1, 2, 3, 3, 6, 4, 4, 9, 8, 7, 5, 12, 12, 14, 6, 6, 15, 16, 21, 12, 12, 7, 18, 20, 28, 18, 24, 8, 8, 21, 24, 35, 24, 36, 16, 15, 9, 24, 28, 42, 30, 48, 24, 30, 13, 10, 27, 32, 49, 36, 60, 32, 45, 26, 18, 11, 30, 36, 56, 42, 72, 40, 60, 39, 36, 12, 12, 33, 40, 63, 48, 84, 48, 75, 52, 54, 24, 28, 13, 36, 44, 70, 54, 96, 56, 90, 65, 72, 36, 56, 14
Offset: 1
Triangle begins:
1;
2, 3;
3, 6, 4;
4, 9, 8, 7;
5, 12, 12, 14, 6;
6, 15, 16, 21, 12, 12;
7, 18, 20, 28, 18, 24, 8;
8, 21, 24, 35, 24, 36, 16, 15;
9, 24, 28, 42, 30, 48, 24, 30, 13;
10, 27, 32, 49, 36, 60, 32, 45, 26, 18;
11, 30, 36, 56, 42, 72, 40, 60, 39, 36, 12;
12, 33, 40, 63, 48, 84, 48, 75, 52, 54, 24, 28;
13, 36, 44, 70, 54, 96, 56, 90, 65, 72, 36, 56, 14;
14, 39, 48, 77, 60, 108, 64, 105, 78, 90, 48, 84, 28, 24;
15, 42, 52, 84, 66, 120, 72, 120, 91, 108, 60, 112, 42, 48, 24;
16, 45, 56, 91, 72, 132, 80, 135, 104, 126, 72, 140, 56, 72, 48, 31;
...
For n = 16 and k = 10 the sum of the divisors of 10 is 1 + 2 + 5 + 10 = 18, and 16 - 10 + 1 = 7, and 7*18 = 126, so T(16,10) = 126.
On the other hand, the symmetric representation of sigma(10) has two parts of 9 cells, giving a total of 18 cells. In the stepped pyramid described in A245092, with 16 levels, there are 16 - 10 + 1 = 7 cubes exactly below every cell of the symmetric representation of sigma(10) up the base of pyramid; hence the total numbers of cubes exactly below the terraces of the 10th level (starting from the top) up the base of the pyramid is equal to 7*18 = 126. So T(16,10) = 126.
The sum of the 16th row of the triangle is 16 + 45 + 56 + 91 + 72 + 132 + 80 + 135 + 104 + 126 + 72 + 140 + 56 + 72 + 48 + 31 = A175254(16) = 1276, equaling the volume (also the number of cubes) of the stepped pyramid with 16 levels described in A245092 (see Links section).
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