A030588 Write odd numbers in base 6 and juxtapose.
1, 3, 5, 1, 1, 1, 3, 1, 5, 2, 1, 2, 3, 2, 5, 3, 1, 3, 3, 3, 5, 4, 1, 4, 3, 4, 5, 5, 1, 5, 3, 5, 5, 1, 0, 1, 1, 0, 3, 1, 0, 5, 1, 1, 1, 1, 1, 3, 1, 1, 5, 1, 2, 1, 1, 2, 3, 1, 2, 5, 1, 3, 1, 1, 3, 3, 1, 3, 5, 1, 4, 1, 1, 4, 3, 1, 4, 5, 1, 5, 1, 1, 5, 3, 1, 5, 5, 2, 0, 1
Offset: 1
Examples
From _Antti Karttunen_, Dec 26 2018: (Start) The first twelve odd numbers and their base-6 representations (A007092) are: 1 1 3 3 5 5 7 11 9 13 11 15 13 21 15 23 17 25 19 31 21 33 23 35 thus the sequence begins with terms 1, 3, 5, 1, 1, 1, 3, 1, 5, 2, 1, 2, 3, 2, 5, 3, 1, 3, 3, 3, 5. (End)
Links
- Antti Karttunen, Table of n, a(n) for n = 1..100000
Crossrefs
Programs
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Mathematica
Flatten[Table[IntegerDigits[2n - 1, 6], {n, 50}]] (* Harvey P. Dale, Jul 22 2012 *)
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PARI
up_to = 100000; A030588list(up_to) = { my(v=vector(up_to),ds=List([]),o=1,j=1); for(i=1,up_to,if(j>#ds,ds=digits(o,6);j=1;o+=2); v[i] = ds[j]; j++); (v); }; v030588 = A030588list(up_to); A030588(n) = v030588[n]; \\ Antti Karttunen, Dec 24 2018
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Scala
(1 to 99 by 2).map(Integer.toString(, 6).toCharArray).flatten // _Alonso del Arte, Apr 02 2020
Comments