cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A060186 Generalized sum of divisors function: third diagonal of A060184.

Original entry on oeis.org

1, 0, 1, 0, 5, -1, 5, -2, 9, 3, 9, -2, 14, -1, 15, 10, 15, 7, 11, 14, 10, 26, 20, 28, 2, 41, -5, 63, -21, 82, -5, 91, -49, 122, -46, 139, -84, 165, -74, 240, -147, 242, -142, 290, -217, 333, -189, 378, -284, 463, -290, 508, -408, 560, -377
Offset: 3

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Author

N. J. A. Sloane, Mar 19 2001

Keywords

Programs

  • Maple
    mufact := proc(k,sumax) local res,c,i,j,isord,s ; res := [] ; for s from k*(k+1)/2 to sumax do c := combinat[composition](s,k) ; for j from 1 to nops(c) do isord := true ; for i from 2 to nops(op(j,c)) do if op(i,op(j,c))<= op(i-1,op(j,c)) then isord := false ; fi ; od ; if isord then res := [op(res),op(j,c)] ; fi ; od ; od ; RETURN(res) ; end: qm := proc(gfpart,n) local f,i ; f := q^add(op(i,gfpart),i=1..nops(gfpart)) ; for i from 1 to nops(gfpart) do f := taylor(f/(1+q^op(i,gfpart)),q=0,n+1) ; od ; RETURN(f) ; end: A060186 := proc(n) local k,ms,gf,gfpart,i ; k := 3 ; ms := mufact(k,n) ; gf := 0; for i from 1 to nops(ms) do gfpart := op(i,ms) ; gf := taylor(gf+qm(gfpart,n),q=0,n+1) ; od ; RETURN(gf) ; end: nmax := 60 : a := A060186(nmax) : for n from 6 to nmax do printf("%d, ",coeftayl(a,q=0,n)) ; od ; # R. J. Mathar, Jun 26 2007
  • Mathematica
    max = 60; t[i_] := Sum[(x^n/(1 + x^(n)))^i, {n, 1, max}]; s = Series[(t[1]^3 - 3*t[1]*t[2] + 2*t[3])/6, {x, 0, max+1}]; a[n_] := SeriesCoefficient[s, {x, 0, n}]; Table[a[n], {n, 6, max}] (* Jean-François Alcover, Jan 17 2014, after Vladeta Jovovic *)

Formula

G.f.: (t(1)^3-3*t(1)*t(2)+2*t(3))/6 where t(i) = Sum((x^n/(1+x^(n)))^i,n=1..inf), i=1..3. - Vladeta Jovovic, Sep 20 2007

Extensions

More terms from R. J. Mathar, Jun 26 2007

A060185 Generalized sum of divisors function: second diagonal of A060184.

Original entry on oeis.org

1, 0, 1, 2, 1, 1, 1, 6, -1, 5, -3, 10, 0, 9, -7, 16, -9, 17, -6, 22, -13, 20, -15, 28, -14, 35, -23, 36, -25, 36, -24, 42, -26, 53, -37, 50, -34, 58, -45, 60, -49, 75, -37, 66, -55, 77, -59, 74, -60, 101, -71, 88, -64, 106, -74, 92, -83, 124, -89, 98, -79, 130, -90, 120, -105, 155, -104, 120, -113, 163, -121, 126, -111
Offset: 3

Views

Author

N. J. A. Sloane, Mar 19 2001

Keywords

Programs

  • Mathematica
    max = 80; s = Sum[q^(m1 + m2)/((1 + q^m1)*(1 + q^m2)), {m1, 1, max-1}, {m2, m1+1, max}]; CoefficientList[Series[s, {q, 0, max}] , q][[4 ;; max]] (* Jean-François Alcover, Jan 21 2014 *)

Extensions

More terms from Vladeta Jovovic, Nov 11 2001

A048272 Number of odd divisors of n minus number of even divisors of n.

Original entry on oeis.org

1, 0, 2, -1, 2, 0, 2, -2, 3, 0, 2, -2, 2, 0, 4, -3, 2, 0, 2, -2, 4, 0, 2, -4, 3, 0, 4, -2, 2, 0, 2, -4, 4, 0, 4, -3, 2, 0, 4, -4, 2, 0, 2, -2, 6, 0, 2, -6, 3, 0, 4, -2, 2, 0, 4, -4, 4, 0, 2, -4, 2, 0, 6, -5, 4, 0, 2, -2, 4, 0, 2, -6, 2, 0, 6, -2, 4, 0, 2, -6, 5, 0, 2, -4, 4, 0, 4, -4, 2, 0, 4, -2, 4
Offset: 1

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Author

Keywords

Comments

abs(a(n)) = (1/2) * (number of pairs (i,j) satisfying n = i^2 - j^2 and -n <= i,j <= n). - Benoit Cloitre, Jun 14 2003
As A001227(n) is the number of ways to write n as the difference of 3-gonal numbers, a(n) describes the number of ways to write n as the difference of e-gonal numbers for e in {0,1,4,8}. If pe(n):=(1/2)*n*((e-2)*n+(4-e)) is the n-th e-gonal number, then 4*a(n) = |{(m,k) of Z X Z; pe(-1)(m+k)-pe(m-1)=n}| for e=1, 2*a(n) = |{(m,k) of Z X Z; pe(-1)(m+k)-pe(m-1)=n}| for e in {0,4} and for a(n) itself is a(n) = |{(m,k) of Z X Z; pe(-1)(m+k)-pe(m-1)=n}| for e=8. (Same for e=-1 see A035218.) - Volker Schmitt (clamsi(AT)gmx.net), Nov 09 2004
An argument by Gareth McCaughan suggests that the average of this sequence is log(2). - Hans Havermann, Feb 10 2013 [Supported by a graph. - Vaclav Kotesovec, Mar 01 2023]
From Keith F. Lynch, Jan 20 2024: (Start)
a(n) takes every possible integer value, positive, negative, and zero. Proof: For all nonnegative integers k, a(3^k) = 1+k, a(2^k) = 1-k.
a(n) takes every possible integer value except 1 and -1 infinitely many times. Proof: a(o^(k-1)) = k and a(4*o^(k-1)) = -k for all positive integers k and odd primes o, of which there are infinitely many. a(n) = 0 iff n = 2 (mod 4). a(n) = 1 iff n = 1. a(n) = -1 iff n = 4.
a(n) takes prime value p only for n = o^(p-1), where o is any odd prime.
Terms have a simple pattern that repeats with a period of 4: Positive, zero, positive, negative.
(End)
Inverse Möbius transform of (-1)^(n+1). - Wesley Ivan Hurt, Jun 22 2024

Examples

			a(20) = -2 because 20 = 2^2*5^1 and (1-2)*(1+1) = -2.
G.f. = x + 2*x^3 - x^4 + 2*x^5 + 2*x^7 - 2*x^8 + 3*x^9 + 2*x^11 - 2*x^12 + ...
		

References

  • Louis Comtet, Advanced Combinatorics, Reidel, 1974, p. 162, #16, (6), first formula.
  • S. Ramanujan, Notebooks, Tata Institute of Fundamental Research, Bombay 1957 Vol. 1, see page 97, 7(ii).

Crossrefs

Cf. A048298. A diagonal of A060184.
First differences of A059851.
Indices of records: A053624 (highs), A369151 (lows).

Programs

  • Haskell
    a048272 n = a001227 n - a183063 n  -- Reinhard Zumkeller, Jan 21 2012
    
  • Magma
    [&+[(-1)^(d+1):d in Divisors(n)] :n in [1..95] ]; // Marius A. Burtea, Aug 10 2019
  • Maple
    add(x^n/(1+x^n), n=1..60): series(%,x,59);
    A048272 := proc(n)
        local a;
        a := 1 ;
        for pfac in ifactors(n)[2] do
            if pfac[1] = 2 then
                a := a*(1-pfac[2]) ;
            else
                a := a*(pfac[2]+1) ;
            end if;
        end do:
        a ;
    end proc: # Schmitt, sign corrected R. J. Mathar, Jun 18 2016
    # alternative Maple program:
    a:= n-> -add((-1)^d, d=numtheory[divisors](n)):
    seq(a(n), n=1..100);  # Alois P. Heinz, Feb 28 2018
  • Mathematica
    Rest[ CoefficientList[ Series[ Sum[x^k/(1 - (-x)^k), {k, 111}], {x, 0, 110}], x]] (* Robert G. Wilson v, Sep 20 2005 *)
    dif[n_]:=Module[{divs=Divisors[n]},Count[divs,?OddQ]-Count[ divs, ?EvenQ]]; Array[dif,100] (* Harvey P. Dale, Aug 21 2011 *)
    a[n]:=Sum[-(-1)^d,{d,Divisors[n]}] (* Steven Foster Clark, May 04 2018 *)
    f[p_, e_] := If[p == 2, 1 - e, 1 + e]; a[n_] := Times @@ f @@@ FactorInteger[n]; a[1] = 1; Array[a, 100] (* Amiram Eldar, Jun 09 2022 *)
  • PARI
    {a(n) = if( n<1, 0, -sumdiv(n, d, (-1)^d))}; /* Michael Somos, Jul 22 2006 */
    
  • PARI
    N=17; default(seriesprecision,N); x=z+O(z^(N+1))
    c=sum(j=1,N,j*x^j); \\ log case
    s=-log(prod(j=1,N,(1+x^j)^(1/j)));
    s=serconvol(s,c)
    v=Vec(s) \\ Joerg Arndt, May 03 2008
    
  • PARI
    a(n)=my(o=valuation(n,2),f=factor(n>>o)[,2]);(1-o)*prod(i=1,#f,f[i]+1) \\ Charles R Greathouse IV, Feb 10 2013
    
  • PARI
    a(n)=direuler(p=1,n,if(p==2,(1-2*X)/(1-X)^2,1/(1-X)^2))[n] /* Ralf Stephan, Mar 27 2015 */
    
  • PARI
    {a(n) = my(d = n -> if(frac(n), 0, numdiv(n))); if( n<1, 0, if( n%4, 1, -1) * (d(n) - 2*d(n/2) + 2*d(n/4)))}; /* Michael Somos, Aug 11 2017 */
    

Formula

Coefficients in expansion of Sum_{n >= 1} x^n/(1+x^n) = Sum_{n >= 1} (-1)^(n-1)*x^n/(1-x^n). Expand Sum 1/(1+x^n) in powers of 1/x.
If n = 2^p1*3^p2*5^p3*7^p4*11^p5*..., a(n) = (1-p1)*Product_{i>=2} (1+p_i).
Multiplicative with a(2^e) = 1 - e and a(p^e) = 1 + e if p > 2. - Vladeta Jovovic, Jan 27 2002
a(n) = (-1)*Sum_{d|n} (-1)^d. - Benoit Cloitre, May 12 2003
Moebius transform is period 2 sequence [1, -1, ...]. - Michael Somos, Jul 22 2006
G.f.: Sum_{k>0} -(-1)^k * x^(k^2) * (1 + x^(2*k)) / (1 - x^(2*k)) [Ramanujan]. - Michael Somos, Jul 22 2006
Equals A051731 * [1, -1, 1, -1, 1, ...]. - Gary W. Adamson, Nov 07 2007
From Reinhard Zumkeller, Jan 21 2012: (Start)
a(n) = A001227(n) - A183063(n).
a(A008586(n)) < 0; a(A005843(n)) <= 0; a(A016825(n)) = 0; a(A042968(n)) >= 0; a(A005408(n)) > 0. (End)
a(n) = Sum_{k=0..n} A081362(k)*A015723(n-k). - Mircea Merca, Feb 26 2014
abs(a(n)) = A112329(n) = A094572(n) / 2. - Ray Chandler, Aug 23 2014
From Peter Bala, Jan 07 2015: (Start)
Logarithmic g.f.: log( Product_{n >= 1} (1 + x^n)^(1/n) ) = Sum_{n >= 1} a(n)*x^n/n.
a(n) = A001227(n) - A183063(n). By considering the logarithmic generating functions of these three sequences we obtain the identity
( Product_{n >= 0} (1 - x^(2*n+1))^(1/(2*n+1)) )^2 = Product_{n >= 1} ( (1 - x^n)/(1 + x^n) )^(1/n). (End)
Dirichlet g.f.: zeta(s)*eta(s) = zeta(s)^2*(1-2^(-s+1)). - Ralf Stephan, Mar 27 2015
a(2*n - 1) = A099774(n). - Michael Somos, Aug 12 2017
From Paul D. Hanna, Aug 10 2019: (Start)
G.f.: Sum_{n>=0} x^n * Sum_{k=0..n} binomial(n,k) * (x^(n+1) - x^k)^(n-k) = Sum_{n>=0} a(n)*x^(2*n).
G.f.: Sum_{n>=0} x^n * Sum_{k=0..n} binomial(n,k) * (x^(n+1) + x^k)^(n-k) * (-1)^k = Sum_{n>=0} a(n)*x^(2*n). (End)
a(n) = 2*A000005(2n) - 3*A000005(n). - Ridouane Oudra, Oct 15 2019
Limit_{m->oo} (1/m) * Sum_{k=1..m} a(k)/A000005(k) = 2*log(2)-1. - Amiram Eldar, Mar 01 2023

Extensions

New definition from Vladeta Jovovic, Jan 27 2002

A060047 Triangle of generalized sum of divisors function, read by rows.

Original entry on oeis.org

1, 2, 4, 1, 4, 2, 6, 4, 8, 8, 8, 14, 8, 1, 18, 13, 2, 28, 12, 4, 40, 12, 8, 52, 16, 14, 70, 14, 24, 88, 16, 40, 104, 24, 1, 56, 140, 16, 2, 84, 168, 18, 4, 122, 196, 26, 8, 168, 240, 20, 14, 232, 278, 24, 24, 312, 320, 32, 40, 408, 380, 24, 64, 528, 440, 24, 100, 672, 504
Offset: 1

Views

Author

N. J. A. Sloane, Mar 19 2001

Keywords

Comments

Lengths of rows are 1 1 1 2 2 2 2 2 3 3 3 3 3 3 3 ... (A000196).

Examples

			Triangle turned on its side begins:
  1  2  4  4  6  8  8  8 13 12 12 ...
           1  2  4  8 14 18 28 40 ...
                          1  2  4 ...
For example, T(6,1) = 8, T(6,2) = 4.
		

Crossrefs

Formula

T(n, k) = sum of s_1*s_2*...*s_k where s_1, s_2, ..., s_k are such that s_1*(2*m_1-1) + s_2*(2*m_2-1) + ... + s_k*(2*m_k-1) = n and the sum is over all such k-partitions of n.
G.f. for k-th diagonal (the k-th row of the sideways triangle shown in the example): Sum_{ m_1 < m_2 < ... < m_k} q^(2*m_1+2*m_2+...+2*m_k-k)/((1-q^{2*m_1-1})*(1-q^{2*m_2-1})*...*(1-q^{2*m_k-1}))^2 = Sum_n T(n, k)*q^n.
G.f. for k-th diagonal: (-1)^k * (1/k) * ( Sum_{j>=k} (-1)^j * j * binomial(j+k-1,2*k-1) * q^(j^2) ) / ( 1 + 2 * Sum_{j>=1} (-q)^(j^2) ). - Seiichi Manyama, Sep 15 2023

Extensions

More terms from Naohiro Nomoto, Jan 24 2002
Showing 1-4 of 4 results.