cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A060295 Decimal expansion of exp(Pi*sqrt(163)).

Original entry on oeis.org

2, 6, 2, 5, 3, 7, 4, 1, 2, 6, 4, 0, 7, 6, 8, 7, 4, 3, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 2, 5, 0, 0, 7, 2, 5, 9, 7, 1, 9, 8, 1, 8, 5, 6, 8, 8, 8, 7, 9, 3, 5, 3, 8, 5, 6, 3, 3, 7, 3, 3, 6, 9, 9, 0, 8, 6, 2, 7, 0, 7, 5, 3, 7, 4, 1, 0, 3, 7, 8, 2, 1, 0, 6, 4, 7, 9, 1, 0, 1, 1, 8, 6, 0, 7, 3, 1, 2, 9, 5, 1, 1, 8, 1
Offset: 18

Views

Author

Jason Earls, Mar 24 2001

Keywords

Comments

From Alexander R. Povolotsky, Jun 23 2009, Apr 04 2012: (Start)
One could observe that the last four of Class Number 1 expressions in T. Piezas "Ramanujan Pages" could be expressed as the following approximation:
exp(Pi*sqrt(19+24*n)) =~ (24*k)^3 + 31*24
which gives 4 (four) "almost integer" solutions:
1) n = 0, 19+24*0 = 19, k = 4;
2) n = 1, 19+24*1 = 43, k = 40;
3) n = 2, 19+24*2 = 67, k = 220;
4) n = 6, 19+24*6 = 163, k = 26680; this of course is the case for Ramanujan constant vs. its integer counterpart approximation. (End)
From Alexander R. Povolotsky, Oct 16 2010, Apr 04 2012: (Start)
Also if one expands the left part above to exp(Pi*sqrt(b(n))) where b(n) = {19, 25, 43, 58, 67, 163, 232, ...} then the expression (exp(Pi*sqrt(b(n))))/m (where m is either integer 1 or 8) yields values being very close to whole integer value:
Note, that the first differences of b(n) are all divisible by 3, giving after the division: {2, 6, 5, 3, 32, 33, ...}. (End)
From Amiram Eldar, Jun 24 2021: (Start)
This constant was discovered by Hermite (1859).
It is sometimes called "Ramanujan's constant" due to an April Fool's joke by Gardner (1975) in which he claimed that Ramanujan conjectured that this constant is an integer, and that a fictitious "John Brillo" of the University of Arizona proved it on May 1974.
In fact, Ramanujan studied similar near-integers of the form exp(Pi*sqrt(k)) (e.g., A169624), but not this constant.
Gauld (1984) discovered that (Pi*sqrt(163))^e = 22806.9992... is also a near-integer. (End)

Examples

			The Ramanujan number = 262537412640768743.99999999999925007259719818568887935...
		

References

  • John H. Conway and Richard K. Guy, The Book of Numbers, New York: Springer-Verlag, 1996. See pp. 225-226.
  • C. Stanley Ogilvy and John T. Anderson, Excursions in Number Theory, Oxford University Press, NY, 1966, p. 106.
  • Harold M. Stark, An Introduction to Number Theory, Markham, Chicago, 1970, p. 179.
  • Dimitris Vathis, Letter to N. J. A. Sloane, Apr 22 1985.
  • David Wells, The Penguin Dictionary of Curious and Interesting Numbers. Penguin Books, NY, 1986, Revised edition 1987. See p. 142.

Crossrefs

Programs

  • Magma
    R:= RealField(); Exp(Pi(R)*Sqrt(163)); // G. C. Greubel, Feb 15 2018
  • Mathematica
    RealDigits[N[E^(Pi*Sqrt[163]), 110]][[1]]
  • PARI
    default(realprecision, 20080); x=exp(Pi*sqrt(163))/10^17; for (n=18, 20000, d=floor(x); x=(x-d)*10; write("b060295.txt", n, " ", d)); \\ Harry J. Smith, Jul 03 2009
    

Formula

exp(Pi*sqrt(163)) = A199743(6)^3 + 744 - 7.4992... * 10^-13. - Charles R Greathouse IV, Jul 15 2020

A212131 Decimal expansion of k such that e^(k*sqrt(163)) = round(e^(Pi*sqrt(163))).

Original entry on oeis.org

3, 1, 4, 1, 5, 9, 2, 6, 5, 3, 5, 8, 9, 7, 9, 3, 2, 3, 8, 4, 6, 2, 6, 4, 3, 3, 8, 3, 2, 7, 9, 7, 2, 6, 6, 1, 9, 3, 4, 7, 5, 4, 9, 8, 8, 0, 8, 8, 3, 5, 2, 2, 4, 2, 2, 2, 9, 2, 9, 6, 2, 8, 7, 7, 4, 4, 2, 2, 5, 8, 7, 3, 9, 0, 5, 1, 0, 4, 9, 3, 7, 8, 7, 5, 5, 1, 0, 7, 4, 4, 5, 7, 7, 6, 7, 2, 0, 2, 4, 1, 5, 7, 9, 6, 7
Offset: 1

Views

Author

Omar E. Pol, Jun 25 2012

Keywords

Comments

Decimal expansion of log(262537412640768744)/sqrt(163).
First differs from A000796 at a(32).
Note that 262537412640768744 = 24*10939058860032031 = 2^3 * 3 * 10939058860032031, is the nearest integer to the value of Ramanujan's constant e^(Pi*sqrt(163)) = 262537412640768743.999999999999250... = A060295.

Examples

			3.14159265358979323846264338327972661934754988... (very close to Pi).
		

Crossrefs

Programs

  • Mathematica
    RealDigits[Log[Round[E^(Pi Sqrt[163])]]/Sqrt[163], 10, 105][[1]] (* Bruno Berselli, Jun 26 2012 *)

Formula

k = log(round(e^(Pi*sqrt(163))))/sqrt(163).

Extensions

More terms from Alois P. Heinz, Jun 25 2012

A210963 Decimal expansion of sqrt(163).

Original entry on oeis.org

1, 2, 7, 6, 7, 1, 4, 5, 3, 3, 4, 8, 0, 3, 7, 0, 4, 6, 6, 1, 7, 1, 0, 9, 5, 2, 0, 0, 9, 7, 8, 0, 8, 9, 2, 3, 4, 7, 3, 8, 2, 3, 6, 3, 7, 8, 0, 3, 0, 1, 2, 5, 8, 8, 5, 1, 2, 1, 2, 6, 0, 2, 9, 8, 3, 8, 4, 8, 7, 2, 6, 1, 7, 2, 8, 9, 0, 2, 3, 9, 2, 5, 9, 5, 5, 9, 4, 2, 3, 4, 8, 3, 8, 6, 7, 5, 3, 1, 8, 7, 2, 4, 2, 2, 8
Offset: 2

Views

Author

Omar E. Pol, Jun 26 2012

Keywords

Comments

Also decimal expansion of log(R_c)/Pi, where R_c is Ramanujan's constant: 262537412640768743.999999999999250... = A060295.

Examples

			163^(1/2) = 12.76714533480370466171095200978...
		

Crossrefs

Programs

  • Mathematica
    RealDigits[Sqrt[163], 10, 105][[1]] (* T. D. Noe, Jun 27 2012 *)
  • PARI
    sqrt(163) \\ Michel Marcus, Mar 26 2017

A210965 Decimal expansion of k such that e^(Pi*k) = round(e^(Pi*sqrt(163))).

Original entry on oeis.org

1, 2, 7, 6, 7, 1, 4, 5, 3, 3, 4, 8, 0, 3, 7, 0, 4, 6, 6, 1, 7, 1, 0, 9, 5, 2, 0, 0, 9, 7, 8, 1, 8, 0, 1, 5, 8, 6, 5, 7, 9, 2, 8, 7, 6, 0, 4, 6, 1, 5, 9, 5, 5, 2, 0, 0, 7, 4, 9, 7, 6, 0, 0, 8, 4, 7, 4, 0, 0, 6, 2, 4, 9, 2, 6, 1, 2, 2, 8, 5, 1, 6, 7, 1, 4, 1, 3, 8, 9, 1
Offset: 2

Views

Author

Omar E. Pol, Jun 26 2012

Keywords

Comments

Decimal expansion of k = log(262537412640768744)/Pi.
Note that 262537412640768744 = 24*10939058860032031 = 2^3 * 3 * 10939058860032031, is the nearest integer to the value of Ramanujan's constant e^(Pi*sqrt(163)) = A060295.
By construction, this constant here is very close to sqrt(163) = A210963.

Examples

			12.767145334803704661710952...
		

Crossrefs

Programs

  • Mathematica
    RealDigits[Log[262537412640768744]/Pi,10,120][[1]] (* Harvey P. Dale, Nov 12 2017 *)

Formula

Equals log(round(e^(Pi*sqrt(163))))/Pi.
Showing 1-4 of 4 results.