A054424 -id:A054424 - cp's OEIS frontend

A054429 Simple self-inverse permutation of natural numbers: List each block of 2^n numbers (from 2^n to 2^(n+1) - 1) in reverse order.

1, 3, 2, 7, 6, 5, 4, 15, 14, 13, 12, 11, 10, 9, 8, 31, 30, 29, 28, 27, 26, 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 63, 62, 61, 60, 59, 58, 57, 56, 55, 54, 53, 52, 51, 50, 49, 48, 47, 46, 45, 44, 43, 42, 41, 40, 39, 38, 37, 36, 35, 34, 33, 32, 127, 126, 125, 124, 123, 122, 121

Offset: 1

Antti Karttunen

a(n) gives the position of the inverse of the n-th term in the full Stern-Brocot tree: A007305(a(n)+2) = A047679(n) and A047679(a(n)) = A007305(n+2). - Reinhard Zumkeller, Dec 22 2008
From Gary W. Adamson, Jun 21 2012: (Start)
The mapping and conversion rules are as follows:
By rows, we have ...
   1;
   3,  2;
   7,  6,  5,  4;
  15, 14, 13, 12, 11, 10, 9, 8;
  ... onto which we are to map one-half of the Stern-Brocot infinite Farey Tree:
  1/2
  1/3, 2/3
  1/4, 2/5, 3/5, 3/4
  1/5, 2/7, 3/8, 3/7, 4/7, 5/8, 5/7, 4/5
  ...
The conversion rules are: Convert the decimal to binary, adding a duplicate of the rightmost binary term to its right. For example, 10 = 1010, which becomes 10100. Then, from the left, record the number of runs = [1,1,1,2], the continued fraction representation of 5/8. Check: 10 decimal corresponds to 5/8 as shown in the overlaid mapping. Take decimal 9 = 1001 which becomes 10011, with a continued fraction representation of [1,2,2] = 5/7. Check: 9 decimal corresponds to 5/7 in the Farey Tree map. (End)
From Indranil Ghosh, Jan 19 2017: (Start)
a(n) is the value generated when n is converted into its Elias gamma code, the 1's and 0's are interchanged and the resultant is converted back to its decimal value for all values of n > 1. For n = 1, A054429(n) = 1 but after converting 1 to Elias gamma code, interchanging the 1's and 0's and converting it back to decimal, the result produced is 0.
For example, let n = 10. The Elias gamma code for 10 is '1110010'. After interchanging the 1's and 0's it becomes "0001101" and 1101_2 = 13_10. So a(10) = 13. (End)
From Yosu Yurramendi, Mar 09 2017 (similar to Zumkeller's comment): (Start)
A002487(a(n)) = A002487(n+1), A002487(a(n)+1) = A002487(n), n > 0.
A162909(a(n)) = A162910(n), A162910(a(n)) = A162909(n), n > 0.
A162911(a(n)) = A162912(n), A162912(a(n)) = A162911(n), n > 0.
A071766(a(n)) = A245326(n), A245326(a(n)) = A071766(n), n > 0.
A229742(a(n)) = A245325(n), A245325(a(n)) = A229742(n), n > 0.
A020651(a(n)) = A245327(n), A245327(a(n)) = A020651(n), n > 0.
A020650(a(n)) = A245328(n), A245328(a(n)) = A020650(n), n > 0. (End)
From Yosu Yurramendi, Mar 29 2017: (Start)
A063946(a(n)) = a(A063946(n)) = A117120(n), n > 0.
A065190(a(n)) = a(A065190(n)) = A092569(n), n > 0.
A258746(a(n)) = a(A258746(n)) = A165199(n), n > 0.
A258996(a(n)) = a(A258996(n)), n > 0.
A117120(a(n)) = a(A117120(n)), n > 0.
A092569(a(n)) = a(A092569(n)), n > 0. (End)

Reinhard Zumkeller, Table of n, a(n) for n = 1..10000
Ralf Stephan, Some divide-and-conquer sequences ...
Ralf Stephan, Table of generating functions
Index entries for sequences that are permutations of the natural numbers
Index entries for sequences related to binary expansion of n

See also A054424, A054430.
{A000027, A054429, A059893, A059894} form a 4-group.
Cf. A053644, A115303, A115304, A115305, A115306, A115307, A115308, A115309, A106649.
This is Guy Steele's sequence GS(6, 5) (see A135416).

a054429 n = a054429_list !! (n-1)
a054429_list = f [1..] where
   f xs@(x:_) = reverse us ++ f vs where (us, vs) = splitAt x xs
-- Reinhard Zumkeller, Jun 01 2015, Feb 21 2014

A054429 := n -> 3*2^ilog2(n) - n - 1:
seq(A054429(n), n = 1..70); # [Updated by Peter Luschny, Apr 24 2024]

Flatten[Table[Range[2^(n+1)-1,2^n,-1],{n,0,6}]] (* Harvey P. Dale, Dec 17 2013 *)

A054429(n)= 3<<#binary(n\2)-n-1 \\ M. F. Hasler, Aug 18 2014

from itertools import count, islice
def A054429_gen(): # generator of terms
    return (m for n in count(0) for m in range((1<A054429_list = list(islice(A054429_gen(),30)) # Chai Wah Wu, Jul 27 2023

maxblock <- 10 # by choice
a <- NULL
for(m in 0:maxblock) a <- c(a, rev(2^m:(2^(m+1)-1)))
a
# Yosu Yurramendi, Mar 10 2017

a(n) = ReflectBinTreePermutation(n).
a(n) = if n=1 then 1 else 2*a(floor(n/2)) + 1 - n mod 2. - Reinhard Zumkeller, Feb 18 2003
G.f.: 1/(1-x) * ((x-2x^2)/(1-x) + Sum_{k>=0} 3*2^k*x^2^k). - Ralf Stephan, Sep 15 2003
A000120(a(n)) = A000120(A059894(n)) = A023416(n) + 1. - Ralf Stephan, Oct 05 2003
A115310(n, 1) = a(n). - Reinhard Zumkeller, Jan 20 2006
a(1) = 1, a(2^(m+1) + k) = a(2^m+k) + 2^(m+1),
a(2^(m+1) + 2^m+k) = a(2^m+k) + 2^m, m >= 0, 0 <= k < 2^m. - Yosu Yurramendi, Apr 06 2017
a(n) = A117120(A063946(n)) = A063946(A117120(n)) = A092569(A065190(n)) = A065190(A092569(n)), n > 0. - Yosu Yurramendi, Apr 10 2017
a(n) = 3*A053644(n) - n - 1. - Alan Michael Gómez Calderón, Feb 28 2025

A007306 Denominators of Farey tree fractions (i.e., the Stern-Brocot subtree in the range [0,1]).

Original entry on oeis.org

1, 1, 2, 3, 3, 4, 5, 5, 4, 5, 7, 8, 7, 7, 8, 7, 5, 6, 9, 11, 10, 11, 13, 12, 9, 9, 12, 13, 11, 10, 11, 9, 6, 7, 11, 14, 13, 15, 18, 17, 13, 14, 19, 21, 18, 17, 19, 16, 11, 11, 16, 19, 17, 18, 21, 19, 14, 13, 17, 18, 15, 13, 14, 11, 7, 8, 13, 17, 16, 19, 23, 22, 17, 19, 26, 29, 25, 24

Offset: 0

N. J. A. Sloane

Also number of odd entries in n-th row of triangle of Stirling numbers of the second kind (A008277). - Benoit Cloitre, Feb 28 2004
Apparently (except for the first term) the number of odd entries in the alternated diagonals of Pascal's triangle at 45 degrees slope. - Javier Torres (adaycalledzero(AT)hotmail.com), Jul 26 2009
The Kn3 and Kn4 triangle sums, see A180662 for their definitions, of Sierpiński's triangle A047999 equal a(n+1). - Johannes W. Meijer, Jun 05 2011
From Yosu Yurramendi, Jun 23 2014: (Start)
If the terms (n>1) are written as an array:
  2,
  3,  3,
  4,  5,  5,  4,
  5,  7,  8,  7,  7,  8,  7,  5,
  6,  9, 11, 10, 11, 13, 12,  9,  9, 12, 13, 11, 10, 11,  9,  6,
  7, 11, 14, 13, 15, 18, 17, 13, 14, 19, 21, 18, 17, 19, 16, 11, 11, 16, 19,17,18,
then the sum of the k-th row is 2*3^(k-2), each column is an arithmetic progression. The differences of the arithmetic progressions give the sequence itself (a(2^(m+1)+1+k) - a(2^m+1+k) = a(k+1), m >= 1, 1 <= k <= 2^m), because a(n) = A002487(2*n-1) and A002487 has these properties. A071585 also has these properties. Each row is a palindrome: a(2^(m+1)+1-k) = a(2^m+k), m >= 0, 1 <= k <= 2^m.
If the terms (n>0) are written in this way:
  1,
  2, 3,
  3, 4,  5,  5,
  4, 5,  7,  8,  7,  7,  8,  7,
  5, 6,  9, 11, 10, 11, 13, 12,  9,  9, 12, 13, 11, 10, 11,  9,
  6, 7, 11, 14, 13, 15, 18, 17, 13, 14, 19, 21, 18, 17, 19, 16, 11, 11, 16, 19,
each column is an arithmetic progression and the steps also give the sequence itself (a(2^(m+1)+k) - a(2^m+k) = a(k), m >= 0, 0 <= k < 2^m). Moreover, by removing the first term of each column:
a(2^(m+1)+k) = A049448(2^m+k+1), m >= 0, 0 <= k < 2^m.
(End)
k > 1 occurs in this sequence phi(k) = A000010(k) times. - Franklin T. Adams-Watters, May 25 2015
Except for the initial 1, this is the odd bisection of A002487. The even bisection of A002487 is A002487 itself. - Franklin T. Adams-Watters, May 25 2015
For all m >= 0, max_{k=1..2^m} a(2^m+k) = A000045(m+3) (Fibonacci sequence). - Yosu Yurramendi, Jun 05 2016
For all n >= 2, max(m: a(2^m+k) = n, 1<=k<=2^m) = n-2. - Yosu Yurramendi, Jun 05 2016
a(2^m+1) = m+2, m >= 0; a(2^m+2) = 2m+1, m>=1; min_{m>=0, k=1..2^m} a(2^m+k) = m+2; min_{m>=2, k=2..2^m-1} a(2^m+k) = 2m+1. - Yosu Yurramendi, Jun 06 2016
a(2^(m+2) + 2^(m+1) - k) - a(2^(m+1) + 2^m-k) = 2*a(k+1), m >= 0, 0 <= k <= 2^m. - Yosu Yurramendi, Jun 09 2016
If the initial 1 is omitted, this is the number of nonzero entries in row n of the generalized Pascal triangle P_2, see A282714 [Leroy et al., 2017]. - N. J. A. Sloane, Mar 02 2017
Apparently, this sequence was introduced by Johann Gustav Hermes in 1894. His paper gives a strong connection between this sequence and the so-called "Gaussian brackets" ("Gauss'schen Klammer"). For an independent discussion about Gaussian brackets, see the relevant MathWorld article and the article by Herzberger (1943). Srinivasan (1958) gave another, more modern, explanation of the connection between this sequence and the Gaussian brackets. (Parenthetically, J. G. Hermes is the mathematician who completed or constructed the regular polygon with 65537 sides.) - Petros Hadjicostas, Sep 18 2019

			[ 0/1; 1/1; ] 1/2; 1/3, 2/3; 1/4, 2/5, 3/5, 3/4; 1/5, 2/7, 3/8, 3/7, 4/7, 5/8, 5/7, 4/5; ...

P. Bachmann, Niedere Zahlentheorie (1902, 1910), reprinted Chelsea, NY, 1968, vol. 2, p. 61.
L. E. Dickson, History of the Theory of Numbers. Carnegie Institute Public. 256, Washington, DC, Vol. 1, 1919; Vol. 2, 1920; Vol. 3, 1923, see vol. 1, p. 158.
J. C. Lagarias, Number Theory and Dynamical Systems, pp. 35-72 of S. A. Burr, ed., The Unreasonable Effectiveness of Number Theory, Proc. Sympos. Appl. Math., 46 (1992). Amer. Math. Soc.
N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Alois P. Heinz, Table of n, a(n) for n = 0..10000
Suayb S. Arslan, Asymptotically MDS Array BP-XOR Codes, arXiv:1709.07949 [cs.IT], 2017.
Alexander Bogomolny, Stern-Brocot tree.
J. Hermes, Anzahl der Zerlegungen einer ganzen, rationalen Zahl in Summanden (The number of partitions of a rational integer, Part I), Mathematischen Annalen 45(3) (1894), 371-380.
J. Hermes, Anzahl der Zerlegungen einer ganzen, rationalen Zahl in Summanden (The number of partitions of a rational integer, Part I), Mathematischen Annalen 45(3) (1894), 371-380.
J. Hermes, Anzahl der Zerlegungen einer ganzen, rationalen Zahl in Summanden, II (The number of partitions of a rational integer, Part II), Mathematischen Annalen 47(2-3) (1896), 281-297.
M. Herzberger, Gaussian optics and Gaussian brackets, Journal of the Optical Society of America 33(12) (1943), 651-655. [This paper gives a clear description of Gaussian brackets that are related to this sequence as explained by Hermes (1894).]
Jennifer Lansing, On the Stern sequence and a related sequence, Ph.D. dissertation in Mathematics, University of Illinois at Urbana-Champaign, 2014. [This doctoral dissertation discusses the so-called Stern sequence on which Hermes' papers are based (according to Srinivasan (1958)).]
Julien Leroy, Michel Rigo, and Manon Stipulanti, Counting the number of non-zero coefficients in rows of generalized Pascal triangles, Discrete Mathematics 340 (2017), 862-881.
Julien Leroy, Michel Rigo, and Manon Stipulanti, Counting subword occurrences in base-b expansions, Integers (2018) 18A, Article #A13.
G. Melançon, Lyndon factorization of sturmian words, Discr. Math. 210 (2000), 137-149.
N. J. A. Sloane, Stern-Brocot or Farey Tree.
M. S. Srinivasan, The enumeration of positive rational numbers, Proc. Indian Acad. Sci. Sect. A 47 (1958), 12-24.
M. Stern, Über eine zahlentheoretische Function, Journal für die reine und angewandte Mathematik 55 (1858), 193-220. [According to Srinivasan (1958), Hermes's (1894) paper, where this sequence is introduced, is based on Stern's sequence.]
Manon Stipulanti, Convergence of Pascal-Like Triangles in Parry-Bertrand Numeration Systems, arXiv:1801.03287 [math.CO], 2018.
Javier Torres Suarez, Number theory - geometric connection (part 2) (YouTube video that mentions this sequence - link sent by Pacha Nambi, Aug 26 2009).
Eric Weisstein's World of Mathematics, Gaussian brackets; they are related to this sequence.
Wikipedia, Johann Gustav Hermes. [He is the person who introduced this sequence and the person who completed or constructed a regular polygon with 65537 sides.]
Index entries for fraction trees
Index entries for sequences related to Stern's sequences

For numerators see A007305.
Cf. A001222, A002487, A006842, A006843, A047679, A054424, A065674-A065675, A065810, A260443, A277324, A277328, A283986, A283987, A283988, A284009, A284265, A284266, A284267, A284268, A284565, A284566, A285106, A285107, A285108, A287731, A287732.
See also A282714.

[1] cat [&+[Binomial(n+k,2*k) mod 2: k in [0..n]]: n in [0..80]]; // Vincenzo Librandi, Jun 10 2019

A007306 := proc(n): if n=0 then 1 else A002487(2*n-1) fi: end: A002487 := proc(m) option remember: local a, b, n; a := 1; b := 0; n := m; while n>0 do if type(n, odd) then b := a + b else a := a + b end if; n := floor(n/2); end do; b; end proc: seq(A007306(n),n=0..77); # Johannes W. Meijer, Jun 05 2011

a[0] = 1; a[n_] := Sum[ Mod[ Binomial[n+k-1, 2k] , 2], {k, 0, n}]; Table[a[n], {n, 0, 77}] (* Jean-François Alcover, Dec 16 2011, after Paul Barry *)
a[0] = 0; a[1] = 1;
Flatten[{1,Table[a[2*n] = a[n]; a[2*n + 1] = a[n] + a[n + 1], {n, 0, 50}]}] (* Horst H. Manninger, Jun 09 2021 *)

{a(n) = if( n<1, n==0, n--; sum( k=0, n, binomial( n+k, n-k)%2))};

{a(n) = my(m); if( n<2, n>=0, m = 2^length( binary( n-1)); a(n - m/2) + a(m-n+1))}; /* Michael Somos, May 30 2005 */

from sympy import binomial
def a(n):
    return 1 if n<1 else sum(binomial(n + k - 1, 2*k) % 2 for k in range(n + 1))
print([a(n) for n in range(101)]) # Indranil Ghosh, Mar 22 2017

from functools import reduce
def A007306(n): return sum(reduce(lambda x,y:(x[0],sum(x)) if int(y) else (sum(x),x[1]),bin((n<<1)-1)[-1:2:-1],(1,0))) if n else 1 # Chai Wah Wu, May 18 2023

maxrow <- 6 # by choice
a <- c(1,2)
for(m in 0:maxrow) for(k in 1:2^m){
  a[2^(m+1)+k  ] <- a[2^m+k] + a[k]
  a[2^(m+1)-k+1] <- a[2^m+k]
}
a
# Yosu Yurramendi, Jan 05 2015

# Given n, compute directly a(n)
# by taking into account the binary representation of n-1
# aa <- function(n){
  b <- as.numeric(intToBits(n))
  l <- sum(b)
  m <- which(b == 1)-1
  d <- 1
  if(l > 1) for(j in 1:(l-1)) d[j] <- m[j+1]-m[j]+1
  f <- c(1,m[1]+2) # In A002487: f <- c(0,1)
  if(l > 1) for(j in 3:(l+1)) f[j] <- d[j-2]*f[j-1]-f[j-2]
  return(f[l+1])
}
# a(0) = 1, a(1) = 1, a(n) = aa(n-1)   n > 1
#
# Example
n <- 73
aa(n-1)
#
# Yosu Yurramendi, Dec 15 2016

@CachedFunction
def a(n):
    return a((odd_part(n-1)+1)/2)+a((odd_part(n)+1)/2) if n>1 else 1
[a(n) for n in (0..77)] # after Alessandro De Luca, Peter Luschny, May 20 2014

def A007306(n):
    if n == 0: return 1
    M = [1, 1]
    for b in (n-1).bits():
        M[b] = M[0] + M[1]
    return M[1]
print([A007306(n) for n in (0..77)]) # Peter Luschny, Nov 28 2017

(define (A007306 n) (if (zero? n) 1 (A002487 (+ n n -1)))) ;; Code for A002487 given in that entry. - Antti Karttunen, Mar 21 2017

Recurrence: a(0) to a(8) are 1, 1, 2, 3, 3, 4, 5, 5, 4; thereafter a(n) = a(n-2^p) + a(2^(p+1)-n+1), where 2^p < n <= 2^(p+1). [J. Hermes, Math. Ann., 1894; quoted by Dickson, Vol. 1, p. 158] - N. J. A. Sloane, Mar 24 2019
a(4*n) = -a(n)+2*a(2*n); a(4*n+1) = -a(n)+a(2*n)+a(2*n+1); a(4*n+2)=a(n)-a(2*n)+2*a(2*n+1); a(4*n+3) = 4*a(n)-4*a(2*n)+3*a(2*n+1). Thus a(n) is a 2-regular sequence. - Jeffrey Shallit, Dec 26 2024
For n > 0, a(n) = A002487(n-1) + A002487(n) = A002487(2*n-1).
a(0) = 1; a(n) = Sum_{k=0..n-1} C(n-1+k, n-1-k) mod 2, n > 0. - Benoit Cloitre, Jun 20 2003
a(n+1) = Sum_{k=0..n} binomial(2*n-k, k) mod 2; a(n) = 0^n + Sum_{k=0..n-1} binomial(2(n-1)-k, k) mod 2. - Paul Barry, Dec 11 2004
a(n) = Sum_{k=0..n} C(n+k,2*k) mod 2. - Paul Barry, Jun 12 2006
a(0) = a(1) = 1; a(n) = a(A003602(n-1)) + a(A003602(n)), n > 1. - Alessandro De Luca, May 08 2014
a(n) = A007305(n+(2^m-1)), m=A029837(n), n=1,2,3,... . - Yosu Yurramendi, Jul 04 2014
a(n) = A007305(2^(m+1)-n) - A007305(2^m-n), m >= (A029837(n)+1), n=1,2,3,... - Yosu Yurramendi, Jul 05 2014
a(2^m) = m+1, a(2^m+1) = m+2 for m >= 0. - Yosu Yurramendi, Jan 01 2015
a(n+2) = A007305(n+2) + A047679(n) n >= 0. - Yosu Yurramendi, Mar 30 2016
a(2^m+2^r+k) = a(2^r+k)(m-r+1) - a(k), m >= 2, 0 <= r <= m-1, 0 <= k < 2^r. Example: a(73) = a(2^6+2^3+1) = a(2^3+1)*(6-3+1) - a(1) = 5*4 - 1 = 19 . - Yosu Yurramendi, Jul 19 2016
From Antti Karttunen, Mar 21 2017 & Apr 12 2017: (Start)
For n > 0, a(n) = A001222(A277324(n-1)) = A001222(A260443(n-1)*A260443(n)).
The following decompositions hold for all n > 0:
a(n) = A277328(n-1) + A284009(n-1).
a(n) = A283986(n) + A283988(n) = A283987(n) + 2*A283988(n).
a(n) = 2*A284265(n-1) + A284266(n-1).
a(n) = A284267(n-1) + A284268(n-1).
a(n) = A284565(n-1) + A284566(n-1).
a(n) = A285106(n-1) + A285108(n-1) = A285107(n-1) + 2*A285108(n-1). (End)
a(A059893(n)) = a(n+1) for n > 0. - Yosu Yurramendi, May 30 2017
a(n) = A287731(n) + A287732(n) for n > 0. - I. V. Serov, Jun 09 2017
a(n) = A287896(n) + A288002(n) for n > 1.
a(n) = A287896(n-1) + A002487(n-1) - A288002(n-1) for n > 1.
a(n) = a(n-1) + A002487(n-1) - 2*A288002(n-1) for n > 1. - I. V. Serov, Jun 14 2017
From Yosu Yurramendi, May 14 2019: (Start)
For m >= 0, M >= m, 0 <= k < 2^m,
a((2^(m+1) + A119608(2^m+k+1))*2^(M-m) - A000035(2^m+k)) =
a((2^(m+2) - A119608(2^m+k+1))*2^(M-m) - A000035(2^m+k)-1) =
a(2^(M+2) - (2^m+k)) = a(2^(M+1) + (2^m+k) + 1) =
a(2^m+k+1)*(M-m) + a(2^(m+1)+2^m+k+1). (End)
a(k) = sqrt(A007305(2^(m+1)+k)*A047679(2^(m+1)+k-2) - A007305(2^m+k)*A047679(2^m+k-2)), m >= 0, 0 <= k < 2^m. - Yosu Yurramendi, Jun 09 2019
G.f.: 1 + x * (1 + x) * Product_{k>=0} (1 + x^(2^k) + x^(2^(k+1))). - Ilya Gutkovskiy, Jul 19 2019
Conjecture: a(n) = a(n-1) + b(n-1) - 2*(a(n-1) mod b(n-1)) for n > 1 with a(0) = a(1) = 1 where b(n) = a(n) - b(n-1) for n > 1 with b(1) = 1. - Mikhail Kurkov, Mar 13 2022

Formula fixed and extended by Franklin T. Adams-Watters, Jul 07 2009

Incorrect Maple program removed by Johannes W. Meijer, Jun 05 2011

A038566 Numerators in canonical bijection from positive integers to positive rationals <= 1: arrange fractions by increasing denominator then by increasing numerator.

Original entry on oeis.org

1, 1, 1, 2, 1, 3, 1, 2, 3, 4, 1, 5, 1, 2, 3, 4, 5, 6, 1, 3, 5, 7, 1, 2, 4, 5, 7, 8, 1, 3, 7, 9, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 1, 5, 7, 11, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 1, 3, 5, 9, 11, 13, 1, 2, 4, 7, 8, 11, 13, 14, 1, 3, 5, 7, 9, 11, 13, 15, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16

Offset: 1

N. J. A. Sloane

For denominators see A038567.
Row n has length A000010(n).
Also numerators in canonical bijection from positive integers to all positive rational numbers: arrange fractions in triangle in which in the n-th row the phi(n) numbers are the fractions i/j with gcd(i,j) = 1, i+j=n, i=1..n-1, j=n-1..1. n>=2. Denominators (A020653) are obtained by reversing each row.
Also triangle in which n-th row gives phi(n) numbers between 1 and n that are relatively prime to n.
A038610(n) = least common multiple of n-th row. - Reinhard Zumkeller, Sep 21 2013
Row n has sum A023896(n). - Jamie Morken, Dec 17 2019
This irregular triangle gives in row n the smallest positive reduced residue system modulo n, for n >= 1. If one takes 0 for n = 1 it becomes the smallest nonnegative residue system modulo n. - Wolfdieter Lang, Feb 29 2020

			The beginning of the list of positive rationals <= 1: 1/1, 1/2, 1/3, 2/3, 1/4, 3/4, 1/5, 2/5, 3/5, .... This is A038566/A038567.
The beginning of the triangle giving all positive rationals: 1/1; 1/2, 2/1; 1/3, 3/1; 1/4, 2/3, 3/2, 4/1; 1/5, 5/1; 1/6, 2/5, 3/4, 4/3, 5/2, 6/1; .... This is A020652/A020653, with A020652(n) = A038566(n+1). [Corrected by _M. F. Hasler_, Mar 06 2020]
The beginning of the triangle in which n-th row gives numbers between 1 and n that are relatively prime to n:
n\k 1 2 3  4  5  6  7  8 9 10 11 12 13 14 15 16 17 18
1:  1
2:  1
3:  1 2
4:  1 3
5:  1 2 3  4
6:  1 5
7:  1 2 3  4  5  6
8:  1 3 5  7
9:  1 2 4  5  7  8
10: 1 3 7  9
11: 1 2 3  4  5  6  7  8 9 10
12: 1 5 7 11
13: 1 2 3  4  5  6  7  8 9 10 11 12
14: 1 3 5  9 11 13
15: 1 2 4  7  8 11 13 14
16: 1 3 5  7  9 11 13 15
17: 1 2 3  4  5  6  7  8 9 10 11 12 13 14 15 16
18: 1 5 7 11 13 17
19: 1 2 3  4  5  6  7  8 9 10 11 12 13 14 15 16 17 18
20: 1 3 7  9 11 13 17 19
... Reformatted. - _Wolfdieter Lang_, Jan 18 2017
------------------------------------------------------

Richard Courant and Herbert Robbins. What Is Mathematics?, Oxford, 1941, pp. 79-80.
H. Lauwerier, Fractals, Princeton Univ. Press, p. 23.
James J. Tattersall, Elementary Number Theory in Nine Chapters, Cambridge University Press, 1999, page 163.

David Wasserman, Table of n, a(n) for n = 1..100001
Wolfdieter Lang, Rows of rationals, n=2..25.
Index entries for "core" sequences
Index entries for sequences related to enumerating the rationals
Index entries for sequences related to Stern's sequences

Cf. A020652, A020653, A038566, A038567, A038568, A038569, A000010 (row lengths), A002088, A060837, A071970, A002260.
A054424 gives mapping to Stern-Brocot tree.
Row sums give rationals A111992(n)/A069220(n), n>=1.
A112484 (primes, rows n >=3).

a038566 n k = a038566_tabf !! (n-1) !! (k-1)
a038566_row n = a038566_tabf !! (n-1)
a038566_tabf=
   zipWith (\v ws -> filter ((== 1) . (gcd v)) ws) [1..] a002260_tabl
a038566_list = concat a038566_tabf
-- Reinhard Zumkeller, Sep 21 2013, Feb 23 2012

s := proc(n) local i,j,k,ans; i := 0; ans := [ ]; for j while i

Flatten[Table[Flatten[Position[GCD[Table[Mod[j, w], {j, 1, w-1}], w], 1]], {w, 1, 100}], 2]
row[n_]:=Select[Range[n],GCD[n,#]==1 &]; Array[row,17]//Flatten (* Stefano Spezia, Jul 20 2025 *)

first(n)=my(v=List(),i,j);while(iCharles R Greathouse IV, Feb 07 2013

row(n) = select(x->gcd(n, x)==1, [1..n]); \\ Michel Marcus, May 05 2020

def aRow(n):
    if n == 1: return 1
    return [k for k in ZZ(n).coprime_integers(n+1)]
print(flatten([aRow(n) for n in range(1, 18)])) # Peter Luschny, Aug 17 2020

The n-th "clump" consists of the phi(n) integers <= n and prime to n.
a(n) = A002260(A169581(n)). - Reinhard Zumkeller, Dec 02 2009
a(n+1) = A020652(n) for n > 1. - Georg Fischer, Oct 27 2020

More terms from Erich Friedman

Offset corrected by Max Alekseyev, Apr 26 2010

A007305 Numerators of Farey (or Stern-Brocot) tree fractions.

Original entry on oeis.org

0, 1, 1, 1, 2, 1, 2, 3, 3, 1, 2, 3, 3, 4, 5, 5, 4, 1, 2, 3, 3, 4, 5, 5, 4, 5, 7, 8, 7, 7, 8, 7, 5, 1, 2, 3, 3, 4, 5, 5, 4, 5, 7, 8, 7, 7, 8, 7, 5, 6, 9, 11, 10, 11, 13, 12, 9, 9, 12, 13, 11, 10, 11, 9, 6, 1, 2, 3, 3, 4, 5, 5, 4, 5, 7, 8, 7, 7, 8, 7, 5, 6, 9, 11, 10, 11, 13, 12, 9, 9, 12, 13, 11

Offset: 0

N. J. A. Sloane

From Yosu Yurramendi, Jun 25 2014: (Start)
If the terms (n>0) are written as an array (left-aligned fashion) with rows of length 2^m, m = 0,1,2,3,...
   1,
   1,2,
   1,2,3,3,
   1,2,3,3,4,5,5,4,
   1,2,3,3,4,5,5,4,5,7,8,7,7,8,7,5,
   1,2,3,3,4,5,5,4,5,7,8,7,7,8,7,5,6,9,11,10,11,13,12,9,9,12,13,11,10,11,9,6,
then the sum of the m-th row is 3^m (m = 0,1,2,), each column k is constant, and the constants are from A007306, denominators of Farey (or Stern-Brocot) tree fractions (see formula).
If the rows are written in a right-aligned fashion:
                                                                          1,
                                                                        1,2,
                                                                   1, 2,3,3,
                                                       1, 2, 3, 3, 4, 5,5,4,
                                  1,2, 3, 3, 4, 5, 5,4,5, 7, 8, 7, 7, 8,7,5,
  1,2,3,3,4,5,5,4,5,7,8,7,7,8,7,5,6,9,11,10,11,13,12,9,9,12,13,11,10,11,9,6,
then each column is an arithmetic sequence. The differences of the arithmetic sequences also give the sequence A007306 (see formula). The first terms of columns are from A007305 itself (a(A004761(n+1)) = a(n), n>0), and the second ones from A049448 (a(A004761(n+1)+2^A070941(n)) = A049448(n), n>0). (End)
If the sequence is considered in blocks of length 2^m, m = 0,1,2,..., the blocks are the reverse of the blocks of A047679: (a(2^m+1+k) = A047679(2^(m+1)-2-k), m = 0,1,2,..., k = 0,1,2,...,2^m-1). - Yosu Yurramendi, Jun 30 2014

			A007305/A007306 = [ 0/1; 1/1; ] 1/2; 1/3, 2/3; 1/4, 2/5, 3/5, 3/4; 1/5, 2/7, 3/8, 3/7, 4/7, 5/8, 5/7, 4/5, ...
Another version of Stern-Brocot is A007305/A047679 = 1, 2, 1/2, 3, 1/3, 3/2, 2/3, 4, 1/4, 4/3, 3/4, 5/2, 2/5, 5/3, 3/5, 5, 1/5, 5/4, 4/5, ...

R. L. Graham, D. E. Knuth and O. Patashnik, Concrete Mathematics. Addison-Wesley, Reading, MA, 1990, p. 117.
G. H. Hardy and E. M. Wright, An Introduction to the Theory of Numbers. 3rd ed., Oxford Univ. Press, 1954, p. 23.
J. C. Lagarias, Number Theory and Dynamical Systems, pp. 35-72 of S. A. Burr, ed., The Unreasonable Effectiveness of Number Theory, Proc. Sympos. Appl. Math., 46 (1992). Amer. Math. Soc.
W. J. LeVeque, Topics in Number Theory. Addison-Wesley, Reading, MA, 2 vols., 1956, Vol. 1, p. 154.
I. Niven and H. S. Zuckerman, An Introduction to the Theory of Numbers. 2nd ed., Wiley, NY, 1966, p. 141.
N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

T. D. Noe, Table of n, a(n) for n=0..4096
A. Bogomolny, Stern-Brocot Tree
A. Bogomolny, Inspiration for Maple code
A. Brocot, Calcul des rouages par approximation, nouvelle méthode, Revue Chonométrique 3, 186-194, 1861.
G. A. Jones, The Farey graph, Séminaire Lotharingien de Combinatoire, B18e (1987), 2 pp.
Shin-ichi Katayama, Modified Farey trees and Pythagorean triples, Journal of mathematics, the University of Tokushima, 47, 2013.
G. Melançon, Lyndon factorization of sturmian words, Discr. Math., 210 (2000), 137-149.
Hugo Pfoertner, Ratio A007305(n)/A007306(n) vs n, using Plot 2.
N. J. A. Sloane, Stern-Brocot or Farey Tree
Noam Zimhoni, A forest of Eisensteinian triplets, arXiv:1904.11782 [math.NT], 2019.
Index entries for fraction trees
Index entries for sequences related to Stern's sequences

Cf. A007306, A006842, A006843, A047679, A054424, A057114, A152975.

A007305 := proc(n) local b; b := proc(n) option remember; local msb, r;
if n < 3 then return 1 fi; msb := ilog2(n); r := n - 2^msb;
if ilog2(r) = msb - 1 then b(r) + b(3*2^(msb-1) - r - 1) else b(2^(msb - 1) + r) fi end: if n = 0 then 0 else b(n-1) fi end: # Antti Karttunen, Mar 19 2000 [Corrected and rewritten by Peter Luschny, Apr 24 2024]
seq(A007305(n), n = 0..92);

sbt[n_] := Module[{R,L,Y}, R={{1,0},{1,1}}; L={{1,1},{0,1}}; Y={{1,0},{0,1}}; w[b_] := Fold[ #1.If[ #2 == 0,L,R] &,Y,b]; u[a_] := {a[[2,1]]+a[[2,2]],a[[1,1]]+a[[1,2]]}; Map[u,Map[w,Tuples[{0,1},n]]]]
A007305(n) = Flatten[Append[{0,1},Table[Map[First,sbt[i]],{i,0,5}]]]
A047679(n) = Flatten[Table[Map[Last,sbt[i]],{i,0,5}]]
(* Peter Luschny, Apr 27 2009 *)

a <- 1
for(m in 1:6) for(k in 0:(2^(m-1)-1)) {
  a[2^m+        k] <- a[2^(m-1)+k]
  a[2^m+2^(m-1)+k] <- a[2^(m-1)+k] + a[2^m-k-1]
}
a
# Yosu Yurramendi, Jun 25 2014

a(n) = SternBrocotTreeNum(n-1) # n starting from 2 gives the sequence from 1, 1, 2, 1, 2, 3, 3, 1, 2, 3, 3, 4, 5, 5, 4, 1, ...
From Reinhard Zumkeller, Dec 22 2008: (Start)
For n > 1: a(n+2) = if A025480(n-1) != 0 and A025480(n) != 0 then a(A025480(n-1)+2) + a(A025480(n)+2) else if A025480(n)=0 then a(A025480(n-1)+2)+1 else 0 + a(A025480(n-1)+2).
a(A054429(n)+2) = A047679(n).
a(n+2) = A047679(A054429(n)).
A153036(n+1) = floor(a(n+2)/A047679(n)). (End)
From Yosu Yurramendi, Jun 25 2014: (Start)
For m = 1,2,3,..., and k = 0,1,2,...,2^(m-1)-1, with a(1)=1:
a(2^m+k) = a(2^(m-1)+k);
a(2^m+2^(m-1)+k) = a(2^(m-1)+k) + a(2^m-k-1). (End)
a(2^(m+2)-k) = A007306(2^(m+1)-k), m=0,1,2,..., k=0,1,2,...,2^m-1. - Yosu Yurramendi, Jul 04 2014
a(2^(m+1)+2^m+k) - a(2^m+k) = A007306(2^m-k+1), m=1,2,..., k=1,2,...,2^(m-1). - Yosu Yurramendi, Jul 05 2014
From Yosu Yurramendi, Jan 01 2015: (Start)
a(2^m+2^q-1) = q+1, q = 0, 1, 2,..., m = q, q+1, q+2,...
a(2^m+2^q)   = q+2, q = 0, 1, 2,..., m = q+1, q+2, q+3,... (End)
a(2^m+k) = A007306(k+1), m >= 0, 0 <= k < 2*m.  - Yosu Yurramendi, May 20 2019
a(n) = A002487(A059893(n)), n > 0. - Yosu Yurramendi, Sep 29 2021

A047679 Denominators in full Stern-Brocot tree.

Original entry on oeis.org

1, 2, 1, 3, 3, 2, 1, 4, 5, 5, 4, 3, 3, 2, 1, 5, 7, 8, 7, 7, 8, 7, 5, 4, 5, 5, 4, 3, 3, 2, 1, 6, 9, 11, 10, 11, 13, 12, 9, 9, 12, 13, 11, 10, 11, 9, 6, 5, 7, 8, 7, 7, 8, 7, 5, 4, 5, 5, 4, 3, 3, 2, 1, 7, 11, 14, 13, 15, 18, 17, 13, 14, 19, 21, 18, 17, 19, 16, 11, 11, 16, 19, 17, 18

Offset: 0

Wouter Meeussen

Numerators are A007305.
Write n in binary; list run lengths; add 1 to last run length; make into continued fraction. Sequence gives denominator of fraction obtained.
From Reinhard Zumkeller, Dec 22 2008: (Start)
  For n > 1: a(n) = if A025480(n-1) != 0 and A025480(n) != 0 then = a(A025480(n-1)) + a(A025480(n)) else if A025480(n)=0 then a(A025480(n-1))+0 else 1+a(A025480(n-1));
  a(n) = A007305(A054429(n)+2) and a(A054429(n)) = A007305(n+2);
  A153036(n+1) = floor(A007305(n+2)/a(n)). (End)
From Yosu Yurramendi, Jun 25 2014 and Jun 30 2014: (Start)
If the terms are written as an array a(m, k) = a(2^(m-1)-1+k) with m >= 1 and k = 0, 1, ..., 2^(m-1)-1:
 1,
 2,1,
 3,3, 2, 1,
 4,5, 5, 4, 3, 3, 2,1,
 5,7, 8, 7, 7, 8, 7,5,4, 5, 5, 4, 3, 3,2,1,
 6,9,11,10,11,13,12,9,9,12,13,11,10,11,9,6,5,7,8,7,7,8,7,5,4,5,5,4,3,3,2,1,
then the sum of the m-th row is 3^(m-1), and each column is an arithmetic sequence. The differences of these arithmetic sequences give the sequence A007306(k+1). The first terms of columns are 1 for k = 0 and a(k-1) for k >= 1.
In a row reversed version A(m, k) = a(m, m-(k+1)):
 1
 1,2
 1,2,3,3,
 1,2,3,3,4,5,5,4
 1,2,3,3,4,5,5,4,5,7,8,7,7,8,7,5
 1,2,3,3,4,5,5,4,5,7,8,7,7,8,7,5,6,9,11,10,11,13,12,12,9,9,12,13,11,10,11,9,6
each column k >= 0 is constant, namely A007306(k+1).
This row reversed version coincides with the array for A007305 (see the Jun 25 2014 comment there). (End)
Looking at the plot, the sequence clearly shows a fractal structure. (The repeating pattern oddly resembles the [first completed] facade of the Sagrada Familia!) - Daniel Forgues, Nov 15 2019

			E.g., 57->111001->[ 3,2,1 ]->[ 3,2,2 ]->3 + 1/(2 + 1/(2) ) = 17/2. For n=1,2, ... we get 2, 3/2, 3, 4/3, 5/3, 5/2, 4, 5/4, 7/5, 8/5, ...
1; 2,1; 3,3,2,1; 4,5,5,4,3,3,2,1; ....
Another version of Stern-Brocot is A007305/A047679 = 1, 2, 1/2, 3, 1/3, 3/2, 2/3, 4, 1/4, 4/3, 3/4, 5/2, 2/5, 5/3, 3/5, 5, 1/5, 5/4, 4/5, ...

Alois P. Heinz, Table of n, a(n) for n = 0..10000
N. J. A. Sloane, Stern-Brocot or Farey Tree
Index entries for fraction trees
Index entries for sequences related to Stern's sequences

Cf. A007305, A007306, A054424, A152976.

CFruns[ n_Integer ] := Fold[ #2+1/#1&, Infinity, Reverse[ MapAt[ #+1&, Length/@Split[ IntegerDigits[ n, 2 ] ], {-1} ] ] ]
(* second program: *)
a[n_] := Module[{LL = Length /@ Split[IntegerDigits[n, 2]]}, LL[[-1]] += 1; FromContinuedFraction[LL] // Denominator]; Table[a[n], {n, 1, 100}] (* Jean-François Alcover, Feb 25 2016 *)

{a(n) = local(v, w); v = binary(n++); w = [1]; for( n=2, #v, if( v[n] != v[n-1], w = concat(w, 1), w[#w]++)); w[#w]++; contfracpnqn(w)[2, 1]} /* Michael Somos, Jul 22 2011 */

a <- 1
for(m in 1:6) for(k in 0:(2^(m-1)-1)) {
  a[2^m+        k] = a[2^(m-1)+k] + a[2^m-k-1]
  a[2^m+2^(m-1)+k] = a[2^(m-1)+k]
}
a
# Yosu Yurramendi, Dec 31 2014

a(n) = SternBrocotTreeDen(n) # n starting from 1.
From Yosu Yurramendi, Jul 02 2014: (Start)
For m >0 and 0 <= k < 2^(m-1), with a(0)=1, a(1)=2:
a(2^m+k-1) = a(2^(m-1)+k-1) + a((2^m-1)-k-1);
a(2^m+2^(m-1)+k-1) = a(2^(m-1)+k-1). (End)
a(2^m-2^q  ) = q+1, q >= 0, m > q
a(2^m-2^q-1) = q+2, q >= 0, m > q+1. - Yosu Yurramendi, Jan 01 2015
a(2^(m+1)-1-k) = A007306(k+1), m >= 0, 0 <= k <= 2^m. - Yosu Yurramendi, May 20 2019
a(n) = A002487(1+A059893(n)), n > 0. - Yosu Yurramendi, Sep 29 2021

Edited by Wolfdieter Lang, Mar 31 2015

A020652 Numerators in canonical bijection from positive integers to positive rationals.

Original entry on oeis.org

1, 1, 2, 1, 3, 1, 2, 3, 4, 1, 5, 1, 2, 3, 4, 5, 6, 1, 3, 5, 7, 1, 2, 4, 5, 7, 8, 1, 3, 7, 9, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 1, 5, 7, 11, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 1, 3, 5, 9, 11, 13, 1, 2, 4, 7, 8, 11, 13, 14, 1, 3, 5, 7, 9, 11, 13, 15, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 1, 5

Offset: 1

David W. Wilson

a(A002088(n)) = 1 for n > 1. - Reinhard Zumkeller, Jul 29 2012
When read as an irregular table with each 1 entry starting a new row, then the n-th row consists of the set of multiplicative units of Z_{n+1}. These rows form a group under multiplication mod n. - Tom Edgar, Aug 20 2013
The pair of sequences A020652/A020653 is defined by ordering the positive fractions p/q (reduced to lowest terms) by increasing p+q, then increasing p: 1/1; 1/2, 2/1; 1/3, 3/1; 1/4, 2/3, 3/2, 4/1; 1/5, 5/1; 2/5, 3/4, 4/3, 5/2; etc. For given p+q, there are A000010(p+q) fractions, listed starting at index A002088(p+q-1). - M. F. Hasler, Mar 06 2020

			Arrange positive fractions < 1 by increasing denominator then by increasing numerator: 1/2, 1/3, 2/3, 1/4, 3/4, 1/5, 2/5, 3/5, 4/5, 1/6 ... (this is A020652/A038567). - _William Rex Marshall_, Dec 16 2010

S. Cook, Problem 511: An Enumeration Problem, Journal of Recreational Mathematics, Vol. 9:2 (1976-77), 137. Solution by the Problem Editor, JRM, Vol. 10:2 (1977-78), 122-123.
Richard Courant and Herbert Robbins. What Is Mathematics?, Oxford, 1941, pp. 79-80.
H. Lauwerier, Fractals, Princeton Univ. Press, p. 23.

David Wasserman, Table of n, a(n) for n = 1..100000
Paul Yiu, Recreational Mathematics, 24.3.1 Appendix: Two enumerations of the rational numbers in (0,1), page 633.
Index entries for "core" sequences
Index entries for sequences related to enumerating the rationals
Index entries for sequences related to Stern's sequences

Essentially the same as A038566, which is the main entry for this sequence.
Cf. A020653, A038567-A038569, A182972-A182976.
A054424 gives mapping to Stern-Brocot tree.
Cf. A037161.

a020652 n = a020652_list !! (n-1)
a020652_list = map fst [(u,v) | v <- [1..], u <- [1..v-1], gcd u v == 1]
-- Reinhard Zumkeller, Jul 29 2012

with (numtheory): A020652 := proc (n) local sum, j, k; sum := 0: k := 2: while (sum < n) do: sum := sum + phi(k): k := k + 1: od: sum := sum - phi(k-1): j := 1; while sum < n do: if gcd(j,k-1) = 1 then sum := sum + 1: fi: j := j+1: od: RETURN (j-1): end: # Ulrich Schimke (ulrschimke(AT)aol.com), Nov 06 2001

Reap[Do[If[GCD[num, den] == 1, Sow[num]], {den, 1, 20}, {num, 1, den-1}] ][[2, 1]] (* Jean-François Alcover, Oct 22 2012 *)

a(n)=my(s,j=1,k=1);while(sCharles R Greathouse IV, Feb 07 2013

from sympy import totient, gcd
def a(n):
    s=0
    k=2
    while sIndranil Ghosh, May 23 2017, after Ulrich Schimke's MAPLE code

A065658 The table of permutations of N, each row induced by the rotation (to the right) of the n-th node in the infinite binary "decimal" fraction tree.

Original entry on oeis.org

7, 25, 1, 31, 22, 1, 1, 3, 2, 1, 223, 10, 247, 2, 1, 15, 94, 4, 3, 2815, 1, 127, 6, 5, 4, 3, 2, 1, 5, 7, 28, 5, 4, 115, 2, 1, 385, 20479, 127, 6, 94, 4, 3, 2, 1, 13, 175, 8, 7, 6, 5, 4, 3, 2, 1, 1792, 46, 9, 280, 7, 234881023, 5, 4, 3, 322, 1, 61, 382, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1

Offset: 0

Antti Karttunen, Nov 22 2001

Consider the following infinite binary tree, where the nodes are numbered in breadth-first, left-to-right fashion from the top as in A065625 and then assigned the following rational values:
--------------------------------------(0.1)---------------------------------------
----------------(0.01)-------------------------------------(0.11)-----------------
-----(0.001)--------------(0.011)---------------(0.101)--------------(0.111)------
(0.0001)-(0.0011)----(0.0101)-(0.0111)-----(0.1001)-(0.1011)-----(0.1101)-(0.1111)
i.e., the elements (1/2, 1/4, 3/4, 1/8, 3/8, 5/8, 7/8, 1/16, 3/16, ..., of the Quasicyclic group Z+((2a+1)/(2^b)) for prime 2) listed here in their binary "decimal" fraction form. Subjecting this tree to any similar binary tree rotation as used in A065625 induces a permutation of the rationals in range ]0,1[ (i.e., including also the ones having infinite binary expansions, corresponding to infinite paths in above tree), which we then convert to permutations of N by taking the positions of the mapped values at the ]0,1[ side of the Stern-Brocot Tree (A007305/A007306). See example at A065670.

Index entries for sequences related to Stern's sequences

The first row (rotate the top node right): A065660, 2nd row (rotate the top node's left child): A065662, 3rd row (rotate the top node's right child): A065664, 4th row: A065666, 5th row: A065668, 6th row: A065670, 7th row: A065672. For the other needed Maple procedures follow A065625, A047679, A054424 and A054429. Cf. also A065674-A065676. Inverse permutations are given in A065659.

Cf. also A065934-A065935.

[seq(RotateBinFracRightTable(j),j=0..119)]; RotateBinFracRightTable := n -> RotateBinFracNodeRight(1+(n-((trinv(n)*(trinv(n)-1))/2)),(((trinv(n)-1)*(((1/2)*trinv(n))+1))-n)+1);
RotateBinFracNodeRight := (t,n) -> frac2position_in_0_1_SB_tree(RotateBinFracNodeRight_x(t,SternBrocot0_1frac(n)));
RotateBinFracNodeRight_x := proc(t,x) local num,den; den := 2^(1+floor_log_2(t)); num := (2*(t-(den/2)))+1; if((x <= (num-1)/den) or (x >= (num+1)/den)) then RETURN(x); fi; if(x <= ((2*(num-1))+1)/(2*den)) then RETURN((2*(x - ((num-1)/den))) + ((num-1)/den)); fi; if(x < (num/den)) then RETURN(x + (1/(2*den))); fi; RETURN((num/den) + ((x-((num-1)/den))/2)); end;
SternBrocot0_1frac := proc(n) local m; m := n + 2^floor_log_2(n); SternBrocotTreeNum(m)/SternBrocotTreeDen(m); end;
frac2position_in_0_1_SB_tree := r -> RETURN(ReflectBinTreePermutation(cfrac2binexp(convert(1/r,confrac))));

A057114 Permutation of N induced by the order-preserving permutation of the rational numbers (x -> x+1); positions in Stern-Brocot tree.

Original entry on oeis.org

3, 1, 7, 2, 6, 14, 15, 4, 5, 12, 13, 28, 29, 30, 31, 8, 9, 10, 11, 24, 25, 26, 27, 56, 57, 58, 59, 60, 61, 62, 63, 16, 17, 18, 19, 20, 21, 22, 23, 48, 49, 50, 51, 52, 53, 54, 55, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 96, 97, 98, 99, 100, 101, 102, 103

Offset: 1

Antti Karttunen, Aug 09 2000

nonn

The "unbalancing operation" used here is what is usually called "rotation of binary trees" (e.g. in Lucas, Ruskey et al. article)

			Consider the following "extended" Stern-Brocot tree (on interval ]-inf,inf[):
....................................0/1
.................-1/1.................................1/1
......-2/1................-1/2...............1/2...............2/1
.-3/1......-3/2......-2/3......-1/3.....1/3.......2/3.....3/2.......3/1
Enumerate the fractions breadth-first (0/1 = 1, -1/1 = 2, 1/1 = 3, -2/1 = 4, -1/2 = 5, etc.) then use this sequence to pick third, first, 7th, 2nd, etc. fractions. We get a bijection (0/1 -> 1/1, -1/1 -> 0/1, 1/1 -> 2/1, -2/1 -> -1/1, -1/2 -> 1/2, etc.) which is the function x -> x+1.
In other words, we cut the edge between 1/1 and 1/2, make 1/1 the new root and create a new edge between 0/1 and 1/2 to get an "unbalanced" Stern-Brocot tree. If we instead make a similar change to subtree 1/1 (cut {2/1,3/2}, create {1/1,3/2} and make 2/1 the new root of the positive side, leaving the negative side as it is), we get the function given in Maple procedure sbtree_perm_1_1_right.
Both mappings belong to Cameron's group "A" of permutations of the rational numbers which preserve their linear order and by applying such unbalancing operations successively (possibly infinitely many times) to the "extended" Stern-Brocot tree given above, the whole group "A" can be generated.

Joan Lucas, Dominique Roelants van Baronaigien and Frank Ruskey, On Rotations and the Generation of Binary Trees, Journal of Algorithms, 15 (1993) 343-366.

A. Bogomolny, About the Stern-Brocot tree
P. J. Cameron, Sequences realized by oligomorphic permutation groups, J. Integ. Seqs. Vol. 3 (2000), #00.1.5.
Index entries for sequences related to Stern's sequences
Index entries for sequences that are permutations of the natural numbers

SternBrocotNum given in A007305, SternBrocotDen in A047679, frac2position_in_whole_SB_tree in A054424. Inverse permutation: A057115. Cf. also A065249 and A065250.
A065259(n) = A059893(A057114(A059893(n)))
The first row of A065625, i.e. a(n) = RotateNodeRight(1, n).

sbtree_perm_1_1_right := x -> (`if`((x <= 0),x,(`if`((x < (1/2)),(x/(1-x)),(`if`((x < 1),(3-(1/x)),(x+1)))))));

a(n) = frac2position_in_whole_SB_tree (sbtree_perm_1_1_right (SternBrocotTreeNum(n) / SternBrocotTreeDen(n))).

cp's OEIS Frontend

A054425 A054424 expanded to normal triangular array, with zeros at those (x,y) where x and y are not relatively prime.

Views

Author

Keywords

Crossrefs

Programs

Maple

A054426 Inverse permutation to A054424.

Views

Author

Keywords

Links

Programs

Maple

Mathematica

Formula

A054429 Simple self-inverse permutation of natural numbers: List each block of 2^n numbers (from 2^n to 2^(n+1) - 1) in reverse order.

Views

Author

Keywords

Comments

Links

Crossrefs

Programs

Haskell

Maple

Mathematica

PARI

Python

R

Formula

A007306 Denominators of Farey tree fractions (i.e., the Stern-Brocot subtree in the range [0,1]).

Views

Author

Keywords

Comments

Examples

References

Links

Crossrefs

Programs

Magma

Maple

Mathematica

PARI

PARI

Python

Python

R

R

Sage

Sage

Scheme

Formula

Extensions

A038566 Numerators in canonical bijection from positive integers to positive rationals <= 1: arrange fractions by increasing denominator then by increasing numerator.

Views

Author

Keywords

Comments

Examples

References

Links

Crossrefs

Programs

Haskell

Maple

Mathematica

PARI

PARI

SageMath

Formula

Extensions

A007305 Numerators of Farey (or Stern-Brocot) tree fractions.

Views

Author

Keywords

Comments

Examples