cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-9 of 9 results.

A181404 Total number of positive integers below 10^n requiring 8 positive cubes in their representation as sum of cubes.

Original entry on oeis.org

0, 3, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15
Offset: 1

Views

Author

Martin Renner, Jan 28 2011

Keywords

Comments

Also continued fraction expansion of (9+sqrt(229))/74. - Bruno Berselli, Sep 09 2011

Crossrefs

Programs

Formula

A061439(n) + A181375(n) + A181377(n) + A181379(n) + A181381(n) + A181400(n) + A181402(n) + a(n) + A130130(n) = A002283(n).
a(n) = 15 for n > 2. - Charles R Greathouse IV, Sep 09 2011
G.f.: 3*x^2*(1+4*x)/(1-x). - Bruno Berselli, Sep 09 2011
E.g.f.: 3*(5*(exp(x) - 1 - x) - 2*x^2). - Stefano Spezia, May 21 2024

Extensions

a(5)-a(7) from Lars Blomberg, May 04 2011

A181405 Total number of n-digit numbers requiring 8 positive cubes in their representation as sum of cubes.

Original entry on oeis.org

0, 3, 12, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
Offset: 1

Views

Author

Martin Renner, Jan 28 2011

Keywords

Comments

Arthur Wieferich proved that only 15 integers require eight cubes, cf. A018889.
A181354(n) + A181376(n) + A181378(n) + A181380(n) + A181384(n) + A181401(n) + A181403(n) + a(n) + A171386(n) = A052268(n)

Crossrefs

Formula

a(n) = A181404(n) - A181404(n-1).

A004829 Numbers that are the sum of at most 7 positive cubes.

Original entry on oeis.org

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 16, 17, 18, 19, 20, 21, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69
Offset: 1

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Author

Keywords

Comments

McCurley proves that every n > exp(exp(13.97)) is in A003330 and hence in this sequence. Siksek proves that all n > 454 are in this sequence. - Charles R Greathouse IV, Jun 29 2022

Crossrefs

Complement of A018889; subsequence of A003330.
Sums of k cubes, number of ways of writing n as, for k=1..9: A010057, A173677, A051343, A173678, A173679, A173680, A173676, A173681, A173682.
Cf. A018888.

A018888 Numbers which are not the sum of seven nonnegative cubes.

Original entry on oeis.org

15, 22, 23, 50, 114, 167, 175, 186, 212, 231, 238, 239, 303, 364, 420, 428, 454
Offset: 1

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Author

Keywords

Comments

Old name: Write n = m_1^3 + ... +m_k^3 where the m_i are positive integers and k is minimal; sequence gives conjectured list of numbers for which k = 8 or 9.
23 and 239 require 9 cubes and no numbers require > 9 cubes.
Kadiri shows that a(n) < e^71000. - Charles R Greathouse IV, Dec 30 2014
Siksek shows that this sequence is complete. - Charles R Greathouse IV, May 05 2015

Examples

			239 = 1^3 + 4(2^3) + 3(3^3) + 5^3 - requires 9 cubes.
		

References

  • J. Roberts, Lure of the Integers, entry 239.
  • F. Romani, Computations concerning Waring's problem, Calcolo, 19 (1982), 415-431.

Crossrefs

Cf. A018889.

Programs

  • Maple
    N:= 10000:
    C1:= {seq(i^3, i=0..floor(N^(1/3)))}:
    C2:= select(`<=`,{seq(seq(a+b,a=C1),b=C1)},N):
    C3:= select(`<=`,{seq(seq(a+b,a=C1),b=C2)},N):
    C5:= select(`<=`,{seq(seq(a+b,a=C2),b=C3)},N):
    C7:= select(`<=`,{seq(seq(a+b,a=C2),b=C5)},N):
    {$1..N} minus C7; # Robert Israel, Dec 30 2014
  • Mathematica
    nn=10000; t=CoefficientList[Series[Sum[x^(k^3), {k,0,Floor[nn^(1/3)]}]^7, {x,0,nn}], x]; Flatten[Position[t,0]]-1 (* T. D. Noe, Sep 05 2006 *)
    Select[Range[500], PowersRepresentations[#, 7, 3] == {} &] (* Eric W. Weisstein, Sep 18 2024 *)
  • PARI
    S=sum(n=0,7,x^n^3,O(x^455)); v=Vec(S^7);v=v[2..#v];
    for(n=1,#v,if(v[n]==0,print1(n", "))) \\ Charles R Greathouse IV, May 05 2015

Extensions

Corrected by T. D. Noe, Sep 05 2006
Corrected the definition. - N. J. A. Sloane, Sep 25 2011
New name from Charles R Greathouse IV, Dec 30 2014

A018890 Numbers whose smallest expression as a sum of positive cubes requires exactly 7 cubes.

Original entry on oeis.org

7, 14, 21, 42, 47, 49, 61, 77, 85, 87, 103, 106, 111, 112, 113, 122, 140, 148, 159, 166, 174, 178, 185, 204, 211, 223, 229, 230, 237, 276, 292, 295, 300, 302, 311, 327, 329, 337, 340, 356, 363, 390, 393, 401, 412, 419, 427, 438, 446, 453, 465, 491, 510, 518, 553, 616
Offset: 1

Views

Author

Anonymous

Keywords

Comments

It is conjectured that a(121)=8042 is the last term - Jud McCranie
An unpublished result of Deshouillers-Hennecart-Landreau, combined with Lemma 3 from Bertault, Ramaré, & Zimmermann implies that if there are any terms beyond a(121) = 8042, they are greater than 1.62 * 10^34. - Charles R Greathouse IV, Jan 23 2014

References

  • J. Roberts, Lure of the Integers, entry 239.

Crossrefs

Programs

  • Mathematica
    Select[Range[700], (pr = PowersRepresentations[#, 7, 3]; pr != {} && Count[pr, r_/; (Times @@ r) == 0] == 0)&] (* Jean-François Alcover, Jul 26 2011 *)

A046040 Numbers that are the sum of 6 but no fewer positive cubes.

Original entry on oeis.org

6, 13, 20, 34, 39, 41, 46, 48, 53, 58, 60, 69, 76, 79, 84, 86, 95, 98, 102, 104, 105, 110, 117, 121, 123, 124, 132, 139, 147, 151, 158, 165, 170, 173, 177, 184, 196, 202, 203, 210, 215, 221, 222, 228, 235, 236, 242, 247, 249, 263, 265, 268, 273, 275, 284, 287
Offset: 1

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Author

Keywords

Comments

According to the McCurley article, it is conjectured that there are exactly 3922 terms of which the largest is a(3922) = 1290740.

Crossrefs

Programs

  • Mathematica
    Select[Range[300], (pr = PowersRepresentations[#, 6, 3]; pr != {} && Count[pr, r_/; (Times @@ r) == 0] == 0)&] (* Jean-François Alcover, Jul 26 2011 *)

Extensions

Corrected by Arlin Anderson (starship1(AT)gmail.com).

A047719 Numbers that are the sum of 8 but no fewer nonzero fourth powers.

Original entry on oeis.org

8, 23, 38, 53, 68, 88, 103, 118, 128, 133, 148, 168, 183, 193, 198, 213, 228, 248, 263, 278, 293, 308, 323, 328, 343, 358, 368, 373, 388, 403, 408, 423, 433, 438, 453, 468, 483, 488, 498, 503, 518, 533, 548, 563, 568, 578, 583, 598, 608, 613, 632, 647, 648
Offset: 1

Views

Author

Arlin Anderson (starship1(AT)gmail.com)

Keywords

Crossrefs

Programs

  • PARI
    upto(n)={my(e=8); my(s=sum(k=1, sqrtint(sqrtint(n)), x^(k^4)) + O(x*x^n)); my(p=s^e, q=(1 + s)^(e-1)); select(k->polcoeff(p,k) && !polcoeff(q,k), [1..n])} \\ Andrew Howroyd, Jul 06 2018

A098821 a(n) = (n-2) * 2^(n-1) + 5.

Original entry on oeis.org

4, 4, 5, 9, 21, 53, 133, 325, 773, 1797, 4101, 9221, 20485, 45061, 98309, 212997, 458757, 983045, 2097157, 4456453, 9437189, 19922949, 41943045, 88080389, 184549381, 385875973, 805306373, 1677721605, 3489660933, 7247757317
Offset: 0

Views

Author

Parthasarathy Nambi, Oct 08 2004

Keywords

Examples

			a(5) = 3*2^4 + 5 = 53.
		

References

  • G. H. Hardy and J. E. Littlewood, "Some problems of partitio numerorum (VI): Further researches in Waring's Problem", Math. Z. vol. 23, 1-37, (1925)
  • T. D. Wooley, "Large improvements in Waring's Problem", Ann. Math. vol. 135, 131-164 (1992)

Crossrefs

Programs

Formula

From Colin Barker, Jan 28 2012: (Start)
G.f.: (4-16*x+17*x^2)/(1-5*x+8*x^2-4*x^3).
a(n)=5*a(n-1)-8*a(n-2)+4*a(n-3). (End)

Extensions

More terms from Stefan Steinerberger, Mar 06 2006

A098823 a(n) = 16*(8*prime(n) + 7).

Original entry on oeis.org

368, 496, 752, 1008, 1520, 1776, 2288, 2544, 3056, 3824, 4080, 4848, 5360, 5616, 6128, 6896, 7664, 7920, 8688, 9200, 9456, 10224, 10736, 11504, 12528, 13040, 13296, 13808, 14064, 14576, 16368, 16880, 17648, 17904, 19184, 19440, 20208, 20976
Offset: 1

Views

Author

Parthasarathy Nambi, Oct 08 2004

Keywords

Examples

			4^2 * (8*2 + 7) = 368 when p=2.
		

Crossrefs

Programs

  • Mathematica
    Table[16*(8*Prime[n] + 7), {n, 1, 40}] (* Stefan Steinerberger, Mar 06 2006 *)
  • PARI
    main(m)=forprime(p=2,m,print1(16 * (8 * p + 7),", ")) \\ Anders Hellström, Aug 26 2015

Extensions

More terms from Stefan Steinerberger, Mar 06 2006
Showing 1-9 of 9 results.