A374683
Irregular triangle read by rows where row n lists the leaders of strictly increasing runs in the n-th composition in standard order.
Original entry on oeis.org
1, 2, 1, 1, 3, 2, 1, 1, 1, 1, 1, 4, 3, 1, 2, 2, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 5, 4, 1, 3, 2, 3, 1, 1, 2, 2, 2, 1, 2, 1, 2, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 6, 5, 1, 4, 2, 4, 1, 1, 3, 3, 3, 2, 1, 3, 1, 3, 1, 1, 1
Offset: 0
The maximal strictly increasing subsequences of the 1234567th composition in standard order are ((3),(2),(1,2),(2),(1,2,5),(1),(1),(1)), so row 1234567 is (3,2,1,2,1,1,1,1).
The nonnegative integers, corresponding compositions, and leaders of strictly increasing runs begin:
0: () -> () 15: (1,1,1,1) -> (1,1,1,1)
1: (1) -> (1) 16: (5) -> (5)
2: (2) -> (2) 17: (4,1) -> (4,1)
3: (1,1) -> (1,1) 18: (3,2) -> (3,2)
4: (3) -> (3) 19: (3,1,1) -> (3,1,1)
5: (2,1) -> (2,1) 20: (2,3) -> (2)
6: (1,2) -> (1) 21: (2,2,1) -> (2,2,1)
7: (1,1,1) -> (1,1,1) 22: (2,1,2) -> (2,1)
8: (4) -> (4) 23: (2,1,1,1) -> (2,1,1,1)
9: (3,1) -> (3,1) 24: (1,4) -> (1)
10: (2,2) -> (2,2) 25: (1,3,1) -> (1,1)
11: (2,1,1) -> (2,1,1) 26: (1,2,2) -> (1,2)
12: (1,3) -> (1) 27: (1,2,1,1) -> (1,1,1)
13: (1,2,1) -> (1,1) 28: (1,1,3) -> (1,1)
14: (1,1,2) -> (1,1) 29: (1,1,2,1) -> (1,1,1)
All of the following pertain to compositions in standard order:
- Ranks of non-contiguous compositions are
A374253, counted by
A335548.
-
stc[n_]:=Differences[Prepend[Join @@ Position[Reverse[IntegerDigits[n,2]],1],0]]//Reverse;
Table[First/@Split[stc[n],Less],{n,0,100}]
A304521
a(n) is the number of prime powers k such that ceiling(log_2(k)) = n.
Original entry on oeis.org
1, 2, 3, 4, 8, 9, 17, 26, 47, 81, 142, 264, 474, 883, 1629, 3045, 5735, 10780, 20429, 38688, 73654, 140426, 268341, 513867, 986034, 1894410, 3646135, 7027826, 13562626, 26208249, 50698866, 98184468, 190338062, 369326691, 717271794, 1394198587, 2712112562
Offset: 1
a(1)=1 because the interval [2,2] contains 1 prime power: 2.
a(2)=2 because the interval [3,4] contains 2 prime powers: 3 and 4=2^2.
a(3)=3 because the prime powers in [5,8] are 5, 7, and 8=2^3.
-
a(n) = sum(k=2^(n-1)+1, 2^n, isprimepower(k) != 0); \\ Michel Marcus, May 17 2018
-
from sympy import primepi, integer_nthroot
def A304521(n):
def f(x):
m = 1<Chai Wah Wu, Jan 19 2025
A374740
Irregular triangle read by rows where row n lists the leaders of weakly decreasing runs in the n-th composition in standard order.
Original entry on oeis.org
1, 2, 1, 3, 2, 1, 2, 1, 4, 3, 2, 2, 1, 3, 1, 2, 1, 2, 1, 5, 4, 3, 3, 2, 3, 2, 2, 2, 2, 1, 4, 1, 3, 1, 2, 1, 2, 1, 3, 1, 2, 1, 2, 1, 6, 5, 4, 4, 3, 3, 3, 2, 3, 2, 4, 2, 3, 2, 2, 2, 3, 2, 2, 2, 2, 2, 1, 5, 1, 4, 1, 3, 1, 3, 1, 2, 3, 1, 2, 1, 2, 2, 1, 2, 1, 4
Offset: 0
The maximal weakly decreasing subsequences of the 1234567th composition in standard order are ((3,2,1),(2,2,1),(2),(5,1,1,1)), so row 1234567 is (3,2,2,5).
The nonnegative integers, corresponding compositions, and leaders of weakly decreasing runs begin:
0: () -> () 15: (1,1,1,1) -> (1)
1: (1) -> (1) 16: (5) -> (5)
2: (2) -> (2) 17: (4,1) -> (4)
3: (1,1) -> (1) 18: (3,2) -> (3)
4: (3) -> (3) 19: (3,1,1) -> (3)
5: (2,1) -> (2) 20: (2,3) -> (2,3)
6: (1,2) -> (1,2) 21: (2,2,1) -> (2)
7: (1,1,1) -> (1) 22: (2,1,2) -> (2,2)
8: (4) -> (4) 23: (2,1,1,1) -> (2)
9: (3,1) -> (3) 24: (1,4) -> (1,4)
10: (2,2) -> (2) 25: (1,3,1) -> (1,3)
11: (2,1,1) -> (2) 26: (1,2,2) -> (1,2)
12: (1,3) -> (1,3) 27: (1,2,1,1) -> (1,2)
13: (1,2,1) -> (1,2) 28: (1,1,3) -> (1,3)
14: (1,1,2) -> (1,2) 29: (1,1,2,1) -> (1,2)
All of the following pertain to compositions in standard order:
- Ranks of non-contiguous compositions are
A374253, counted by
A335548.
-
stc[n_]:=Differences[Prepend[Join @@ Position[Reverse[IntegerDigits[n,2]],1],0]]//Reverse;
Table[First/@Split[stc[n],GreaterEqual],{n,0,100}]
A089633
Numbers having no more than one 0 in their binary representation.
Original entry on oeis.org
0, 1, 2, 3, 5, 6, 7, 11, 13, 14, 15, 23, 27, 29, 30, 31, 47, 55, 59, 61, 62, 63, 95, 111, 119, 123, 125, 126, 127, 191, 223, 239, 247, 251, 253, 254, 255, 383, 447, 479, 495, 503, 507, 509, 510, 511, 767, 895, 959, 991, 1007, 1015, 1019, 1021, 1022, 1023
Offset: 0
From _Tilman Piesk_, May 09 2012: (Start)
This may also be viewed as a triangle: In binary:
0 0
1 2 01 10
3 5 6 011 101 110
7 11 13 14 0111 1011 1101 1110
15 23 27 29 30 01111 10111 11011 11101 11110
31 47 55 59 61 62
63 95 111 119 123 125 126
Left three diagonals are A000225, A055010, A086224. Right diagonal is A000918. Central column is A129868. Numbers in row n (counted from 0) have n binary 1s. (End)
From _Gus Wiseman_, May 24 2024: (Start)
The terms together with their binary expansions and binary indices begin:
0: 0 ~ {}
1: 1 ~ {1}
2: 10 ~ {2}
3: 11 ~ {1,2}
5: 101 ~ {1,3}
6: 110 ~ {2,3}
7: 111 ~ {1,2,3}
11: 1011 ~ {1,2,4}
13: 1101 ~ {1,3,4}
14: 1110 ~ {2,3,4}
15: 1111 ~ {1,2,3,4}
23: 10111 ~ {1,2,3,5}
27: 11011 ~ {1,2,4,5}
29: 11101 ~ {1,3,4,5}
30: 11110 ~ {2,3,4,5}
31: 11111 ~ {1,2,3,4,5}
47: 101111 ~ {1,2,3,4,6}
55: 110111 ~ {1,2,3,5,6}
59: 111011 ~ {1,2,4,5,6}
61: 111101 ~ {1,3,4,5,6}
62: 111110 ~ {2,3,4,5,6}
(End)
- Reinhard Zumkeller, Table of n, a(n) for n = 0..10000
- Vladimir Shevelev, On the Basis Polynomials in the Theory of Permutations with Prescribed Up-Down Structure, arXiv:0801.0072 [math.CO], 2007-201. See Section 14.
- Vladimir Shevelev, Binomial Coefficient Predictors, Journal of Integer Sequences, Vol. 14 (2011), Article 11.2.8.
- Vladimir Shevelev, The number of permutations with prescribed up-down structure as a function of two variables, INTEGERS, 12 (2012), #A1.
- Index entries for sequences related to binary expansion of n.
For least binary index (instead of rank) we have
A001511.
Row minima of
A118462 (binary ranks of strict partitions).
A277905 groups all positive integers by binary rank of prime indices.
-
a089633 n = a089633_list !! (n-1)
a089633_list = [2 ^ t - 2 ^ k - 1 | t <- [1..], k <- [t-1,t-2..0]]
-- Reinhard Zumkeller, Feb 23 2012
-
seq(seq(2^a-1-2^b,b=a-1..0,-1),a=1..11); # Robert Israel, Dec 14 2018
-
fQ[n_] := DigitCount[n, 2, 0] < 2; Select[ Range[0, 2^10], fQ] (* Robert G. Wilson v, Aug 02 2012 *)
-
{insq(n) = local(dd, hf, v); v=binary(n);hf=length(v);dd=sum(i=1,hf,v[i]);if(dd<=hf-2,-1,1)}
{for(w=0,1536,if(insq(w)>=0,print1(w,", ")))}
\\ Douglas Latimer, May 07 2013
-
isoka(n) = #select(x->(x==0), binary(n)) <= 1; \\ Michel Marcus, Dec 14 2018
-
from itertools import count, islice
def A089633_gen(): # generator of terms
return ((1<A089633_list = list(islice(A089633_gen(),30)) # Chai Wah Wu, Feb 10 2023
-
from math import isqrt, comb
def A089633(n): return (1<<(a:=(isqrt((n<<3)+1)-1>>1)+1))-(1<Chai Wah Wu, Dec 19 2024
A104080
Smallest prime >= 2^n.
Original entry on oeis.org
2, 2, 5, 11, 17, 37, 67, 131, 257, 521, 1031, 2053, 4099, 8209, 16411, 32771, 65537, 131101, 262147, 524309, 1048583, 2097169, 4194319, 8388617, 16777259, 33554467, 67108879, 134217757, 268435459, 536870923, 1073741827, 2147483659
Offset: 0
The indices of these prime are given by
A372684.
-
Join[{2,2},NextPrime[#]&/@(2^Range[2,40])] (* Harvey P. Dale, Jan 26 2011 *)
NextPrime[2^Range[0,50]-1] (* Vladimir Joseph Stephan Orlovsky, Apr 11 2011 *)
-
g(n,b=2) = for(x=0,n,print1(nextprime(b^x)","))
-
a(n) = nextprime(2^n); \\ Michel Marcus, Nov 01 2020
A374515
Irregular triangle read by rows where row n lists the leaders of anti-runs in the n-th composition in standard order.
Original entry on oeis.org
1, 2, 1, 1, 3, 2, 1, 1, 1, 1, 4, 3, 2, 2, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 5, 4, 3, 3, 1, 2, 2, 2, 2, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 6, 5, 4, 4, 1, 3, 3, 3, 3, 3, 1, 1, 2, 2, 2, 2, 2, 2, 2, 1, 2, 2, 2, 1, 2, 1, 1, 1, 1, 1, 1
Offset: 0
The maximal anti-runs of the 1234567th composition in standard order are ((3,2,1,2),(2,1,2,5,1),(1),(1)), so row 1234567 is (3,2,1,1).
The nonnegative integers, corresponding compositions, and leaders of anti-runs begin:
0: () -> () 15: (1,1,1,1) -> (1,1,1,1)
1: (1) -> (1) 16: (5) -> (5)
2: (2) -> (2) 17: (4,1) -> (4)
3: (1,1) -> (1,1) 18: (3,2) -> (3)
4: (3) -> (3) 19: (3,1,1) -> (3,1)
5: (2,1) -> (2) 20: (2,3) -> (2)
6: (1,2) -> (1) 21: (2,2,1) -> (2,2)
7: (1,1,1) -> (1,1,1) 22: (2,1,2) -> (2)
8: (4) -> (4) 23: (2,1,1,1) -> (2,1,1)
9: (3,1) -> (3) 24: (1,4) -> (1)
10: (2,2) -> (2,2) 25: (1,3,1) -> (1)
11: (2,1,1) -> (2,1) 26: (1,2,2) -> (1,2)
12: (1,3) -> (1) 27: (1,2,1,1) -> (1,1)
13: (1,2,1) -> (1) 28: (1,1,3) -> (1,1)
14: (1,1,2) -> (1,1) 29: (1,1,2,1) -> (1,1)
Row-leaders of nonempty rows are
A065120.
A106356 counts compositions by number of maximal anti-runs.
A238279 counts compositions by number of maximal runs
A238424 counts partitions whose first differences are an anti-run.
All of the following pertain to compositions in standard order:
Six types of maximal runs:
-
stc[n_]:=Differences[Prepend[Join @@ Position[Reverse[IntegerDigits[n,2]],1],0]]//Reverse;
Table[First/@Split[stc[n],UnsameQ],{n,0,100}]
A077643
Number of squarefree integers in closed interval [2^n, -1 + 2*2^n], i.e., among 2^n consecutive numbers beginning with 2^n.
Original entry on oeis.org
1, 2, 3, 5, 9, 19, 39, 79, 157, 310, 621, 1246, 2491, 4980, 9958, 19924, 39844, 79672, 159365, 318736, 637457, 1274916, 2549816, 5099651, 10199363, 20398663, 40797299, 81594571, 163189087, 326378438, 652756861, 1305513511, 2611026987, 5222053970, 10444108084
Offset: 0
For n=4: among the 16 numbers of {16, ..., 31}, nine are squarefree [17, 19, 21, 22, 23, 26, 29, 30, 31], so a(4) = 9.
Partial sums (except first term) are
A143658.
A053797 gives nonempty lengths of exclusive gaps between squarefree numbers.
For primes between powers of 2:
For squarefree numbers between primes:
-
Table[Apply[Plus, Table[Abs[MoebiusMu[2^w+j]], {j, 0, 2^w-1}]], {w, 0, 15}]
(* second program *)
Length/@Split[IntegerLength[Select[Range[10000],SquareFreeQ],2]]//Most (* Gus Wiseman, Jun 02 2024 *)
-
{ a(n) = sum(m=1,sqrtint(2^(n+1)-1), moebius(m) * ((2^(n+1)-1)\m^2 - (2^n-1)\m^2) ) } \\ Max Alekseyev, Oct 18 2008
More terms from Mark Hudson (mrmarkhudson(AT)hotmail.com), Feb 12 2003
A372429
Sum of binary indices of prime(n). Sum of positions of ones in the reversed binary expansion of prime(n).
Original entry on oeis.org
2, 3, 4, 6, 7, 8, 6, 8, 11, 13, 15, 10, 11, 13, 16, 15, 18, 19, 10, 13, 12, 17, 15, 17, 14, 17, 19, 20, 21, 19, 28, 11, 13, 15, 17, 19, 21, 17, 20, 22, 22, 23, 29, 16, 19, 21, 23, 30, 24, 25, 26, 31, 27, 33, 10, 15, 17, 19, 18, 19, 21, 19, 23, 26, 25, 28, 23
Offset: 1
The primes together with their binary expansions and binary indices begin:
2: 10 ~ {2}
3: 11 ~ {1,2}
5: 101 ~ {1,3}
7: 111 ~ {1,2,3}
11: 1011 ~ {1,2,4}
13: 1101 ~ {1,3,4}
17: 10001 ~ {1,5}
19: 10011 ~ {1,2,5}
23: 10111 ~ {1,2,3,5}
29: 11101 ~ {1,3,4,5}
31: 11111 ~ {1,2,3,4,5}
37: 100101 ~ {1,3,6}
41: 101001 ~ {1,4,6}
43: 101011 ~ {1,2,4,6}
47: 101111 ~ {1,2,3,4,6}
53: 110101 ~ {1,3,5,6}
59: 111011 ~ {1,2,4,5,6}
61: 111101 ~ {1,3,4,5,6}
67: 1000011 ~ {1,2,7}
71: 1000111 ~ {1,2,3,7}
73: 1001001 ~ {1,4,7}
79: 1001111 ~ {1,2,3,4,7}
The number instead of sum of binary indices is
A014499.
The maximum instead of sum of binary indices is
A035100, see also
A023506.
A070939 gives length of binary expansion.
A096111 gives product of binary indices.
A326031 gives weight of the set-system with BII-number n.
A372427 lists numbers whose binary and prime indices have the same sum.
Cf.
A005940,
A030101,
A059893,
A071814,
A230877,
A231204,
A358134,
A359359,
A359401,
A372430-
A372437,
A372441.
-
bix[n_]:=Join@@Position[Reverse[IntegerDigits[n,2]],1];
Table[Total[bix[Prime[n]]],{n,100}]
A374768
Numbers k such that the leaders of weakly increasing runs in the k-th composition in standard order (A066099) are distinct.
Original entry on oeis.org
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 26, 28, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 46, 47, 48, 50, 52, 56, 58, 60, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 78, 79, 80, 81
Offset: 1
The 4444th composition in standard order is (4,2,2,1,1,3), with weakly increasing runs ((4),(2,2),(1,1,3)), with leaders (4,2,1), so 4444 is in the sequence.
These are the positions of strict rows in
A374629 (which has sums
A374630).
Identical instead of distinct leaders are
A374633, counted by
A374631.
For leaders of strictly increasing runs we have
A374698, counted by
A374687.
For leaders of weakly decreasing runs we have
A374701, counted by
A374743.
For leaders of strictly decreasing runs we have
A374767, counted by
A374761.
All of the following pertain to compositions in standard order:
- Ranks of strict compositions are
A233564.
- Ranks of constant compositions are
A272919.
Cf.
A065120,
A188920,
A189076,
A238343,
A333213,
A335449,
A373949,
A274174,
A374249,
A374635,
A374637.
-
stc[n_]:=Differences[Prepend[Join @@ Position[Reverse[IntegerDigits[n,2]],1],0]]//Reverse;
Select[Range[0,166],UnsameQ@@First/@Split[stc[#],LessEqual]&]
A253565
Permutation of natural numbers: a(0) = 1, a(1) = 2; after which, a(2n) = A253550(a(n)), a(2n+1) = A253560(a(n)).
Original entry on oeis.org
1, 2, 3, 4, 5, 9, 6, 8, 7, 25, 15, 27, 10, 18, 12, 16, 11, 49, 35, 125, 21, 75, 45, 81, 14, 50, 30, 54, 20, 36, 24, 32, 13, 121, 77, 343, 55, 245, 175, 625, 33, 147, 105, 375, 63, 225, 135, 243, 22, 98, 70, 250, 42, 150, 90, 162, 28, 100, 60, 108, 40, 72, 48, 64, 17, 169, 143, 1331, 91, 847, 539, 2401, 65, 605, 385, 1715, 275, 1225, 875, 3125, 39
Offset: 0
From _Gus Wiseman_, Dec 23 2022: (Start)
This represents the following bijection between compositions and partitions. The n-th composition in standard order together with the reversed prime indices of a(n) are:
0: () -> ()
1: (1) -> (1)
2: (2) -> (2)
3: (1,1) -> (1,1)
4: (3) -> (3)
5: (2,1) -> (2,2)
6: (1,2) -> (2,1)
7: (1,1,1) -> (1,1,1)
8: (4) -> (4)
9: (3,1) -> (3,3)
10: (2,2) -> (3,2)
11: (2,1,1) -> (2,2,2)
12: (1,3) -> (3,1)
13: (1,2,1) -> (2,2,1)
14: (1,1,2) -> (2,1,1)
15: (1,1,1,1) -> (1,1,1,1)
(End)
These are the Heinz numbers of the rows of
A242628.
A048793 gives partial sums of reversed standard comps, Heinz number
A019565.
A066099 lists standard compositions.
A358134 gives partial sums of standard compositions, Heinz number
A358170.
-
stc[n_]:=Differences[Prepend[Join @@ Position[Reverse[IntegerDigits[n,2]],1],0]]//Reverse;
Times@@Prime/@#&/@Table[Accumulate[stc[n]-1]+1,{n,0,60}] (* Gus Wiseman, Dec 17 2022 *)
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