A130510 ABC conjecture: values of c in the list of "abc-hits".
9, 32, 49, 64, 81, 81, 125, 128, 225, 243, 245, 250, 256, 256, 289, 343, 375, 512, 512, 513, 539, 625, 625, 625, 676, 729, 729, 729, 729, 961, 968, 1025, 1029, 1216, 1331, 1331, 1331, 1369, 1587, 1681, 2048, 2048, 2048, 2057, 2187, 2187, 2187, 2197, 2197
Offset: 1
Keywords
Examples
81 appears twice because 1+80=81 and 32+49=81 are two abc-hits.
References
- See A120498
Links
- T. D. Noe, Table of n, a(n) for n=1..1269 (for c up to 10^6)
- Sander R. Dahmen, Lower bounds for numbers of ABC-hits, J. Numb. Theory, Volume 128, Issue 6, June 2008, pp. 1864-1873.
- Noam D. Elkies, The ABC's of Number Theory, The Harvard College Mathematics Review, Vol. 1, No. 1, Spring 2007, pp. 57-76.
- Brian Hayes, Easy as abc
- Wikipedia, abc conjecture
Crossrefs
Programs
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Mathematica
rad[n_] := If[n==1, 1, Times@@(Transpose[FactorInteger[n]][[1]])]; nn=1000; Do[If[ !PrimeQ[c], Do[b=c-a; If[GCD[a,b]==1 && rad[a*b*c]
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Python
from itertools import count, islice from math import prod, gcd from sympy import primefactors def A130510_gen(startvalue=1): # generator of terms >= startvalue for c in count(max(startvalue,1)): pc = set(primefactors(c)) for a in range(1,(c>>1)+1): b = c-a if gcd(a,b)==1 and c>prod(set(primefactors(a))|set(primefactors(b))|pc): yield c A130510_list = list(islice(A130510_gen(),30)) # Chai Wah Wu, Oct 19 2023
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