A006632 a(n) = 3*binomial(4*n-1, n-1)/(4*n-1).
1, 3, 15, 91, 612, 4389, 32890, 254475, 2017356, 16301164, 133767543, 1111731933, 9338434700, 79155435870, 676196049060, 5815796869995, 50318860986108, 437662920058980, 3824609516638444, 33563127932394060, 295655735395397520, 2613391671568320765
Offset: 1
References
- H. M. Finucan, Some decompositions of generalized Catalan numbers, pp. 275-293 of Combinatorial Mathematics IX. Proc. Ninth Australian Conference (Brisbane, August 1981). Ed. E. J. Billington, S. Oates-Williams and A. P. Street. Lecture Notes Math., 952. Springer-Verlag, 1982.
- N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
Links
- G. C. Greubel, Table of n, a(n) for n = 1..1000
- O. Aichholzer, A. Asinowski and T. Miltzow, Disjoint compatibility graph of non-crossing matchings of points in convex position, arXiv preprint arXiv:1403.5546 [math.CO], 2014.
- Paul Barry, Characterizations of the Borel triangle and Borel polynomials, arXiv:2001.08799 [math.CO], 2020.
- Clemens Heuberger, Sarah J. Selkirk, and Stephan Wagner, Enumeration of Generalized Dyck Paths Based on the Height of Down-Steps Modulo k, arXiv:2204.14023 [math.CO], 2022.
- INRIA Algorithms Project, Encyclopedia of Combinatorial Structures 438
- Elżbieta Liszewska and Wojciech Młotkowski, Some relatives of the Catalan sequence, arXiv:1907.10725 [math.CO], 2019.
- J. Sawada, J. Sears, A. Trautrim, and A. Williams, Demystifying our Grandparent's De Bruijn Sequences with Concatenation Trees, arXiv:2308.12405 [math.CO], 2023.
Programs
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Magma
A006632:= func< n | Binomial(4*n-2,n-1)/n >; [A006632(n): n in [1..40]]; // G. C. Greubel, Sep 01 2025
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Maple
A006632:=n->3*binomial(4*n-1,n-1)/(4*n-1): seq(A006632(n), n=1..30); # Wesley Ivan Hurt, Oct 23 2017
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Mathematica
InverseSeries[Series[y*(1-y)^3, {y, 0, 24}], x] (* then A(x)=y(x) *) (* Len Smiley, Apr 07 2000 *) a[ n_] := If[n<1, 0, Binomial[4 n - 2, n - 1] / n]; (* Michael Somos, Aug 22 2014 *)
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PARI
a(n) = 3*binomial(4*n-1, n-1)/(4*n-1) \\ Felix Fröhlich, Oct 23 2017
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SageMath
def A006632(n): return binomial(4*n-2,n-1)//n print([A006632(n) for n in range(1,41)]) # G. C. Greubel, Sep 01 2025
Formula
a(n) = binomial(4*n-1, n)/(4*n-1) = 3*binomial(4*n-2, n-1) - binomial(4*n-2, n). - David Callan, Sep 15 2004
G.f.: g^3 where g = 1+x*g^4 is the g.f. of A002293. - Mark van Hoeij, Nov 11 2011
a(n) = (3/4)*binomial(4*n,n)/(4*n-1). - Bruno Berselli, Jan 17 2014
From Wolfdieter Lang, Feb 06 2020: (Start)
G.f.: (3/4)*(1 - hypergeometric3F2([-1, 1, 2]/4, [1, 2]/3, (4^4/3^3)*x)).
E.g.f.: (3/4)*(1 - hypergeometric3F3([-1, 1, 2]/4, [1, 2, 3]/3, (4^4/3^3)*x)). (End)
D-finite with recurrence 3*n*(3*n-1)*(3*n-2)*a(n) -8*(4*n-5)*(4*n-3)*(2*n-1)*a(n-1)=0. - R. J. Mathar, May 07 2021
a(n) = (2n-1)*A000260(n). - F. Chapoton, Jul 15 2021
G.f. A(x) satisfies: A(x) = x / (1 - A(x))^3. - Ilya Gutkovskiy, Nov 03 2021
G.f.: x*( Sum_{n >= 0} binomial(4*n+3, n)*x^n ) / ( Sum_{n >= 0} binomial(4*n, n)*x^n ) = x*( Sum_{n >= 0} binomial(4*n+3, n)*x^n ) / ( 1 + 4*x*Sum_{n >= 0} binomial(4*n+3, n)*x^n ). - Peter Bala, Dec 13 2024
Working with a offset of 0, the g.f. A(x) = 1 + 3*x + 15*x^2 + ... is uniquely determined by the conditions A(0) = 1 and [x^n] A(x)^(-n) = -3 for all n >= 1. - Peter Bala, Jul 24 2025
Comments