cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A127963 Number of 1's in A127962(n).

Original entry on oeis.org

2, 3, 4, 6, 7, 9, 10, 12, 16, 22, 31, 40, 51, 64, 84, 96, 100, 157, 174, 351, 855, 1309, 1770, 2904, 5251, 5346, 5640, 6196, 7240, 21369, 41670, 47685, 58620, 63516, 69469, 70540, 133509, 134994, 187161, 493096, 2015700
Offset: 1

Views

Author

Artur Jasinski, Feb 09 2007

Keywords

Crossrefs

Programs

  • Mathematica
    b = {}; Do[c = 1 + Sum[2^(2n - 1), {n, 1, x}]; If[PrimeQ[c], AppendTo[b, c]], {x, 0, 1000}]; a = {}; Do[AppendTo[a, FromDigits[IntegerDigits[b[[x]], 2]]], {x, 1, Length[b]}]; d = {}; Do[AppendTo[d, DigitCount[a[[x]], 10, 1]], {x, 1, Length[a]}]; d (* Artur Jasinski, Feb 09 2007 *)
    DigitCount[#, 2, 1]& /@ Select[Table[(2^p + 1)/3, {p, Prime[Range[300]]}], PrimeQ] (* Amiram Eldar, Jul 23 2023 *)

Formula

a(n) = A000120(A000979(n)). - Michel Marcus, Nov 07 2013
a(n) = A007953(A127962(n)). - Amiram Eldar, Jul 23 2023

Extensions

a(22)-a(29) from Vincenzo Librandi, Mar 31 2012
a(30)-a(41) from Amiram Eldar, Jul 23 2023

A127964 Number of 0's in the binary expansion of A127962(n).

Original entry on oeis.org

0, 1, 2, 4, 5, 7, 8, 10, 14, 20, 29, 38, 49, 62, 82, 94, 98, 155, 172, 349, 853, 1307, 1768, 2902, 5249, 5344, 5638, 6194, 7238, 21367, 41668, 47683, 58618, 63514, 69467, 70538, 133507, 134992, 187159, 493094, 2015698
Offset: 1

Views

Author

Artur Jasinski, Feb 09 2007

Keywords

Comments

Apparently numbers k such that (2^(2*k+3)+1)/3 is prime. - James R. Buddenhagen, Apr 14 2011 [This is true. See the second formula. - Amiram Eldar, Oct 13 2024]

Crossrefs

Programs

  • Mathematica
    b = {}; Do[c = 1 + Sum[2^(2n - 1), {n, 1, x}]; If[PrimeQ[c], AppendTo[b, c]], {x, 0, 1000}]; a = {}; Do[AppendTo[a, FromDigits[IntegerDigits[b[[x]], 2]]], {x, 1, Length[b]}]; d = {}; Do[AppendTo[d, DigitCount[a[[x]], 10, 0]], {x, 1, Length[a]}]; d
    (Select[Prime[Range[200]], PrimeQ[(2^# + 1)/3] &] - 3)/2 (* Amiram Eldar, Oct 13 2024 *)

Formula

a(n) = A023416(A000979(n)). - Michel Marcus, Nov 07 2013
a(n) = (A000978(n)-3)/2. - Amiram Eldar, Oct 13 2024

Extensions

a(22)-a(29) from Vincenzo Librandi, Mar 31 2012
a(30)-a(41) from Amiram Eldar, Oct 13 2024

A127965 Number of bits in A127962(n).

Original entry on oeis.org

2, 4, 6, 10, 12, 16, 18, 22, 30, 42, 60, 78, 100, 126, 166, 190, 198, 312, 346, 700, 1708, 2616, 3538, 5806, 10500, 10690, 11278, 12390, 14478, 42736, 83338, 95368, 117238, 127030, 138936, 141078, 267016, 269986, 374320, 986190, 4031398
Offset: 1

Views

Author

Artur Jasinski, Feb 09 2007

Keywords

Crossrefs

Programs

  • Mathematica
    b = {}; Do[c = 1 + Sum[2^(2n - 1), {n, 1, x}]; If[PrimeQ[c], AppendTo[b, c]], {x, 0, 1000}]; a = {}; Do[AppendTo[a, FromDigits[IntegerDigits[b[[x]], 2]]], {x, 1, Length[b]}]; d = {}; Do[AppendTo[d, DigitCount[a[[x]], 10, 0]+DigitCount[a[[x]], 10, 1]], {x, 1, Length[a]}]; d

Formula

a(n) = A127964(n) + A127963(n).
a(n) = 1 + floor(log_2(A000979(n))) = 1 + floor(log_2(2^A000978(n)+1) - A020857) = A000978(n) - 1. - R. J. Mathar, Feb 01 2008

Extensions

a(22)-a(29) from Vincenzo Librandi, Mar 30 2012
a(30)-a(41) from Amiram Eldar, Oct 19 2024

A194810 Indices k such that A139250(k) = A000979(n).

Original entry on oeis.org

2, 4, 8, 32, 64, 256, 512, 2048, 32768, 2097152, 1073741824, 549755813888, 1125899906842624, 9223372036854775808, 9671406556917033397649408, 39614081257132168796771975168, 633825300114114700748351602688
Offset: 1

Views

Author

Omar E. Pol, Oct 23 2011

Keywords

Comments

Indices k such that the number of toothpicks in the toothpick structure of A139250 after k-th stage equals the n-th Wagstaff prime A000979. All terms of this sequence are powers of 2 (see formulas).
For a picture of the n-th Wagstaff prime as a toothpick structure see the Applegate link "A139250: the movie version", then enter N = a(n) and click "Update", for N = a(n) <= 32768 (due to the resolution of the movie).

Examples

			For n = 5 we have that a(5) = 64, then we can see that the number of toothpicks in the toothpick structure of A139250 after 64 stages is 2731 which coincides with the fifth Wagstaff prime, so we can write A139250(64) = A000979(5) = 2731. See the illustration in the Applegate-Pol-Sloane paper, figure 3: T(64) = 2731 toothpicks.
		

Crossrefs

Programs

  • Mathematica
    2^Reap[Do[If[PrimeQ[1+Sum[2^(2n-1), {n, m}]], Sow[m]], {m, 100}]][[2, 1]] (* Jean-François Alcover, Oct 06 2018 *)

Formula

a(n) = 2^A127936(n) = 2^(floor(A000978(n)/2)) = 2^(ceiling(log_4(A000979(n)))).
A139250(2^n) = A007583(n), n >= 0.
A139250(a(n)) = A000979(n).

Extensions

More terms from Omar E. Pol, Mar 14 2012

A235683 Numbers n such that (46^n + 1)/47 is prime.

Original entry on oeis.org

7, 23, 59, 71, 107, 223, 331, 2207, 6841, 94841
Offset: 1

Views

Author

Robert Price, Jan 13 2014

Keywords

Comments

All terms up to a(10) are primes.
a(11) > 10^5.

Crossrefs

Programs

  • Mathematica
    Do[ p=Prime[n]; If[ PrimeQ[ (46^p + 1)/47 ], Print[p] ], {n, 1, 9592} ]
  • PARI
    is(n)=ispseudoprime((46^n+1)/47) \\ Charles R Greathouse IV, May 22 2017

A237052 Numbers n such that (49^n + 1)/50 is prime.

Original entry on oeis.org

7, 19, 37, 83, 1481, 12527, 20149
Offset: 1

Views

Author

Robert Price, Feb 02 2014

Keywords

Comments

All terms are primes.
a(8) > 10^5.

Crossrefs

Programs

  • Mathematica
    Do[ p=Prime[n]; If[ PrimeQ[ (49^p + 1)/50 ], Print[p] ], {n, 1, 9592} ]
  • PARI
    is(n)=ispseudoprime((49^n+1)/50) \\ Charles R Greathouse IV, Jun 13 2017

Extensions

Typo in description corrected by Ray Chandler, Feb 20 2017

A247244 Smallest prime p such that (n^p + (n+1)^p)/(2n+1) is prime, or -1 if no such p exists.

Original entry on oeis.org

3, 3, 3, 5, 3, 3, 7, 3, 7, 53, 47, 3, 7, 3, 3, 41, 3, 5, 11, 3, 3, 11, 11, 3, 5, 103, 3, 37, 17, 7, 13, 37, 3, 269, 17, 5, 17, 3, 5, 139, 3, 11, 78697, 5, 17, 3671, 13, 491, 5, 3, 31, 43, 7, 3, 7, 2633, 3, 7, 3, 5, 349, 3, 41, 31, 5, 3, 7, 127, 3, 19, 3, 11, 19, 101, 3, 5, 3, 3
Offset: 1

Views

Author

Eric Chen, Nov 28 2014

Keywords

Comments

All terms are odd primes.
a(79) > 10000, if it exists.
a(80)..a(93) = {3, 7, 13, 7, 19, 31, 13, 163, 797, 3, 3, 11, 13, 5}, a(95)..a(112) = {5, 2657, 19, 787, 3, 17, 3, 7, 11, 1009, 3, 61, 53, 2371, 5, 3, 3, 11}, a(114)..a(126) = {103, 461, 7, 3, 13, 3, 7, 5, 31, 41, 23, 41, 587}, a(128)..a(132) = {7, 13, 37, 3, 23}, a(n) is currently unknown for n = {79, 94, 113, 127, 133, ...} (see the status file under Links).

Examples

			a(10) = 53 because (10^p + 11^p)/21 is composite for all p < 53 and prime for p = 53.
		

Crossrefs

Programs

  • Mathematica
    lmt = 4200; f[n_] := Block[{p = 2}, While[p < lmt && !PrimeQ[((n + 1)^p + n^p)/(2n + 1)], p = NextPrime@ p]; If[p > lmt, 0, p]]; Do[Print[{n, f[n] // Timing}], {n, 1000}] (* Robert G. Wilson v, Dec 01 2014 *)
  • PARI
    a(n)=forprime(p=3, , if(ispseudoprime((n^p+(n+1)^p)/(2*n+1)), return(p)))

Formula

a(n) = 3 if and only if n^2 + n + 1 is a prime (A002384).

Extensions

a(43) from Aurelien Gibier, Nov 27 2023

A283657 Numbers m such that 2^m + 1 has at most 2 distinct prime factors.

Original entry on oeis.org

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 16, 17, 19, 20, 23, 28, 31, 32, 40, 43, 61, 64, 79, 92, 101, 104, 127, 128, 148, 167, 191, 199, 256, 313, 347, 356, 596, 692, 701, 1004, 1228, 1268, 1709, 2617, 3539, 3824, 5807, 10501, 10691, 11279, 12391, 14479
Offset: 1

Views

Author

Vladimir Shevelev, Mar 13 2017

Keywords

Comments

Using comment in A283364, note that if a(n) is odd > 9, then it is prime.
503 <= a(41) <= 596. - Robert Israel, Mar 13 2017
Could (4^p + 1)/5^t be prime, where p is prime, 5^t is the highest power of 5 dividing 4^p + 1, other than for p=2, 3 and 5? - Vladimir Shevelev, Mar 14 2017
In his message to seqfans from Mar 15 2017, Jack Brennen beautifully proved that there are no more primes of such form. From his proof one can see also that there are no terms of the form 2*p > 10 in the sequence. - Vladimir Shevelev, Mar 15 2017
Where A046799(n)=2. - Robert G. Wilson v, Mar 15 2017
From Giuseppe Coppoletta, May 16 2017: (Start)
The only terms that are not in A066263 are those m giving 2^m + 1 = prime (i.e. m = 0 and any number m such that 2^m + 1 is a Fermat prime) and the values of m giving 2^m + 1 = power of a prime, giving m = 3 as the only possible case (by Mihăilescu-Catalan's result, see links).
For the relation with Fermat numbers and for other possible terms to check, see comments in A073936 and A066263.
All terms after a(59) refer to probabilistic primality tests for 2^a(n) + 1 (see Caldwell's link for the list of the largest certified Wagstaff primes).
After a(65), the values 267017, 269987, 374321, 986191, 4031399 and 4101572 are also terms, but there still remains the remote possibility of some gaps in between. In addition, 13347311 and 13372531 are also terms, but possibly much further along in the numbering (see comments in A000978).
(End).

Examples

			0 is a term as 2^0 + 1 = 2 is a prime.
10 is a term as 2^10 + 1 = 5^2 * 41.
14 is not a term as 2^14 + 1 = 5 * 29 * 113.
		

Crossrefs

Programs

  • Maple
    # this uses A002587[i] for i<=500, e.g., from the b-file for that sequence
    count:= 0:
    for i from 0 to 500 do
      m:= 0;
      r:= (2^i+1);
      if i::odd then
        m:= 1;
        r:= r/3^padic:-ordp(r,3);
      elif i > 2 then
        q:= max(numtheory:-factorset(i));
        if q > 2 then
          m:= 1;
          r:= r/B[i/q]^padic:-ordp(r,A002587[i/q]);
        fi
      fi;
      if r mod B[i] = 0 then m:= m+1;
          j:= padic:-ordp(r, A002587[i]);
          r:= r/B[i]^j;
      fi;
      mmax:= m;
      if isprime(r) then m:= m+1; mmax:= m
      elif r > 1 then mmax:= m+2
      fi;
      if mmax <= 2 or (m <= 1 and m + nops(numtheory:-factorset(r)) <= 2) then
           count:= count+1;
         A[count]:= i;
      fi
    od:
    seq(A[i],i=1..count); # Robert Israel, Mar 13 2017
  • Mathematica
    Select[Range[0, 313], PrimeNu[2^# + 1]<3 &] (* Indranil Ghosh, Mar 13 2017 *)
  • PARI
    for(n=0, 313, if(omega(2^n + 1)<3, print1(n,", "))) \\ Indranil Ghosh, Mar 13 2017

Extensions

a(16)-a(38) from Peter J. C. Moses, Mar 13 2017
a(39)-a(40) from Robert Israel, Mar 13 2017
a(41)-a(65) from Giuseppe Coppoletta, May 08 2017

A309533 Numbers k such that (144^k + 1)/145 is prime.

Original entry on oeis.org

23, 41, 317, 3371, 45259, 119671
Offset: 1

Views

Author

Paul Bourdelais, Aug 06 2019

Keywords

Comments

The corresponding primes are terms of A059055. - Bernard Schott, Aug 09 2019

Crossrefs

Programs

  • Mathematica
    Do[p=Prime[n]; If[PrimeQ[(144^p + 1)/145], Print[p]], {n, 1, 1000000}]
  • PARI
    is(n)=ispseudoprime((144^n+1)/145)

A033289 Odd power perfect numbers: numbers k such that opsigma(k) = 2*k, where opsigma(k) = A033634(k).

Original entry on oeis.org

6, 264, 45408, 10177920, 9310826880, 27806077440, 25437179036160, 303753589954560, 277875743791011840, 14504815632384, 13269098919960576, 2534919599177957376, 2318960803647990104064
Offset: 1

Views

Author

Keywords

Comments

If x is OPP and x=2^k*y, gcd(2^k,y)=1, (2^(k+4)+1)/3 is prime, then 4*x*(2^(k+4)+1)/3 is also OPP.
By applying the rule above to a(12) we get that 1772040615644549459607552 is also a term. - Amiram Eldar, Aug 26 2022

Crossrefs

Programs

  • Mathematica
    f[e_] := If[OddQ[e], e+2, e+1]; fun[p_, e_] := 1 + (p^f[e] - p)/(p^2 - 1); opsigma[1] = 1; opsigma[n_] := Times @@ fun @@@ FactorInteger[n]; Select[Range[50000], opsigma[#] == 2*# &] (* Amiram Eldar, Aug 26 2022 *)

Formula

{k: A033634(k) = 2*k}.
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