cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A008466 a(n) = 2^n - Fibonacci(n+2).

Original entry on oeis.org

0, 0, 1, 3, 8, 19, 43, 94, 201, 423, 880, 1815, 3719, 7582, 15397, 31171, 62952, 126891, 255379, 513342, 1030865, 2068495, 4147936, 8313583, 16655823, 33358014, 66791053, 133703499, 267603416, 535524643, 1071563515, 2143959070, 4289264409, 8580707127
Offset: 0

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Keywords

Comments

Toss a fair coin n times; a(n) is number of possible outcomes having a run of 2 or more heads.
Also the number of binary words of length n with at least two neighboring 1 digits. For example, a(4)=8 because 8 binary words of length 4 have two or more neighboring 1 digits: 0011, 0110, 0111, 1011, 1100, 1101, 1110, 1111 (cf. A143291). - Alois P. Heinz, Jul 18 2008
Equivalently, number of solutions (x_1, ..., x_n) to the equation x_1*x_2 + x_2*x_3 + x_3*x_4 + ... + x_{n-1}*x_n = 1 in base-2 lunar arithmetic. - N. J. A. Sloane, Apr 23 2011
Row sums of triangle A153281 = (1, 3, 8, 19, 43, ...). - Gary W. Adamson, Dec 23 2008
a(n-1) is the number of compositions of n with at least one part >= 3. - Joerg Arndt, Aug 06 2012
One less than the cardinality of the set of possible numbers of (leaf-) nodes of AVL trees with height n (cf. A143897, A217298). a(3) = 4-1, the set of possible numbers of (leaf-) nodes of AVL trees with height 3 is {5,6,7,8}. - Alois P. Heinz, Mar 20 2013
a(n) is the number of binary words of length n such that some prefix contains three more 1's than 0's or two more 0's than 1's. a(4) = 8 because we have: {0,0,0,0}, {0,0,0,1}, {0,0,1,0}, {0,0,1,1}, {0,1,0,0}, {1,0,0,0}, {1,1,1,0}, {1,1,1,1}. - Geoffrey Critzer, Dec 30 2013
With offset 0: antidiagonal sums of P(j,n) array of j-th partial sums of Fibonacci numbers. - Luciano Ancora, Apr 26 2015

Examples

			From _Gus Wiseman_, Jun 25 2020: (Start)
The a(2) = 1 through a(5) = 19 compositions of n + 1 with at least one part >= 3 are:
  (3)  (4)    (5)      (6)
       (1,3)  (1,4)    (1,5)
       (3,1)  (2,3)    (2,4)
              (3,2)    (3,3)
              (4,1)    (4,2)
              (1,1,3)  (5,1)
              (1,3,1)  (1,1,4)
              (3,1,1)  (1,2,3)
                       (1,3,2)
                       (1,4,1)
                       (2,1,3)
                       (2,3,1)
                       (3,1,2)
                       (3,2,1)
                       (4,1,1)
                       (1,1,1,3)
                       (1,1,3,1)
                       (1,3,1,1)
                       (3,1,1,1)
(End)
		

References

  • W. Feller, An Introduction to Probability Theory and Its Applications, Vol. 1, 2nd ed. New York: Wiley, p. 300, 1968.
  • J. Riordan, An Introduction to Combinatorial Analysis, Wiley, 1958, p. 14, Exercise 1.

Crossrefs

Cf. A153281, A186244 (ternary words), A335457, A335458, A335516.
The non-contiguous version is A335455.
Row 2 of A340156. Column 3 of A109435.

Programs

  • Magma
    [2^n-Fibonacci(n+2): n in [0..40]]; // Vincenzo Librandi, Apr 27 2015
    
  • Maple
    a:= n-> (<<3|1|0>, <-1|0|1>, <-2|0|0>>^n)[1, 3]:
    seq(a(n), n=0..50); # Alois P. Heinz, Jul 18 2008
    # second Maple program:
    with(combinat): F:=fibonacci; f:=n->add(2^(n-1-i)*F(i),i=0..n-1); [seq(f(n),n=0..50)]; # N. J. A. Sloane, Mar 31 2014
  • Mathematica
    Table[2^n-Fibonacci[n+2],{n,0,20}] (* Vladimir Joseph Stephan Orlovsky, Jul 22 2008 *)
    MMM = 30;
    For[ M=2, M <= MMM, M++,
    vlist = Array[x, M];
    cl[i_] := And[ x[i], x[i+1] ];
    cl2 = False; For [ i=1, i <= M-1, i++, cl2 = Or[cl2, cl[i]] ];
    R[M] = SatisfiabilityCount[ cl2, vlist ] ]
    Table[ R[M], {M,2,MMM}]
    (* Find Boolean values of variables that satisfy the formula x1 x2 + x2 x3 + ... + xn-1 xn = 1; N. J. A. Sloane, Apr 23 2011 *)
    LinearRecurrence[{3,-1,-2},{0,0,1},40] (* Harvey P. Dale, Aug 09 2013 *)
    nn=33; a=1/(1-2x); b=1/(1-2x^2-x^4-x^6/(1-x^2));
    CoefficientList[Series[b(a x^3/(1-x^2)+x^2a),{x,0,nn}],x] (* Geoffrey Critzer, Dec 30 2013 *)
    Table[Length[Select[Join@@Permutations/@IntegerPartitions[n+1],Max@@#>2&]],{n,0,10}] (* Gus Wiseman, Jun 25 2020 *)
  • PARI
    a(n) = 2^n-fibonacci(n+2) \\ Charles R Greathouse IV, Feb 03 2014
    
  • SageMath
    def A008466(n): return 2^n - fibonacci(n+2) # G. C. Greubel, Apr 23 2025

Formula

a(1)=0, a(2)=1, a(3)=3, a(n) = 3*a(n-1) - a(n-2) - 2*a(n-3). - Miklos Kristof, Nov 24 2003
G.f.: x^2/((1-2*x)*(1-x-x^2)). - Paul Barry, Feb 16 2004
From Paul Barry, May 19 2004: (Start)
Convolution of Fibonacci(n) and (2^n - 0^n)/2.
a(n) = Sum_{k=0..n} (2^k-0^k)*Fibonacci(n-k)/2.
a(n+1) = Sum_{k=0..n} Fibonacci(k)*2^(n-k).
a(n) = 2^n*Sum_{k=0..n} Fibonacci(k)/2^k. (End)
a(n) = a(n-1) + a(n-2) + 2^(n-2). - Jon Stadler (jstadler(AT)capital.edu), Aug 21 2006
a(n) = 2*a(n-1) + Fibonacci(n-1). - Thomas M. Green, Aug 21 2007
a(n) = term (1,3) in the 3 X 3 matrix [3,1,0; -1,0,1; -2,0,0]^n. - Alois P. Heinz, Jul 18 2008
a(n) = 2*a(n-1) - a(n-3) + 2^(n-3). - Carmine Suriano, Mar 08 2011