A242033 a(n) = lpf(A245024(n)-1), where lpf = least prime factor (A020639).
3, 3, 3, 5, 3, 3, 3, 3, 7, 3, 5, 3, 3, 3, 3, 3, 5, 3, 7, 3, 3, 3, 3, 5, 3, 3, 3, 7, 3, 3, 5, 3, 3, 3, 3, 13, 3, 5, 3, 3, 3, 3, 3, 5, 3, 3, 3, 3, 3, 5, 3, 3, 3, 11, 3, 7, 3, 5, 3, 3, 3, 3, 3, 5, 3, 7, 3, 3, 3, 11, 3, 5, 3, 3, 3, 7, 3, 3, 5, 3, 19, 3, 3, 3, 3, 5
Offset: 1
Keywords
Links
- Amiram Eldar, Table of n, a(n) for n = 1..10000
Programs
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Maple
lpf:= n -> min(numtheory:-factorset(n)): L:= [seq(lpf(2*i+1),i=1..1000)]: L[select(i->L[i] < L[i-1], [$2..nops(L)])]; # Robert Israel, Aug 13 2014
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Mathematica
lpf[n_]:=lpf[n]=First[First[FactorInteger[n]]]; (* least prime factor *) A242033=Map[lpf[#-1]&,Select[Range[6,300,2],lpf[#-1]
A245024*) ] (* Peter J. C. Moses, Aug 14 2014 *)
Extensions
More terms from Peter J. C. Moses, Aug 12 2014
Comments