A240672 Number of the first evil exponents (A001969) in the prime power factorization of (2n)!.
0, 1, 0, 0, 0, 2, 0, 3, 0, 1, 0, 0, 4, 0, 0, 0, 0, 2, 0, 0, 1, 0, 0, 1, 0, 0, 0, 1, 2, 0, 1, 2, 0, 1, 0, 0, 2, 0, 0, 2, 0, 0, 0, 1, 1, 0, 2, 0, 2, 0, 0, 1, 1, 0, 2, 0, 0, 0, 9, 2, 0, 1, 1, 0, 0, 2, 0, 0, 1, 0, 0, 1, 0, 0, 0, 2, 1, 0, 2, 0, 3, 0, 0, 1, 1, 0, 2
Offset: 1
Keywords
Examples
26! = 2^23*3^10*5^6*7^3*11^2*13^2*17*19*23, and the first 4 exponents (23,10,6,3) are evil, so a(13) = 4.
Links
- Peter J. C. Moses, Table of n, a(n) for n = 1..2000
- Y.-G. Chen, On the parity of exponents in the standard factorization of n!, J. Number Theory, 100 (2003), 326-331.
Programs
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Mathematica
Map[Count[First[Split[Map[EvenQ[DigitCount[#,2][[1]]]&,Last[Transpose[FactorInteger[(2*#)!]]&[#]]]]],True]&,Range[75]] (* Peter J. C. Moses, Apr 10 2014 *)
Formula
a(n)*A240669(n) = 0.
Comments