x_k (for any k), with max{x_i}<=n.

Examples

			a(4) = 7 since there are seven compositions into parts {1/1, 1/2, 1/3, 1/4}:
1 = 1/1, 1 = 1/2 + 1/2, 1 = 1/3 + 1/3 + 1/3, 1 = 1/2 + 1/4 + 1/4, 1 = 1/4 + 1/2 + 1/4, 1 = 1/4 + 1/4 + 1/2, and 1 = 1/4 + 1/4 + 1/4 + 1/4.
		

Crossrefs

Formula

a(n) = Sum_{i=1..n} A092667(i).
a(p) = a(p-1) + 1 for p prime. - Chai Wah Wu, Dec 27 2024

Extensions

More terms from Max Alekseyev, Mar 02 2004

A092667 a(n) = number of Egyptian fractions 1 = 1/x_1 + ... + 1/x_k (for any k), with max{x_i}=n.

Original entry on oeis.org

1, 1, 1, 4, 1, 44, 1, 235, 921, 4038, 1, 66147, 1, 304383, 6581754, 45353329, 1, 1100311690, 1, 44423279911, 1250831952086, 284120133400, 1, 71664788693247, 511162204140999, 55479698795314, 10715917223431762, 505603414069366830, 1, 28696102343693431631, 1, 857699266471525509621, 30399386408588668316839, 63063040603038091480
Offset: 1

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Author

Max Alekseyev, Mar 02 2004

Keywords

Examples

			a(4) = 4 since there are four fractions 1=1/2+1/4+1/4, 1=1/4+1/2+1/4, 1=1/4+1/4+1/2 and 1=1/4+1/4+1/4+1/4.
		

Crossrefs

Formula

a(n) = A038034(n) - A038034(n-1).
a(n) = 1 if n is prime.

A280517 Number of sequences of n positive integers with reciprocals adding up to an integer.

Original entry on oeis.org

1, 2, 14, 263, 13462, 2104021, 1366427911, 6266456586228
Offset: 1

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Author

Max Alekseyev, Jan 04 2017

Keywords

Crossrefs

Row sums of A280519.
Cf. A002967 (adding up to 1), A156871 (nondecreasing sequences), A280518 (increasing sequences).

A280519 Triangle read by rows: T(n,k) = number of sequences of n positive integers with reciprocals adding up to k (k=1,2,...,n).

Original entry on oeis.org

1, 1, 1, 10, 3, 1, 215, 41, 6, 1, 12231, 1115, 105, 10, 1, 2025462, 74862, 3466, 215, 15, 1, 1351857641, 14294210, 267281, 8372, 385, 21, 1, 6255560531733, 10837663111, 57646358, 727049, 17318, 630, 28, 1
Offset: 1

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Author

Max Alekseyev, Jan 04 2017

Keywords

Examples

			Triangle starts with:
n=1: 1
n=2: 1, 1
n=3: 10, 3, 1
n=4: 215, 41, 6, 1
n=5: 12231, 1115, 105, 10, 1
n=6: 2025462, 74862, 3466, 215, 15, 1
...
		

Crossrefs

Cf. A280517 (row sums), A002967 (column k=1), A156869 (nondecreasing sequences), A280520 (increasing sequences).

A144063 Egyptian fractions: number of solutions of 1 = 1/x_1 + ... + 1/x_n in positive integers x_1 < ... < x_n <= 256.

Original entry on oeis.org

1, 0, 1, 6, 62, 642, 5623, 47126, 368680, 2715613, 18876751, 124137535, 774232619, 4595291801, 26030660449, 141031079451, 731862267491, 3641135367129, 17379359388167, 79633646141291, 350541406992141, 1483638948734104, 6043258919626951, 23713645892145709
Offset: 1

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Author

Zhao Hui Du, Sep 09 2008

Keywords

Comments

Egyptian fraction for a rational number is to represent the number in sum of some distinct unit fraction, such as 1 = 1/2 + 1/3 + 1/6, here we represent 1 by a three terms Egyptian fraction and the largest denominator is 6. And the representation is non-unique.
There are a total of 3007198863516917545589795267613 Egyptian fractions for 1 whose largest denominator is no more than 256.

Examples

			a(1)=1 since 1 = 1/1.
a(2)=0 since the sum of any two distinct unit fractions are not 1.
a(3)=1 since the only three terms Egyptian fraction for 1 is 1/2 + 1/3 + 1/6.
		

Crossrefs

Formula

a(n) = 0 for n > 114.

A343214 Number of compositions (ordered partitions) of 1/n into n reciprocals of positive integers.

Original entry on oeis.org

1, 3, 106, 15259, 13879541, 95073863568
Offset: 1

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Author

Ilya Gutkovskiy, Apr 08 2021

Keywords

Examples

			a(2) = 3 because we have 1/2 = 1/4 + 1/4 = 1/3 + 1/6 = 1/6 + 1/3.
		

Crossrefs

Extensions

a(5)-a(6) from Max Alekseyev, Jan 24 2024

A374583 a(n) = number of Egyptian fractions 1 = 1/x_1 + ... + 1/x_n such that 0 < x_1 < ... < x_n and x_k | x_n for all k = 1..n.

Original entry on oeis.org

1, 0, 1, 5, 44, 975, 59234, 15474226
Offset: 1

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Author

Max Alekseyev, Jul 12 2024

Keywords

Comments

Also, number of integers m such that m is the sum of n distinct divisors of m including 1.
x_n <= A000058(n-1)-1.

Crossrefs

A379452 Number of compositions (ordered partitions) of 1 into n distinct reciprocals of positive integers.

Original entry on oeis.org

1, 0, 6, 144, 8640, 1670400, 1238655600, 6095673521280
Offset: 1

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Author

Ilya Gutkovskiy, Dec 23 2024

Keywords

Examples

			a(3) = 6 because we have 1 = 1/2 + 1/3 + 1/6
                           = 1/2 + 1/6 + 1/3
                           = 1/3 + 1/2 + 1/6
                           = 1/3 + 1/6 + 1/2
                           = 1/6 + 1/2 + 1/3
                           = 1/6 + 1/3 + 1/2.
		

Crossrefs

Formula

a(n) = n! * A006585(n).
Showing 1-10 of 11 results. Next