cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-10 of 18 results. Next

A049541 Decimal expansion of 1/Pi.

Original entry on oeis.org

3, 1, 8, 3, 0, 9, 8, 8, 6, 1, 8, 3, 7, 9, 0, 6, 7, 1, 5, 3, 7, 7, 6, 7, 5, 2, 6, 7, 4, 5, 0, 2, 8, 7, 2, 4, 0, 6, 8, 9, 1, 9, 2, 9, 1, 4, 8, 0, 9, 1, 2, 8, 9, 7, 4, 9, 5, 3, 3, 4, 6, 8, 8, 1, 1, 7, 7, 9, 3, 5, 9, 5, 2, 6, 8, 4, 5, 3, 0, 7, 0, 1, 8, 0, 2, 2, 7, 6, 0, 5, 5, 3, 2, 5, 0, 6, 1, 7, 1
Offset: 0

Views

Author

N. J. A. Sloane, Dec 11 1999

Keywords

Comments

The ratio of the volume of a regular octahedron to the volume of the circumscribed sphere (which has circumradius a*sqrt(2)/2 = a*A010503, where a is the octahedron's edge length; see MathWorld link). For similar ratios for other Platonic solids, see A165922, A165952, A165953 and A165954. - Rick L. Shepherd, Oct 01 2009
Corresponds to a gauge point marked "M" on slide rule calculating devices in the 20th century. The Pickworth reference notes its use in calculating the area of the curved surface of a cylinder. - Peter Munn, Aug 14 2020

Examples

			0.3183098861837906715377675267450287240689192914809128974953...
		

References

  • J.-P. Delahaye, Pi - die Story (German translation), Birkhäuser, 1999 Baasel, p. 245. French original: Le fascinant nombre Pi, Pour la Science, Paris, 1997.
  • C. N. Pickworth, The Slide Rule, 24th Ed., Pitman, London, 1945, p. 53, Gauge Points.
  • David Wells, The Penguin Dictionary of Curious and Interesting Numbers. Penguin Books, NY, 1986, Revised edition 1987, p. 27.

Crossrefs

Programs

Formula

Equals (1/(12-16*A002162))*Sum_{n>=0} A002894(n)*H(n)/(A001025(n) * A016754(n-1)), where H(n) denotes the n-th harmonic number. - John M. Campbell, Aug 28 2016
1/Pi = Sum_{m>=0} binomial(2*m, m)^3 * (42*m+5)/(2^(12*m+4)), Ramanujan, from the J.-P. Delahaye reference. - Wolfdieter Lang, Sep 18 2018; corrected by Bernard Schott, Mar 26 2020
1/Pi = 12*Sum_{n >= 0} (-1)^n*((6*n)!/(n!^3*(3*n)!))*(13591409 + 545140134*n)/640320^(3*n + 3/2) [Chudnovsky]. - Sanjar Abrarov, Mar 31 2020
1/Pi = (sqrt(8)/9801) * Sum_{n >= 0} ((4*n)!/((n!)^4)) * (26390*n + 1103)/(396^(4*n)) [Ramanujan, 1914]. - Bernard Schott, Mar 26 2020
Equal Sum_{k>=2} tan(Pi/2^k)/2^k. - Amiram Eldar, Aug 05 2020
Floor((3/8)*Sum_{n>=1} sigma[3](n)*n/exp(Pi*n/(10^((1/5)*k+(1/5))))) mod 10, will give the k-th digit of 1/Pi. - Simon Plouffe, Dec 19 2023

A053016 Numbers of vertices of Platonic solids in the order tetrahedron, octahedron, cube, icosahedron, dodecahedron. Equally, numbers of faces of Platonic solids in the order tetrahedron, cube, octahedron, dodecahedron, icosahedron.

Original entry on oeis.org

4, 6, 8, 12, 20
Offset: 1

Views

Author

Jeffrey Keller (jeff(AT)auctionflow.com), Feb 24 2000

Keywords

Comments

It appears that the stereographic projection of the Platonic solids requires respectively 4, 6, 8, 6, 10, different colors to represent them. - Eric Desbiaux, Feb 15 2009

References

  • H. S. M. Coxeter, Regular Polytopes, 3rd. ed., Dover, NY, 1973.

Crossrefs

Extensions

Definition expanded by N. J. A. Sloane, Nov 06 2020

A338622 Irregular table read by rows: The number of k-faced polyhedra, where k>=4, formed when the five Platonic solids, in the order tetrahedron, octahedron, cube, icosahedron, dodecahedron, are internally cut by all the planes defined by any three of their vertices.

Original entry on oeis.org

1, 8, 72, 24, 2160, 360, 205320, 208680, 94800, 34200, 7920, 1560, 120
Offset: 1

Views

Author

Scott R. Shannon, Nov 04 2020

Keywords

Comments

See A338571 for further details and images of this sequence.
The author thanks Zach J. Shannon for producing the images for this sequence.

Examples

			The cube is cut with 14 internal planes defined by all 3-vertex combinations of its 8 vertices. This leads to the creation of 72 4-faced polyhedra and 24 5-faced polyhedra, 96 pieces in all. See A338571 and A333539.
The table is:
1;
8;
72, 24;
2160, 360;
205320, 208680, 94800, 34200, 7920, 1560, 120;
		

Crossrefs

Cf. A338571 (total number of polyhedra), A333539 (n-dimensional cube), A053016, A063722, A063723, A098427, A333543.

Formula

Sum of row n = A338571(n).

A063722 Number of edges in the Platonic solids (in the order tetrahedron, cube, octahedron, dodecahedron, icosahedron).

Original entry on oeis.org

6, 12, 12, 30, 30
Offset: 1

Views

Author

Henry Bottomley, Aug 14 2001

Keywords

Examples

			a(2) = 12 since a cube has twelve edges.
		

Crossrefs

Formula

a(n) = A053016(n)+A063723(n)-2.

A063924 Number of 3-dimensional cells in the regular 4-dimensional polytopes.

Original entry on oeis.org

5, 8, 16, 24, 120, 600
Offset: 1

Views

Author

Henry Bottomley, Aug 15 2001

Keywords

Comments

Sorted by number of 3-dimensional cells.
Also, number of vertices of the regular 4-dimensional polyhedra. - Douglas Boffey, Aug 12 2012

Examples

			a(2) = 8 since a 4D hypercube contains eight cubes.
		

References

  • H. S. M. Coxeter, Regular Polytopes, 3rd ed., Dover, NY, 1973.

Crossrefs

Formula

a(n) = A063925(n) - A063926(n) + A063927(n).

Extensions

Corrected faces to cells by Douglas Boffey, Aug 12 2012

A063927 Number of vertices in the regular 4-dimensional polytopes.

Original entry on oeis.org

5, 16, 8, 24, 600, 120
Offset: 1

Views

Author

Henry Bottomley, Aug 15 2001

Keywords

Comments

Sorted by number of 3-dimensional faces.

Examples

			a(2) = 16 since a 4D hypercube contains sixteen vertices.
		

References

  • H. S. M. Coxeter, Regular Polytopes, 3rd ed., Dover, NY, 1973.

Crossrefs

Formula

a(n) = A063926(n) - A063925(n) + A063924(n).

A165952 Decimal expansion of 2*sqrt(3)/(3*Pi).

Original entry on oeis.org

3, 6, 7, 5, 5, 2, 5, 9, 6, 9, 4, 7, 8, 6, 1, 3, 6, 6, 3, 4, 0, 8, 8, 4, 3, 3, 2, 2, 0, 8, 6, 4, 6, 2, 9, 4, 2, 6, 4, 9, 2, 4, 3, 2, 0, 2, 4, 4, 4, 2, 7, 1, 0, 1, 8, 6, 6, 2, 4, 4, 0, 1, 3, 5, 2, 7, 3, 5, 3, 5, 3, 5, 6, 4, 6, 1, 7, 9, 8, 6, 3, 2, 2, 6, 9, 2, 0, 0, 1, 9, 2, 1, 5, 4, 4, 7, 2, 5, 9, 4, 7, 1, 7, 9, 8
Offset: 0

Views

Author

Rick L. Shepherd, Oct 02 2009

Keywords

Comments

The ratio of the volume of a cube to the volume of the circumscribed sphere (which has circumradius a*sqrt(3)/2 = a*A010527, where a is the cube's edge length; see MathWorld link). For similar ratios for other Platonic solids, see A165922, A049541, A165953, and A165954. A063723 shows the order of these by size.

Examples

			0.3675525969478613663408843322086462942649243202444271018662440135273535356...
		

Crossrefs

Programs

  • Mathematica
    RealDigits[(2*Sqrt[3])/(3Pi),10,120][[1]] (* Harvey P. Dale, Oct 08 2012 *)
  • PARI
    2*sqrt(3)/(3*Pi)

Formula

2*sqrt(3)/(3*Pi) = 2*A002194/(3*A000796) = 3*A165922 = (2*sqrt(3)/3)*A049541 = 10*A020832*A049541 = 2*A020760*A049541.

A338571 Number of polyhedra formed when the five Platonic solids, in the order tetrahedron, octahedron, cube, icosahedron, dodecahedron, are internally cut by all the planes defined by any three of their vertices.

Original entry on oeis.org

1, 8, 96, 2520, 552600
Offset: 1

Views

Author

Scott R. Shannon, Nov 03 2020

Keywords

Comments

For a Platonic solid create all possible planes defined by connecting any three of its vertices. For example, in the case of a cube this results in fourteen planes; six planes between the pairs of parallel edges connected to each end of the face diagonals, and eight planes from connecting the three vertices adjacent to each corner vertex. Use all the resulting planes to cut the solid into individual smaller polyhedra. The sequence lists the numbers of resulting polyhedra for the Platonic solids, ordered by number of vertices: tetrahedron, octahedron, cube, icosahedron, dodecahedron.
See A338622 for the number and images of the k-faced polyhedra in each dissection for each of the five solids.
The author thanks Zach J. Shannon for producing the images for this sequence.

Examples

			a(1) = 1. The tetrahedron has no internal cutting planes so the single polyhedron after cutting is the tetrahedron itself.
a(2) = 8. The octahedron has 3 internal cutting planes resulting in 8 polyhedra.
a(3) = 96. The cube has 14 internal cutting planes resulting in 96 polyhedra. See also A333539.
a(4) = 2520. The icosahedron has 47 cutting planes resulting in 2520 polyhedra.
See A338622 for a breakdown of the above totals into the corresponding number of k-faced polyhedra.
a(5) = 552600. The dodecahedron has 307 internal cutting planes resulting in 552600 polyhedra. It is the only Platonic solid which produces polyhedra with 6 or more faces.
		

Crossrefs

Cf. A338622 (number of k-faced polyhedra in each dissection), A333539 (n-dimensional cube), A053016, A063722, A063723, A098427.

A063925 Number of 2-dimensional faces in the regular 4-dimensional polytopes.

Original entry on oeis.org

10, 24, 32, 96, 720, 1200
Offset: 1

Views

Author

Henry Bottomley, Aug 15 2001

Keywords

Comments

Sorted by number of 2-dimensional faces.
Also the number of edges in the regular 4-dimensional polytopes [Douglas Boffey, Aug 12 2012]

Examples

			a(2) = 24 since a 4D hypercube contains twenty-four faces.
		

References

  • H. S. M. Coxeter, Regular Polytopes, 3rd ed., Dover, NY, 1973.

Crossrefs

Formula

a(n) = A063924(n)+A063926(n)-A063927(n).

A063926 Number of edges in the six regular 4-dimensional polytopes.

Original entry on oeis.org

10, 32, 24, 96, 1200, 720
Offset: 1

Views

Author

Henry Bottomley, Aug 15 2001

Keywords

Comments

Sorted by number of 3-dimensional faces.

Examples

			a(2) = 32 since a 4D hypercube contains thirty-two edges.
		

References

  • H. S. M. Coxeter, Regular Polytopes, 3rd ed., Dover, NY, 1973.

Crossrefs

Formula

a(n) = A063927(n) + A063925(n) - A063924(n).
Showing 1-10 of 18 results. Next