cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A035317 Pascal-like triangle associated with A000670.

Original entry on oeis.org

1, 1, 1, 1, 2, 2, 1, 3, 4, 2, 1, 4, 7, 6, 3, 1, 5, 11, 13, 9, 3, 1, 6, 16, 24, 22, 12, 4, 1, 7, 22, 40, 46, 34, 16, 4, 1, 8, 29, 62, 86, 80, 50, 20, 5, 1, 9, 37, 91, 148, 166, 130, 70, 25, 5, 1, 10, 46, 128, 239, 314, 296, 200, 95, 30, 6, 1, 11, 56, 174, 367, 553, 610, 496, 295, 125
Offset: 0

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Author

Keywords

Comments

From Johannes W. Meijer, Jul 20 2011: (Start)
The triangle sums, see A180662 for their definitions, link this "Races with Ties" triangle with several sequences, see the crossrefs. Observe that the Kn4 sums lead to the golden rectangle numbers A001654 and that the Fi1 and Fi2 sums lead to the Jacobsthal sequence A001045.
The series expansion of G(x, y) = 1/((y*x-1)*(y*x+1)*((y+1)*x-1)) as function of x leads to this sequence, see the second Maple program. (End)
T(2n,k) = the number of hatted frog arrangements with k frogs on the 2xn grid. See the linked paper "Frogs, hats and common subsequences". - Chris Cox, Apr 12 2024

Examples

			Triangle begins:
  1;
  1,  1;
  1,  2,  2;
  1,  3,  4,   2;
  1,  4,  7,   6,   3;
  1,  5, 11,  13,   9,   3;
  1,  6, 16,  24,  22,  12,   4;
  1,  7, 22,  40,  46,  34,  16,   4;
  1,  8, 29,  62,  86,  80,  50,  20,  5;
  1,  9, 37,  91, 148, 166, 130,  70, 25,  5;
  1, 10, 46, 128, 239, 314, 296, 200, 95, 30, 6;
  ...
		

Crossrefs

Row sums are A000975, diagonal sums are A080239.
Central terms are A014300.
Similar to the triangles A059259, A080242, A108561, A112555.
Cf. A059260.
Triangle sums (see the comments): A000975 (Row1), A059841 (Row2), A080239 (Kn11), A052952 (Kn21), A129696 (Kn22), A001906 (Kn3), A001654 (Kn4), A001045 (Fi1, Fi2), A023435 (Ca2), Gi2 (A193146), A190525 (Ze2), A193147 (Ze3), A181532 (Ze4). - Johannes W. Meijer, Jul 20 2011
Cf. A181971.

Programs

  • Haskell
    a035317 n k = a035317_tabl !! n !! k
    a035317_row n = a035317_tabl !! n
    a035317_tabl = map snd $ iterate f (0, [1]) where
       f (i, row) = (1 - i, zipWith (+) ([0] ++ row) (row ++ [i]))
    -- Reinhard Zumkeller, Jul 09 2012
    
  • Maple
    A035317 := proc(n,k): add((-1)^(i+k) * binomial(i+n-k+1, i), i=0..k) end: seq(seq(A035317(n,k), k=0..n), n=0..10); # Johannes W. Meijer, Jul 20 2011
    A035317 := proc(n,k): coeff(coeftayl(1/((y*x-1)*(y*x+1)*((y+1)*x-1)), x=0, n), y, k) end: seq(seq(A035317(n,k), k=0..n), n=0..10); # Johannes W. Meijer, Jul 20 2011
  • Mathematica
    t[n_, k_] := (-1)^k*(((-1)^k*(n+2)!*Hypergeometric2F1[1, n+3, k+2, -1])/((k+1)!*(n-k+1)!) + 2^(k-n-2)); Flatten[ Table[ t[n, k], {n, 0, 11}, {k, 0, n}]] (* Jean-François Alcover, Dec 14 2011, after Johannes W. Meijer *)
  • PARI
    {T(n,k)=if(n==k,(n+2)\2,if(k==0,1,if(n>k,T(n-1,k-1)+T(n-1,k))))}
    for(n=0,12,for(k=0,n,print1(T(n,k),","));print("")) \\ Paul D. Hanna, Jul 18 2012
    
  • Sage
    def A035317_row(n):
        @cached_function
        def prec(n, k):
            if k==n: return 1
            if k==0: return 0
            return -prec(n-1,k-1)-sum(prec(n,k+i-1) for i in (2..n-k+1))
        return [(-1)^k*prec(n+2, k) for k in (1..n)]
    for n in (1..11): print(A035317_row(n)) # Peter Luschny, Mar 16 2016

Formula

T(n,k) = Sum_{j=0..floor(n/2)} binomial(n-2j, k-2j). - Paul Barry, Feb 11 2003
From Johannes W. Meijer, Jul 20 2011: (Start)
T(n, k) = Sum_{i=0..k}((-1)^(i+k) * binomial(i+n-k+1,i)). (Mendelson)
T(n, k) = T(n-1, k-1) + T(n-1, k) with T(n, 0) = 1 and T(n, n) = floor(n/2) + 1. (Mendelson)
Sum_{k = 0..n}((-1)^k * (n-k+1)^n * T(n, k)) = A000670(n). (Mendelson)
T(n, n-k) = A128176(n, k); T(n+k, n-k) = A158909(n, k); T(2*n-k, k) = A092879(n, k). (End)
T(2*n+1,n) = A014301(n+1); T(2*n+1,n+1) = A026641(n+1). - Reinhard Zumkeller, Jul 19 2012

Extensions

More terms from James Sellers

A060945 Number of compositions (ordered partitions) of n into 1's, 2's and 4's.

Original entry on oeis.org

1, 1, 2, 3, 6, 10, 18, 31, 55, 96, 169, 296, 520, 912, 1601, 2809, 4930, 8651, 15182, 26642, 46754, 82047, 143983, 252672, 443409, 778128, 1365520, 2396320, 4205249, 7379697, 12950466, 22726483, 39882198, 69988378, 122821042, 215535903, 378239143, 663763424, 1164823609
Offset: 0

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Author

Len Smiley, May 07 2001

Keywords

Comments

Diagonal sums of A038137. - Paul Barry, Oct 24 2005
From Gary W. Adamson, Oct 28 2010: (Start)
INVERT transform of the aerated Fibonacci sequence (1, 0, 1, 0, 2, 0, 3, 0, 5, ...).
a(n) = term (4,4) in the n-th power of the matrix [0,1,0,0; 0,0,1,0; 0,0,0,1; 1,0,1,1]. (End)
Number of permutations satisfying -k <= p(i)-i <= r and p(i)-i not in I, i=1..n, with k=1, r=3, I={2}. - Vladimir Baltic, Mar 07 2012
Number of compositions of n if the summand 2 is frozen in place or equivalently, if the ordering of the summand 2 does not count. - Gregory L. Simay, Jul 18 2016
a(n) - a(n-2) = number of compositions of n with no 2's = A005251(n+1). - Gregory L. Simay, Jul 18 2016
In general, the number of compositions of n with summand k frozen in place is equal to the number of compositions of n with only summands 1,...,k,2k. - Gregory L. Simay, May 10 2017
In the same way that the sum of any two alternating terms of A006498 produces a term from A000045 (the Fibonacci sequence), so it could be thought of as a "meta-Fibonacci," and the sum of any two alternating terms of A013979 produces a term from A000930 (Narayana’s cows), so it could analogously be called "meta-Narayana’s cows," this sequence embeds (can generate) A000931 (the Padovan sequence), as the odd terms of A000931 are generated by the sum of successive elements (e.g. 1+2=3, 2+3=5, 3+6=9, 6+10=16) and its even terms are generated by the difference of "supersuccessive" (second-order successive or "alternating," separated by a single other term) terms (e.g. 10-3=7, 18-6=12, 31-10=21, 55-18=37) — or, equivalently, adding "supersupersuccessive" terms (separated by 2 other terms, e.g. 1+6=7, 2+10=12, 3+18=21, 6+31=37) — so it could be dubbed the "metaPadovan." - Michael Cohen and Yasuyuki Kachi, Jun 13 2024

Examples

			There are 18=a(6) compositions of 6 with the summand 2 frozen in place: (6), (51), (15), (4[2]), (33), (411), (141), (114), (3[2]1), (1[2]3), ([222]), (3111), (1311), (1131), (1113), ([22]11), ([2]1111), (111111). Equivalently, the position of the summand 2 does not affect the composition count. For example, (321)=(231)=(312) and (123)=(213)=(132).
		

Crossrefs

Cf. A000045 (1's and 2's only), A023359 (all powers of 2)
Same as unsigned version of A077930.
All of A060945, A077930, A181532 are variations of the same sequence. - N. J. A. Sloane, Mar 04 2012

Programs

  • Haskell
    a060945 n = a060945_list !! (n-1)
    a060945_list = 1 : 1 : 2 : 3 : 6 : zipWith (+) a060945_list
       (zipWith (+) (drop 2 a060945_list) (drop 3 a060945_list))
    -- Reinhard Zumkeller, Mar 23 2012
    
  • Magma
    R:=PowerSeriesRing(Integers(), 40);
    Coefficients(R!( 1/(1-x-x^2-x^4) )); // G. C. Greubel, Apr 09 2021
    
  • Maple
    m:= 40; S:= series( 1/(1-x-x^2-x^4), x, m+1);
    seq(coeff(S, x, j), j = 0..m); # G. C. Greubel, Apr 09 2021
  • Mathematica
    LinearRecurrence[{1,1,0,1}, {1,1,2,3}, 39] (* or *)
    CoefficientList[Series[1/(1-x-x^2-x^4), {x, 0, 38}], x] (* Michael De Vlieger, May 10 2017 *)
  • PARI
    N=66; my(x='x+O('x^N));
    Vec(1/(1-x-x^2-x^4))
    /* Joerg Arndt, Oct 21 2012 */
    
  • Sage
    def A060945_list(prec):
        P. = PowerSeriesRing(ZZ, prec)
        return P( 1/(1-x-x^2-x^4) ).list()
    A060945_list(40) # G. C. Greubel, Apr 09 2021

Formula

a(n) = a(n-1) + a(n-2) + a(n-4).
G.f.: 1 / (1 - x - x^2 - x^4).
a(n) = Sum_{k=0..floor(n/2)} Sum_{i=0..n-k} C(i, n-k-i)*C(2*i-n+k, 3*k-2*n+2*i). - Paul Barry, Oct 24 2005
a(2n) = A238236(n), a(2n+1) = A097472(n). - Philippe Deléham, Feb 20 2014
a(n) + a(n+1) = A005314(n+2). - R. J. Mathar, Jun 17 2020

Extensions

a(0) = 1 prepended by Joerg Arndt, Oct 21 2012

A077930 Expansion of (1-x)^(-1)/(1+2*x+x^2+x^3).

Original entry on oeis.org

1, -1, 2, -3, 6, -10, 18, -31, 55, -96, 169, -296, 520, -912, 1601, -2809, 4930, -8651, 15182, -26642, 46754, -82047, 143983, -252672, 443409, -778128, 1365520, -2396320, 4205249, -7379697, 12950466, -22726483, 39882198, -69988378, 122821042, -215535903, 378239143, -663763424
Offset: 0

Views

Author

N. J. A. Sloane, Nov 17 2002

Keywords

Comments

Signed version of A060945: a(n) = (-1)^n * A060945(n).

Crossrefs

All of A060945, A077930, A181532 are variations of the same sequence. - N. J. A. Sloane, Mar 04 2012

Programs

  • Mathematica
    CoefficientList[Series[1/(1-x)/(1+2x+x^2+x^3),{x,0,50}],x] (* or *) LinearRecurrence[ {-1,1,0,1},{1,-1,2,-3},50] (* Harvey P. Dale, Feb 20 2013 *)
  • PARI
    Vec((1-x)^(-1)/(1+2*x+x^2+x^3)+O(x^99)) \\ Charles R Greathouse IV, Sep 24 2012

Formula

a(n+1)-a(n) = (-1)^(n+1)*A005314(n+2). - R. J. Mathar, Mar 14 2011
a(0)=1, a(1)=-1, a(2)=2, a(3)=-3, a(n)=-a(n-1)+a(n-2)+a(n-4). - Harvey P. Dale, Feb 20 2013

A368299 a(n) is the number of permutations pi of [n] that avoid {231,321} so that pi^4 avoids 132.

Original entry on oeis.org

0, 1, 2, 4, 7, 13, 23, 41, 72, 127, 223, 392, 688, 1208, 2120, 3721, 6530, 11460, 20111, 35293, 61935, 108689, 190736, 334719, 587391, 1030800, 1808928, 3174448, 5570768, 9776017, 17155714, 30106180, 52832663, 92714861, 162703239, 285524281, 501060184, 879299327
Offset: 0

Views

Author

Kassie Archer, Dec 20 2023

Keywords

Comments

Number of compositions of n of the form d_1+d_2+...+d_k=n where d_i is in {1,2,4} if i>1 and d_1 is any positive integer.

Crossrefs

Cf. A000071 (d_i in {1,2}), A077868 (d_i in {1,3}), A274110, A303666.
Partial sums of A181532.

Programs

  • Maple
    a:= proc(n) option remember;
         `if`(n<1, 0, 1+add(a(n-j), j=[1, 2, 4]))
        end:
    seq(a(n), n=0..37);  # Alois P. Heinz, Dec 20 2023
  • Mathematica
    LinearRecurrence[{2,0,-1,1,-1},{0,1,2,4,7},38] (* Stefano Spezia, Dec 21 2023 *)

Formula

G.f.: x/((1-x)*(1-x-x^2-x^4)).
a(n) = Sum_{m=0..n-1} Sum_{r=0..floor(m/4)} Sum_{j=0..floor((m-4*r)/2)} binomial(m-3*r-j,r)*binomial(m-4*r-j,j).
a(n) = 1+a(n-1)+a(n-2)+a(n-4) where a(0)=0, a(1)=1, a(2)=2, a(3)=4.
a(n) = A274110(n+1) - 1.
Showing 1-4 of 4 results.