cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A014448 Even Lucas numbers: L(3n).

Original entry on oeis.org

2, 4, 18, 76, 322, 1364, 5778, 24476, 103682, 439204, 1860498, 7881196, 33385282, 141422324, 599074578, 2537720636, 10749957122, 45537549124, 192900153618, 817138163596, 3461452808002, 14662949395604, 62113250390418
Offset: 0

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Comments

This is the Lucas sequence V(4,-1). - Bruno Berselli, Jan 08 2013

Examples

			a(4) = L(3 * 4) = L(12) = 322. - _Indranil Ghosh_, Feb 05 2017
		

Crossrefs

Cf. Lucas(k*n): A005248 (k = 2), A056854 (k = 4), A001946 (k = 5), A087215 (k = 6), A087281 (k = 7), A087265 (k = 8), A087287 (k = 9), A089772 (k = 11), A089775 (k = 12).

Programs

  • Magma
    [Lucas(3*n) : n in [0..100]]; // Vincenzo Librandi, Apr 14 2011
  • Mathematica
    Table[LucasL[3*n], {n,0,100}] (* G. C. Greubel, Nov 07 2018 *)
  • PARI
    polsym(x^2-4*x-1,100)
    
  • PARI
    a(n)=sum(k=0,n,binomial(n,k)*(fibonacci(n+k-1)+fibonacci(n+k+1))) \\ Paul D. Hanna, Oct 19 2010
    
  • Sage
    [lucas_number2(n,4,-1) for n in range(0, 23)] # Zerinvary Lajos, May 14 2009
    

Formula

G.f.: (2-4*x)/(1-4*x-x^2).
a(n) = 4*a(n-1) +a(n-2) with n>1, a(0)=2, a(1)=4.
a(n) = (2+sqrt(5))^n + (2-sqrt(5))^n.
a(n) = 2*A001077(n).
a(n) = A000032(3*n).
a(n) = Sum_{k=0..n} C(n,k)*Lucas(n+k). - Paul D. Hanna, Oct 19 2010
a(n) = Fibonacci(6*n)/Fibonacci(3*n), n>0. - Gary Detlefs, Dec 26 2010
From Peter Bala, Mar 22 2015: (Start)
a(n) = ( Fibonacci(3*n + 2*k) - F(3*n - 2*k) )/Fibonacci(2*k) for nonzero integer k.
a(n) = ( Fibonacci(3*n + 2*k + 1) + F(3*n - 2*k - 1) )/Fibonacci(2*k + 1) for arbitrary integer k. (End)
a(n) = [x^n] ( (1 + 4*x + sqrt(1 + 8*x + 20*x^2))/2 )^n for n >= 1. - Peter Bala, Jun 23 2015
a(n) = L(n)*(L(n-1)*L(n+1) + 2*(-1)^n). - J. M. Bergot, Feb 05 2016
From Peter Bala Oct 14 2019: (Start)
Sum_{n >= 1} 1/( a(n) + (-1)^(n+1)*20/a(n) ) = 3/16.
Sum_{n >= 1} (-1)^(n+1)/( a(n) + (-1)^(n+1)*20/a(n) ) = 1/16. (End)
a(n) = (15*Fibonacci(n)^2*Lucas(n) + Lucas(n)^3)/4 (Ferns, 1967). - Amiram Eldar, Feb 06 2022
E.g.f.: 2*exp(2*x)*cosh(sqrt(5)*x). - Stefano Spezia, Jan 18 2025

Extensions

More terms from Erich Friedman