cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A038502 Remove 3's from n.

Original entry on oeis.org

1, 2, 1, 4, 5, 2, 7, 8, 1, 10, 11, 4, 13, 14, 5, 16, 17, 2, 19, 20, 7, 22, 23, 8, 25, 26, 1, 28, 29, 10, 31, 32, 11, 34, 35, 4, 37, 38, 13, 40, 41, 14, 43, 44, 5, 46, 47, 16, 49, 50, 17, 52, 53, 2, 55, 56, 19, 58, 59, 20, 61, 62, 7, 64, 65, 22, 67, 68, 23, 70, 71, 8, 73, 74, 25, 76
Offset: 1

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Author

Keywords

Comments

As well as being multiplicative, a(n) is a strong divisibility sequence, that is, gcd(a(n),a(m)) = a(gcd(n,m)) for n, m >= 1. In particular, a(n) is a divisibility sequence: if n divides m then a(n) divides a(m). - Peter Bala, Feb 21 2019
The largest divisor of n not divisible by 3. - Amiram Eldar, Sep 15 2020

Examples

			From _Peter Bala_, Feb 21 2019: (Start)
Sum_{n >= 1} n*a(n)*x^n = G(x) - (2*3)*G(x^3) - (2*9)*G(x^9) - (2*27)*G(x^27) - ..., where G(x) = x*(1 + x)/(1 - x)^3.
Sum_{n >= 1} (1/n)*a(n)*x^n = H(x) - (2/3)*H(x^3) - (2/9)*H(x^9) - (2/27)*H(x^27) - ..., where H(x) = x/(1 - x).
Sum_{n >= 1} (1/n^2)*a(n)*x^n = L(x) - (2/3^2)*L(x^3) - (2/9^2)*L(x^9) - (2/27^2)*L(x^27) - ..., where L(x) = Log(1/(1 - x)).
Also, Sum_{n >= 1} 1/a(n)*x^n = L(x) + (2/3)*L(x^3) + (2/3)*L(x^9) + (2/3)*L(x^27) + ... .
(End)
		

Crossrefs

Result of iterative removal of other factors: A000265 (2), A065883 (4), A132739 (5), A244414 (6), A242603 (7), A004151 (10).

Programs

  • Haskell
    a038502 n = if m > 0 then n else a038502 n'  where (n', m) = divMod n 3
    -- Reinhard Zumkeller, Jan 03 2011
    
  • Magma
    [n/3^Valuation(n,3): n in [1..80]]; // Bruno Berselli, May 21 2013
  • Mathematica
    f[n_] := Times @@ (First@#^Last@# & /@ Select[ FactorInteger@n, First@# != 3 &]); Array[f, 76] (* Robert G. Wilson v, Jul 31 2006 *)
    Table[n/3^IntegerExponent[n, 3], {n, 100}] (* Amiram Eldar, Sep 15 2020 *)
  • PARI
    a(n)=if(n<1, 0, n/3^valuation(n,3)) /* Michael Somos, Nov 10 2005 */
    

Formula

Multiplicative with a(p^e) = 1 if p = 3, otherwise p^e. - Mitch Harris, Apr 19 2005
a(0) = 0, a(3*n) = a(n), a(3*n+1) = 3*n+1, a(3*n+2) = 3*n+2.
Dirichlet g.f. zeta(s-1)*(3^s-3)/(3^s-1). - R. J. Mathar, Feb 11 2011
From Peter Bala, Feb 21 2019: (Start)
a(n) = n/gcd(n,3^n).
O.g.f.: F(x) - 2*F(x^3) - 2*F(x^9) - 2*F(x^27) - ..., where F(x) = x/(1 - x)^2 is the generating function for the positive integers. More generally, for m >= 1,
Sum_{n >= 0} a(n)^m*x^n = F(m,x) - (3^m - 1)( F(m,x^3) + F(m,x^9) + F(m,x^27) + ... ), where F(m,x) = A(m,x)/(1 - x)^(m+1) with A(m,x) the m_th Eulerian polynomial: A(1,x) = x, A(2,x) = x*(1 + x), A(3,x) = x*(1 + 4*x + x^2) - see A008292.
Repeatedly applying the Euler operator x*d/dx or its inverse operator to the o.g.f. for the sequence produces generating functions for the sequences n^m*a(n), m in Z. Some examples are given below. (End)
Sum_{k=1..n} a(k) ~ (3/8) * n^2. - Amiram Eldar, Oct 29 2022
a(n) = n / A038500(n). - R. J. Mathar, Mar 13 2024

A065883 Remove factors of 4 from n (i.e., write n in base 4, drop final zeros, then rewrite in decimal).

Original entry on oeis.org

1, 2, 3, 1, 5, 6, 7, 2, 9, 10, 11, 3, 13, 14, 15, 1, 17, 18, 19, 5, 21, 22, 23, 6, 25, 26, 27, 7, 29, 30, 31, 2, 33, 34, 35, 9, 37, 38, 39, 10, 41, 42, 43, 11, 45, 46, 47, 3, 49, 50, 51, 13, 53, 54, 55, 14, 57, 58, 59, 15, 61, 62, 63, 1, 65, 66, 67, 17, 69, 70, 71, 18, 73, 74, 75
Offset: 1

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Author

Henry Bottomley, Nov 26 2001

Keywords

Examples

			a(7)=7, a(14)=14, a(28)=a(4*7)=7, a(56)=a(4*14)=14, a(112)=a(4^2*7)=7.
		

Crossrefs

Cf. A214392, A235127, A350091 (drop final 2's).
Remove other factors: A000265, A038502, A132739, A244414, A242603, A004151.

Programs

  • Maple
    A065883:= n -> n/4^floor(padic:-ordp(n,2)/2):
    map(A065883, [$1..1000]); # Robert Israel, Dec 08 2015
  • Mathematica
    If[Divisible[#,4],#/4^IntegerExponent[#,4],#]&/@Range[80] (* Harvey P. Dale, Aug 31 2013 *)
  • PARI
    a(n)=n/4^valuation(n,4); \\ Joerg Arndt, Dec 09 2015
    
  • Python
    def A065883(n): return n>>((~n&n-1).bit_length()&-2) # Chai Wah Wu, Jul 09 2022

Formula

If n mod 4 = 0 then a(n) = a(n/4), otherwise a(n) = n.
Multiplicative with a(p^e) = 2^(e (mod 2)) if p = 2 and a(p^e) = p^e if p is an odd prime.
a(n) = n/4^A235127(n).
a(n) = A214392(n) if n mod 16 != 0. - Peter Kagey, Sep 02 2015
From Robert Israel, Dec 08 2015: (Start)
G.f.: x/(1-x)^2 - 3 Sum_{j>=1} x^(4^j)/(1-x^(4^j))^2.
G.f. satisfies G(x) = G(x^4) + x/(1-x)^2 - 4 x^4/(1-x^4)^2. (End)
Sum_{k=1..n} a(k) ~ (2/5) * n^2. - Amiram Eldar, Nov 20 2022
Dirichlet g.f.: zeta(s-1)*(4^s-4)/(4^s-1). - Amiram Eldar, Jan 04 2023

A277544 a(n) = n/6^m mod 6, where 6^m is the greatest power of 6 that divides n.

Original entry on oeis.org

1, 2, 3, 4, 5, 1, 1, 2, 3, 4, 5, 2, 1, 2, 3, 4, 5, 3, 1, 2, 3, 4, 5, 4, 1, 2, 3, 4, 5, 5, 1, 2, 3, 4, 5, 1, 1, 2, 3, 4, 5, 1, 1, 2, 3, 4, 5, 2, 1, 2, 3, 4, 5, 3, 1, 2, 3, 4, 5, 4, 1, 2, 3, 4, 5, 5, 1, 2, 3, 4, 5, 2, 1, 2, 3, 4, 5, 1, 1, 2, 3, 4, 5, 2, 1, 2
Offset: 1

Views

Author

Clark Kimberling, Oct 19 2016

Keywords

Comments

a(n) is the rightmost nonzero digit in the base 6 expansion of n.

Examples

			a(8) = (8/6 mod 6) = 2.
		

Crossrefs

Programs

  • Mathematica
    Table[Mod[n/6^IntegerExponent[n, 6], 6], {n, 1, 160}]
  • PARI
    a(n) = n/6^valuation(n, 6) % 6; \\ Michel Marcus, Oct 20 2016

Formula

a(n) = A244414(n) mod 6. - Michel Marcus, Oct 20 2016

A214394 If n mod 6 = 0 then n/6 else n.

Original entry on oeis.org

0, 1, 2, 3, 4, 5, 1, 7, 8, 9, 10, 11, 2, 13, 14, 15, 16, 17, 3, 19, 20, 21, 22, 23, 4, 25, 26, 27, 28, 29, 5, 31, 32, 33, 34, 35, 6, 37, 38, 39, 40, 41, 7, 43, 44, 45, 46, 47, 8, 49, 50, 51, 52, 53, 9, 55, 56, 57, 58, 59, 10, 61
Offset: 0

Views

Author

Jeremy Gardiner, Jul 15 2012

Keywords

Examples

			a(36) = 36/6 = 6.
		

Crossrefs

Programs

  • Mathematica
    Table[If[Mod[n, 6] == 0, n/6, n], {n, 0, 50}] (* G. C. Greubel, Oct 26 2017 *)
  • PARI
    a(n)=if(n%6,n,n/6) \\ G. C. Greubel, Oct 26 2017
    
  • PARI
    first(n) = my(res = vector(n, i, i-1)); forstep(i = 1, n, 6, res[i] \= 6); res \\ David A. Corneth, Oct 28 2017

Formula

a(n) = 2*a(n-6) - a(n-12). - G. C. Greubel, Oct 26 2017 [corrected by Georg Fischer, Mar 12 2020]
a(n) = A244414(n) when n is not a multiple of 36 (A044102). - Michel Marcus, Oct 28 2017
a(n) = floor(n/6) + sign(n mod 6) * (n - floor(n/6)). - Wesley Ivan Hurt, Oct 28 2017
Showing 1-4 of 4 results.