cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-10 of 10 results.

A286368 a(n) = 4*A072401(n) + 2*A229062(n) + A010052(n).

Original entry on oeis.org

3, 2, 0, 3, 2, 0, 4, 2, 3, 2, 0, 0, 2, 0, 4, 3, 2, 2, 0, 2, 0, 0, 4, 0, 3, 2, 0, 4, 2, 0, 4, 2, 0, 2, 0, 3, 2, 0, 4, 2, 2, 0, 0, 0, 2, 0, 4, 0, 3, 2, 0, 2, 2, 0, 4, 0, 0, 2, 0, 4, 2, 0, 4, 3, 2, 0, 0, 2, 0, 0, 4, 2, 2, 2, 0, 0, 0, 0, 4, 2, 3, 2, 0, 0, 2, 0, 4, 0, 2, 2, 0, 4, 0, 0, 4, 0, 2, 2, 0, 3, 2, 0, 4, 2, 0, 2, 0, 0, 2, 0, 4, 4, 2, 0, 0, 2, 2, 0, 4, 0
Offset: 1

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Author

Antti Karttunen, May 08 2017

Keywords

Comments

Partitions natural numbers to the same equivalence classes as A002828. That is, for all i, j: a(i) = a(j) <=> A002828(i) = A002828(j). To get A002828 replace 0's with 3's, 3's with 1's and keep 2's as 2's and 4's as 4's.

Crossrefs

Programs

Formula

a(n) = 4*A072401(n) + 2*A229062(n) + A010052(n).

A004215 Numbers that are the sum of 4 but no fewer nonzero squares.

Original entry on oeis.org

7, 15, 23, 28, 31, 39, 47, 55, 60, 63, 71, 79, 87, 92, 95, 103, 111, 112, 119, 124, 127, 135, 143, 151, 156, 159, 167, 175, 183, 188, 191, 199, 207, 215, 220, 223, 231, 239, 240, 247, 252, 255, 263, 271, 279, 284, 287, 295, 303, 311, 316, 319, 327, 335, 343
Offset: 1

Views

Author

Keywords

Comments

Lagrange's theorem tells us that each positive integer can be written as a sum of four squares.
If n is in the sequence and k is an odd positive integer then n^k is in the sequence because n^k is of the form 4^i(8j+7). - Farideh Firoozbakht, Nov 23 2006
Numbers whose cubes do not have a partition as a sum of 3 squares. a(n)^3 = A134738(n). - Artur Jasinski, Nov 07 2007
A002828(a(n)) = 4; A025427(a(n)) > 0. - Reinhard Zumkeller, Feb 26 2015
There are infinitely many adjacent pairs (for example, 128n + 111 and 128n + 112 for any n), but never a triple of consecutive integers. - Ivan Neretin, Aug 17 2017
These numbers are called "forbidden numbers" in crystallography: for a cubic crystal, no reflection with index hkl such that h^2 + k^2 + l^2 = a(n) appears in the crystal's diffraction pattern. - A. Timothy Royappa, Aug 11 2021

Examples

			15 is in the sequence because it is the sum of four squares, namely, 3^2 + 2^2 + 1^2 + 1^2, and it can't be expressed as the sum of fewer squares.
16 is not in the sequence, because, although it can be expressed as 2^2 + 2^2 + 2^2 + 2^2, it can also be expressed as 4^2.
		

References

  • L. E. Dickson, History of the Theory of Numbers. Carnegie Institute Public. 256, Washington, DC, Vol. 1, 1919; Vol. 2, 1920; Vol. 3, 1923, see vol. 2, p. 261.
  • G. H. Hardy, Ramanujan: twelve lectures on subjects suggested by his life and work, Cambridge, University Press, 1940, p. 12.
  • E. Poznanski, 1901. Pierwiastki pierwotne liczb pierwszych. Warszawa, pp. 1-63.
  • W. Sierpiński, 1925. Teorja Liczb. pp. 1-410 (p. 125).
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
  • David Wells, The Penguin Dictionary of Curious and Interesting Numbers, entry 4181.

Crossrefs

Complement of A000378.
Cf. A000118 (ways to write n as sum of 4 squares), A025427.

Programs

  • Haskell
    a004215 n = a004215_list !! (n-1)
    a004215_list = filter ((== 4) . a002828) [1..]
    -- Reinhard Zumkeller, Feb 26 2015
    
  • Maple
    N:= 1000: # to get all terms <= N
    {seq(seq(4^i * (8*j + 7), j = 0 .. floor((N/4^i - 7)/8)), i = 0 .. floor(log[4](N)))}; # Robert Israel, Sep 02 2014
  • Mathematica
    Sort[Flatten[Table[4^i(8j + 7), {i, 0, 2}, {j, 0, 42}]]] (* Alonso del Arte, Jul 05 2005 *)
    Select[Range[120], Mod[ #/4^IntegerExponent[ #, 4], 8] == 7 &] (* Ant King, Oct 14 2010 *)
  • PARI
    isA004215(n)={ local(fouri,j) ; fouri=1 ; while( n >=7*fouri, if( n % fouri ==0, j= n/fouri -7 ; if( j % 8 ==0, return(1) ) ; ) ; fouri *= 4 ; ) ; return(0) ; } { for(n=1,400, if(isA004215(n), print1(n,",") ; ) ; ) ; } \\ R. J. Mathar, Nov 22 2006
    
  • PARI
    isA004215(n)= n\4^valuation(n,4)%8==7 \\ M. F. Hasler, Mar 18 2011
    
  • Python
    def valuation(n, b):
        v = 0
        while n > 1 and n%b == 0: n //= b; v += 1
        return v
    def ok(n): return n//4**valuation(n, 4)%8 == 7 # after M. F. Hasler
    print(list(filter(ok, range(344)))) # Michael S. Branicky, Jul 15 2021
    
  • Python
    from itertools import count, islice
    def A004215_gen(startvalue=1): # generator of terms >= startvalue
        return filter(lambda n:not (m:=(~n&n-1).bit_length())&1 and (n>>m)&7==7,count(max(startvalue,1)))
    A004215_list = list(islice(A004215_gen(),30)) # Chai Wah Wu, Jul 09 2022
    
  • Python
    def A004215(n):
        def bisection(f,kmin=0,kmax=1):
            while f(kmax) > kmax: kmax <<= 1
            kmin = kmax >> 1
            while kmax-kmin > 1:
                kmid = kmax+kmin>>1
                if f(kmid) <= kmid:
                    kmax = kmid
                else:
                    kmin = kmid
            return kmax
        def f(x): return n+x-sum(((x>>(i<<1))-7>>3)+1 for i in range(x.bit_length()>>1))
        return bisection(f,n,n) # Chai Wah Wu, Feb 14 2025

Formula

a(n) = A055039(n)/2. - Ray Chandler, Jan 30 2009
Numbers of the form 4^i*(8*j+7), i >= 0, j >= 0. [A.-M. Legendre & C. F. Gauss]
Products of the form A000302(i)*A004771(j), i, j >= 0. - R. J. Mathar, Nov 29 2006
a(n) = 6*n + O(log(n)). - Charles R Greathouse IV, Dec 19 2013
Conjecture: The number of terms < 2^n is A023105(n) - 2. - Tilman Neumann, Sep 20 2020

Extensions

More terms from Arlin Anderson (starship1(AT)gmail.com)
Additional comments from Jud McCranie, Mar 19 2000

A002828 Least number of squares that add up to n.

Original entry on oeis.org

0, 1, 2, 3, 1, 2, 3, 4, 2, 1, 2, 3, 3, 2, 3, 4, 1, 2, 2, 3, 2, 3, 3, 4, 3, 1, 2, 3, 4, 2, 3, 4, 2, 3, 2, 3, 1, 2, 3, 4, 2, 2, 3, 3, 3, 2, 3, 4, 3, 1, 2, 3, 2, 2, 3, 4, 3, 3, 2, 3, 4, 2, 3, 4, 1, 2, 3, 3, 2, 3, 3, 4, 2, 2, 2, 3, 3, 3, 3, 4, 2, 1, 2, 3, 3, 2, 3, 4, 3, 2, 2, 3, 4, 3, 3, 4, 3, 2, 2, 3, 1, 2, 3, 4, 2, 3
Offset: 0

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Author

Keywords

Comments

Lagrange's "Four Squares theorem" states that a(n) <= 4.
It is easy to show that this is also the least number of squares that add up to n^3.
a(n) is the number of iterations in f(...f(f(n))...) to reach 0, where f(n) = A262678(n) = n - A262689(n)^2. Allows computation of this sequence without Lagrange's theorem. - Antti Karttunen, Sep 09 2016
It is also easy to show that a(k^2*n) = a(n) for k > 0: Clearly a(k^2*n) <= a(n) but for all 4 cases of a(n) there is no k which would result in a(k^2*n) < a(n). - Peter Schorn, Sep 06 2021

References

  • N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Crossrefs

Programs

  • Haskell
    a002828 0 = 0  -- confessedly  /= 1, as sum [] == 0
    a002828 n | a010052 n == 1 = 1
              | a025426 n > 0 = 2 | a025427 n > 0 = 3 | otherwise = 4
    -- Reinhard Zumkeller, Feb 26 2015
    
  • Maple
    with(transforms);
    sq:=[seq(n^2, n=1..20)];
    LAGRANGE(sq,4,120);
    # alternative:
    f:= proc(n) local F,x;
       if issqr(n) then return 1 fi;
       if nops(select(t -> t[1] mod 4 = 3 and t[2]::odd, ifactors(n)[2])) = 0 then return 2 fi;
       x:= n/4^floor(padic:-ordp(n,2)/2);
       if x mod 8 = 7 then 4 else 3 fi
    end proc:
    0, seq(f(n),n=1..200); # Robert Israel, Jun 14 2016
    # next Maple program:
    b:= proc(n, i) option remember; convert(series(`if`(n=0, 1, `if`(i<1, 0,
          b(n, i-1)+(s-> `if`(s>n, 0, x*b(n-s, i)))(i^2))), x, 5), polynom)
        end:
    a:= n-> ldegree(b(n, isqrt(n))):
    seq(a(n), n=0..105);  # Alois P. Heinz, Oct 30 2021
  • Mathematica
    SquareCnt[n_] := If[SquaresR[1, n] > 0, 1, If[SquaresR[2, n] > 0, 2, If[SquaresR[3, n] > 0, 3, 4]]]; Table[SquareCnt[n], {n, 150}] (* T. D. Noe, Apr 01 2011 *)
    sc[n_]:=Module[{s=SquaresR[Range[4],n]},If[First[s]>0,1,Length[ First[ Split[ s]]]+1]]; Join[{0},Array[sc,110]] (* Harvey P. Dale, May 21 2014 *)
  • PARI
    istwo(n:int)=my(f);if(n<3,return(n>=0););f=factor(n>>valuation(n, 2)); for(i=1,#f[,1],if(bitand(f[i,2],1)==1&&bitand(f[i,1],3)==3, return(0)));1
    isthree(n:int)=my(tmp=valuation(n,2));bitand(tmp,1)||bitand(n>>tmp,7)!=7
    a(n)=if(isthree(n), if(issquare(n), !!n, 3-istwo(n)), 4) \\ Charles R Greathouse IV, Jul 19 2011, revised Mar 17 2022
    
  • Python
    from sympy import factorint
    def A002828(n):
        if n == 0: return 0
        f = factorint(n).items()
        if not any(e&1 for p,e in f): return 1
        if all(p&3<3 or e&1^1 for p,e in f): return 2
        return 3+(((m:=(~n&n-1).bit_length())&1^1)&int((n>>m)&7==7)) # Chai Wah Wu, Aug 01 2023
    
  • Python
    from sympy.core.power import isqrt
    def A002828(n):
        dp = [-1] * (n + 1)
        dp[0] = 0
        for i in range(1, n + 1):
            S = []
            r = isqrt(i)
            for j in range(1, r + 1):
                S.append(1 + dp[i - (j**2)])
            dp[i] = min(S)
        return dp[-1] # Darío Clavijo, Apr 21 2025
  • Scheme
    ;; The first one follows Charles R Greathouse IV's PARI-code above:
    (define (A002828 n) (cond ((zero? n) n) ((= 1 (A010052 n)) 1) ((= 1 (A229062 n)) 2) (else (+ 3 (A072401 n)))))
    (define (A229062 n) (- 1 (A000035 (A260728 n))))
    ;; We can also compute this without relying on Lagrange's theorem. The following recursion-formula should be used together with the second Scheme-implementation of A262689 given in the Program section that entry:
    (definec (A002828 n) (if (zero? n) n (+ 1 (A002828 (- n (A000290 (A262689 n)))))))
    ;; Antti Karttunen, Sep 09 2016
    

Formula

From Antti Karttunen, Sep 09 2016: (Start)
a(0) = 0; and for n >= 1, if A010052(n) = 1 [when n is a square], a(n) = 1, otherwise, if A229062(n)=1, then a(n) = 2, otherwise a(n) = 3 + A072401(n). [After Charles R Greathouse IV's PARI program.]
a(0) = 0; for n >= 1, a(n) = 1 + a(n - A262689(n)^2), (see comments).
a(n) = A053610(n) - A062535(n).
(End)

Extensions

More terms from Arlin Anderson (starship1(AT)gmail.com)

A000378 Sums of three squares: numbers of the form x^2 + y^2 + z^2.

Original entry on oeis.org

0, 1, 2, 3, 4, 5, 6, 8, 9, 10, 11, 12, 13, 14, 16, 17, 18, 19, 20, 21, 22, 24, 25, 26, 27, 29, 30, 32, 33, 34, 35, 36, 37, 38, 40, 41, 42, 43, 44, 45, 46, 48, 49, 50, 51, 52, 53, 54, 56, 57, 58, 59, 61, 62, 64, 65, 66, 67, 68, 69, 70, 72, 73, 74, 75, 76, 77, 78, 80, 81, 82, 83
Offset: 1

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Author

Keywords

Comments

An equivalent definition: numbers of the form x^2 + y^2 + z^2 with x,y,z >= 0.
Bourgain studies "the spatial distribution of the representation of a large integer as a sum of three squares, on the small and critical scale as well as their electrostatic energy. The main results announced give strong evidence to the thesis that the solutions behave randomly. This is in sharp contrast to what happens with sums of two or four or more square." Sums of two nonzero squares are A000404. - Jonathan Vos Post, Apr 03 2012
The multiplicities for a(n) (if 0 <= x <= y <= z) are given as A000164(a(n)), n >= 1. Compare with A005875(a(n)) for integer x, y and z, and order taken into account. - Wolfdieter Lang, Apr 08 2013
a(n)^k is a member of this sequence for any k > 1. - Boris Putievskiy, May 05 2013
The selection rule for the planes with Miller indices (hkl) to undergo X-ray diffraction in a simple cubic lattice is h^2+k^2+l^2 = N where N is a term of this sequence. See A004014 for f.c.c. lattice. - Mohammed Yaseen, Nov 06 2022

Examples

			a(1) = 0 = 0^2 + 0^2 + 0^2. A005875(0) = 1 = A000164(0).
a(9) = 9 = 0^2 + 0^2 + 3^2 =  1^2 +  2^2 + 2^2. A000164(9) = 2. A000164(9) = 30 = 2*3 + 8*3 (counting signs and order). - _Wolfdieter Lang_, Apr 08 2013
		

References

  • J. H. Conway and N. J. A. Sloane, "Sphere Packings, Lattices and Groups", Springer-Verlag, p. 107.
  • E. Grosswald, Representations of Integers as Sums of Squares. Springer-Verlag, NY, 1985, p. 37.
  • R. K. Guy, Unsolved Problems in Number Theory, Springer, 1st edition, 1981. See section C20.
  • G. H. Hardy and E. M. Wright, An Introduction to the Theory of Numbers. 3rd ed., Oxford Univ. Press, 1954, p. 311.

Crossrefs

Union of A000290, A000404 and A000408 (common elements).
Union of A000290, A000415 and A000419 (disjunct sets).
Complement of A004215.
Cf. A005875 (number of representations if x, y and z are integers).

Programs

  • Maple
    isA000378 := proc(n) # return true or false depending on n being in the list
        local x,y ;
        for x from 0 do
            if 3*x^2 > n then
                return false;
            end if;
            for y from x do
                if x^2+2*y^2 > n then
                    break;
                else
                    if issqr(n-x^2-y^2) then
                        return true;
                    end if;
                end if;
            end do:
        end do:
    end proc:
    A000378 := proc(n) # generate A000378(n)
        option remember;
        local a;
        if n = 1 then
            0;
        else
            for a from procname(n-1)+1 do
                if isA000378(a) then
                    return a;
                end if;
            end do:
        end if;
    end proc:
    seq(A000378(n),n=1..100) ; # R. J. Mathar, Sep 09 2015
  • Mathematica
    okQ[n_] := If[EvenQ[k = IntegerExponent[n, 2]], m = n/2^k; Mod[m, 8] != 7, True]; Select[Range[0, 100], okQ] (* Jean-François Alcover, Feb 08 2016, adapted from PARI *)
  • PARI
    isA000378(n)=my(k=valuation(n, 2)); if(k%2==0, n>>=k; n%8!=7, 1)
    
  • PARI
    list(lim)=my(v=List(),k,t); for(x=0,sqrtint(lim\=1), for(y=0, min(sqrtint(lim-x^2),x), k=x^2+y^2; for(z=0,min(sqrtint(lim-k), y), listput(v,k+z^2)))); Set(v) \\ Charles R Greathouse IV, Sep 14 2015
    
  • Python
    def valuation(n, b):
        v = 0
        while n > 1 and n%b == 0: n //= b; v += 1
        return v
    def ok(n): return n//4**valuation(n, 4)%8 != 7
    print(list(filter(ok, range(84)))) # Michael S. Branicky, Jul 15 2021
    
  • Python
    from itertools import count, islice
    def A000378_gen(): # generator of terms
        return filter(lambda n:n>>2*(bin(n)[:1:-1].index('1')//2) & 7 < 7, count(1))
    A000378_list = list(islice(A000378_gen(),30)) # Chai Wah Wu, Jun 27 2022
    
  • Python
    def A000378(n):
        def f(x): return n-1+sum(((x>>(i<<1))-7>>3)+1 for i in range(x.bit_length()>>1))
        m, k = n-1, f(n-1)
        while m != k: m, k = k, f(k)
        return m # Chai Wah Wu, Feb 14 2025

Formula

Legendre: a nonnegative integer is a sum of three squares iff it is not of the form 4^k m with m == 7 (mod 8).
n^(2k+1) is in the sequence iff n is in the sequence. - Ray Chandler, Feb 03 2009
Complement of A004215; complement of A000302(i)*A004771(j), i,j>=0. - Boris Putievskiy, May 05 2013
a(n) = 6n/5 + O(log n). - Charles R Greathouse IV, Mar 14 2014

Extensions

More terms from Ray Chandler, Sep 05 2004

A064873 First of four sequences representing the lexicographical minimal decomposition of n in 4 squares: n = a(n)^2 + A064874(n)^2 + A064875(n)^2 + A064876(n)^2.

Original entry on oeis.org

0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0
Offset: 0

Views

Author

Reinhard Zumkeller, Oct 10 2001

Keywords

Comments

A072401(n) = A057427(a(n)).
For k<112: a(n)=A072401(n), but A072401(112) = 1<>a(112)=2, as also A072401(112 - 1) = 1.

Examples

			a(25) = 0: 25 = a(25)^2 + A064874(25)^2 + A064875(25)^2 + A064876(25)^2 = 0 + 0 + 0 + 25 and the other decompositions (0, 0, 3, 4) and (1, 2, 2, 4) are greater than (0, 0, 0, 5).
		

Crossrefs

A072400 (Factors of 4 removed from n) modulo 8.

Original entry on oeis.org

1, 2, 3, 1, 5, 6, 7, 2, 1, 2, 3, 3, 5, 6, 7, 1, 1, 2, 3, 5, 5, 6, 7, 6, 1, 2, 3, 7, 5, 6, 7, 2, 1, 2, 3, 1, 5, 6, 7, 2, 1, 2, 3, 3, 5, 6, 7, 3, 1, 2, 3, 5, 5, 6, 7, 6, 1, 2, 3, 7, 5, 6, 7, 1, 1, 2, 3, 1, 5, 6, 7, 2, 1, 2, 3, 3, 5, 6, 7, 5, 1, 2, 3, 5, 5, 6, 7, 6, 1, 2, 3, 7, 5, 6, 7, 6
Offset: 1

Views

Author

Reinhard Zumkeller, Jun 16 2002

Keywords

Comments

a(n) <> 7 iff n equals the sum of 3 integer squares.
a(A004215(k)) = 7 for k>0;

Examples

			From _Michael De Vlieger_, May 08 2017: (Start)
a(4) = 1 since 4 = 1 * 4^1 and 4 / 4^1 = 1; 1 = 1 (mod 8).
a(5) = 5 since it is not a multiple of 4; 5 = 5 (mod 8).
a(12) = 3 since 12 = 3 * 4^1 and 12 / 4^1 = 3; 3 = 3 (mod 8).
a(44) = 3 since 44 = 11 * 4^1 and 44 / 4^1 = 11; 3 = 11 (mod 8).
a(64) = 1 since 64 = 1 * 4^3 and 64 / 4^3 = 1; 1 = 1 (mod 8). (End)
		

Crossrefs

Programs

  • Mathematica
    Array[Mod[If[Mod[#, 4] == 0, #/4^IntegerExponent[#, 4], #], 8] &, 96] (* Michael De Vlieger, May 08 2017 *)
  • PARI
    a(n) = (n >> (2*valuation(n, 4))) % 8; \\ Amiram Eldar, May 15 2025
  • Python
    def A072400(n): return (n>>((~n&n-1).bit_length()&-2))&7 # Chai Wah Wu, Aug 01 2023
    

Formula

a(n) = A065883(n) mod 8.
A072401(n) = 1 - A057427(7 - a(n)).
Asymptotic mean: Limit_{m->oo} (1/m) * Sum_{k=1..m} a(k) = 4. - Amiram Eldar, May 15 2025

Extensions

Offset corrected (from 0 to 1) by Antti Karttunen, May 08 2017

A278494 Primes p for which there does not exist any such integer k that k - A002828(k) = p.

Original entry on oeis.org

2, 5, 7, 13, 17, 23, 29, 31, 37, 47, 61, 79, 89, 97, 101, 103, 109, 113, 127, 157, 167, 193, 197, 199, 223, 229, 241, 257, 269, 271, 281, 293, 313, 317, 337, 353, 359, 383, 389, 397, 401, 409, 421, 433, 439, 449, 461, 463, 487, 509, 541, 569, 577, 593, 601, 607, 631, 647, 653, 673, 677, 709, 719, 727, 751, 761, 769, 773, 797
Offset: 1

Views

Author

Antti Karttunen, Nov 25 2016, with additional comments Nov 28 2016

Keywords

Comments

Primes that are leaves in the tree defined by edge relation parent = A255131(child), "the least squares beanstalk".
Primes p such that (A002828(1+p) <> 1), (A002828(2+p) <> 2), (A002828(3+p) <> 3) and (A002828(4+p) <> 4).
See comments in A278495 which gives the count of these primes in each range [n^2, (n+1)^2].
This is a subsequence of A045352 as no prime of the form 8n+3 ever occurs in this sequence. This stems from a more general fact that A278490 contains no numbers of the form 8n+3, because A002828(8n+7) = 4 for all n. (See A004215.)

Crossrefs

Intersection of A000040 and A278490.
No common terms with A277888, some common terms with A278487.
Subsequence of A045352.
Cf. also A263091.

A071374 0 iff n is of the form 4^a*(8k+7), otherwise 1.

Original entry on oeis.org

1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 0, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 0, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 0, 1, 1, 0, 1, 1, 1
Offset: 0

Views

Author

N. J. A. Sloane, Jun 12 2002

Keywords

Comments

0 iff n is not the sum of three squares.

Crossrefs

1's complement to A072401. Cf. A071377.

Programs

  • PARI
    a(n) = if(n, (n >> (2*valuation(n, 4))) % 8 < 7, 1); \\ Amiram Eldar, May 15 2025

Formula

From Amiram Eldar, May 15 2025: (Start)
a(n) = 1 - A072401(n);
Asymptotic mean: Limit_{m->oo} (1/m) * Sum_{k=1..m} a(k) = 5/6. (End)

A277193 Number of integers k in range [n^2, ((n+1)^2)-1] for which 3 = the least number of squares that add up to k (A002828).

Original entry on oeis.org

0, 1, 1, 3, 4, 4, 6, 6, 8, 9, 9, 12, 11, 14, 15, 14, 17, 18, 19, 19, 23, 20, 24, 25, 25, 26, 29, 29, 30, 32, 32, 32, 36, 36, 37, 39, 41, 40, 42, 43, 45, 45, 47, 46, 50, 49, 50, 54, 52, 55, 56, 57, 60, 60, 63, 60, 62, 65, 68, 64, 67, 70, 72, 69, 73, 74, 75, 76, 78, 78, 80, 84, 79, 85, 84, 84, 88, 89, 90, 90, 91, 94, 94, 97, 94, 99
Offset: 0

Views

Author

Antti Karttunen, Oct 04 2016

Keywords

Crossrefs

After the initial zero, one less than A277191.

Programs

  • Scheme
    (define (A277193 n) (add (lambda (i) (* (- 1 (A010052 i)) (- 1 (A229062 i)) (- 1 (A072401 i)))) (A000290 n) (+ -1 (A000290 (+ 1 n)))))
    ;; Implements sum_{i=lowlim..uplim} intfun(i)
    (define (add intfun lowlim uplim) (let sumloop ((i lowlim) (res 0)) (cond ((> i uplim) res) (else (sumloop (1+ i) (+ res (intfun i)))))))

Formula

Sum_{i=n^2 .. ((n+1)^2)-1} (1-A010052(i))*(1-A229062(i))*(1-A072401(i)).
Other identities. For all n >= 0:
1 + A077773(n) + a(n) + A277194(n) = 2n+1.
For n >= 1, a(n) = A277191(n)-1.

A277194 Number of integers k in range [n^2, ((n+1)^2)-1] for which 4 = the least number of squares that add up to k (A002828).

Original entry on oeis.org

0, 0, 1, 1, 1, 2, 2, 3, 2, 3, 4, 4, 4, 4, 5, 6, 5, 5, 6, 7, 6, 8, 8, 8, 8, 8, 8, 10, 9, 10, 11, 11, 10, 11, 11, 12, 11, 13, 14, 13, 13, 13, 15, 15, 15, 15, 16, 16, 15, 17, 17, 17, 17, 17, 19, 19, 18, 19, 19, 21, 20, 21, 21, 22, 21, 21, 22, 23, 22, 23, 23, 25, 23, 24, 26, 25, 26, 26, 26, 27, 26, 27, 27, 28, 29, 28, 29, 30, 29, 30, 30, 31
Offset: 0

Views

Author

Antti Karttunen, Oct 04 2016

Keywords

Crossrefs

Programs

  • Scheme
    (define (A277194 n) (add A072401 (A000290 n) (+ -1 (A000290 (+ 1 n)))))
    ;; Implements sum_{i=lowlim..uplim} intfun(i)
    (define (add intfun lowlim uplim) (let sumloop ((i lowlim) (res 0)) (cond ((> i uplim) res) (else (sumloop (1+ i) (+ res (intfun i)))))))

Formula

a(n) = Sum_{i=n^2 .. ((n+1)^2)-1} A072401(i).
Other identities.
For n >= 0, 1 + A077773(n) + A277193(n) + a(n) = 2n+1.
For n >= 1, A277192(n) = A077773(n) + a(n).
Showing 1-10 of 10 results.