cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Previous Showing 31-40 of 41 results. Next

A066067 Number of binary strings u of any length with property that length(u) + number of 0's in u <= n (only one of a string and its reversal are counted).

Original entry on oeis.org

1, 2, 3, 6, 10, 18, 29, 49, 78, 128, 203, 329, 523, 844, 1347, 2172, 3480, 5614, 9023, 14567, 23466, 37910, 61165, 98865, 159677, 258190, 417283, 674890, 1091214, 1765146, 2854793, 4618373, 7470614, 12086436, 19552903, 31635193, 51181367, 82809832
Offset: 1

Views

Author

Frank Ellermann, Dec 02 2001

Keywords

Comments

If 0 is replaced by 2 (as in A007931) "length + 0-bits" is simply the total of ternary digits (e.g., 3 for 21 instead of 01).

Examples

			a(3) = 3: 0 01 111 (e.g. 01: length 2 + 1 zero = 3).
a(4) = 6: 0 01 00 011 101 1111.
a(5) =10: 0 01 00 011 101 001 010 0111 1011 11111.
		

Crossrefs

If reversals are counted as distinct then we obtain A000126.
A007931 (binary strings represented by ternary numbers),
Cf. A035615 (binary "same game").

Programs

  • Mathematica
    CoefficientList[Series[x (-x^7-x^4+3x^3-2x^2-x+1)/((1-x-x^2) (1-x^2-x^4) (1-x)^2),{x,0,50}],x] (* Harvey P. Dale, Jun 15 2011 *)

Formula

G.f.: x*(-x^7-x^4+3x^3-2x^2-x+1)/((1-x-x^2)*(1-x^2-x^4)*(1-x)^2).

Extensions

More terms from Harvey P. Dale, Jun 15 2011

A210677 a(n) = a(n-1) + a(n-2) + n + 1, a(0) = a(1) = 1.

Original entry on oeis.org

1, 1, 5, 10, 20, 36, 63, 107, 179, 296, 486, 794, 1293, 2101, 3409, 5526, 8952, 14496, 23467, 37983, 61471, 99476, 160970, 260470, 421465, 681961, 1103453, 1785442, 2888924, 4674396, 7563351, 12237779, 19801163, 32038976, 51840174, 83879186, 135719397, 219598621, 355318057
Offset: 0

Views

Author

Alex Ratushnyak, May 09 2012

Keywords

Crossrefs

Cf. A081659: a(n)=a(n-1)+a(n-2)+n-5, a(0)=a(1)=1 (except first 2 terms and sign).
Cf. A001924: a(n)=a(n-1)+a(n-2)+n-4, a(0)=a(1)=1 (except first 4 terms).
Cf. A000126: a(n)=a(n-1)+a(n-2)+n-2, a(0)=a(1)=1 (except first term).
Cf. A066982: a(n)=a(n-1)+a(n-2)+n-1, a(0)=a(1)=1.
Cf. A030119: a(n)=a(n-1)+a(n-2)+n, a(0)=a(1)=1.
Cf. A210678: a(n)=a(n-1)+a(n-2)+n+2, a(0)=a(1)=1.

Programs

Formula

From Colin Barker, Jun 30 2012: (Start)
a(n) = 3*a(n-1) - 2*a(n-2) - a(n-3) + a(n-4).
G.f.: (1 - 2*x + 4*x^2 - 2*x^3)/((1 - x)^2*(1 - x - x^2)). (End)
E.g.f.: exp(x/2)*(25*cosh(sqrt(5)*x/2) + 7*sqrt(5)*sinh(sqrt(5)*x/2))/5 - exp(x)*(4 + x). - Stefano Spezia, Feb 24 2023

A210728 a(n) = a(n-1) + a(n-2) + n + 2 with n>1, a(0)=1, a(1)=2.

Original entry on oeis.org

1, 2, 7, 14, 27, 48, 83, 140, 233, 384, 629, 1026, 1669, 2710, 4395, 7122, 11535, 18676, 30231, 48928, 79181, 128132, 207337, 335494, 542857, 878378, 1421263, 2299670, 3720963, 6020664, 9741659, 15762356, 25504049, 41266440, 66770525, 108037002, 174807565
Offset: 0

Views

Author

Alex Ratushnyak, May 10 2012

Keywords

Crossrefs

Cf. A065220: a(n)=a(n-1)+a(n-2)+n-5, a(0)=1,a(1)=2 (except first 2 terms).
Cf. A168043: a(n)=a(n-1)+a(n-2)+n-3, a(0)=1,a(1)=2 (except first 2 terms).
Cf. A131269: a(n)=a(n-1)+a(n-2)+n-2, a(0)=1,a(1)=2.
Cf. A000126: a(n)=a(n-1)+a(n-2)+n-1, a(0)=1,a(1)=2.
Cf. A104161: a(n)=a(n-1)+a(n-2)+n, a(0)=1,a(1)=2 (except the first term).
Cf. A192969: a(n)=a(n-1)+a(n-2)+n+1, a(0)=1,a(1)=2.
Cf. A210729: a(n)=a(n-1)+a(n-2)+n+3, a(0)=1,a(1)=2.

Programs

  • Mathematica
    RecurrenceTable[{a[0] == 1, a[1] == 2, a[n] == a[n - 1] + a[n - 2] + n + 2}, a, {n, 36}] (* Bruno Berselli, Jun 27 2012 *)
    nxt[{n_,a_,b_}]:={n+1,b,a+b+n+3}; NestList[nxt,{1,1,2},40][[;;,2]] (* Harvey P. Dale, Aug 26 2024 *)

Formula

G.f.: (1-x+3*x^2-2*x^3)/((1-x)^2*(1-x-x^2)). - Bruno Berselli, Jun 27 2012
a(n) = ((5+sqrt(5))*(1+sqrt(5))^(n+1)-(5-sqrt(5))*(1-sqrt(5))^(n+1))/(2^(n+1)*sqrt(5))-n-5. - Bruno Berselli, Jun 27 2012
a(n) = -n-5+A022112(n+1). R. J. Mathar, Jul 03 2012

A210729 a(n) = a(n-1) + a(n-2) + n + 3 with n>1, a(0)=1, a(1)=2.

Original entry on oeis.org

1, 2, 8, 16, 31, 55, 95, 160, 266, 438, 717, 1169, 1901, 3086, 5004, 8108, 13131, 21259, 34411, 55692, 90126, 145842, 235993, 381861, 617881, 999770, 1617680, 2617480, 4235191, 6852703, 11087927, 17940664, 29028626, 46969326, 75997989, 122967353
Offset: 0

Views

Author

Alex Ratushnyak, May 10 2012

Keywords

Crossrefs

Cf. A065220: a(n)=a(n-1)+a(n-2)+n-5, a(0)=1,a(1)=2 (except first 2 terms).
Cf. A168043: a(n)=a(n-1)+a(n-2)+n-3, a(0)=1,a(1)=2 (except first 2 terms).
Cf. A131269: a(n)=a(n-1)+a(n-2)+n-2, a(0)=1,a(1)=2.
Cf. A000126: a(n)=a(n-1)+a(n-2)+n-1, a(0)=1,a(1)=2.
Cf. A104161: a(n)=a(n-1)+a(n-2)+n, a(0)=1,a(1)=2 (except the first term).
Cf. A192969: a(n)=a(n-1)+a(n-2)+n+1, a(0)=1,a(1)=2.
Cf. A210728: a(n)=a(n-1)+a(n-2)+n+2, a(0)=1,a(1)=2.

Programs

  • GAP
    F:=Fibonacci;; List([0..40], n-> 2*F(n+3)+3*F(n+1)-n-6); # G. C. Greubel, Jul 09 2019
  • Magma
    [3*Fibonacci(n+1)+2*Fibonacci(n+3)-n-6: n in [0..40]]; // Vincenzo Librandi, Jul 18 2013
    
  • Mathematica
    Table[3*Fibonacci[n+1]+2*Fibonacci[n+3]-n-6,{n,0,40}] (* Vaclav Kotesovec, May 13 2012 *)
  • PARI
    vector(40, n, n--; f=fibonacci; 2*f(n+3)+3*f(n+1)-n-6) \\ G. C. Greubel, Jul 09 2019
    
  • Python
    prpr, prev = 1,2
    for n in range(2, 99):
        current = prev+prpr+n+3
        print(prpr, end=',')
        prpr = prev
        prev = current
    
  • Sage
    f=fibonacci; [2*f(n+3)+3*f(n+1)-n-6 for n in (0..40)] # G. C. Greubel, Jul 09 2019
    

Formula

G.f.: (1-x+4*x^2-3*x^3)/((1-x-x^2)*(1-x)^2).
a(n) = 3*Fibonacci(n+1)+2*Fibonacci(n+3)-n-6. - Vaclav Kotesovec, May 13 2012
a(n) = 2*Lucas(n+2) + Fibonacci(n+1) - (n+6). - G. C. Greubel, Jul 09 2019

A306416 Number of ordered set partitions of {1, ..., n} with no singletons or cyclical adjacencies (successive elements in the same block, where 1 is a successor of n).

Original entry on oeis.org

1, 0, 0, 0, 2, 0, 26, 84, 950, 6000, 62522, 556116, 6259598, 69319848, 874356338, 11384093196, 161462123894, 2397736692144, 37994808171962, 631767062124564, 11088109048500158, 203828700127054008, 3928762035148317314, 79079452776283889820, 1661265965479375937030, 36332908076071038467520, 826376466514358722894154
Offset: 0

Views

Author

Gus Wiseman, Feb 14 2019

Keywords

Examples

			The a(4) = 2 ordered set partitions are: {{1,3},{2,4}}, {{2,4},{1,3}}.
		

Crossrefs

Cf. A000110, A000126, A000296, A000670, A001610, A032032 (adjacencies allowed), A052841 (singletons allowed), A124323, A169985, A306417, A324011 (orderless case), A324012, A324015.

Programs

  • Mathematica
    sps[{}]:={{}};sps[set:{i_,_}]:=Join@@Function[s,Prepend[#,s]&/@sps[Complement[set,s]]]/@Cases[Subsets[set],{i,_}];
    Table[Sum[Length[stn]!,{stn,Select[sps[Range[n]],And[Count[#,{_}]==0,Total[If[First[#]==1&&Last[#]==n,1,0]+Count[Subtract@@@Partition[#,2,1],-1]&/@#]==0]&]}],{n,0,10}]

Extensions

a(12)-a(26) from Alois P. Heinz, Feb 14 2019

A306418 Regular triangle read by rows where T(n, k) is the number of set partitions of {1, ..., n} requiring k steps of removing singletons and cyclical adjacency initiators until reaching a fixed point, n >= 0, 0 <= k <= n.

Original entry on oeis.org

1, 0, 1, 0, 2, 0, 0, 2, 3, 0, 1, 2, 12, 0, 0, 0, 12, 35, 5, 0, 0, 5, 56, 100, 42, 0, 0, 0, 14, 282, 343, 231, 7, 0, 0, 0, 66, 1406, 1476, 1088, 104, 0, 0, 0, 0, 307, 7592, 7383, 4929, 909, 27, 0, 0, 0, 0, 1554, 44227, 40514, 22950, 6240, 470, 20, 0, 0, 0, 0
Offset: 0

Views

Author

Gus Wiseman, Feb 14 2019

Keywords

Comments

See Callan's article for details on this transformation (SeparateIS).

Examples

			Triangle begins:
    1
    0    1
    0    2    0
    0    2    3    0
    1    2   12    0    0
    0   12   35    5    0    0
    5   56  100   42    0    0    0
   14  282  343  231    7    0    0    0
   66 1406 1476 1088  104    0    0    0    0
  307 7592 7383 4929  909   27    0    0    0    0
		

Crossrefs

Row sums are A000110. First column is A324011.

Programs

  • Mathematica
    sps[{}]:={{}};sps[set:{i_,_}]:=Join@@Function[s,Prepend[#,s]&/@sps[Complement[set,s]]]/@Cases[Subsets[set],{i,_}];
    qbj[stn_]:=With[{ini=Join@@Table[Select[s,If[#==Max@@Max@@@stn,MemberQ[s,First[Union@@stn]],MemberQ[s,(Union@@stn)[[Position[Union@@stn,#][[1,1]]+1]]]]&],{s,stn}],sng=Join@@Select[stn,Length[#]==1&]},DeleteCases[Table[Complement[s,Union[sng,ini]],{s,stn}],{}]];
    Table[Length[Select[sps[Range[n]],Length[FixedPointList[qbj,#]]-2==k&]],{n,0,8},{k,0,n}]

A350603 Irregular triangle read by rows: row n lists the elements of the set S_n in increasing order, where S_0 = {0}, and S_n is obtained by applying the operations x -> x+1 and x -> 2*x to S_{n-1}.

Original entry on oeis.org

0, 0, 1, 0, 1, 2, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 5, 6, 8, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 16, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 16, 17, 18, 20, 24, 32, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 24, 25, 26, 28, 32, 33, 34, 36, 40, 48, 64
Offset: 0

Views

Author

N. J. A. Sloane, Jan 12 2022, following a suggestion from James Propp

Keywords

Comments

Theorem: S_n contains Fibonacci(n+2) elements.
Proof from Adam P. Goucher, Jan 12 2022 (Start)
Let 'D' and 'I' be the 'double' and 'increment' operators, acting on 0 from the right. Then every element of S_n can be written as a length-n word over {D,I}. E.g., S_4 contains
0: DDDD
1: DDDI
2: DDID
3: DIDI
4: DIDD
5: IDDI
6: IDID
8: IDDD
We can avoid having two adjacent 'I's (because we can transform it into an equivalent word by prepending a 'D' -- which has no effect -- and then replacing the first 'DII' with 'ID').
Subject to the constraint that there are no two adjacent 'I's, these 'II'-less words all represent distinct integers (because of the uniqueness of binary expansions).
So we're left with the problem of enumerating length-n words over the alphabet {I, D} which do not contain 'II' as a substring. These are easily seen to be the Fibonacci numbers because we can check n=0 and n=1 and verify that the recurrence relation holds since a length-n word is either a length-(n-1) word followed by 'D' or a length-(n-2) word followed by 'DI'. QED (End)
From Rémy Sigrist, Jan 12 2022: (Start)
For any m >= 0, the value m first appears on row A056792(m).
For any n > 0: row n minus row n-1 corresponds to row n of A243571.
(End)

Examples

			The first few sets S_n are:
[0],
[0, 1],
[0, 1, 2],
[0, 1, 2, 3, 4],
[0, 1, 2, 3, 4, 5, 6, 8],
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 16],
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 16, 17, 18, 20, 24, 32],
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 24, 25, 26, 28, 32, 33, 34, 36, 40, 48, 64],
...
		

Crossrefs

Programs

  • Maple
    T:= proc(n) option remember; `if`(n=0, 0,
          sort([map(x-> [x+1, 2*x][], {T(n-1)})[]])[])
        end:
    seq(T(n), n=0..8);  # Alois P. Heinz, Jan 12 2022
  • Mathematica
    T[n_] := T[n] = If[n==0, {0}, {#+1, 2#}& /@ T[n-1] // Flatten //
          Union];
    Table[T[n], {n, 0, 8}] // Flatten (* Jean-François Alcover, May 06 2022, after Alois P. Heinz *)
  • Python
    from itertools import chain, islice
    def A350603_gen(): # generator of terms
        s = {0}
        while True:
            yield from sorted(s)
            s = set(chain.from_iterable((x+1,2*x) for x in s))
    A350603_list = list(islice(A350603_gen(),30)) # Chai Wah Wu, Jan 12 2022

Extensions

Definition made more precise by Chai Wah Wu, Jan 12 2022

A111645 Expansion of (x+1)*(1-3*x)/((x^2+4*x+1)*(x^2-2*x-1)).

Original entry on oeis.org

-1, 8, -37, 156, -625, 2436, -9341, 35464, -133809, 502896, -1885317, 7056580, -26384961, 98589388, -368228797, 1374944336, -5133041825, 19160828056, -71518973861, 266936079404, -996276071249, 3718290672596, -13877182280637, 51791152239960, -193289149920721
Offset: 0

Views

Author

Creighton Dement, Aug 10 2005

Keywords

Comments

In reference to the program code, the sequence of Pell numbers A000126 is given by 1kbaseseq[C*J]. A001353 is 1ibaseiseq[C*J].
Floretion Algebra Multiplication Program, FAMP Code: 1jbasejseq[C*J] with C = - 'j + 'k - j' + k' - 'ii' - 'ij' - 'ik' - 'ji' - 'ki' and J = + j' + k' + 1.5'ii' + .5'jj' + .5'kk' + .5e

Crossrefs

Programs

  • Mathematica
    CoefficientList[Series[(x+1)(1-3x)/((x^2+4x+1)(x^2-2x-1)),{x,0,30}],x] (* or *) LinearRecurrence[{-6,-8,2,1},{-1,8,-37,156},30] (* Harvey P. Dale, Nov 19 2015 *)

Formula

a(0)=-1, a(1)=8, a(2)=-37, a(3)=156, a(n)=-6*a(n-1)-8*a(n-2)+2*a(n-3)+a(n-4). - Harvey P. Dale, Nov 19 2015
2*a(n) = -7*A125905(n)-A125905(n-1) -A077985(n-1)+5*A077985(n). - R. J. Mathar, Sep 11 2019

A196875 a(n) = a(n-4) + a(n-3) + a(n-2) + a(n-1) + (n-5).

Original entry on oeis.org

1, 1, 1, 1, 4, 8, 16, 32, 64, 125, 243, 471, 911, 1759, 3394, 6546, 12622, 24334, 46910, 90427, 174309, 335997, 647661, 1248413, 2406400, 4638492, 8940988, 17234316, 33220220, 64034041, 123429591, 237918195, 458602075, 883983931, 1703933822, 3284438054
Offset: 1

Views

Author

Aditya Subramanian, Oct 07 2011

Keywords

Crossrefs

Programs

  • Maple
    a:= n-> (Matrix(6, (i, j)-> `if`(i=j-1, 1, `if`(i=6, [1, -1, 0, 0, -2, 3][j], 0)))^n. <<-1, 1, 1, 1, 1, 4>>)[1, 1]: seq(a(n), n=1..50); # Alois P. Heinz, Oct 15 2011
  • Mathematica
    nn = 40; a[1] = a[2] = a[3] = a[4] = 1; Do[a[n] = a[n - 1] + a[n - 2] + a[n - 3] + a[n - 4] + (n - 5), {n, 5, nn}]; Table[a[n], {n, nn}] (* T. D. Noe, Oct 07 2011 *)
    RecurrenceTable[{a[1]==a[2]==a[3]==a[4]==1,a[n]==a[n-1]+a[n-2]+a[n-3]+a[n-4]+(n-5)},a,{n,40}] (* or *) LinearRecurrence[{3,-2,0,0,-1,1},{1,1,1,1,4,8},40] (* Harvey P. Dale, Aug 25 2014 *)

Formula

G.f.: (x^5-3*x^4+2*x-1)*x / ((x^4+x^3+x^2+x-1)*(x-1)^2 ).
a(n) = +3*a(n-1) -2*a(n-2) -a(n-5) +a(n-6).
a(n) = 5/9-n/3 +(10*A000078(n) +17*A000078(n+1) +21*A000078(n+2) -14*A000078(n+3))/9. - R. J. Mathar, Oct 16 2011

A196876 a(n) = a(n-no-1)+....+a(n-1)+(n-no-2) where no is the 'no+1'th order of the series and 'n' is the element number, here no=6.

Original entry on oeis.org

1, 1, 1, 1, 1, 1, 1, 7, 14, 28, 56, 112, 224, 448, 896, 1786, 3559, 7091, 14127, 28143, 56063, 111679, 222463, 443141, 882724, 1758358, 3502590, 6977038, 13898014, 27684350, 55146238, 109849336, 218815949, 435873541, 868244493, 1729511949, 3445125885
Offset: 1

Views

Author

Aditya Subramanian, Oct 07 2011

Keywords

Comments

A196787, A000126, and A000124 are all specific series of this general formula of series. When no=2 the series is A196787. When no=0 the series is A000124 with an additional '1' at the beginning. When no=1 the series is A000126 with an additional '1' at the beginning.
The data given above is the series with no=6 and n=25, having a(1)=.....a(no+1)=1 initially.

Examples

			For n=25, no=6, then a(1)=1, a(2)=1, ......, a(no)=1 and a(7)=a(1)+a(2)+....a(no)+(6-no), a(8)=a(2)+...a(no+1)+(7-no), a(n)=a(n-no)+....a(n-1)+((n-1)-no) and so a(25)=a(19)+....a(24)+(24-6).
		

Programs

  • Maple
    A196876 := proc(n)
            option remember;
            if n <= 7 then
                    1;
            else
                    n-6-2+add(procname(n-i),i=1..7) ;
            end if;
    end proc: # R. J. Mathar, Oct 21 2011
  • Mathematica
    CoefficientList[Series[(- 1 + 2 x - 6 x^7 + 4 x^8)/((x^7 + x^6 + x^5 + x^4 + x^3 + x^2 + x - 1) (x - 1)^2), {x, 0, 40}], x] (* Vincenzo Librandi, Dec 11 2012 *)

Formula

a(n)=1 if n<=7, else a(n) = n-no-2+sum_{i=1..no+1} a(n-i), no=6.
G.f.: x*( -1+2*x-6*x^7+4*x^8 ) / ( (x^7+x^6+x^5+x^4+x^3+x^2+x-1)*(x-1)^2 ). - R. J. Mathar, Oct 21 2011
Previous Showing 31-40 of 41 results. Next