A000138
Expansion of e.g.f. exp(-x^4/4)/(1-x).
Original entry on oeis.org
1, 1, 2, 6, 18, 90, 540, 3780, 31500, 283500, 2835000, 31185000, 372972600, 4848643800, 67881013200, 1018215198000, 16294848570000, 277012425690000, 4986223662420000, 94738249585980000, 1894745192712372000, 39789649046959812000, 875372279033115864000
Offset: 0
a(4) = 18 because in S_4 the permutations with no 4-cycle are the complement of the six 4-cycles so a(4) = 4! - 6 = 18.
- J. Riordan, An Introduction to Combinatorial Analysis, Wiley, 1958, p. 85.
- N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
- N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
- R. P. Stanley, Enumerative Combinatorics, Wadsworth, Vol. 1, 1986, page 93, problem 7.
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nn=20;Range[0,nn]!CoefficientList[Series[Exp[-x^4/4]/(1-x),{x,0,nn}],x] (* Geoffrey Critzer, Oct 28 2012 *)
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{a(n) = if( n<0, 0, n! * polcoeff( exp( -(x^4/4) + x*O(x^n)) / (1 - x), n))} /* Michael Somos, Jul 28 2009 */
A060725
E.g.f.: exp(-(x^5/5))/(1-x).
Original entry on oeis.org
1, 1, 2, 6, 24, 96, 576, 4032, 32256, 290304, 2975616, 32731776, 392781312, 5106157056, 71486198784, 1070549415936, 17128790654976, 291189441134592, 5241409940422656, 99586788868030464, 1991897970827821056, 41829857387384242176, 920256862522453327872
Offset: 0
Avi Peretz (njk(AT)netvision.net.il), Apr 22 2001
a(5) = 96 because in S_5 the permutations with no 5-cycle are the complement of the 24 5-cycles so a(5) = 5! - 24 = 96.
- R. P. Stanley, Enumerative Combinatorics, Wadsworth, Vol. 1, 1986, page 93, problem 7.
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for n from 0 to 30 do printf(`%d,`, n! * sum(( (-1)^i /(i! * 5^i)), i=0..floor(n/5))) od:
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With[{nn=30},CoefficientList[Series[Exp[-(x^5/5)]/(1-x),{x,0,nn}],x] Range[ 0,nn]!] (* Harvey P. Dale, Aug 24 2019 *)
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{ for (n=0, 100, write("b060725.txt", n, " ", n! * sum(i=0, n\5, (-1)^i / (i! * 5^i))); ) } \\ Harry J. Smith, Jul 10 2009
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{a(n) = if( n<0, 0, n! * polcoeff( exp( -(x^5 / 5) + x*O(x^n)) / (1 - x), n))} /* Michael Somos, Jul 28 2009 */
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{ A060725_list(numterms) = Vec(serlaplace(exp(-x^5/5 + O(x^numterms))/(1-x))); } /* Eric M. Schmidt, Aug 22 2012 */
A060726
For n >= 1, a(n) is the number of permutations in the symmetric group S_n such that their cycle decomposition contains no 6-cycle.
Original entry on oeis.org
1, 1, 2, 6, 24, 120, 600, 4200, 33600, 302400, 3024000, 33264000, 405820800, 5275670400, 73859385600, 1107890784000, 17726252544000, 301346293248000, 5419293175296000, 102966570330624000, 2059331406612480000
Offset: 0
Avi Peretz (njk(AT)netvision.net.il), Apr 22 2001
a(6) = 600 because in S_6 the permutations with no 6-cycle are the complement of the 120 6-cycles so a(6) = 6! - 120 = 600.
- R. P. Stanley, Enumerative Combinatorics, Wadsworth, Vol. 1, 1986, page 93, problem 7.
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for n from 0 to 30 do printf(`%d,`, n! * sum(( (-1)^i /(i! * 6^i)), i=0..floor(n/6))) od:
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a(n)={n! * sum(i=0, n\6, (-1)^i / (i! * 6^i))} \\ Harry J. Smith, Jul 10 2009
A122974
Triangle T(n,k), the number of permutations on n elements that have no cycles of length k.
Original entry on oeis.org
0, 1, 1, 2, 3, 4, 9, 15, 16, 18, 44, 75, 80, 90, 96, 265, 435, 520, 540, 576, 600, 1854, 3045, 3640, 3780, 4032, 4200, 4320, 14833, 24465, 29120, 31500, 32256, 33600, 34560, 35280, 133496, 220185, 259840, 283500, 290304, 302400, 311040, 317520, 322560
Offset: 1
T(3,2)=3 since there are exactly 3 permutations of 1,2,3 that have no cycles of length 2, namely, (1)(2)(3),(1 2 3) and (2 1 3).
Triangle T(n,k) begins:
0;
1, 1;
2, 3, 4;
9, 15, 16, 18;
44, 75, 80, 90, 96;
265, 435, 520, 540, 576, 600;
1854, 3045, 3640, 3780, 4032, 4200, 4320;
14833, 24465, 29120, 31500, 32256, 33600, 34560, 35280;
...
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seq((round((2*n)^.5))!*sum((-1/(n-binomial(round((2*n)^.5),2)))^r/r!,r=0..floor(round((2*n)^.5)/(n-binomial(round((2*n)^.5),2)))),n=1..66);
# second Maple program:
T:= proc(n, k) option remember; `if`(n=0, 1, add(`if`(j=k, 0,
T(n-j, k)*binomial(n-1, j-1)*(j-1)!), j=1..n))
end:
seq(seq(T(n, k), k=1..n), n=1..12); # Alois P. Heinz, Nov 24 2019
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T[n_, k_] := T[n, k] = If[n==0, 1, Sum[If[j==k, 0, T[n - j, k] Binomial[n - 1, j - 1] (j - 1)!], {j, 1, n}]];
Table[Table[T[n, k], {k, 1, n}], {n, 1, 12}] // Flatten (* Jean-François Alcover, Dec 08 2019, after Alois P. Heinz *)
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