A248109 Integer part of square root of A010811(n) = n^23.
0, 1, 2896, 306827, 8388608, 109183006, 888667667, 5231514822, 24296003999, 94143178827, 316227766016, 946271759726, 2573856496961, 6461726194556, 15152085430295, 33500360392119, 70368744177664, 141306648466586
Offset: 0
Examples
for n = 4, floor(sqrt(n^23)) = 8388608.
Links
- Karl V. Keller, Jr., Table of n, a(n) for n = 0..1000
Crossrefs
Cf. A010811 (n^23).
Programs
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Mathematica
IntegerPart[Sqrt[#]]&/@(Range[0,20]^23) (* Harvey P. Dale, Feb 03 2015 *)
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PARI
a(n)=sqrtint(n^23) \\ Charles R Greathouse IV, Oct 01 2014
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Python
from decimal import Decimal, getcontext getcontext().prec = 100 for n in range(0,1001): print(n, int(Decimal(n**23).sqrt()))
Formula
a(n) = floor(sqrt(n^23)).
Comments