cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-6 of 6 results.

A082582 Expansion of (1 + x^2 - sqrt( 1 - 4*x + 2*x^2 + x^4)) / (2*x) in powers of x.

Original entry on oeis.org

1, 1, 1, 2, 5, 13, 35, 97, 275, 794, 2327, 6905, 20705, 62642, 190987, 586219, 1810011, 5617914, 17518463, 54857506, 172431935, 543861219, 1720737981, 5459867166, 17369553427, 55391735455, 177040109419, 567019562429, 1819536774089
Offset: 0

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Author

Emanuele Munarini, May 07 2003

Keywords

Comments

a(n) is the number of Dyck paths of semilength n with no UUDD. See A025242 for a bijection between paths avoiding DDUU versus UUDD.
Also number of lattice paths from (0,0) to (n,n) which do not go above the diagonal x=y using steps (1,k), (k,1) with k>=1. - Alois P. Heinz, Oct 07 2015
a(n) is the number of bargraphs of semiperimeter n (n>=2). Example: a(4) = 5; the 5 bargraphs correspond to the compositions [1,1,1], [1,2], [2,1], [2,2], [3]. - Emeric Deutsch, May 20 2016 [a(n) are the row sums of A271942 for n >= 2. Peter Luschny, Oct 18 2020]
a(n) is the number of skew Motzkin paths of length n. A skew Motzkin path is a path in the first quadrant which begins at the origin, ends on the x-axis, consists of steps U=(1,1) (up), D=(1,-1) (down), F=(1,0) (flat) and A=(-1,1) (anti-down) so that down and anti-down steps do not overlap. - Sergey Kirgizov, Oct 03 2018
From Gus Wiseman, Jul 04 2019: (Start)
Conjecture: Also the number of maximal simple graphs with vertices {1..n} and no weakly nesting edges. Two edges {a,b}, {c,d} are weakly nesting if a <= c < d <= b or c <= a < b <= d. For example, the a(1) = 1 through a(5) = 13 edge-sets are:
{} {12} {13} {14} {15}
{12,23} {12,24} {12,25}
{13,24} {13,25}
{13,34} {14,25}
{12,23,34} {14,35}
{14,45}
{12,23,35}
{12,24,35}
{12,24,45}
{13,24,35}
{13,24,45}
{13,34,45}
{12,23,34,45}
(End)
a(n) is the number of Dyck n-paths in which no nonterminal descent has the same length as the preceding ascent. Example: a(3) = 2 counts UUDUDD and UUUDDD where the latter path qualifies because DDD is the terminal descent. - David Callan, Dec 14 2021

Examples

			1 + x + x^2 + 2*x^3 + 5*x^4 + 13*x^5 + 35*x^6 + 97*x^7 + 275*x^8 + ...
a(3)=2 because the only Dyck paths of semilength 3 with no UUDD in them are UDUDUD and UUDUDD (the nonqualifying ones being UDUUDD, UUDDUD and UUUDDD). - _Emeric Deutsch_, Jan 27 2003
		

Crossrefs

Apart from initial term, same as A025242.
See A086581 for Dyck paths avoiding DDUU.
Cf. A000108, A218321, A263316, A271942 (refinement).
Column k=0 of A098978.

Programs

  • Haskell
    a082582 n = a082582_list !! n
    a082582_list = 1 : 1 : f [1,1] where
       f xs'@(x:_:xs) = y : f (y : xs') where
         y = x + sum (zipWith (*) xs' $ reverse xs)
    -- Reinhard Zumkeller, Nov 13 2012
    
  • Maple
    f:= gfun:-rectoproc({(n-1)*a(n)+(2*n+4)*a(n+2)+(-14-4*n)*a(n+3)+(5+n)*a(n+4), a(0) = 1, a(1) = 1, a(2) = 1, a(3) = 2},a(n),remember):
    map(f,[$0..100]); # Robert Israel, May 20 2016
  • Mathematica
    a[0]=1;a[n_Integer]:=a[n]=a[n-1]+Sum[a[k]*a[n-1-k],{k,2,n-1}];Table[a[n],{n,0,40}] (* Vladimir Joseph Stephan Orlovsky, Mar 30 2011 *)
    a[ n_] := SeriesCoefficient[ 2 / (1 + x^2 + Sqrt[1 - 4 x + 2 x^2 + x^4]), {x, 0, n}] (* Michael Somos, Jul 01 2011 *)
    a[n_] := Sum[HypergeometricPFQ[{-k, 3 + k, k - n}, {1, 2}, 1], {k, 0, n}];
    Join[{1, 1}, Table[a[n], {n, 0, 26}]] (* Peter Luschny, Oct 18 2020 *)
  • Maxima
    a(n):=sum(sum((binomial(n-k-2,j)*binomial(k,j)*binomial(k+j+2,j))/(j+1),j,0,n-k-1),k,0,n-2); /* Vladimir Kruchinin, Oct 18 2020 */
  • PARI
    {a(n) = polcoeff( (1 + x^2 - sqrt( 1 - 4*x + 2*x^2 + x^4 + x^2 * O(x^n))) / 2, n+1)} /* Michael Somos, Jul 22 2003 */
    
  • PARI
    {a(n) = if( n<0, 0, polcoeff( 2 /(1 + x^2 + sqrt( 1 - 4*x + 2*x^2 + x^4 + x * O(x^n))),n))} /* Michael Somos, Jul 01 2011 */
    
  • PARI
    {a(n) = local(A); if( n<0, 0, A = O(x); for( k = 0, n, A = 1 / (1 + x^2 - x * A)); polcoeff( A, n))} /* Michael Somos, Mar 28 2011 */
    

Formula

G.f.: (1 + x^2 - sqrt( 1 - 4*x + 2*x^2 + x^4)) / (2*x) = 2 /(1 + x^2 + sqrt( 1 - 4*x + 2*x^2 + x^4)).
G.f. A(x) satisfies the equation 0 = 1 - (1 + x^2) * A(x) + x * A(x)^2. - Michael Somos, Jul 22 2003
G.f. A(x) satisfies A(x) = 1 / (1 + x^2 - x * A(x)). - Michael Somos, Mar 28 2011
G.f. A(x) = 1 / (1 + x^2 - x / (1 + x^2 - x / (1 + x^2 - ... ))) continued fraction. - Michael Somos, Jul 01 2011
Series reversion of x * A(x) is x * A007477(-x). - Michael Somos, Jul 22 2003
a(n+1) = a(n) + Sum(a(k)*a(n-k): k=2..n), a(0) = a(1) = 1. - Reinhard Zumkeller, Nov 13 2012
G.f.: 1 + x - x*G(0), where G(k)= 1 - 1/(1 - x/(1 - x/(1 - x/(1 - x/(x - 1/G(k+1) ))))); (continued fraction). - Sergei N. Gladkovskii, Jul 12 2013
D-finite with recurrence: (n-1)*a(n)+(2*n+4)*a(n+2)+(-14-4*n)*a(n+3)+(5+n)*a(n+4) = 0. - Robert Israel, May 20 2016
a(n) = Sum_{k=0..n-2} Sum_{j=0..n-k-1} C(n-k-2,j)*C(k,j)*C(k+j+2,j)/(j+1), n>1, a(0)=1, a(1)=1. - Vladimir Kruchinin, Oct 18 2020
a(n) = Sum_{k=0..n-2} HypergeometricPFQ[{-k, 3 +k, k - n + 2}, {1, 2}, 1] for n >= 2. - Peter Luschny, Oct 18 2020
a(n) ~ sqrt(2+r) / (2 * sqrt(Pi) * n^(3/2) * r^n), where r = 0.295597742522084... is the real root of the equation r^3 + r^2 + 3*r - 1 = 0. - Vaclav Kotesovec, Jun 05 2022
G.f.: 1/G(x), with G(x) = 1 - (x-x^2)/(1-x/G(x)) (continued fraction). - Nikolaos Pantelidis, Jan 11 2023

A105633 Row sums of triangle A105632.

Original entry on oeis.org

1, 2, 4, 9, 22, 57, 154, 429, 1223, 3550, 10455, 31160, 93802, 284789, 871008, 2681019, 8298933, 25817396, 80674902, 253106837, 796968056, 2517706037, 7977573203, 25347126630, 80738862085, 257778971504, 824798533933
Offset: 0

Views

Author

Paul D. Hanna, Apr 17 2005

Keywords

Comments

Binomial transform of A007477. INVERT transform of A082582. First differences give A086581 and A025242 (offset 1). Is this sequence equal to A057580?
a(n) = the number of Dyck paths of semilength n+1 avoiding UUDU. a(n) = the number of Dyck paths of semilength n+1 avoiding UDUU = the number of binary trees without zigzag (i.e., with no node with a father, with a right son and with no left son). This sequence is the first column of the triangle A116424. E.g., a(2) = 4 because there exist four Dyck paths of semilength 3 that avoid UUDU: UDUDUD, UDUUDD, UUDDUD, UUUDDD, as well as four Dyck paths of semilength 3 that avoid UDUU: UDUDUD, UUDUDD, UUDDUD, UUUDDD. - I. Tasoulas (jtas(AT)unipi.gr), Feb 15 2006
The sequence beginning 1,1,2,4,9,... gives the diagonal sums of A130749, and has g.f. 1/(1-x-x^2/(1-x/(1-x-x^2/(1-x/(1-x-x^2/(1-... (continued fraction); and general term Sum_{k=0..floor(n/2)} Sum_{j=0..n-k} binomial(n-k,j)*A090181(j,k). Its Hankel transform is A099443(n+1). - Paul Barry, Jun 30 2009
The number of plain lambda terms presented by de Bruijn indices, see Bendkowski et al. - Kellen Myers, Jun 15 2015
a(n) = the number of Dyck paths of semilength n+1 with no pairs of
consecutive valleys at the same height. Sergi Elizalde, Feb 25 2021

Examples

			G.f.: A(x) = 1 + 2*x + 4*x^2 + 9*x^3 + 22*x^4 + 57*x^5 + 154*x^6 + 429*x^7 + ...
with A(x)^2 = 1 + 4*x + 12*x^2 + 34*x^3 + 96*x^4 + 274*x^5 + 793*x^6 + ...
where A(x) = 1 + x*(2-x)*A(x) + x^2*(1-x)*A(x)^2.
The logarithm of the g.f. begins:
log(A(x)) = (1 + (1-x))*x + (1 + 2^2*(1-x) + (1-x)^2)*x^2/2 +
(1 + 3^2*(1-x) + 3^2*(1-x)^2 + (1-x)^3)*x^3/3 +
(1 + 4^2*(1-x) + 6^2*(1-x)^2 + 4^2*(1-x)^3 + (1-x)^4)*x^4/4 +
(1 + 5^2*(1-x) + 10^2*(1-x)^2 + 10^2*(1-x)^3 + 5^2*(1-x)^4 + (1-x)^5)*x^5/5 + ...
Explicitly,
log(A(x)) = 2*x + 4*x^2/2 + 11*x^3/3 + 32*x^4/4 + 97*x^5/5 + 301*x^6/6 + 947*x^7/7 + 3008*x^8/8 + 9623*x^9/9 + 30959*x^10/10 + ...
		

Crossrefs

Programs

  • Maple
    a := n -> add((-1)^i*hypergeom([(i+1)/2, i/2+1, i-n-1], [1, 2], -4), i=0..n+1):
    seq(simplify(a(n)), n=0..26); # Peter Luschny, May 03 2018
  • Mathematica
    CoefficientList[Series[(1 - x - Sqrt[(1 - x)^2 - 4 x^2/(1 - x)])/(2 x^2), {x, 0, 40}], x] (* Vincenzo Librandi, Mar 15 2014 *)
  • PARI
    {a(n)=local(X=x+x*O(x^n)); polcoeff(2/(1-X)/(1-X+sqrt((1-X)^2-4*X^2/(1-X))),n,x)}
    
  • PARI
    {a(n)=polcoeff(exp(sum(m=1,n+1,x^m/m*sum(k=0,m,binomial(m,k)^2*(1-x)^(m-k) + x*O(x^n)))),n)} \\ Paul D. Hanna, Sep 12 2012

Formula

G.f.: A(x) = (1-x - sqrt((1-x)^2 - 4*x^2/(1-x)))/(2*x^2).
a(n) = 2*a(n-1) + Sum_{i=1..n-2} a(i)*(a(n-1-i) - a(n-2-i)). a(n) = Sum_{i=0..floor(n/2)} (-1)^i * binomial(n+1-i,i) * binomial(2*(n+1)-3*i, n-2*i) /(n+1-i). - I. Tasoulas (jtas(AT)unipi.gr), Feb 15 2006
G.f.: (1/(1-x)^2)c(x^2/(1-x)^3), where c(x) is the g.f. of A000108. - Paul Barry, May 22 2009
1/(1-x-x/(1-x^2/(1-x-x/(1-x^2/(1-x-x/(1-x^2/(1-... (continued fraction). - Paul Barry, Jun 30 2009
a(n) = Sum_{k=0..floor(n/2)} Sum_{j=0..n-k} binomial(n-k,j)(0^(j+k)+(1/(j+0^j))*binomial(j,k)*binomial(j,k+1)). - Paul Barry, Jun 30 2009
G.f. satisfies: A(x) = (1 + x*A(x)) * (1 + x*(1-x)*A(x)). - Paul D. Hanna, Sep 12 2012
G.f.: exp( Sum_{n>=1} x^n/n * Sum_{k=0..n} binomial(n,k)^2 * (1-x)^k ). - Paul D. Hanna, Sep 12 2012
D-finite with recurrence: (n+2)*a(n) + (-4*n-3)*a(n-1) + (2*n+1)*a(n-2) + a(n-3) + (n-3)*a(n-4) = 0. - R. J. Mathar, Nov 26 2012
The recurrence is true, since by holonomic transformation, it can be computed formally using GFUN, associated with the equation: x^3 + x^2 - 2x + (x^3 + 3 x^2 -3x +1) A(x) + (x^5 + 2x^3 -4 x^2 + x) A'(x) = 0. - Pierre Lescanne, Jun 30 2015
G.f.: (1 - 1/(G(0)-x))/x^2 where G(k) = 1 + x/(1 + x/(x^2 - 1/G(k+1) )); (continued fraction). - Sergei N. Gladkovskii, Dec 16 2012
a(n) ~ 2^(n/3-1/6) * 3^(n+2) * (13+3*sqrt(33))^((n+1)/3) * sqrt(4*(2879 + 561*sqrt(33))^(1/3) + 8*(7822 + 1362*sqrt(33))^(1/3) - 91 - 21*sqrt(33)) / (((26+6*sqrt(33))^(2/3) - (26+6*sqrt(33))^(1/3) - 8)^(n+3/2) * (4*(26+6*sqrt(33))^(1/3) - (26+6*sqrt(33))^(2/3) + 8) * n^(3/2) * sqrt(Pi)). - Vaclav Kotesovec, Mar 13 2014
a(n) = Sum_{i=0..n+1} (-1)^i*hypergeom([(i+1)/2, i/2+1, i-n-1], [1, 2], -4). - Peter Luschny, May 03 2018

Extensions

More terms from I. Tasoulas (jtas(AT)unipi.gr), Feb 15 2006

A086581 Number of Dyck paths of semilength n with no DDUU.

Original entry on oeis.org

1, 1, 2, 5, 13, 35, 97, 275, 794, 2327, 6905, 20705, 62642, 190987, 586219, 1810011, 5617914, 17518463, 54857506, 172431935, 543861219, 1720737981, 5459867166, 17369553427, 55391735455, 177040109419, 567019562429, 1819536774089
Offset: 0

Views

Author

Michael Somos, Jul 22 2003

Keywords

Comments

See A025242 for a bijection between paths avoiding UUDD versus DDUU.
Number of lattice paths, never going below the x-axis, from (0,0) to (n,0) consisting of up steps U(k) = (k,1) for every positive integer k, down steps D = (1,-1) and horizontal steps H. - José Luis Ramírez Ramírez, Apr 19 2015
Given a sequence variant with 0 inserted between the two 1's, the INVERT transform of the modified sequence is this sequence. - Gary W. Adamson, Jun 28 2015

Examples

			a(4) = 13 because of the 14 Dyck 4-paths only UUDDUUDD contains DDUU.
		

Crossrefs

Column k=0 of A114492.

Programs

  • Maple
    F:= gfun:-rectoproc({(n+2)*a(n) +(n+3)*a(n-1) +2*(-9*n+4)*a(n-2) +10*(n-2)*a(n-3) +(n-4)*a(n-4) +5*(n-5)*a(n-5)=0, seq(a(n)=[1,1,2,5,13][n+1],n=0..4)},a(n),remember):
    map(F, [$0..30]); # Robert Israel, Jun 29 2015
  • Mathematica
    CoefficientList[ Series[(1 - 2 x + x^2 - Sqrt[1 - 4 x + 2 x^2 + x^4])/(2 x^2), {x, 0, 27}], x] (* Robert G. Wilson v, Mar 25 2011 *)
  • PARI
    {a(n) = polcoeff((1 - 2*x + x^2 - sqrt(1 - 4*x + 2*x^2 + x^4 + x^3 * O(x^n))) / 2, n+2)}
    
  • PARI
    a(n)=1+sum(k=0,n,sum(i=0,k,binomial(n-1,k)*binomial(2*i+2,i)*binomial(i+2,k-2*i-1)/(i+1))) \\ Thomas Baruchel, Jan 19 2015

Formula

G.f. A(x) satisfies the equation 0 = 1 - x - (1 - x)^2 * A(x) + (x * A(x))^2.
a(n) = A025242(n+1) = A082582(n+1).
G.f.: (1 - 2*x + x^2 - sqrt(1 - 4*x + 2*x^2 + x^4)) /(2 * x^2).
a(n+2) - 2*a(n+1) + a(n) = a(0)*a(n) + a(1)*a(n-1) + ... + a(n)*a(0).
G.f.: (1/(1-x))*c(x^2/(1-x)^3), c(x) the g.f. of A000108; a(n)=sum{k=0..floor(n/2), C(n+k,3k)*A000108(k)}. - Paul Barry, May 31 2006
Conjecture: (n+2)*a(n) +(n+3)*a(n-1) +2*(-9*n+4)*a(n-2) +10*(n-2)*a(n-3) +(n-4)*a(n-4) +5*(n-5)*a(n-5)=0. - R. J. Mathar, Nov 26 2012
G.f. satisfies (10*x^3-28*x^2+4*x+2)*A(x) + (5*x^6+x^5+10*x^4-18*x^3+x^2+x)*A'(x) = 5*x^4+x^3-15*x^2+7*x+2. This confirms R. J. Mathar's recurrence equation. - Robert Israel, Jun 29 2015
G.f.: 1 - G(0), where G(k)= 1 - 1/(1 - x/(1 - x/(1 - x/(1 - x/(x - 1/G(k+1) ))))); (continued fraction). - Sergei N. Gladkovskii, Jul 12 2013
G.f.: 1/G(0) where G(k) = 1 - q/(1 - q - q^2 / G(k+1) ); (continued fraction). - Joerg Arndt, Feb 27 2014
From Thomas Baruchel, Jan 19 2015: (Start)
a(n) = 1+Sum_{k=0..n} Sum_{i=0..k} C(n-1,k)*C(2i+2,i)*C(i+2,k-2i-1)/(i+1).
a(n) = Sum_{k=0..n} C(2k,k)*C(n+k,3k)/(k+1).
Sum_{k=0..n} a(k+1)*A108626(n-k) = Sum_{k=0..n} Sum_{i=0..k} binomial(n-k+1,i-1)*binomial(n-k+1,i)*binomial(n-i+1,k-i). (End)

Extensions

Name corrected by David Scambler, Mar 28 2011

A098978 Triangle read by rows: T(n,k) is number of Dyck n-paths with k UUDDs, 0 <= k <= n/2.

Original entry on oeis.org

1, 1, 1, 1, 2, 3, 5, 8, 1, 13, 23, 6, 35, 69, 27, 1, 97, 212, 110, 10, 275, 662, 426, 66, 1, 794, 2091, 1602, 360, 15, 2327, 6661, 5912, 1760, 135, 1, 6905, 21359, 21534, 8022, 945, 21, 20705, 68850, 77685, 34840, 5685, 246, 1, 62642, 222892, 278192, 146092
Offset: 0

Views

Author

David Callan, Oct 24 2004

Keywords

Comments

T(n,k) is the number of Łukasiewicz paths of length n having k peaks. A Łukasiewicz path of length n is a path in the first quadrant from (0,0) to (n,0) using rise steps (1,k) for any positive integer k, level steps (1,0) and fall steps (1,-1). Example: T(3,1)=3 because we have HUD, UDH and U(2)DD, where H=(1,0), U(1,1), U(2)=(1,2) and D=(1,-1). (see R. P. Stanley reference). - Emeric Deutsch, Jan 06 2005

Examples

			Table begins
\ k  0,   1,   2, ...
n
0 |  1;
1 |  1;
2 |  1,   1;
3 |  2,   3;
4 |  5,   8,   1;
5 | 13,  23,   6;
6 | 35,  69,  27,  1;
7 | 97, 212, 110, 10;
8 |275, 662, 426, 66, 1;
T(3,1) = 3 because each of UUUDDD, UDUUDD, UUDDUD has one UUDD.
		

References

  • R. P. Stanley, Enumerative Combinatorics, Vol. 2, Cambridge Univ. Press, Cambridge, 1999, p. 223, Exercise 6.19w; the integers are the slopes of the steps. - Emeric Deutsch, Jan 06 2005

Crossrefs

Column k=0 is A025242 (apart from first term).
Cf. A243752.

Programs

  • Maple
    b:= proc(x, y, t) option remember; `if`(y<0 or y>x, 0,
         `if`(x=0, 1, expand(b(x-1, y+1, [2, 3, 3, 2][t])
          +b(x-1, y-1, [1, 1, 4, 1][t])*`if`(t=4, z, 1))))
        end:
    T:= n-> (p-> seq(coeff(p, z, i), i=0..degree(p)))(b(2*n, 0, 1)):
    seq(T(n), n=0..15);  # Alois P. Heinz, Jun 10 2014
  • Mathematica
    T[n_, k_] := Binomial[n-k, k] Binomial[2n-3k, n-k-1] HypergeometricPFQ[{k -n/2-1/2, k-n/2, k-n/2, k-n/2+1/2}, {k-2n/3, k-2n/3+1/3, k-2n/3+2/3}, 16/27]/(n-k); T[0, 0] = 1; Flatten[Table[T[n, k], {n, 0, 15}, {k, 0, n/2}]] (* Jean-François Alcover, Dec 21 2016, after 2nd formula *)

Formula

G.f.: (1 + z^2 - t*z^2 - (-4*z + (-1 - z^2 + t*z^2)^2)^(1/2))/(2*z) = Sum_{n>=0, 0<=k<=n/2} T(n, k)z^n*t^k and it satisfies G = 1 + G^2*z + G*(-z^2 + t*z^2).
T(n,k) = Sum_{j=0..floor(n/2)-k} (-1)^j * binomial(n-(j+k), j+k) * binomial(2n-3(j+k), n-(j+k)-1) * binomial(j+k, k)/(n-(j+k)). - I. Tasoulas (jtas(AT)unipi.gr), Feb 19 2006

A346660 Number of cyclic patterns of length n that avoid the vincular pattern 23-1-4.

Original entry on oeis.org

1, 1, 1, 2, 5, 14, 42, 133, 442, 1537, 5583, 21165, 83707, 345324, 1485687, 6663354, 31134078, 151408319, 765462514, 4017644518, 21860398111, 123120413119, 716701884408, 4305828784896, 26661920519485, 169937265101628, 1113616036893636, 7494786443901137
Offset: 0

Views

Author

Rupert Li, Aug 03 2021

Keywords

Comments

The vincular pattern 23-1-4 requires the 2 and the 3 to be adjacent.
By the trivial Wilf equivalence obtained by reversing the permutations, a(n) is also the number of cyclic patterns of length n that avoid the vincular pattern 32-4-1.

Crossrefs

Formula

For n >= 2, a(n) = Sum_{i=0..n-2} binomial(n-2,i) * A092920(i).

A346661 Number of cyclic patterns of length n that avoid the vincular pattern 23-4-1.

Original entry on oeis.org

1, 1, 2, 5, 15, 50, 180, 690, 2792, 11857, 52633, 243455, 1170525, 5837934, 30151474, 161021581, 888001485, 5051014786, 29600662480, 178541105770, 1107321666920, 7055339825171, 46142654894331, 309513540865544, 2127744119042216, 14979904453920111, 107932371558460341, 795363217306369817, 5990768203554158167, 46094392105916344968, 362092868720288824992
Offset: 0

Views

Author

Rupert Li, Aug 03 2021

Keywords

Comments

The vincular pattern 23-4-1 requires the 2 and the 3 to be adjacent.
By the trivial Wilf equivalence obtained by reversing the permutations, a(n) is also the number of cyclic patterns of length n that avoid the vincular pattern 32-1-4.

Crossrefs

Extensions

More terms from Vaclav Kotesovec, Nov 09 2021, computed by Toufik Mansour and Mark Shattuck
Showing 1-6 of 6 results.