cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A069190 Centered 24-gonal numbers.

Original entry on oeis.org

1, 25, 73, 145, 241, 361, 505, 673, 865, 1081, 1321, 1585, 1873, 2185, 2521, 2881, 3265, 3673, 4105, 4561, 5041, 5545, 6073, 6625, 7201, 7801, 8425, 9073, 9745, 10441, 11161, 11905, 12673, 13465, 14281, 15121, 15985, 16873, 17785, 18721, 19681, 20665, 21673
Offset: 1

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Author

Terrel Trotter, Jr., Apr 10 2002

Keywords

Comments

Sequence found by reading the line from 1, in the direction 1, 25, ..., in the square spiral whose vertices are the generalized octagonal numbers A001082. Semi-axis opposite to A135453 in the same spiral. - Omar E. Pol, Sep 16 2011

Examples

			a(5) = 241 because 12*5^2 - 12*5 + 1 = 300 - 60 + 1 = 241.
		

Crossrefs

Programs

Formula

a(n) = 12*n^2 - 12*n + 1.
a(n) = 24*n + a(n-1) - 24 with a(1)=1. - Vincenzo Librandi, Aug 08 2010
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3); a(1)=1, a(2)=25, a(3)=73. - Harvey P. Dale, Jul 17 2011
G.f.: x*(1+22*x+x^2)/(1-x)^3. - Harvey P. Dale, Jul 17 2011
Binomial transform of [1, 24, 24, 0, 0, 0, ...] and Narayana transform (cf. A001263) of [1, 24, 0, 0, 0, ...]. - Gary W. Adamson, Jul 26 2011
From Amiram Eldar, Jun 21 2020: (Start)
Sum_{n>=1} 1/a(n) = Pi*tan(Pi/sqrt(6))/(4*sqrt(6)).
Sum_{n>=1} a(n)/n! = 13*e - 1.
Sum_{n>=1} (-1)^n * a(n)/n! = 13/e - 1. (End)
E.g.f.: exp(x)*(1 + 12*x^2) - 1. - Stefano Spezia, May 31 2022

Extensions

More terms from Harvey P. Dale, Jul 17 2011

A262221 a(n) = 25*n*(n + 1)/2 + 1.

Original entry on oeis.org

1, 26, 76, 151, 251, 376, 526, 701, 901, 1126, 1376, 1651, 1951, 2276, 2626, 3001, 3401, 3826, 4276, 4751, 5251, 5776, 6326, 6901, 7501, 8126, 8776, 9451, 10151, 10876, 11626, 12401, 13201, 14026, 14876, 15751, 16651, 17576, 18526, 19501, 20501, 21526, 22576, 23651
Offset: 0

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Author

Bruno Berselli, Sep 15 2015

Keywords

Comments

Also centered 25-gonal (or icosipentagonal) numbers.
This is the case k=25 of the formula (k*n*(n+1) - (-1)^k + 1)/2. See table in Links section for similar sequences.
For k=2*n, the formula shown above gives A011379.
Primes in sequence: 151, 251, 701, 1951, 3001, 4751, 10151, 12401, ...

References

  • E. Deza and M. M. Deza, Figurate numbers, World Scientific Publishing (2012), page 51 (23rd row of the table).

Crossrefs

Cf. centered polygonal numbers listed in A069190.
Similar sequences of the form (k*n*(n+1) - (-1)^k + 1)/2 with -1 <= k <= 26: A000004, A000124, A002378, A005448, A005891, A028896, A033996, A035008, A046092, A049598, A060544, A064200, A069099, A069125, A069126, A069128, A069130, A069132, A069174, A069178, A080956, A124080, A163756, A163758, A163761, A164136, A173307.

Programs

  • Magma
    [25*n*(n+1)/2+1: n in [0..50]];
  • Mathematica
    Table[25 n (n + 1)/2 + 1, {n, 0, 50}]
    25*Accumulate[Range[0,50]]+1 (* or *) LinearRecurrence[{3,-3,1},{1,26,76},50] (* Harvey P. Dale, Jan 29 2023 *)
  • PARI
    vector(50, n, n--; 25*n*(n+1)/2+1)
    
  • Sage
    [25*n*(n+1)/2+1 for n in (0..50)]
    

Formula

G.f.: (1 + 23*x + x^2)/(1 - x)^3.
a(n) = a(-n-1) = 3*a(n-1) - 3*a(n-2) + a(n-3).
a(n) = A123296(n) + 1.
a(n) = A000217(5*n+2) - 2.
a(n) = A034856(5*n+1).
a(n) = A186349(10*n+1).
a(n) = A054254(5*n+2) with n>0, a(0)=1.
a(n) = A000217(n+1) + 23*A000217(n) + A000217(n-1) with A000217(-1)=0.
Sum_{i>=0} 1/a(i) = 1.078209111... = 2*Pi*tan(Pi*sqrt(17)/10)/(5*sqrt(17)).
From Amiram Eldar, Jun 21 2020: (Start)
Sum_{n>=0} a(n)/n! = 77*e/2.
Sum_{n>=0} (-1)^(n+1) * a(n)/n! = 23/(2*e). (End)
E.g.f.: exp(x)*(2 + 50*x + 25*x^2)/2. - Elmo R. Oliveira, Dec 24 2024

A276261 Centered 21-gonal primes.

Original entry on oeis.org

127, 211, 757, 2521, 2857, 6301, 8527, 16381, 19867, 23689, 24697, 27847, 32341, 37171, 38431, 42337, 66361, 68041, 82237, 89839, 97777, 103951, 114661, 140071, 152461, 162751, 170689, 192781, 204331, 216217, 231547, 240997, 284131, 308827, 353557, 357421, 385057, 389089
Offset: 1

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Author

Ilya Gutkovskiy, Aug 26 2016

Keywords

Comments

Primes of the form (21*k^2 + 21*k + 2)/2.
Numbers k such that (21*k^2 + 21*k + 2)/2 is prime: 3, 4, 8, 15, 16, 24, 28, 39, 43, 47, 48, 51, 55, 059, 60, 63, 79, 80, 88, 92, 96, 99, ...

Crossrefs

Cf. similar sequences of the centered k-gonal primes: A125602 (k = 3), A027862 (k = 4), A145838 (k = 5), A002407 (k = 6), A144974 (k = 7), A090562 (k = 10), A262344 (k = 11), A262493 (k = 13), A264821 (k = 14), A264822 (k = 15), A264823 (k = 16), A264824 (k = 17), A264825 (k = 18), A264844 (k = 19), A264845 (k = 20), A201715 (k = 24).

Programs

  • Mathematica
    Intersection[Table[(21 k^2 + 21 k + 2)/2, {k, 0, 1000}], Prime[Range[33000]]]
  • PARI
    lista(nn) = for(n=1, nn, if(isprime(p=(21*n^2 + 21*n + 2)/2), print1(p, ", "))); \\ Altug Alkan, Aug 26 2016

A010011 a(0) = 1, a(n) = 21*n^2 + 2 for n>0.

Original entry on oeis.org

1, 23, 86, 191, 338, 527, 758, 1031, 1346, 1703, 2102, 2543, 3026, 3551, 4118, 4727, 5378, 6071, 6806, 7583, 8402, 9263, 10166, 11111, 12098, 13127, 14198, 15311, 16466, 17663, 18902, 20183, 21506, 22871, 24278, 25727, 27218, 28751, 30326, 31943, 33602, 35303
Offset: 0

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Author

Keywords

Crossrefs

Cf. A206399.

Programs

Formula

O.g.f.: 1-x*(23+17*x+2*x^2)/(-1+x)^3. - R. J. Mathar, Apr 12 2008
E.g.f.: (21*x*(x+1)+2)*e^x-1. - Gopinath A. R., Feb 13 2012
Sum_{n>=0} 1/a(n) = 3/4+sqrt(42)/84*Pi*coth( Pi*sqrt(42)/21) = 1.0738233857899... - R. J. Mathar, May 07 2024
a(n) = A069178(n)+A069178(n+1). - R. J. Mathar, May 07 2024

A081929 Sum of the n-th row of A077339.

Original entry on oeis.org

1, 22, 64, 127, 211, 316, 442, 589, 757, 946, 1156, 2467, 3979, 5692, 7606, 9721, 12037, 14554, 17272, 20191, 23311, 26632, 30154, 33877, 37801, 41926, 46252, 50779, 55507, 60436, 65566, 70897, 76429, 82162, 88096, 94231, 100567, 107104
Offset: 1

Views

Author

Amarnath Murthy, Apr 01 2003

Keywords

Crossrefs

Not the same as A069178 (A069178(12)=1387 <> 2467=a(12) ). Cf. A077339, A077340.

Formula

For n>10, a(n) = 1/2 * (201n^2 - 2001n + 2).
From Chai Wah Wu, Jan 12 2023: (Start)
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3) for n > 13.
G.f.: x*(900*x^12 - 1080*x^11 - x^2 - 19*x - 1)/(x - 1)^3. (End)

Extensions

More terms from Antonio G. Astudillo (afg_astudillo(AT)lycos.com), Apr 19 2003
Showing 1-5 of 5 results.