cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A050292 a(2n) = 2n - a(n), a(2n+1) = 2n + 1 - a(n) (for n >= 0).

Original entry on oeis.org

0, 1, 1, 2, 3, 4, 4, 5, 5, 6, 6, 7, 8, 9, 9, 10, 11, 12, 12, 13, 14, 15, 15, 16, 16, 17, 17, 18, 19, 20, 20, 21, 21, 22, 22, 23, 24, 25, 25, 26, 26, 27, 27, 28, 29, 30, 30, 31, 32, 33, 33, 34, 35, 36, 36, 37, 37, 38, 38, 39, 40, 41, 41, 42, 43, 44, 44, 45, 46, 47, 47, 48, 48, 49, 49, 50, 51, 52, 52, 53, 54
Offset: 0

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Author

Keywords

Comments

Note that the first equation implies a(0)=0, so there is no need to specify an initial value.
Maximal cardinality of a double-free subset of {1, 2, ..., n}, or in other words, maximal size of a subset S of {1, 2, ..., n} with the property that if x is in S then 2x is not. a(0)=0 by convention.
Least k such that a(k)=n is equal to A003159(n).
To construct the sequence: let [a, b, c, a, a, a, b, c, a, b, c, ...] be the fixed point of the morphism a -> abc, b ->a, c -> a, starting from a(1) = a, then write the indices of a, b, c, that of a being written twice; see A092606. - Philippe Deléham, Apr 13 2004
Number of integers from {1,...,n} for which the subtraction of 1 changes the parity of the number of 1's in their binary expansion. - Vladimir Shevelev, Apr 15 2010
Number of integers from {1,...,n} the factorization of which over different terms of A050376 does not contain 2. - Vladimir Shevelev, Apr 16 2010
a(n) modulo 2 is the Prouhet-Thue-Morse sequence A010060. Each number n appears A026465(n+1) times. - Philippe Deléham, Oct 19 2011
Another way of stating the last two comments from Philippe Deléham: the sequence can be obtained by replacing each term of the Thue-Morse sequence A010060 by the run number that term is in. - N. J. A. Sloane, Dec 31 2013

Examples

			Examples for n = 1 through 8: {1}, {1}, {1,3}, {1,3,4}, {1,3,4,5}, {1,3,4,5}, {1,3,4,5,7}, {1,3,4,5,7}.
Binary expansion of 5 is 101, so Sum{i>=0} b_i*(-1)^i = 2. Therefore a(5) = 10/3 + 2/3 = 4. - _Vladimir Shevelev_, Apr 15 2010
		

References

  • S. R. Finch, Mathematical Constants, Cambridge, 2003, Section 2.26.
  • Wang, E. T. H. "On Double-Free Sets of Integers." Ars Combin. 28, 97-100, 1989.

Crossrefs

Programs

  • Haskell
    a050292 n = a050292_list !! (n-1)
    a050292_list = scanl (+) 0 a035263_list
    -- Reinhard Zumkeller, Jan 21 2013
    
  • Maple
    A050292:=n->add((-1)^k*floor(n/2^k), k=0..n); seq(A050292(n), n=0..100); # Wesley Ivan Hurt, Feb 14 2014
  • Mathematica
    a[n_] := a[n] = If[n < 2, 1, n - a[Floor[n/2]]]; Table[ a[n], {n, 1, 75}]
    Join[{0},Accumulate[Nest[Flatten[#/.{0->{1,1},1->{1,0}}]&,{0},7]]] (* Harvey P. Dale, Apr 29 2018 *)
  • PARI
    a(n)=if(n<2,1,n-a(floor(n/2)))
    
  • Python
    from sympy.ntheory import digits
    def A050292(n): return ((n<<1)+sum((0,1,-1,0)[i] for i in digits(n,4)[1:]))//3 # Chai Wah Wu, Jan 30 2025

Formula

Partial sums of A035263. Close to (2/3)*n.
a(n) = A123087(2*n) = n - A123087(n). - Max Alekseyev, Mar 05 2023
From Benoit Cloitre, Nov 24 2002: (Start)
a(1)=1, a(n) = n - a(floor(n/2));
a(n) = (2/3)*n + (1/3)*A065359(n);
more generally, for m>=0, a(2^m*n) - 2^m*a(n) = A001045(m)*A065359(n) where A001045(m) = (2^m - (-1)^m)/3 is the Jacobsthal sequence;
a(A039004(n)) = (2/3)*A039004(n);
a(2*A039004(n)) = 2*a(A039004(n));
a(A003159(n)) = n;
a(A003159(n)-1) = n-1;
a(n) mod 2 = A010060(n) the Thue-Morse sequence;
a(n+1) - a(n) = A035263(n+1);
a(n+2) - a(n) = abs(A029884(n)).
(End)
G.f.: (1/(x-1)) * Sum_{i>=0} (-1)^i*x^(2^i)/(x^(2^i)-1). - Antonio G. Astudillo (afg_astudillo(AT)hotmail.com), Feb 17 2003
a(n) = Sum_{k>=0} (-1)^k*floor(n/2^k). - Benoit Cloitre, Jun 03 2003
a(A091785(n)) = 2n; a(A091855(n)) = 2n-1. - Philippe Deléham, Mar 26 2004
a(2^n) = (2^(n+1) + (-1)^n)/3. - Vladimir Shevelev, Apr 15 2010
If n = Sum_{i>=0} b_i*2^i is the binary expansion of n, then a(n) = 2n/3 + (1/3)Sum_{i>=0} b_i*(-1)^i. Thus a(n) = 2n/3 + O(log(n)). - Vladimir Shevelev, Apr 15 2010
Moreover, the equation a(3m)=2m has infinitely many solutions, e.g., a(3*2^k)=2*2^k; on the other hand, a((4^k-1)/3)=(2*(4^k-1))/9+k/3, i.e., limsup |a(n)-2n/3| = infinity. - Vladimir Shevelev, Feb 23 2011
a(n) = Sum_{k>=0} A030308(n,k)*A001045(k+1). - Philippe Deléham, Oct 19 2011
From Peter Bala, Feb 02 2013: (Start)
Product_{n >= 1} (1 + x^((2^n - (-1)^n)/3 )) = (1 + x)^2(1 + x^3)(1 + x^5)(1 + x^11)(1 + x^21)... = 1 + sum {n >= 1} x^a(n) = 1 + 2x + x^2 + x^3 + 2x^4 + 2x^5 + .... Hence this sequence lists the numbers representable as a sum of distinct Jacobsthal numbers A001045 = [1, 1', 3, 5, 11, 21, ...], where we distinguish between the two occurrences of 1 by writing them as 1 and 1'. For example, 9 occurs twice in the present sequence because 9 = 5 + 3 + 1 and 9 = 5 + 3 + 1'. Cf. A197911 and A080277. See also A120385.
(End)

Extensions

Extended with formula by Christian G. Bower, Sep 15 1999
Corrected and extended by Reinhard Zumkeller, Aug 16 2006
Extended with formula by Philippe Deléham, Oct 19 2011
Entry revised to give a simpler definition by N. J. A. Sloane, Jan 03 2014

A003158 A self-generating sequence (see Comments in A003156 for the definition).

Original entry on oeis.org

2, 7, 10, 13, 18, 23, 28, 31, 34, 39, 42, 45, 50, 53, 56, 61, 66, 71, 74, 77, 82, 87, 92, 95, 98, 103, 108, 113, 116, 119, 124, 127, 130, 135, 138, 141, 146, 151, 156, 159
Offset: 1

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Author

Keywords

Comments

Numbers not of the form Sum_{i>=2} e_i*A001045(i), with e(i) = 0 or 1.
Indices of b in the sequence closed under a -> abc, b -> a, c -> a, starting with a(1) = a; see A092606 where a = 0, b = 2, c = 1. - Philippe Deléham, Apr 12 2004

References

  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Crossrefs

Programs

  • Python
    def A003158(n):
        def bisection(f,kmin=0,kmax=1):
            while f(kmax) > kmax: kmax <<= 1
            kmin = kmax >> 1
            while kmax-kmin > 1:
                kmid = kmax+kmin>>1
                if f(kmid) <= kmid:
                    kmax = kmid
                else:
                    kmin = kmid
            return kmax
        def f(x):
            c, s = n+x, bin(x)[2:]
            l = len(s)
            for i in range(l&1,l,2):
                c -= int(s[i])+int('0'+s[:i],2)
            return c
        return bisection(f,n,n)+n-1 # Chai Wah Wu, Jan 29 2025

Formula

a(n) = A003157(n) - 1 = A079523(n) + n. - Philippe Deléham, Feb 22 2004

Extensions

Definition clarified by N. J. A. Sloane, Dec 26 2020

A003156 A self-generating sequence (see Comments for definition).

Original entry on oeis.org

1, 4, 5, 6, 9, 12, 15, 16, 17, 20, 21, 22, 25, 26, 27, 30, 33, 36, 37, 38, 41, 44, 47, 48, 49, 52, 55, 58, 59, 60, 63, 64, 65, 68, 69, 70, 73, 76, 79, 80, 81, 84, 85, 86, 89, 90, 91, 94, 97, 100, 101, 102, 105, 106, 107, 110, 111, 112, 115, 118, 121, 122, 123, 126, 129, 132
Offset: 1

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Author

Keywords

Comments

From N. J. A. Sloane, Dec 26 2020: (Start)
The best definitions of the triple [this sequence, A003157, A003158] are as the rows a(n), b(n), c(n) of the table:
n: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, ...
a: 1, 4, 5, 6, 9, 12, 15, 16, 17, 20, 21, 22, ...
b: 3, 8, 11, 14, 19, 24, 29, 32, 35, 40, 43, 46, ...
c: 2, 7, 10, 13, 18, 23, 28, 31, 34, 39, 42, 45, ...
where a(1)=1, b(1)=3, c(1)=2, and thereafter
a(n) = mex{a(i), b(i), c(i), i
b(n) = a(n) + 2*n,
c(n) = b(n) - 1.
Then a,b,c form a partition of the positive integers.
Note that there is another triple of sequences (A003144, A003145, A003146) also called a, b, c and also a partition of the positive integers, in a different paper by the same authors (Carlitz-Scovelle-Hoggatt) in the same volume of the same journal.
(End)
a(n) is the number of ones before the n-th zero in the Feigenbaum sequence A035263. - Philippe Deléham, Mar 27 2004
Number of odd numbers before the n-th even number in A007413, A007913, A001511, A029883, A033485, A035263, A036585, A065882, A065883, A088172, A092412. - Philippe Deléham, Apr 03 2004
Indices of a in the sequence closed under a -> abc, b -> a, c -> a, starting with a(1) = a; see A092606 where a = 0, b = 2, c = 1. - Philippe Deléham, Apr 12 2004

References

  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Programs

  • Haskell
    following Deléham
    a003156 n = a003156_list !! (n-1)
    a003156_list = scanl1 (+) a080426_list
    -- Reinhard Zumkeller, Oct 27 2014
    
  • Maple
    a:= proc(n) global l; while nops(l) [1, 3$d, 1][], l) od; `if` (n=1, 1, a(n-1) +l[n]) end: l:= [1]: seq (a(n), n=1..80); # Alois P. Heinz, Oct 31 2009
  • Mathematica
    Position[Nest[Flatten[# /. {0 -> {0, 2, 1}, 1 -> {0}, 2 -> {0}}]&, {0}, 7], 0] // Flatten (* Jean-François Alcover, Mar 14 2014 *)
  • Python
    def A003156(n):
        def bisection(f,kmin=0,kmax=1):
            while f(kmax) > kmax: kmax <<= 1
            kmin = kmax >> 1
            while kmax-kmin > 1:
                kmid = kmax+kmin>>1
                if f(kmid) <= kmid:
                    kmax = kmid
                else:
                    kmin = kmid
            return kmax
        def f(x):
            c, s = n+x, bin(x)[2:]
            l = len(s)
            for i in range(l&1,l,2):
                c -= int(s[i])+int('0'+s[:i],2)
            return c
        return bisection(f,n,n)-n # Chai Wah Wu, Jan 29 2025

Formula

a(n) = A079523(n) - n + 1 = A003157(n) - 2n = A003158(n) - 2n + 1. - Philippe Deléham, Feb 28 2004
a(n) = A036554(n) - n = A072939(n) - n - 1 = 2*A003159(n) - n. - Philippe Deléham, Apr 10 2004
a(n) = Sum_{k = 1..n} A080426(k). - Philippe Deléham, Apr 16 2004

Extensions

More terms from Alois P. Heinz, Oct 31 2009
Incorrect equation removed from formula by Peter Munn, Dec 11 2020

A003157 A self-generating sequence (see Comments in A003156 for the definition).

Original entry on oeis.org

3, 8, 11, 14, 19, 24, 29, 32, 35, 40, 43, 46, 51, 54, 57, 62, 67, 72, 75, 78, 83, 88, 93, 96, 99, 104, 109, 114, 117, 120, 125, 128, 131, 136, 139, 142, 147, 152, 157, 160
Offset: 1

Keywords

Comments

Indices of c in the sequence closed under a -> abc, b -> a, c -> a, starting with a(1) = a; see A092606 where a = 0, b = 2, c = 1. - Philippe Deléham, Apr 12 2004
These are the positions of 1 in A286044; complement of A286045; conjecture: a(n)/n -> 4. - Clark Kimberling, May 07 2017

Examples

			As a word, A286044 = 001000010010010000100..., in which 1 is in positions a(n) for n>=1.  - _Clark Kimberling_, May 07 2017
		

References

  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Crossrefs

Programs

  • Mathematica
    s = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {1, 0}}] &, {0}, 9] (* Thue-Morse, A010060 *)
    w = StringJoin[Map[ToString, s]]
    w1 = StringReplace[w, {"011" -> "0"}]
    st = ToCharacterCode[w1] - 48 (* A286044 *)
    Flatten[Position[st, 0]]  (* A286045 *)
    Flatten[Position[st, 1]]  (* A003157 *)
    (* Clark Kimberling, May 07 2017 *)
  • Python
    def A003157(n):
        def bisection(f,kmin=0,kmax=1):
            while f(kmax) > kmax: kmax <<= 1
            kmin = kmax >> 1
            while kmax-kmin > 1:
                kmid = kmax+kmin>>1
                if f(kmid) <= kmid:
                    kmax = kmid
                else:
                    kmin = kmid
            return kmax
        def f(x):
            c, s = n+x, bin(x)[2:]
            l = len(s)
            for i in range(l&1,l,2):
                c -= int(s[i])+int('0'+s[:i],2)
            return c
        return bisection(f,n,n)+n # Chai Wah Wu, Jan 29 2025

Formula

Numbers n such that A003159(n) is even. a(n) = A003158(n) + 1 = A036554(n) + n. - Philippe Deléham, Feb 22 2004

A339584 A ternary sequence: a(n) = 1 if n is in A003156, 2 if n is in A003157, 3 if n is in A003158.

Original entry on oeis.org

1, 3, 2, 1, 1, 1, 3, 2, 1, 3, 2, 1, 3, 2, 1, 1, 1, 3, 2, 1, 1, 1, 3, 2, 1, 1, 1, 3, 2, 1, 3, 2, 1, 3, 2, 1, 1, 1, 3, 2, 1, 3, 2, 1, 3, 2, 1, 1, 1, 3, 2, 1, 3, 2, 1, 3, 2, 1, 1, 1, 3, 2, 1, 1, 1, 3, 2, 1, 1, 1, 3, 2, 1, 3, 2, 1, 3, 2, 1, 1, 1, 3, 2, 1, 1, 1, 3, 2, 1, 1, 1, 3, 2, 1
Offset: 1

Author

N. J. A. Sloane, Dec 26 2020

Keywords

Comments

This has the same relationship to A003156-A003158 as A092782 does to A003144-A003146.

Programs

  • Mathematica
    Nest[Flatten[# /. {1 -> {1, 3, 2}, 2 -> 1, 3 -> 1}] &, {1}, 8] (* John Keith, Dec 28 2020 after Robert G. Wilson v's program for A092782. *)

Formula

a(n) = A092606(n) + 1. - John Keith, Dec 28 2020
Showing 1-5 of 5 results.