cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-7 of 7 results.

A047053 a(n) = 4^n * n!.

Original entry on oeis.org

1, 4, 32, 384, 6144, 122880, 2949120, 82575360, 2642411520, 95126814720, 3805072588800, 167423193907200, 8036313307545600, 417888291992371200, 23401744351572787200, 1404104661094367232000, 89862698310039502848000
Offset: 0

Views

Author

Joe Keane (jgk(AT)jgk.org)

Keywords

Comments

Original name was "Quadruple factorial numbers".
For n >= 1, a(n) is the order of the wreath product of the cyclic group C_4 and the symmetric group S_n. - Ahmed Fares (ahmedfares(AT)my-deja.com), May 07 2001
Number of n X n monomial matrices with entries 0, +/-1, +/-i.
a(n) is the product of the positive integers <= 4*n that are multiples of 4. - Peter Luschny, Jun 23 2011
Also, a(n) is the number of signed permutations of length 2*n that are equal to their reverse-complements. (See the Hardt and Troyka reference.) - Justin M. Troyka, Aug 13 2011.
Pi^n/a(n) is the volume of a 2*n-dimensional ball with radius 1/2. - Peter Luschny, Jul 24 2012
Equals the first right hand column of A167557, and also equals the first right hand column of A167569. - Johannes W. Meijer, Nov 12 2009
a(n) is the order of the group U_n(Z[i]) = {A in M_n(Z[i]): A*A^H = I_n}, the group of n X n unitary matrices over the Gaussian integers. Here A^H is the conjugate transpose of A. - Jianing Song, Mar 29 2021

Examples

			G.f. = 1 + 4*x + 32*x^2 + 384*x^3 + 6144*x^4 + 122880*x^5 + 2949120*x^6 + ...
		

Crossrefs

a(n)= A051142(n+1, 0) (first column of triangle).

Programs

  • Magma
    [4^n*Factorial(n): n in [0..20]]; // Vincenzo Librandi, Jul 20 2011
  • Maple
    A047053:= n -> mul(k, k = select(k-> k mod 4 = 0, [$1..4*n])): seq(A047053(n), n = 0.. 16); # Peter Luschny, Jun 23 2011
  • Mathematica
    a[n_]:= With[{m=2n}, If[ m<0, 0, m!*SeriesCoefficient[1 +Sqrt[Pi]*x*Exp[x^2]*Erf[x], {x, 0, m}]]]; (* Michael Somos, Jan 03 2015 *)
    Table[4^n n!,{n,0,20}] (* Harvey P. Dale, Sep 19 2021 *)
  • PARI
    a(n)=4^n*n!;
    

Formula

a(n) = 4^n * n!.
E.g.f.: 1/(1 - 4*x).
Integral representation as the n-th moment of a positive function on a positive half-axis: a(n) = Integral_{x=0..oo} x^n*exp(-x/4)/4, n >= 0. This representation is unique. - Karol A. Penson, Jan 28 2002 [corrected by Jason Yuen, May 04 2025]
Sum_{k>=0} (-1)^k/(2*k + 1)^n = (-1)^n * n * (PolyGamma[n-1, 1/4] - PolyGamma[n-1, 3/4]) / a(n) for n > 0. - Joseph Biberstine (jrbibers(AT)indiana.edu), Jul 27 2006
a(n) = Sum_{k=0..n} C(n,k)*(2k)!*(2(n-k))!/(k!(n-k)!) = Sum_{k=0..n} C(n,k)*A001813(k)*A001813(n-k). - Paul Barry, May 04 2007
E.g.f.: With interpolated zeros, 1 + sqrt(Pi)*x*exp(x^2)*erf(x). - Paul Barry, Apr 10 2010
From Gary W. Adamson, Jul 19 2011: (Start)
a(n) = sum of top row terms of M^n, M = an infinite square production matrix as follows:
2, 2, 0, 0, 0, 0, ...
4, 4, 4, 0, 0, 0, ...
6, 6, 6, 6, 0, 0, ...
8, 8, 8, 8, 8, 0, ...
... (End)
G.f.: 1/(1 - 4*x/(1 - 4*x/(1 - 8*x/(1 - 8*x/(1 - 12*x/(1 - 12*x/(1 - 16*x/(1 - ... (continued fraction). - Philippe Deléham, Jan 08 2012
G.f.: 2/G(0), where G(k) = 1 + 1/(1 - 8*x*(k + 1)/(8*x*(k + 1) - 1 + 8*x*(k + 1)/G(k+1))); (continued fraction). - Sergei N. Gladkovskii, May 30 2013
G.f.: 1/Q(0), where Q(k) = 1 - 4*x*(2*k + 1) - 16*x^2*(k + 1)^2/Q(k+1); (continued fraction). - Sergei N. Gladkovskii, Sep 28 2013
a(n) = A000142(n) * A000302(n). - Michel Marcus, Nov 28 2013
a(n) = A087299(2*n). - Michael Somos, Jan 03 2015
D-finite with recurrence: a(n) - 4*n*a(n-1) = 0. - R. J. Mathar, Jan 27 2020
From Amiram Eldar, Jun 25 2020: (Start)
Sum_{n>=0} 1/a(n) = e^(1/4) (A092042).
Sum_{n>=0} (-1)^n/a(n) = e^(-1/4) (A092616). (End)

Extensions

Edited by Karol A. Penson, Jan 22 2002

A331501 Decimal expansion of exp(3/4).

Original entry on oeis.org

2, 1, 1, 7, 0, 0, 0, 0, 1, 6, 6, 1, 2, 6, 7, 4, 6, 6, 8, 5, 4, 5, 3, 6, 9, 8, 1, 9, 8, 3, 7, 0, 9, 5, 6, 1, 0, 1, 3, 4, 4, 9, 1, 5, 8, 4, 7, 0, 2, 4, 0, 3, 4, 2, 1, 7, 7, 9, 1, 3, 3, 0, 3, 0, 8, 1, 0, 9, 8, 4, 5, 3, 3, 3, 6, 4, 0, 1, 2, 8, 2, 0, 0, 0, 2, 7, 9, 1, 5, 6, 0, 2, 6, 6, 6, 1, 5, 7, 9, 8, 2, 1, 8, 8, 8
Offset: 1

Views

Author

Washington Bomfim, Feb 27 2020

Keywords

Comments

Considering graph evolutions (see the Flajolet link) with 2n vertices initially isolated, the probability of the occurrence of an acyclic graph at the critical point n in the uniform model, will be denoted by P(n). In the case of the permutation model, the respective probability will be denoted by Pp(n).
Pp(n) / P(n) ~ exp(3/4) since Pp(n) = A302112(n) / A331505(2n) = A302112(n) / C(C(2n,2), n), and P(n) = A302112(n) * n! * 2^n / (2n)^(2n), Pp(n) / P(n) = (2n)^(2n) / (C(C(2n,2), n) * n! * 2^n), and lim_{n->oo} Pp(n) / P(n) = exp(3/4).

Examples

			2.1170000166126746685453698198370956101344915847024...
		

Crossrefs

Programs

Formula

Equals lim_{n->oo} Pp(n) / P(n) = lim_{n->oo} (2*n)^(2*n) / (binomial(binomial(2n,2), n) * n! * 2^n).
Equals lim_{n->oo} sqrt(n)/A000178(n)^(1/(n*(n+1))) (Giugiuc and Marinescu, 2017). - Amiram Eldar, Apr 12 2022

A379411 a(n) = n + floor(n*s/r) + floor(n*t/r), where r = e^(1/4), s = e^(1/2), t = e^(3/4).

Original entry on oeis.org

3, 7, 10, 15, 19, 22, 26, 31, 34, 38, 43, 46, 50, 54, 58, 62, 66, 70, 74, 77, 81, 86, 89, 93, 98, 101, 105, 109, 113, 117, 121, 125, 129, 133, 136, 141, 145, 148, 153, 156, 160, 164, 168, 172, 176, 180, 184, 188, 191, 196, 200, 203, 208, 212, 215, 219, 223
Offset: 1

Views

Author

Clark Kimberling, Jan 18 2025

Keywords

Comments

This sequence and A379412 and A379413 partition the positive integers; see A184812 for a proof. For each k in A000027, write "a" if k=A379411(n) for some n, "b" if k=A379412(n) for some n, and "c" if k=A379413(n) for some n. Concatenating these letters for k = 1,2,3,... spells the following infinite word:
cbacbcabcacbcbacbcabcacbcabcbcacbacbcabcbcacbacbcabccabcbacbcabccabcbacbcacbacbcabcbcacbacbcabccbacbacbcabccabcbacbcacbcabcbacbcacbcabcabccbacb...

Crossrefs

Programs

  • Mathematica
    r = E^(1/4); s = E^(1/2); t = E^(3/4);
    Table[n + Floor[n*s/r] + Floor[n*t/r], {n, 1, 120}]  (* A379411 *)
    Table[n + Floor[n*r/s] + Floor[n*t/s], {n, 1, 120}]  (* A379412 *)
    Table[n + Floor[n*r/t] + Floor[n*s/t], {n, 1, 120}]  (* A379413 *)

Formula

a(n) = n + floor(n*r) + floor(n*r^2), where r = e^(1/4).

A379413 a(n) = n + floor(n*r/t) + floor(n*s/t), where r = e^(1/4), s = e^(1/2), t = e^(3/4).

Original entry on oeis.org

1, 4, 6, 9, 11, 13, 16, 18, 21, 23, 25, 28, 30, 32, 35, 37, 40, 42, 44, 47, 49, 52, 53, 56, 59, 61, 64, 65, 68, 71, 73, 75, 78, 80, 83, 85, 87, 90, 92, 95, 96, 99, 102, 104, 107, 108, 111, 114, 116, 118, 120, 123, 126, 128, 130, 132, 135, 138, 139, 142, 144
Offset: 1

Views

Author

Clark Kimberling, Jan 18 2025

Keywords

Comments

This sequence and A379411 and A379412 partition the positive integers; see A378142 for a proof.

Crossrefs

Programs

  • Mathematica
    r = E^(1/4); s = E^(1/2); t = E^(3/4);
    Table[n + Floor[n*s/r] + Floor[n*t/r], {n, 1, 120}]  (* A379411 *)
    Table[n + Floor[n*r/s] + Floor[n*t/s], {n, 1, 120}]  (* A379412 *)
    Table[n + Floor[n*r/t] + Floor[n*s/t], {n, 1, 120}]  (* A379413 *)

Formula

a(n) = n + floor(n/r) + floor(n*r^2), where r = e^(1/4).

A113550 a(n) = product of n successive numbers up to n, if n is odd a(n) = n*(n-1)*.. = n!, if n is even a(n) = n(n+1)(n+2)... 'n' terms.

Original entry on oeis.org

1, 6, 6, 840, 120, 332640, 5040, 259459200, 362880, 335221286400, 39916800, 647647525324800, 6227020800, 1748648318376960000, 1307674368000, 6288139352883548160000, 355687428096000, 29051203810321992499200000, 121645100408832000, 167683548393178540705382400000
Offset: 1

Views

Author

Amarnath Murthy, Nov 03 2005

Keywords

Examples

			a(3) = 3*2*1 = 6.
a(4) = 4*5*6*7 = 840.
		

Crossrefs

Programs

  • Mathematica
    n = 1; anfunc[n_] := (If [EvenQ[n], {an = n, Do[an = an*(n + i), {i, n - 1}]}, an = n! ]; an); Table[anfunc[n], {n, 1, 20}] (* Elizabeth A. Blickley (Elizabeth.Blickley(AT)gmail.com), Mar 10 2006 *)

Formula

a(2n-1) = (2n-1)!, a(2n) = (4n-1)!/(2n-1)!.
a(2n-1)*a(2n) = (4n-1)!.
Sum_{n>=1} 1/a(n) = sinh(1) + (sqrt(Pi)/2) * (exp(1/4) * erf(1/2) - exp(-1/4) * erfi(1/2)). - Amiram Eldar, Aug 15 2025

Extensions

More terms from Elizabeth A. Blickley (Elizabeth.Blickley(AT)gmail.com), Mar 10 2006

A331502 Decimal expansion of exp(4/9).

Original entry on oeis.org

1, 5, 5, 9, 6, 2, 3, 4, 9, 7, 6, 0, 6, 7, 8, 0, 7, 1, 5, 5, 3, 3, 7, 0, 9, 2, 8, 6, 9, 7, 9, 4, 7, 1, 1, 8, 6, 3, 9, 4, 8, 2, 4, 0, 1, 1, 4, 2, 2, 1, 4, 2, 3, 5, 4, 3, 9, 0, 2, 7, 8, 4, 3, 1, 5, 4, 3, 5, 6, 3, 8, 5, 0, 1, 3, 3, 1, 0, 6, 3, 2, 6, 4, 2, 7, 5, 8, 1, 6, 1, 2, 4, 9, 2, 9, 9, 4, 0, 1, 5, 4, 2, 9, 1, 6, 9
Offset: 1

Views

Author

Washington Bomfim, Mar 04 2020

Keywords

Comments

Considering graph evolutions (see the Flajolet link) with 3n vertices initially isolated, the probability of the occurrence of an acyclic graph at the point n, (n = 1/3 * 3n), in the uniform model, will be denoted by P13(n). In the case of the permutation model, the respective probability will be denoted by Pp13(n).
Pp13(n) / P13(n) ~ exp(4/9) since Pp13(n) = f(n) / C(N,n), where f(n) is the number of labeled forests with 3n nodes and n edges, and C(N,n), N = 3n *(3n-1)/2 (see the Lucatero link) is the number of labeled graphs with 3n nodes and n edges.
Because P13(n) = f(n)* n!* 2^n / (3n)^(2n), Pp13(n) / P13(n) = (3n)^(2n) / (C(N,n)* n! *2^n), and Lim_{n->oo} Pp13(n) / P13(n) = exp(4/9).

Examples

			1.55962349760678071553370928697947118639482401142214...
		

Crossrefs

Programs

  • Maple
    evalf(exp(4/9), 134);
  • Mathematica
    RealDigits[Exp[4/9],10,120][[1]] (* Harvey P. Dale, Jun 05 2023 *)
  • PARI
    exp(4/9)

Formula

Equals Lim_{n->oo} Pp13(n) / P13(n) = Lim_{n->oo} (3*n)^(2*n) / (binomial((3*n *(3*n-1)/2), n) * n! * 2^n).

A367549 Decimal expansion of 1 - DawsonF(1/2).

Original entry on oeis.org

5, 7, 5, 5, 6, 3, 6, 1, 6, 4, 9, 7, 9, 7, 7, 7, 0, 4, 0, 6, 5, 9, 5, 7, 6, 4, 7, 5, 1, 0, 3, 3, 0, 4, 2, 8, 9, 0, 3, 5, 7, 0, 5, 2, 2, 6, 4, 0, 3, 0, 7, 9, 6, 1, 8, 4, 8, 6, 6, 0, 3, 0, 3, 3, 6, 6, 7, 5, 4, 8, 4, 5, 2, 4, 0, 4, 0, 8, 0, 5, 2, 3, 8, 3, 2, 2, 8, 7, 9, 8, 7, 1, 5, 2, 1, 3, 8, 7, 7, 7, 8, 5, 7, 4, 0, 3, 8, 3, 0, 2
Offset: 0

Views

Author

Peter Luschny, Nov 23 2023

Keywords

Examples

			0.57556361649797770406595764751033042890357052264030796184866030336675484524040...
		

Crossrefs

Programs

  • Maple
    1 - sqrt(Pi/4)*erfi(1/2)/exp(1/4): evalf(%, 109);
  • Mathematica
    N[1 - DawsonF[1/2], 110] // RealDigits // First

Formula

Equals 1 - sqrt(Pi/4) * erfi(1/2) / exp(1/4) = 1 - A019704 * A367563 / A092042.
Let C denote the constant. Then:
2*C - 1 = Sum_{n>=0} (-1)^n / Pochhammer(n, n).
2*(C - 1) = Sum_{n>=1} (-1)^n*Gamma(n) / Gamma(2*n).
Equals Integral_{x=0..oo} exp(-x)*cos(sqrt(x)) dx. - Kritsada Moomuang, Jun 06 2025
Showing 1-7 of 7 results.