A308411 Number of ways to write n as 2^i*3^j + A008347(k), where i, j and k > 0 are nonnegative integers.
0, 1, 2, 3, 4, 4, 4, 4, 5, 5, 5, 3, 5, 5, 4, 5, 5, 3, 6, 7, 6, 6, 5, 6, 7, 4, 5, 8, 6, 8, 7, 5, 5, 8, 8, 6, 7, 5, 7, 8, 7, 6, 6, 6, 8, 6, 5, 8, 6, 7, 7, 5, 8, 7, 8, 10, 9, 9, 6, 7, 8, 8, 6, 7, 10, 8, 8, 6, 9, 6, 7, 9, 8, 7, 7, 8, 9, 4, 8, 11, 10, 6, 9, 7, 11, 8, 8, 10, 9, 6, 4, 7, 10, 7, 7, 3, 11, 9, 10, 7
Offset: 1
Keywords
Examples
a(2) = 1 with 2 = 2^0*3^0 + A008347(2). a(3) = 2 with 3 = 2^0*3^0 + A008347(1) = 2^1*3^0 + A008347(2).
Links
- Zhi-Wei Sun, Table of n, a(n) for n = 1..10000
- Zhi-Wei Sun, On functions taking only prime values, J. Number Theory 133(2013), no.8, 2794-2812.
Programs
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Mathematica
f[n_]:=f[n]=FactorInteger[n]; FQ[n_]:=FQ[n]=n>0&&Part[f[n],Length[f[n]]][[1]]<4; s[0]=0; s[n_]:=s[n]=Prime[n]-s[n-1]; tab={};Do[r=0;Do[If[FQ[n-s[k]],r=r+1],{k,1,2n-1}];tab=Append[tab,r],{n,1,100}];Print[tab]
Comments