cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Previous Showing 31-40 of 151 results. Next

A267116 Bitwise-OR of the exponents of primes in the prime factorization of n.

Original entry on oeis.org

0, 1, 1, 2, 1, 1, 1, 3, 2, 1, 1, 3, 1, 1, 1, 4, 1, 3, 1, 3, 1, 1, 1, 3, 2, 1, 3, 3, 1, 1, 1, 5, 1, 1, 1, 2, 1, 1, 1, 3, 1, 1, 1, 3, 3, 1, 1, 5, 2, 3, 1, 3, 1, 3, 1, 3, 1, 1, 1, 3, 1, 1, 3, 6, 1, 1, 1, 3, 1, 1, 1, 3, 1, 1, 3, 3, 1, 1, 1, 5, 4, 1, 1, 3, 1, 1, 1, 3, 1, 3, 1, 3, 1, 1, 1, 5, 1, 3, 3, 2, 1, 1, 1, 3, 1, 1, 1, 3, 1, 1, 1, 5, 1, 1, 1, 3, 3, 1, 1, 3
Offset: 1

Views

Author

Antti Karttunen, Feb 03 2016

Keywords

Examples

			For n = 4 = 2^2, bitwise-OR of 2 alone is 2, thus a(4) = 2.
For n = 6 = 2^1 * 3^1, when we take a bitwise-or of 1 and 1, we get 1, thus a(6) = 1.
For n = 24 = 2^3 * 3^1, bitwise-or of 3 and 1 ("11" and "01" in binary) gives "11", thus a(24) = 3.
For n = 210 = 2^1 * 3^1 * 5^1 * 7^1, bitwise-or of 1, 1, 1 and 1 gives 1, thus a(210) = 1.
For n = 720 = 2^4 * 3^2 * 5^1, bitwise-or of 4, 2 and 1 ("100", "10" and "1" in binary) gives 7 ("111" in binary), thus a(720) = 7.
		

Crossrefs

Cf. A000290 (indices of even numbers).
Cf. A000037 (indices of odd numbers).
Nonunit terms of A005117, A062503, A113849 give the positions of ones, twos, fours respectively in this sequence.
Sequences with similar definitions: A260728, A267113, A267115 (bitwise-AND) and A268387 (bitwise-XOR of exponents).
Sequences with related analysis: A267114, A268374, A268375, A268376.
Sequences A088529, A136565 and A181591 coincide with a(n) for n: 2 <= n < 24.
A003961, A059896 are used to express relationship between terms of this sequence.
Related to A087207 via A225546.

Programs

  • Maple
    read("transforms"):
    A267116 := proc(n)
        local a,e ;
        a := 0 ;
        for e in ifactors(n)[2] do
            a := ORnos(a,op(2,e)) ;
        end do:
        a ;
    end proc: # R. J. Mathar, Feb 16 2021
  • Mathematica
    {0}~Join~Rest@ Array[BitOr @@ Map[Last, FactorInteger@ #] &, 120] (* Michael De Vlieger, Feb 04 2016 *)
  • PARI
    a(n)=my(f = factor(n)); my(b = 0); for (k=1, #f~, b = bitor(b, f[k,2]);); b; \\ Michel Marcus, Feb 05 2016
    
  • PARI
    a(n)=if(n>1, fold(bitor, factor(n)[,2]), 0) \\ Charles R Greathouse IV, Aug 04 2016
    
  • Python
    from functools import reduce
    from operator import or_
    from sympy import factorint
    def A267116(n): return reduce(or_,factorint(n).values(),0) # Chai Wah Wu, Aug 31 2022

Formula

a(1) = 0; for n > 1: a(n) = A067029(n) OR a(A028234(n)). [Here OR stands for bitwise-or, A003986.]
Other identities and observations. For all n >= 1:
a(n) = A007814(n) OR A260728(n) OR A267113(n).
a(n) = A001222(n) - A268374(n).
A268387(n) <= a(n) <= A001222(n).
From Peter Munn, Jan 08 2020: (Start)
a(A059896(n,k)) = a(n) OR a(k).
a(A003961(n)) = a(n).
a(n^2) = 2*a(n).
a(n) = A087207(A225546(n)).
a(A225546(n)) = A087207(n).
(End)

A072411 LCM of exponents in prime factorization of n, a(1) = 1.

Original entry on oeis.org

1, 1, 1, 2, 1, 1, 1, 3, 2, 1, 1, 2, 1, 1, 1, 4, 1, 2, 1, 2, 1, 1, 1, 3, 2, 1, 3, 2, 1, 1, 1, 5, 1, 1, 1, 2, 1, 1, 1, 3, 1, 1, 1, 2, 2, 1, 1, 4, 2, 2, 1, 2, 1, 3, 1, 3, 1, 1, 1, 2, 1, 1, 2, 6, 1, 1, 1, 2, 1, 1, 1, 6, 1, 1, 2, 2, 1, 1, 1, 4, 4, 1, 1, 2, 1, 1, 1, 3, 1, 2, 1, 2, 1, 1, 1, 5, 1, 2, 2, 2, 1, 1, 1, 3, 1, 1, 1, 6, 1, 1, 1, 4, 1, 1, 1, 2, 2, 1, 1, 3
Offset: 1

Views

Author

Labos Elemer, Jun 17 2002

Keywords

Comments

The sums of the first 10^k terms, for k = 1, 2, ..., are 14, 168, 1779, 17959, 180665, 1808044, 18084622, 180856637, 1808585068, 18085891506, ... . Apparently, the asymptotic mean of this sequence is limit_{m->oo} (1/m) * Sum_{k=1..m} a(k) = 1.8085... . - Amiram Eldar, Sep 10 2022

Examples

			n = 288 = 2*2*2*2*2*3*3; lcm(5,2) = 10; Product(5,2) = 10, max(5,2) = 5;
n = 180 = 2*2*3*3*5; lcm(2,2,1) = 2; Product(2,2,1) = 4; max(2,2,1) = 2; it deviates both from maximum of exponents (A051903, for the first time at n=72), and product of exponents (A005361, for the first time at n=36).
For n = 36 = 2*2*3*3 = 2^2 * 3^2 we have a(36) = lcm(2,2) = 2.
For n = 72 = 2*2*2*3*3 = 2^3 * 3^2 we have a(72) = lcm(2,3) = 6.
For n = 144 = 2^4 * 3^2 we have a(144) = lcm(2,4) = 4.
For n = 360 = 2^3 * 3^2 * 5^1 we have a(360) = lcm(1,2,3) = 6.
		

Crossrefs

Similar sequences: A001222 (sum of exponents), A005361 (product), A051903 (maximal exponent), A051904 (minimal exponent), A052409 (gcd of exponents), A267115 (bitwise-and), A267116 (bitwise-or), A268387 (bitwise-xor).
Cf. also A055092, A060131.
Differs from A290107 for the first time at n=144.
After the initial term, differs from A157754 for the first time at n=360.

Programs

  • Mathematica
    Table[LCM @@ Last /@ FactorInteger[n], {n, 2, 100}] (* Ray Chandler, Jan 24 2006 *)
  • PARI
    a(n) = lcm(factor(n)[,2]); \\ Michel Marcus, Mar 25 2017
  • Python
    from sympy import lcm, factorint
    def a(n):
        l=[]
        f=factorint(n)
        for i in f: l+=[f[i],]
        return lcm(l)
    print([a(n) for n in range(1, 151)]) # Indranil Ghosh, Mar 25 2017
    

Formula

a(1) = 1; for n > 1, a(n) = lcm(A067029(n), a(A028234(n))). - Antti Karttunen, Aug 09 2016
From Antti Karttunen, Aug 22 2017: (Start)
a(n) = A284569(A156552(n)).
a(n) = A290103(A181819(n)).
a(A289625(n)) = A002322(n).
a(A290095(n)) = A055092(n).
a(A275725(n)) = A060131(n).
a(A260443(n)) = A277326(n).
a(A283477(n)) = A284002(n). (End)

Extensions

a(1) = 1 prepended and the data section filled up to 120 terms by Antti Karttunen, Aug 09 2016

A162642 Number of odd exponents in the canonical prime factorization of n.

Original entry on oeis.org

0, 1, 1, 0, 1, 2, 1, 1, 0, 2, 1, 1, 1, 2, 2, 0, 1, 1, 1, 1, 2, 2, 1, 2, 0, 2, 1, 1, 1, 3, 1, 1, 2, 2, 2, 0, 1, 2, 2, 2, 1, 3, 1, 1, 1, 2, 1, 1, 0, 1, 2, 1, 1, 2, 2, 2, 2, 2, 1, 2, 1, 2, 1, 0, 2, 3, 1, 1, 2, 3, 1, 1, 1, 2, 1, 1, 2, 3, 1, 1, 0, 2, 1, 2, 2, 2, 2, 2, 1, 2, 2, 1, 2, 2, 2, 2, 1, 1, 1, 0, 1, 3, 1, 2, 3
Offset: 1

Views

Author

Reinhard Zumkeller, Jul 08 2009

Keywords

Comments

a(n) is also known as the squarefree rank of n. - Jason Kimberley, Jul 08 2017
The number of primes that are infinitary divisors of n. - Amiram Eldar, Oct 01 2023

Crossrefs

Programs

Formula

a(n) = A001221(n) - A162641(n).
a(n) = A001221(A007913(n)). - Jason Kimberley, Jan 06 2016
a(A000290(n)) = 0, n > 0. - Michel Marcus, Jan 08 2016
G.f.: Sum_{i>=1} Sum_{j>=1} (-1)^j x^(prime(i)^j)/(x^(prime(i)^j) - 1). - Robert Israel, Jan 15 2016
From Antti Karttunen, Nov 28 2017: (Start)
Additive with a(p^e) = A000035(e).
a(n) = A056169(n) + A295662(n).
A056169(n) <= a(n) <= A056169(n) + A295659(n).
a(n) <= A295664(n).
(End)
Sum_{k=1..n} a(k) = n * log(log(n)) + c * n + O(n/log(n)), where c = gamma + Sum_{p prime} (log(1-1/p) + 1/(p+1)) = A077761 - A179119 = -0.0687327134... and gamma is Euler's constant (A001620). - Amiram Eldar, Dec 25 2021

A065339 Number of primes congruent to 3 modulo 4 dividing n (with multiplicity).

Original entry on oeis.org

0, 0, 1, 0, 0, 1, 1, 0, 2, 0, 1, 1, 0, 1, 1, 0, 0, 2, 1, 0, 2, 1, 1, 1, 0, 0, 3, 1, 0, 1, 1, 0, 2, 0, 1, 2, 0, 1, 1, 0, 0, 2, 1, 1, 2, 1, 1, 1, 2, 0, 1, 0, 0, 3, 1, 1, 2, 0, 1, 1, 0, 1, 3, 0, 0, 2, 1, 0, 2, 1, 1, 2, 0, 0, 1, 1, 2, 1, 1, 0, 4, 0, 1, 2, 0, 1, 1, 1, 0, 2, 1, 1, 2, 1, 1, 1, 0, 2, 3, 0, 0, 1, 1, 0, 2
Offset: 1

Views

Author

Reinhard Zumkeller, Oct 29 2001

Keywords

Crossrefs

Programs

  • Haskell
    a065339 1 = 0
    a065339 n = length [x | x <- a027746_row n, mod x 4 == 3]
    -- Reinhard Zumkeller, Jan 10 2012
    
  • Maple
    A065339 := proc(n)
        a := 0 ;
        for f in ifactors(n)[2] do
            if op(1,f) mod 4 = 3 then
                a := a+op(2,f) ;
            end if;
        end do:
        a ;
    end proc: # R. J. Mathar, Dec 16 2011
  • Mathematica
    f[n_]:=Plus@@Last/@Select[If[n==1,{},FactorInteger[n]],Mod[#[[1]],4]==3&]; Table[f[n],{n,100}] (* Ray Chandler, Dec 18 2011 *)
  • PARI
    A065339(n)=sum(i=1,#n=factor(n)~,if(n[1,i]%4==3,n[2,i]))  \\ M. F. Hasler, Apr 16 2012
    
  • Scheme
    ;; using memoization-macro definec
    (definec (A065339 n) (cond ((< n 3) 0) ((even? n) (A065339 (/ n 2))) (else (+ (/ (- (modulo (A020639 n) 4) 1) 2) (A065339 (A032742 n))))))
    ;; Antti Karttunen, Aug 14 2015
    
  • Scheme
    ;; using memoization-macro definec
    (definec (A065339 n) (cond ((< n 3) 0) ((even? n) (A065339 (/ n 2))) ((= 1 (modulo (A020639 n) 4)) (A065339 (A032742 n))) (else (+ (A067029 n) (A065339 (A028234 n))))))
    ;; Antti Karttunen, Aug 14 2015

Formula

a(n) = A001222(n) - A007814(n) - A083025(n).
(2^A007814(n)) * (3^a(n)) = A065338(n).
From Antti Karttunen, Aug 14 2015: (Start)
a(1) = a(2) = 0; thereafter, if n is even, a(n) = a(n/2), otherwise a(n) = ((A020639(n) mod 4)-1)/2 + a(n/A020639(n)). [Where A020639(n) gives the smallest prime factor of n.]
Other identities and observations. For all n >= 1:
a(n) = A007949(A065338(n)).
a(n) = A001222(A097706(n)).
a(n) >= A260728(n). [See A260730 for the positions of differences.] (End)
Totally additive with a(2) = 0, a(p) = 1 if p == 3 (mod 4), and a(p) = 0 if p == 1 (mod 4). - Amiram Eldar, Jun 17 2024

A156061 a(n) = product of indices of distinct prime factors of n, where index(prime(k)) = k.

Original entry on oeis.org

1, 1, 2, 1, 3, 2, 4, 1, 2, 3, 5, 2, 6, 4, 6, 1, 7, 2, 8, 3, 8, 5, 9, 2, 3, 6, 2, 4, 10, 6, 11, 1, 10, 7, 12, 2, 12, 8, 12, 3, 13, 8, 14, 5, 6, 9, 15, 2, 4, 3, 14, 6, 16, 2, 15, 4, 16, 10, 17, 6, 18, 11, 8, 1, 18, 10, 19, 7, 18, 12, 20, 2, 21, 12, 6, 8, 20, 12, 22, 3, 2, 13, 23, 8, 21, 14, 20, 5, 24, 6, 24, 9, 22, 15, 24, 2, 25, 4, 10, 3
Offset: 1

Views

Author

Ctibor O. Zizka, Feb 03 2009

Keywords

Comments

a(n) = the product of the distinct parts of the partition with Heinz number n. We define the Heinz number of a partition p = [p_1, p_2, ..., p_r] as Product(p_j-th prime, j=1...r) (concept used by Alois P. Heinz in A215366 as an "encoding" of a partition). For example, for the partition [1, 1, 2, 4, 10] we get 2*2*3*7*29 = 2436. Example: a(252)= 8; indeed, the partition having Heinz number 252 = 2*2*3*3*7 is [1,1,2,2,4] and 1*2*4 = 8. - Emeric Deutsch, Jun 03 2015
Multiplicative with a(prime(k)^e) = k. Note that in contrast to A003963, this is not fully multiplicative. a(1) = 1 as an empty product. - Antti Karttunen, Aug 13 2017

Examples

			Here primepi (A000720) gives the index of its prime argument:
n = 14 = 2 * 7, thus a(14) = primepi(2)*primepi(7) = 1*4 = 4.
n = 21 = 3 * 7, thus a(21) = primepi(3)*primepi(7) = 2*4 = 8.
n = 168 = 2^3 * 3 * 7, thus a(168)= primepi(2)*primepi(3)*primepi(7) = 1*2*4 = 8.
		

Crossrefs

Differs from related A290103 for the first time at n=21.

Programs

  • Maple
    with(numtheory): a := proc(n) options operator, arrow: product(pi(factorset(n)[j]), j = 1 .. nops(factorset(n))) end proc: seq(a(n), n = 1 .. 100);  #  Emeric Deutsch, Jun 03 2015
  • Mathematica
    Table[Apply[Times, PrimePi@ FactorInteger[n][[All, 1]]] + Boole[n == 1], {n, 100}] (* Michael De Vlieger, Aug 14 2017 *)
  • PARI
    a(n) = {my(f=factor(n)); for (k=1, #f~, f[k,1] = primepi(f[k,1]); f[k,2] = 1); factorback(f);} \\ Michel Marcus, Aug 14 2017
  • Scheme
    (define (A156061 n) (if (= 1 n) 1 (* (A055396 n) (A156061 (A028234 n))))) ;; Antti Karttunen, Aug 13 2017
    

Formula

From Antti Karttunen, Aug 13 2017: (Start)
a(1) = 1; for n > 1, a(n) = A055396(n) * a(A028234(n)).
a(n) = A003963(A007947(n)) = a(A007947(n)).
a(n) = A003963(n) / A290106(n) = A290103(n) * A290105(n).
a(A181819(n)) = A290107(n).
(End)

Extensions

a(1) = 1 prepended by Antti Karttunen, Aug 13 2017

A028233 If n = p_1^e_1 * ... * p_k^e_k, p_1 < ... < p_k primes, then a(n) = p_1^e_1, with a(1) = 1.

Original entry on oeis.org

1, 2, 3, 4, 5, 2, 7, 8, 9, 2, 11, 4, 13, 2, 3, 16, 17, 2, 19, 4, 3, 2, 23, 8, 25, 2, 27, 4, 29, 2, 31, 32, 3, 2, 5, 4, 37, 2, 3, 8, 41, 2, 43, 4, 9, 2, 47, 16, 49, 2, 3, 4, 53, 2, 5, 8, 3, 2, 59, 4, 61, 2, 9, 64, 5, 2, 67, 4, 3, 2, 71, 8, 73, 2, 3, 4, 7, 2, 79, 16, 81, 2, 83, 4, 5, 2
Offset: 1

Views

Author

Keywords

Comments

Highest power of smallest prime dividing n. - Reinhard Zumkeller, Apr 09 2015

Examples

			From _Muniru A Asiru_, Jan 27 2018: (Start)
If n=10, then a(10) = 2 since 10 = 2^1*5^1.
If n=16, then a(16) = 16 since 16 = 2^4.
If n=29, then a(29) = 29 since 29 = 29^1.
(End)
		

Crossrefs

Programs

  • GAP
    List(List(List(List([1..10^3], Factors), Collected), i -> i[1]), j -> j[1]^j[2]); # Muniru A Asiru, Jan 27 2018
  • Haskell
    a028233 = head . a141809_row
    -- Reinhard Zumkeller, Jun 04 2012, Aug 17 2011
    
  • Maple
    A028233 := proc(n)
        local spf,pf;
        if n = 1 then
            return 1 ;
        end if;
        spf := A020639(n) ;
        for pf in ifactors(n)[2] do
            if pf[1] = spf then
                return pf[1]^pf[2] ;
            end if;
        end do:
    end proc: # R. J. Mathar, Jul 09 2016
    # second Maple program:
    a:= n-> `if`(n=1, 1, (i->i[1]^i[2])(sort(ifactors(n)[2])[1])):
    seq(a(n), n=1..100);  # Alois P. Heinz, Jan 29 2018
  • Mathematica
    a[n_] := Power @@ First[ FactorInteger[n]]; Table[a[n], {n, 1, 86}] (* Jean-François Alcover, Dec 01 2011 *)
  • PARI
    a(n)=if(n>1,n=factor(n);n[1,1]^n[1,2],1) \\ Charles R Greathouse IV, Apr 26 2012
    
  • Python
    from sympy import factorint
    def a(n):
        f = factorint(n)
        return 1 if n==1 else min(f)**f[min(f)] # Indranil Ghosh, May 12 2017
    
  • Scheme
    ;; Naive implementation of A020639 is given under that entry. All of these functions could be also defined with definec to make them faster on the later calls. See http://oeis.org/wiki/Memoization#Scheme
    (define (A028233 n) (if (< n 2) n (let ((lpf (A020639 n))) (let loop ((m lpf) (n (/ n lpf))) (cond ((not (zero? (modulo n lpf))) m) (else (loop (* m lpf) (/ n lpf)))))))) ;; Antti Karttunen, May 29 2017
    

Formula

a(n) = A020639(n)^A067029(n). - Reinhard Zumkeller, May 13 2006
a(n) = A141809(n,1). - Reinhard Zumkeller, Jun 04 2012
a(n) = n / A028234(n). - Antti Karttunen, May 29 2017

Extensions

Name edited to include a(1) = 1 by Franklin T. Adams-Watters, Jan 27 2018

A046643 From square root of Riemann zeta function: form Dirichlet series Sum b_n/n^s whose square is zeta function; sequence gives numerator of b_n.

Original entry on oeis.org

1, 1, 1, 3, 1, 1, 1, 5, 3, 1, 1, 3, 1, 1, 1, 35, 1, 3, 1, 3, 1, 1, 1, 5, 3, 1, 5, 3, 1, 1, 1, 63, 1, 1, 1, 9, 1, 1, 1, 5, 1, 1, 1, 3, 3, 1, 1, 35, 3, 3, 1, 3, 1, 5, 1, 5, 1, 1, 1, 3, 1, 1, 3, 231, 1, 1, 1, 3, 1, 1, 1, 15, 1, 1, 3, 3, 1, 1, 1, 35, 35, 1, 1, 3, 1, 1, 1, 5, 1, 3
Offset: 1

Views

Author

N. J. A. Sloane, Dec 11 1999

Keywords

Comments

b(n) = A046643(n)/A046644(n) is multiplicative with b(p^n) = (2n-1)!!/2^n/n!. Dirichlet g.f. of A046643(n)/A046644(n) is sqrt(zeta(x)). - Christian G. Bower, May 16 2005
That is, b(p^n) = A001147(n) / (A000079(n)*A000142(n)) = A010050(n)/A000290(A000165(n)) = (2n)!/((2^n*n!)^2). - Antti Karttunen, Jul 08 2017

Examples

			b_1, b_2, ... = 1, 1/2, 1/2, 3/8, 1/2, 1/4, 1/2, 5/16, 3/8, 1/4, 1/2, 3/16, ...
		

Crossrefs

Programs

Formula

Sum_{b|d} b(d)b(n/d) = 1. Also b_{2^j} = A001790[ j ]/2^A005187[ j ].
From Antti Karttunen, Jul 08 2017: (Start)
Multiplicative with a(p^n) = A001790(n).
a(1) = 1; for n > 1, a(n) = A001790(A067029(n)) * a(A028234(n)).
(End)
Sum_{j=1..n} A046643(j)/A046644(j) ~ n / sqrt(Pi*log(n)) * (1 + (1 - gamma/2)/(2*log(n))), where gamma is the Euler-Mascheroni constant A001620. - Vaclav Kotesovec, May 04 2025

A059896 The set of Fermi-Dirac factors of A(n,k) is the union of the Fermi-Dirac factors of n and k. Symmetric square array read by antidiagonals.

Original entry on oeis.org

1, 2, 2, 3, 2, 3, 4, 6, 6, 4, 5, 8, 3, 8, 5, 6, 10, 12, 12, 10, 6, 7, 6, 15, 4, 15, 6, 7, 8, 14, 6, 20, 20, 6, 14, 8, 9, 8, 21, 24, 5, 24, 21, 8, 9, 10, 18, 24, 28, 30, 30, 28, 24, 18, 10, 11, 10, 27, 8, 35, 6, 35, 8, 27, 10, 11, 12, 22, 30, 36, 40, 42, 42, 40, 36, 30, 22, 12, 13, 24
Offset: 1

Views

Author

Marc LeBrun, Feb 06 2001

Keywords

Comments

Every positive integer, m, is the product of a unique subset, S(m), of the numbers listed in A050376 (primes, squares of primes etc.) The Fermi-Dirac factors of m are the members of S(m). So T(n,k) is the product of the members of (S(n) U S(k)).
Old name: Table a(i,j) = product prime(k)^(Ei(k) OR Ej(k)) where Ei and Ej are the vectors of exponents in the prime factorizations of i and j; OR is the bitwise operation on binary representation of the exponents.
Analogous to LCM, with OR replacing MAX.
A003418-analog seems to be A066616. - Antti Karttunen, Apr 12 2017
Considered as a binary operation, the result is the lowest common multiple of the squarefree parts of its operands multiplied by the square of the operation's result when applied to the square roots of the square parts of its operands. - Peter Munn, Mar 02 2022

Examples

			A(864,1944) = A(2^5*3^3,2^3*3^5) = 2^(5 OR 3) * 3^(3 OR 5) = 2^7*3^7 = 279936.
The top left 12 X 12 corner of the array:
   1,  2,  3,  4,  5,  6,  7,  8,   9,  10,  11,  12
   2,  2,  6,  8, 10,  6, 14,  8,  18,  10,  22,  24
   3,  6,  3, 12, 15,  6, 21, 24,  27,  30,  33,  12
   4,  8, 12,  4, 20, 24, 28,  8,  36,  40,  44,  12
   5, 10, 15, 20,  5, 30, 35, 40,  45,  10,  55,  60
   6,  6,  6, 24, 30,  6, 42, 24,  54,  30,  66,  24
   7, 14, 21, 28, 35, 42,  7, 56,  63,  70,  77,  84
   8,  8, 24,  8, 40, 24, 56,  8,  72,  40,  88,  24
   9, 18, 27, 36, 45, 54, 63, 72,   9,  90,  99, 108
  10, 10, 30, 40, 10, 30, 70, 40,  90,  10, 110, 120
  11, 22, 33, 44, 55, 66, 77, 88,  99, 110,  11, 132
  12, 24, 12, 12, 60, 24, 84, 24, 108, 120, 132,  12
		

Crossrefs

Sequences used in a definition of this sequence: A003986, A000188/A007913/A008833, A052330/A052331.
Has simple/very significant relationships with A003961, A059895/A059897, A225546, A267116.

Programs

Formula

From Antti Karttunen, Apr 11 2017: (Start)
A(x,y) = A059895(x,y) * A059897(x,y).
A(x,y) * A059895(x,y) = x*y.
(End).
From Peter Munn, Mar 02 2022: (Start)
OR denotes the bitwise operation (A003986).
Limited multiplicative property: if gcd(n_1*k_1, n_2*k_2) = 1 then A(n_1*n_2, k_1*k_2) = A(n_1, k_1) * A(n_2, k_2).
For prime p, A(p^e_1, p^e_2) = p^(e_1 OR e_2).
A(n, A(m, k)) = A(A(n, m), k).
A(n, k) = A(k, n).
A(n, 1) = A(n, n) = n.
A(n^2, k^2) = A(n, k)^2.
A(n, k) = A(A007913(n), A007913(k)) * A(A008833(n), A008833(k)) = lcm(A007913(n), A007913(k)) * A(A000188(n), A000188(k))^2.
A007947(A(n, k)) = A007947(n*k).
Isomorphism: A(A052330(n), A052330(k)) = A052330(n OR k).
Equivalently, A(n, k) = A052330(A052331(n) OR A052331(k)).
A(A003961(n), A003961(k)) = A003961(A(n, k)).
A(A225546(n), A225546(k)) = A225546(A(n, k)).
(End)

Extensions

New name from Peter Munn, Mar 02 2022

A162641 Number of even exponents in canonical prime factorization of n.

Original entry on oeis.org

0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 1, 2, 0, 0, 0, 0, 0
Offset: 1

Views

Author

Reinhard Zumkeller, Jul 08 2009

Keywords

Crossrefs

Cf. A268335 (positions of zeros), A295316.

Programs

Formula

a(n) = A001221(n) - A162642(n).
a(A002035(n)) = 0.
a(A072587(n)) > 0.
Additive with a(p^e) = A059841(e). - Antti Karttunen, Jul 23 2017
From Antti Karttunen, Nov 28 2017: (Start)
a(n) = A162642(A003557(n)).
a(n) <= A056170(n).
(End)
Asymptotic mean: lim_{m->oo} (1/m) * Sum_{k=1..m} a(k) = Sum_{p prime} 1/(p*(p+1)) = 0.3302299262... (A179119). - Amiram Eldar, Dec 25 2021

A276075 a(1) = 0, a(n) = (e1*i1! + e2*i2! + ... + ez*iz!) for n = prime(i1)^e1 * prime(i2)^e2 * ... * prime(iz)^ez, where prime(k) is the k-th prime, A000040(k).

Original entry on oeis.org

0, 1, 2, 2, 6, 3, 24, 3, 4, 7, 120, 4, 720, 25, 8, 4, 5040, 5, 40320, 8, 26, 121, 362880, 5, 12, 721, 6, 26, 3628800, 9, 39916800, 5, 122, 5041, 30, 6, 479001600, 40321, 722, 9, 6227020800, 27, 87178291200, 122, 10, 362881, 1307674368000, 6, 48, 13, 5042, 722, 20922789888000, 7, 126, 27, 40322, 3628801, 355687428096000, 10, 6402373705728000, 39916801, 28, 6, 726, 123
Offset: 1

Views

Author

Antti Karttunen, Aug 18 2016

Keywords

Comments

Additive with a(p^e) = e * (PrimePi(p)!), where PrimePi(n) = A000720(n).
a(3181) has 1001 decimal digits. - Michael De Vlieger, Dec 24 2017

Crossrefs

Programs

  • Mathematica
    Array[If[# == 1, 0, Total[FactorInteger[#] /. {p_, e_} /; p > 1 :> e PrimePi[p]!]] &, 66] (* Michael De Vlieger, Dec 24 2017 *)
  • Python
    from sympy import factorint, factorial as f, primepi
    def a(n):
        F=factorint(n)
        return 0 if n==1 else sum(F[i]*f(primepi(i)) for i in F)
    print([a(n) for n in range(1, 121)]) # Indranil Ghosh, Jun 21 2017

Formula

a(1) = 0; for n > 1, a(n) = a(A028234(n)) + (A067029(n) * A000142(A055396(n))).
Other identities.
For all n >= 0:
a(A276076(n)) = n.
a(A002110(n)) = A007489(n).
a(A019565(n)) = A059590(n).
a(A206296(n)) = A276080(n).
a(A260443(n)) = A276081(n).
For all n >= 1:
a(A000040(n)) = n! = A000142(n).
a(A076954(n-1)) = A033312(n).
Previous Showing 31-40 of 151 results. Next