1, 0, 1, 1, 1, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 2, 0, 0, 1, 0, 2, 0, 1, 0, 2, 0, 0, 0, 0, 2, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 2, 0, 0, 2, 2, 0, 0, 0, 2, 0, 1, 0, 0, 2, 0, 0, 0, 1, 0, 0, 2, 0, 0
Offset: 1
The array A(n, k) begins:
n, D(n) \k 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 ...
------------------------------------------------------------
1, 2: 1 1 0 0 0 0 2 0 0 0 0 0 0 2 0
2, 3: 1 0 0 0 0 1 0 0 0 0 0 0 2 0 0
3, 5: 1 0 0 2 1 0 0 0 0 0 2 0 0 0 0
4, 6: 1 0 1 0 0 0 0 0 0 2 0 0 0 0 0
5, 7: 1 1 0 0 0 0 0 0 2 0 0 0 0 0 0
6, 8: 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0
7, 10: 1 0 0 0 0 2 0 0 2 1 0 0 0 0 2
8, 11: 1 0 0 0 2 0 0 0 0 0 0 0 0 2 0
9, 12: 1 0 0 1 0 0 0 0 0 0 0 0 2 0 0
10, 13: 1 0 2 2 0 0 0 0 2 0 0 4 1 0 0
11, 14: 1 1 0 0 0 0 0 0 0 0 2 0 0 0 0
12, 15: 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0
13, 17: 1 0 0 0 0 0 0 2 0 0 0 0 2 0 0
14, 18: 1 0 0 0 0 0 2 0 1 0 0 0 0 0 0
15, 19: 1 0 0 0 2 2 0 0 2 0 0 0 0 0 0
16, 20: 1 0 0 0 1 0 0 0 0 0 0 0 0 0 0
17, 21: 1 0 0 2 0 0 1 0 0 0 0 0 0 0 2
18, 22: 1 0 2 0 0 0 0 0 2 0 1 0 0 2 0
19, 23: 1 1 0 0 0 0 0 0 0 0 0 0 2 0 0
20, 24: 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0
...
-------------------------------------------------------------
The triangle T(n, k) begins:
n\k 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 ...
1: 1
2: 1 1
3: 1 0 0
4: 1 0 0 0
5: 1 0 0 0 0
6: 1 1 1 2 0 0
7: 1 0 0 0 1 1 2
8: 1 0 0 0 0 0 0 0
9: 1 0 0 0 0 0 0 0 0
10: 1 0 0 0 0 0 0 0 0 0
11: 1 0 0 0 0 0 0 0 0 0 0
12: 1 1 2 1 2 2 0 0 0 0 0 0
13: 1 0 0 2 0 0 0 1 2 2 2 0 0
14: 1 0 0 0 0 0 0 0 0 0 0 0 2 2
15: 1 0 0 0 0 0 0 0 2 0 0 0 0 0 0
16: 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0
17: 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2
18: 1 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0 0
19: 1 0 0 0 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0
20: 1 1 2 2 1 2 2 2 0 0 0 0 0 0 0 0 0 0 0 0
... For this triangle more of the columns of the array have been used than those that are shown.
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A(5, 9) = 2 = T(13, 9) because D(5) = 7, and the Pell form F(5) with disc(F(5)) = 4*7 = 28 representing k = +9 has 2 families (classes) of proper solutions generated from the two positive fundamental positive solutions (x10, y10) = (11, 4) and (x20, y20) = (4, 1). They are obtained from the trivial solutions of the parallel forms [9, 8, 1] and [9, 10, 2], respectively. See the W. Lang link in A324251, section 3.
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