cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A384039 The number of integers k from 1 to n such that gcd(n,k) is a powerful number.

Original entry on oeis.org

1, 1, 2, 3, 4, 2, 6, 6, 7, 4, 10, 6, 12, 6, 8, 12, 16, 7, 18, 12, 12, 10, 22, 12, 21, 12, 21, 18, 28, 8, 30, 24, 20, 16, 24, 21, 36, 18, 24, 24, 40, 12, 42, 30, 28, 22, 46, 24, 43, 21, 32, 36, 52, 21, 40, 36, 36, 28, 58, 24, 60, 30, 42, 48, 48, 20, 66, 48, 44
Offset: 1

Views

Author

Amiram Eldar, May 18 2025

Keywords

Comments

The number of integers k from 1 to n such that the powerfree part (A055231) of gcd(n,k) is 1.

Crossrefs

The number of integers k from 1 to n such that gcd(n,k) is: A026741 (odd), A062570 (power of 2), A063659 (squarefree), A078429 (cube), A116512 (power of a prime), A117494 (prime), A126246 (1 or 2), A206369 (square), A254926 (cubefree), A372671 (3-smooth), this sequence (powerful), A384040 (cubefull), A384041 (exponentially odd), A384042 (5-rough).

Programs

  • Mathematica
    f[p_, e_] := If[e == 1, p-1, (p^2-p+1)*p^(e-2)]; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100]
  • PARI
    a(n) = {my(f = factor(n)); prod(i = 1, #f~, if(f[i,2] == 1, f[i,1]-1, (f[i,1]^2-f[i,1]+1)*f[i,1]^(f[i,2]-2)));}

Formula

Multiplicative with a(p^e) = (p^2-p+1)*p^(e-2) if e >= 2, and p-1 otherwise.
a(n) >= A000010(n), with equality if and only if n is squarefree (A005117).
Dirichlet g.f.: zeta(s-1) * Product_{p prime} (1 - 1/p^s + 1/p^(2*s)).
Sum_{k=1..n} a(k) ~ c * n^2 / 2, where c = Product_{p prime} (1 - 1/p^2 + 1/p^4) = 0.66922021803510257394... .

A384040 The number of integers k from 1 to n such that gcd(n,k) is a cubefull number.

Original entry on oeis.org

1, 1, 2, 2, 4, 2, 6, 5, 6, 4, 10, 4, 12, 6, 8, 10, 16, 6, 18, 8, 12, 10, 22, 10, 20, 12, 19, 12, 28, 8, 30, 20, 20, 16, 24, 12, 36, 18, 24, 20, 40, 12, 42, 20, 24, 22, 46, 20, 42, 20, 32, 24, 52, 19, 40, 30, 36, 28, 58, 16, 60, 30, 36, 40, 48, 20, 66, 32, 44, 24
Offset: 1

Views

Author

Amiram Eldar, May 18 2025

Keywords

Comments

The number of integers k from 1 to n such that the cubefree part (A360539) of gcd(n,k) is 1.

Crossrefs

The number of integers k from 1 to n such that gcd(n,k) is: A026741 (odd), A062570 (power of 2), A063659 (squarefree), A078429 (cube), A116512 (power of a prime), A117494 (prime), A126246 (1 or 2), A206369 (square), A254926 (cubefree), A372671 (3-smooth), A384039 (powerful), this sequence (cubefull), A384041 (exponentially odd), A384042 (5-rough).

Programs

  • Mathematica
    f[p_, e_] := Switch[e, 1, p-1, 2, p^2-p, , (p^3-p^2+1)*p^(e-3)]; a[1] = 1; a[n] := Times @@ f @@@ FactorInteger[n]; Array[a, 100]
  • PARI
    a(n) = {my(f = factor(n)); prod(i = 1, #f~, if(f[i,2] == 1, f[i,1]-1, if(f[i,2] == 2, f[i,1]*(f[i,1]-1), (f[i,1]^3-f[i,1]^2+1)*f[i,1]^(f[i,2]-3))));}

Formula

Multiplicative with a(p^e) = (p^3-p^2+1)*p^(e-3) if e >= 3, p*(p-1) if e = 2, and p-1 otherwise.
a(n) >= A384039(n), with equality if and only if n is squarefree (A005117).
Dirichlet g.f.: zeta(s-1) * Product_{p prime} (1 - 1/p^s + 1/p^(3*s)).
Sum_{k=1..n} a(k) ~ c * n^2 / 2, where c = Product_{p prime} (1 - 1/p^2 + 1/p^6) = 0.62159731307414305346... .

A384041 The number of integers k from 1 to n such that gcd(n,k) is an exponentially odd number.

Original entry on oeis.org

1, 2, 3, 3, 5, 6, 7, 7, 8, 10, 11, 9, 13, 14, 15, 13, 17, 16, 19, 15, 21, 22, 23, 21, 24, 26, 25, 21, 29, 30, 31, 27, 33, 34, 35, 24, 37, 38, 39, 35, 41, 42, 43, 33, 40, 46, 47, 39, 48, 48, 51, 39, 53, 50, 55, 49, 57, 58, 59, 45, 61, 62, 56, 53, 65, 66, 67, 51
Offset: 1

Views

Author

Amiram Eldar, May 18 2025

Keywords

Crossrefs

The number of integers k from 1 to n such that gcd(n,k) is: A026741 (odd), A062570 (power of 2), A063659 (squarefree), A078429 (cube), A116512 (power of a prime), A117494 (prime), A126246 (1 or 2), A206369 (square), A254926 (cubefree), A372671 (3-smooth), A384039 (powerful), A384040 (cubefull), this sequence (exponentially odd), A384042 (5-rough).

Programs

  • Mathematica
    f[p_, e_] := ((p^2+p-1)*p^(e-1) - (-1)^e)/(p+1); a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100]
  • PARI
    a(n) = {my(f = factor(n)); prod(i = 1, #f~, ((f[i,1]^2+f[i,1]-1)*f[i,1]^(f[i,2]-1) - (-1)^f[i,2])/(f[i,1] + 1));}

Formula

Multiplicative with a(p^e) = ((p^2+p-1)*p^(e-1) - (-1)^e)/(p+1).
a(n) >= A000010(n), with equality if and only if n = 1.
Dirichlet g.f.: (zeta(s-1)*zeta(2*s)/zeta(s)) * Product_{p prime} (1 + 1/p^s - 1/p^(3*s)).
Sum_{k=1..n} a(k) ~ c * n^2 / 2, where c = Product_{p prime} (1 - 1/p^2 + 1/(p^2+1)) = 0.93749428273130025078... .

A384042 The number of integers k from 1 to n such that gcd(n,k) is a 5-rough number (A007310).

Original entry on oeis.org

1, 1, 2, 2, 5, 2, 7, 4, 6, 5, 11, 4, 13, 7, 10, 8, 17, 6, 19, 10, 14, 11, 23, 8, 25, 13, 18, 14, 29, 10, 31, 16, 22, 17, 35, 12, 37, 19, 26, 20, 41, 14, 43, 22, 30, 23, 47, 16, 49, 25, 34, 26, 53, 18, 55, 28, 38, 29, 59, 20, 61, 31, 42, 32, 65, 22, 67, 34, 46
Offset: 1

Views

Author

Amiram Eldar, May 18 2025

Keywords

Crossrefs

The number of integers k from 1 to n such that gcd(n,k) is: A026741 (odd), A062570 (power of 2), A063659 (squarefree), A078429 (cube), A116512 (power of a prime), A117494 (prime), A126246 (1 or 2), A206369 (square), A254926 (cubefree), A372671 (3-smooth), A384039 (powerful), A384040 (cubefull), A384041 (exponentially odd), this sequence (5-rough).

Programs

  • Mathematica
    f[p_, e_] := If[p < 5, (p-1)*p^(e-1), p^e]; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100]
  • PARI
    a(n) = {my(f = factor(n)); prod(i = 1, #f~, if(f[i,1] < 5, (f[i,1]-1)*f[i,1]^(f[i,2]-1), f[i,1]^f[i,2]));}

Formula

Multiplicative with a(p^e) = (p-1)*p^(e-1) if p <= 3 and p^e if p >= 5.
a(n) >= A000010(n), with equality if and only if n is 3-smooth (A003586).
a(n) = A000010(A065331(n)) * A065330(n).
a(n) = 2 * n * phi(n)/phi(6*n) = n * A000010(n) / A372671(n).
Dirichlet g.f.: zeta(s-1) * (1-1/2^s) * (1-1/3^s).
Sum_{k=1..n} a(k) ~ n^2 / 3.

A384249 The number of integers k from 1 to n such that the greatest divisor of k that is an infinitary divisor of n is squarefree.

Original entry on oeis.org

1, 2, 3, 3, 5, 6, 7, 6, 8, 10, 11, 9, 13, 14, 15, 15, 17, 16, 19, 15, 21, 22, 23, 18, 24, 26, 24, 21, 29, 30, 31, 30, 33, 34, 35, 24, 37, 38, 39, 30, 41, 42, 43, 33, 40, 46, 47, 45, 48, 48, 51, 39, 53, 48, 55, 42, 57, 58, 59, 45, 61, 62, 56, 48, 65, 66, 67, 51
Offset: 1

Views

Author

Amiram Eldar, May 23 2025

Keywords

Crossrefs

Analogous sequences: A063659, A384048.
The number of integers k from 1 to n such that the greatest divisor of k that is an infinitary divisor of n is: A384247(1), this sequence (squarefree), A384250 (powerful), A384251 (odd), A384252 (power of 2).

Programs

  • Mathematica
    f[p_, e_] := p^e*(1 - 1/p^(2^IntegerExponent[e - Mod[e, 2], 2])); f[p_, 1] := p; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100]
  • PARI
    a(n) = {my(f = factor(n)); n * prod(i = 1, #f~, if(f[i,2] == 1, 1, 1 - 1/f[i,1]^(1 << valuation(f[i,2] - f[i,2]%2, 2))));}

Formula

Multiplicative with a(p) = p, and a(p^e) = p^e * (1 - 1/p^A065176(e)) for e >= 2.
Sum_{k=1..n} a(k) ~ c * n^2 / 2, where c = Product_{p prime} f(1/p) = 0.93444998595445071889..., and f(x) = 1 - (1-x^2) * Sum_{k>=2} x^(2^k)/(1-x^(2^k));

A063658 The number of integers m in [1..n] for which gcd(m,n) is divisible by a square greater than 1.

Original entry on oeis.org

0, 0, 0, 1, 0, 0, 0, 2, 1, 0, 0, 3, 0, 0, 0, 4, 0, 2, 0, 5, 0, 0, 0, 6, 1, 0, 3, 7, 0, 0, 0, 8, 0, 0, 0, 12, 0, 0, 0, 10, 0, 0, 0, 11, 5, 0, 0, 12, 1, 2, 0, 13, 0, 6, 0, 14, 0, 0, 0, 15, 0, 0, 7, 16, 0, 0, 0, 17, 0, 0, 0, 24, 0, 0, 3, 19, 0, 0, 0, 20, 9, 0, 0, 21, 0, 0, 0, 22, 0, 10, 0, 23, 0, 0, 0, 24
Offset: 1

Views

Author

Floor van Lamoen, Jul 24 2001

Keywords

Comments

Haviland (1944) proved that a(n) is the number of those arithmetic progressions among (m*n + s: m >= 0), s = 0, 1, ..., n-1, which contain a finite number of squarefree numbers. - Petros Hadjicostas, Jul 21 2019

Examples

			For n=12 we find gcd(4,12), gcd(8,12) and gcd(12,12) divisible by 4, so a(12) = 3.
From _Petros Hadjicostas_, Jul 21 2019: (Start)
We have a(2) = 0 because each of the two arithmetic progressions (2*m: m >= 0) and (2*m + 1: m >= 0) contains infinitely many squarefree numbers.
We have a(3) = 0 because each of the three arithmetic progressions (3*m: m >= 0), (3*m + 1: m >= 0), and (3*m + 2: m >= 0) contains infinitely many squarefree numbers.
We have  a(4) = 1 because, among the four arithmetic progressions (4*m: m >= 0), (4*m + 1: m >= 0), (4*m + 2: m >= 0), and (4*m + 3: m >= 0), only the first one contains a finite number of squarefree numbers (in this case, zero!).
We have a(8) = 2 because only the arithmetic progressions (8*m: m >= 0) and (8*m + 4: m >= 0) contain a finite number of squarefree numbers (in this case, zero!).
(End)
		

Crossrefs

a(n) = n - A063659(n).

Programs

  • Mathematica
    f[list_, i_] := list[[i]]; nn = 100; a =Table[EulerPhi[n], {n, 1, nn}]; b =Table[If[Max[FactorInteger[n][[All, 2]]] > 1, 1, 0], {n,1,nn}]; Table[DirichletConvolve[f[a, n], f[b, n], n, m], {m, 1, nn}] (* Geoffrey Critzer, Mar 21 2015 *)
    Table[Sum[EulerPhi[n/d]*(1-MoebiusMu[d]^2), {d, Divisors[n]}], {n, 1, 100}] (* Vaclav Kotesovec, Feb 01 2019 *)
  • PARI
    { for (n=1, 2000, a=0; for (m=2, n, if (!issquarefree(gcd(m, n)), a++)); write("b063658.txt", n, " ", a) ) } \\ Harry J. Smith, Aug 27 2009
    
  • PARI
    a(n) = sumdiv(n, d, eulerphi(n/d) * (1 - moebius(d)^2)); \\ Daniel Suteu, Jun 27 2018

Formula

Dirichlet g.f.: zeta(s - 1)/zeta(s)*(zeta(s) - zeta(s)/zeta(2*s)) = zeta(s-1)*(zeta(2s)-1)/zeta(2s). - Geoffrey Critzer, Mar 21 2015
a(n) = Sum_{d|n} phi(n/d) * (1 - mu(d)^2). - Daniel Suteu, Jun 27 2018
Sum_{k=1..n} a(k) ~ n^2 * (1 - 90/Pi^4) / 2. - Vaclav Kotesovec, Feb 01 2019

Extensions

More terms from Larry Reeves (larryr(AT)acm.org), Vladeta Jovovic and Dean Hickerson, Jul 26 2001
Name edited by Petros Hadjicostas, Jul 21 2019

A078439 a(n) = Sum_{k=1..n} gcd(k,n)*mu(gcd(k,n))^2.

Original entry on oeis.org

1, 3, 5, 4, 9, 15, 13, 8, 12, 27, 21, 20, 25, 39, 45, 16, 33, 36, 37, 36, 65, 63, 45, 40, 40, 75, 36, 52, 57, 135, 61, 32, 105, 99, 117, 48, 73, 111, 125, 72, 81, 195, 85, 84, 108, 135, 93, 80, 84, 120, 165, 100, 105, 108, 189, 104, 185, 171, 117, 180, 121, 183, 156, 64
Offset: 1

Views

Author

Vladeta Jovovic, Dec 31 2002

Keywords

Crossrefs

Programs

  • Magma
    [&+[Gcd(k,n)*MoebiusMu(Gcd(n,k))^2:k  in [1..n]]:n in [1..70]]; // Marius A. Burtea, Sep 15 2019
  • Mathematica
    Table[Sum[d*MoebiusMu[d]^2*EulerPhi[n/d], {d, Divisors[n]}], {n, 1, 100}] (* Vaclav Kotesovec, Feb 01 2019 *)
    f[p_, e_] := If[e==1, 2*p-1, 2*(p-1)*p^(e-1)]; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100] (* Amiram Eldar, Apr 30 2023 *)
  • PARI
    vector(80, n, sumdiv(n, d, d*moebius(d)^2*eulerphi(n/d))) \\ Michel Marcus, Mar 20 2015
    

Formula

a(n) = Sum_{d|n} d*mu(d)^2*phi(n/d).
Multiplicative with a(p) = 2*p-1 and a(p^e) = 2*(p-1)*p^(e-1), e>1.
Dirichlet g.f.: zeta(s-1)^2 / (zeta(s) * zeta(2s-2)). - Álvar Ibeas, Mar 20 2015
Sum_{k=1..n} a(k) ~ 9 * n^2 * (2*log(n) + 4*gamma - 1 - 36*Zeta'(2)/Pi^2) / Pi^4, where gamma is the Euler-Mascheroni constant A001620. - Vaclav Kotesovec, Feb 01 2019

A332685 a(n) = Sum_{k=1..n} mu(k/gcd(n, k)).

Original entry on oeis.org

1, 2, 1, 2, 0, 2, 0, 0, -1, 0, 0, 0, -1, -2, -2, -3, 0, -4, -1, -5, -4, -2, 0, -8, -3, -4, -4, -7, 0, -8, -2, -10, -5, -4, -4, -13, 0, -5, -4, -13, 1, -15, -1, -9, -10, -5, -1, -22, -4, -12, -5, -11, -1, -19, -6, -17, -6, -4, 1, -28, 0, -8, -12, -18, -6, -19, 0, -12, -5, -17
Offset: 1

Views

Author

Ilya Gutkovskiy, Feb 19 2020

Keywords

Comments

Inverse Moebius transform of A112399.

Crossrefs

Programs

  • Mathematica
    Table[Sum[MoebiusMu[k/GCD[n, k]], {k, 1, n}], {n, 1, 70}]
  • PARI
    a(n) = sum(k=1, n, moebius(k/gcd(n, k))); \\ Michel Marcus, Feb 21 2020

Formula

a(n) = Sum_{k=1..n} mu(lcm(n, k)/n).
a(n) = Sum_{d|n} A112399(d).

A347230 Möbius transform of A344695, gcd(sigma(n), psi(n)).

Original entry on oeis.org

1, 2, 3, -2, 5, 6, 7, 2, -3, 10, 11, -6, 13, 14, 15, -2, 17, -6, 19, -10, 21, 22, 23, 6, -5, 26, 3, -14, 29, 30, 31, 2, 33, 34, 35, 6, 37, 38, 39, 10, 41, 42, 43, -22, -15, 46, 47, -6, -7, -10, 51, -26, 53, 6, 55, 14, 57, 58, 59, -30, 61, 62, -21, -2, 65, 66, 67, -34, 69, 70, 71, -6, 73, 74, -15, -38, 77, 78, 79
Offset: 1

Views

Author

Antti Karttunen, Aug 25 2021

Keywords

Comments

Not multiplicative because A344695 isn't either. For example, a(4) = -2, a(27) = 3, but a(108) = -2 != -6.
The absolute values are not equal to A007947. The first n where abs(a(n)) != A007947(n) is at n=108, with a(108) = -2, while A007947(108) = 6.
The first n such that a(n) does not divide n are: 196, 216, 392, 432, 441, 588, etc.
The zeros occur at n = 288, 576, 1440, 2016, 2880, 3168, 3744, 4032, etc.

Crossrefs

Programs

  • PARI
    A001615(n) = if(1==n,n, my(f=factor(n)); prod(i=1, #f~, f[i, 1]^f[i, 2] + f[i, 1]^(f[i, 2]-1))); \\ After code in A001615
    A344695(n) = gcd(sigma(n), A001615(n));
    A347230(n) = sumdiv(n,d,moebius(n/d)*A344695(d));

Formula

a(n) = Sum_{d|n} A008683(n/d) * A344695(d).
a(n) = A344695(n) - A347231(n).

A309287 Square array T(v, m), read by antidiagonals, for the Rogel-Klee arithmetic function: number of positive integers h in the set [m] for which gcd(h, m) is v-th-power-free, i.e., gcd(h, m) is not divisible by any v-th power of an integer > 1 (with v, m >= 1).

Original entry on oeis.org

1, 1, 1, 2, 2, 1, 2, 3, 2, 1, 4, 3, 3, 2, 1, 2, 5, 4, 3, 2, 1, 6, 6, 5, 4, 3, 2, 1, 4, 7, 6, 5, 4, 3, 2, 1, 6, 6, 7, 6, 5, 4, 3, 2, 1, 4, 8, 7, 7, 6, 5, 4, 3, 2, 1, 10, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 4, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 12, 9, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 6, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1
Offset: 1

Views

Author

Petros Hadjicostas, Jul 21 2019

Keywords

Comments

For fixed v >= 1, T(v, .) is a multiplicative arithmetic function with T(v, 1) = 1; T(v, p^e) = p^e, if e < v; and T(v, p^e) = p^e - p^(e-v) if e >= v (where p is a prime >= 2).
Here, T(v=1, m) = phi(m) is the number of arithmetic progressions (s*m + k: s >= 0), k = 1, ..., m, that contain infinitely many primes (by Dirichlet's theorem). For v >= 2, T(v, m) is the number of these arithmetic progressions that contain infinitely many v-th-power-free numbers.
In Section 6 of his paper, Cohen (1959) mentions that this function was introduced by Rogel (1900) in an article published in a Bohemian journal. Roger's (1900) paper is a continuation of Rogel (1897) and the two should be read together.
McCarthy (1958) uses the asymptotic result given in the FORMULA section below to prove that the probability that the GCD of two positive integers is v-th-power-free is 1/zeta(2*v).

Examples

			Table for T(v, m) (with rows v >= 1 and columns m >= 1) begins as follows:
  v=1: 1, 1, 2, 2, 4, 2, 6, 4, 6,  4, 10,  4, 12,  6,  8,  8, ...
  v=2: 1, 2, 3, 3, 5, 6, 7, 6, 8, 10, 11,  9, 13, 14, 15, 12, ...
  v=3: 1, 2, 3, 4, 5, 6, 7, 7, 9, 10, 11, 12, 13, 14, 15, 14, ...
  v=4: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 15, ...
  v=5: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, ...
  v=6: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, ...
  v=7: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, ...
  ...
Clearly, lim_{v -> infinity} T(v, m) = m.
		

References

  • Paul J. McCarthy, Introduction to Arithmetical Functions, Springer-Verlag, 1986; see pp. 38-40 and 69.

Crossrefs

A000010 (row v = 1 is Euler's phi function), A063659 (row v = 2 is Haviland's function), A254926 (row v = 3).

Programs

  • PARI
    /* Modification of Michel Marcus's program from sequence A254926: */
    T(v, m) = {f = factor(m); for (i=1, #f~, if ((e=f[i, 2])>=v, f[i, 1] = f[i, 1]^e - f[i, 1]^(e-v); f[i, 2]=1); ); factorback(f); }
    /* Print the first 40 terms of each of the first 10 rows: */
    { for (v=1, 10, for (m=1, 40, print1(T(v, m), ", "); ); print(); ); }

Formula

T(v, m) = m * Product_{p prime and p^v|m} (1 - p^(-v)) for v, m >= 1.
T(v, m) = Sum_{n >= 1} mu(n) * [m, n^v] * (m/n^v), where [m, n^v] = 1 when m is a multiple of n^v, and = 0 otherwise. [This is Eq. (53) in Rogel (1900) and Eq. (6.1) in Cohen (1959).]
Dirichlet g.f. for row v: Sum_{m >= 1} T(v, m)/m^s = zeta(s-1)/zeta(v*s) for Re(s) > 1.
Asymptotics: Sum_{m = 1..n} T(v, m) = n^2/(2*zeta(2*v)) + O(n) for v >= 2 and = n^2/(2*zeta(2)) + O(n*log(n)) for v = 1 (for Euler's phi-function).
Analog of Fermat's theorem: if gcd(a, m) = 1 with a >= 1, then m/gcd(a^T(v, m) - 1, m) is v-th-power-free. (For v = 1, this means m/gcd(a^T(v=1, m) - 1, m) = 1.)
T(v, m^v)/m^v = Sum_{d|m} mu(d)/d^v for m, v >= 1. (It generalizes the formula phi(m)/m = Sum_{d|m} mu(d)/d since phi(m) = T(v=1, m).)
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